1 Nicolaas Vroom | The two postulates in Special Relativity | Wednesday 6 may 2015 |
2 robert bristow-johnson | Re :The two postulates in Special Relativity | Thursday 7 may 2015 |
3 Gerry Quinn | Re :The two postulates in Special Relativity | Saturday 9 may 2015 |
4 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 13 may 2015 |
5 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 19 may 2015 |
6 robert bristow-johnson | Re :The two postulates in Special Relativity | Wednesday 20 may 2015 |
7 Tom Roberts | Re :The two postulates in Special Relativity | Thursday 21 may 2015 |
8 Hendrik van Hees | Re :The two postulates in Special Relativity | Saturday 23 may 2015 |
9 al...@interia.pl | Re :The two postulates in Special Relativity | Sunday 24 may 2015 |
10 robert bristow-johnson | Re :The two postulates in Special Relativity | Monday 25 may 2015 |
11 Roland Franzius | Re :The two postulates in Special Relativity | Monday 25 may 2015 |
12 al...@interia.pl | Re :The two postulates in Special Relativity | Wednesday 27 may 2015 |
13 Jos Bergervoet | Re :The two postulates in Special Relativity | Wednesday 27 may 2015 |
14 Roland Franzius | Re :The two postulates in Special Relativity | Wednesday 27 may 2015 |
15 Nicolaas Vroom | Re :The two postulates in Special Relativity | Friday 29 may 2015 |
16 al...@interia.pl | Re :The two postulates in Special Relativity | Saturday 30 may 2015 |
17 al...@interia.pl | Re :The two postulates in Special Relativity | Saturday 30 may 2015 |
18 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 1 june 2015 |
19 Gary Harnagel | Re :The two postulates in Special Relativity | Monday 1 june 2015 |
20 Nicolaas Vroom | Re :The two postulates in Special Relativity | Friday 5 june 2015 |
21 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 6 june 2015 |
22 Gary Harnagel | Re :The two postulates in Special Relativity | Saturday 6 june 2015 |
23 Gerry Quinn | Re :The two postulates in Special Relativity | Saturday 6 june 2015 |
24 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 9 june 2015 |
25 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 9 june 2015 |
26 Gerry Quinn | Re :The two postulates in Special Relativity | Thursday 11 june 2015 |
27 al...@interia.pl | Re :The two postulates in Special Relativity | Saturday 13 june 2015 |
28 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 20 june 2015 |
29 Roland Franzius | Re :The two postulates in Special Relativity | Saturday 20 june 2015 |
30 al...@interia.pl | Re :The two postulates in Special Relativity | Saturday 20 june 2015 |
31 Tom Roberts | Re :The two postulates in Special Relativity | Saturday 20 june 2015 |
32 Gerry Quinn | Re :The two postulates in Special Relativity | Saturday 27 june 2015 |
33 Nicolaas Vroom | Re :The two postulates in Special Relativity | Sunday 28 june 2015 |
34 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 29 june 2015 |
35 Tom Roberts | Re :The two postulates in Special Relativity | Friday 3 july 2015 |
36 Gerry Quinn | Re :The two postulates in Special Relativity | Monday 6 july 2015 |
37 John Heath | Re :The two postulates in Special Relativity | Saturday 11 july 2015 |
38 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 5 augustus 2015 |
39 Nicolaas Vroom | Re :The two postulates in Special Relativity | Wednesday 12 augustus 2015 |
40 Gregor Scholten | Re :The two postulates in Special Relativity | Monday 17 augustus 2015 |
41 Tom Roberts | Re :The two postulates in Special Relativity | Saturday 22 augustus 2015 |
42 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 8 september 2015 |
43 Nicolaas Vroom | Re :The two postulates in Special Relativity | Thursday 10 september 2015 |
44 Gregor Scholten | Re :The two postulates in Special Relativity | Thursday 10 september 2015 |
45 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 12 september 2015 |
46 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 12 september 2015 |
47 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 29 september 2015 |
48 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 11 october 2015 |
49 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 17 october 2015 |
50 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 17 october 2015 |
51 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 25 october 2015 |
52 Oliver Jennrich | Re :The two postulates in Special Relativity | Sunday 25 october 2015 |
53 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 28 november 2015 |
54 Gregor Scholten | Re :The two postulates in Special Relativity | Tuesday 1 december 2015 |
55 John Heath | Re :The two postulates in Special Relativity | Monday 7 december 2015 |
56 Gregor Scholten | Re :The two postulates in Special Relativity | Tuesday 8 december 2015 |
57 John Heath | Re :The two postulates in Special Relativity | Thursday 10 december 2015 |
58 Gregor Scholten | Re :The two postulates in Special Relativity | Friday 11 december 2015 |
59 Gary Harnagel | Re :The two postulates in Special Relativity | Friday 11 december 2015 |
60 John Heath | Re :The two postulates in Special Relativity | Friday 11 december 2015 |
61 Jonathan Thornburg | Re :The two postulates in Special Relativity | Saturday 12 december 2015 |
62 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 12 december 2015 |
63 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 12 december 2015 |
64 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 13 december 2015 |
65 Gerry Quinn | Re :The two postulates in Special Relativity | Sunday 13 december 2015 |
66 Gary Harnagel | Re :The two postulates in Special Relativity | Sunday 13 december 2015 |
67 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 13 december 2015 |
68 Steven Carlip | Re :The two postulates in Special Relativity | Monday 14 december 2015 |
69 John Heath | Re :The two postulates in Special Relativity | Tuesday 15 december 2015 |
70 Jos Bergervoet | Re :The two postulates in Special Relativity | Tuesday 15 december 2015 |
71 John Heath | Re :The two postulates in Special Relativity | Tuesday 15 december 2015 |
72 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 16 december 2015 |
73 Gregor Scholten | Re :The two postulates in Special Relativity | Wednesday 16 december 2015 |
74 Gregor Scholten | Re :The two postulates in Special Relativity | Friday 18 december 2015 |
75 John Heath | Re :The two postulates in Special Relativity | Friday 18 december 2015 |
76 Gerry Quinn | Re :The two postulates in Special Relativity | Friday 18 december 2015 |
77 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 19 december 2015 |
78 Gary Harnagel | Re :The two postulates in Special Relativity | Sunday 20 december 2015 |
79 Tom Roberts | Re :The two postulates in Special Relativity | Sunday 20 december 2015 |
80 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 20 december 2015 |
81 Gerry Quinn | Re :The two postulates in Special Relativity | Sunday 20 december 2015 |
82 Gerry Quinn | Re :The two postulates in Special Relativity | Monday 21 december 2015 |
83 Gerry Quinn | Re :The two postulates in Special Relativity | Monday 21 december 2015 |
84 Jonathan Thornburg | Re :The two postulates in Special Relativity | Thursday 31 december 2015 |
85 Jonathan Thornburg | Re :The two postulates in Special Relativity | Thursday 31 december 2015 |
86 Gerry Quinn | Re :The two postulates in Special Relativity | Friday 1 january 2016 |
87 John Heath | Re :The two postulates in Special Relativity | Friday 1 january 2016 |
88 Jonathan Thornburg | Re :The two postulates in Special Relativity | Saturday 2 january 2016 |
89 Tom Roberts | Re :The two postulates in Special Relativity | Monday 11 january 2016 |
90 Gerry Quinn | Re :The two postulates in Special Relativity | Tuesday 12 january 2016 |
91 John Heath | Re :The two postulates in Special Relativity | Wednesday 13 january 2016 |
92 Jos Bergervoet | Re :The two postulates in Special Relativity | Wednesday 13 january 2016 |
93 Gerry Quinn | Re :The two postulates in Special Relativity | Friday 15 january 2016 |
94 Jos Bergervoet | Re :The two postulates in Special Relativity | Sunday 17 january 2016 |
95 Gary Harnagel | Re :The two postulates in Special Relativity | Sunday 17 january 2016 |
96 Mike Fontenot | Re :The two postulates in Special Relativity | Sunday 17 january 2016 |
97 Tom Roberts | Re :The two postulates in Special Relativity | Sunday 17 january 2016 |
98 Jos Bergervoet | Re :The two postulates in Special Relativity | Monday 18 january 2016 |
99 Jos Bergervoet | Re :The two postulates in Special Relativity | Monday 18 january 2016 |
100 Tom Roberts | Re :The two postulates in Special Relativity | Tuesday 19 january 2016 |
101 John Heath | Re :The two postulates in Special Relativity | Wednesday 20 january 2016 |
102 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 20 january 2016 |
103 Mike Fontenot | Re :The two postulates in Special Relativity | Wednesday 20 january 2016 |
104 erkd...@gmail.com | Re :The two postulates in Special Relativity | Sunday 28 february 2016 |
105 Eric Baird | Re :The two postulates in Special Relativity | Tuesday 10 may 2016 |
106 Ralph Frost | Re :The two postulates in Special Relativity | Friday 13 may 2016 |
107 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 16 may 2016 |
108 Jos Bergervoet | Re :The two postulates in Special Relativity | Monday 16 may 2016 |
109 Poutnik | Re :The two postulates in Special Relativity | Friday 20 may 2016 |
110 Nicolaas Vroom | Re :The two postulates in Special Relativity | Friday 20 may 2016 |
111 Poutnik | Re :The two postulates in Special Relativity | Saturday 21 may 2016 |
112 Tom Roberts | Re :The two postulates in Special Relativity | Sunday 22 may 2016 |
113 Nicolaas Vroom | Re :The two postulates in Special Relativity | Tuesday 24 may 2016 |
114 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 1 june 2016 |
115 Nicolaas Vroom | Re :The two postulates in Special Relativity | Sunday 5 june 2016 |
116 John Heath | Re :The two postulates in Special Relativity | Wednesday 22 june 2016 |
117 Nicolaas Vroom | Re :The two postulates in Special Relativity | Thursday 30 june 2016 |
118 Phillip Helbig | Re :The two postulates in Special Relativity | Friday 1 july 2016 |
119 Oliver Jennrich | Re :The two postulates in Special Relativity | Saturday 2 july 2016 |
120 Phillip Helbig | Re :The two postulates in Special Relativity | Saturday 2 july 2016 |
121 Dr J R Stockton | Re :The two postulates in Special Relativity | Sunday 3 july 2016 |
122 Nicolaas Vroom | Re :The two postulates in Special Relativity | Sunday 3 july 2016 |
123 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 3 july 2016 |
124 Nicolaas Vroom | Re :The two postulates in Special Relativity | Thursday 7 july 2016 |
125 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 10 july 2016 |
126 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 10 july 2016 |
127 Tom Roberts | Re :The two postulates in Special Relativity | Wednesday 13 july 2016 |
128 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 18 july 2016 |
129 Gregor Scholten | Re :The two postulates in Special Relativity | Tuesday 19 july 2016 |
130 Tom Roberts | Re :The two postulates in Special Relativity | Thursday 21 july 2016 |
131 Nicolaas Vroom | Re :The two postulates in Special Relativity | Friday 22 july 2016 |
132 Tom Roberts | Re :The two postulates in Special Relativity | Friday 22 july 2016 |
133 Phillip Helbig | Re :The two postulates in Special Relativity | Saturday 23 july 2016 |
134 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 23 july 2016 |
135 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 25 july 2016 |
136 Dr J R Stockton | Re :The two postulates in Special Relativity | Sunday 31 july 2016 |
137 Gregor Scholten | Re :The two postulates in Special Relativity | Sunday 7 augustus 2016 |
138 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 15 augustus 2016 |
139 Gregor Scholten | Re :The two postulates in Special Relativity | Monday 29 augustus 2016 |
140 Nicolaas Vroom | Re :The two postulates in Special Relativity | Saturday 29 october 2016 |
141 Tom Roberts | Re :The two postulates in Special Relativity | Tuesday 8 november 2016 |
142 Nicolaas Vroom | Re :The two postulates in Special Relativity | Sunday 13 november 2016 |
143 Phillip Helbig | Re :The two postulates in Special Relativity | Sunday 13 november 2016 |
144 Roland Franzius | Re :The two postulates in Special Relativity | Sunday 13 november 2016 |
145 Gregor Scholten | Re :The two postulates in Special Relativity | Wednesday 16 november 2016 |
146 Poutnik | Re :The two postulates in Special Relativity | Wednesday 16 november 2016 |
147 Gregor Scholten | Re :The two postulates in Special Relativity | Friday 18 november 2016 |
148 Nicolaas Vroom | Re :The two postulates in Special Relativity | Friday 18 november 2016 |
149 Gregor Scholten | Re :The two postulates in Special Relativity | Friday 18 november 2016 |
150 Poutnik | Re :The two postulates in Special Relativity | Monday 21 november 2016 |
151 Maryann Tonn | Re :The two postulates in Special Relativity | Monday 21 november 2016 |
152 Nicolaas Vroom | Re :The two postulates in Special Relativity | Wednesday 30 november 2016 |
153 Gregor Scholten | Re :The two postulates in Special Relativity | Saturday 1 october 2016 |
154 Nicolaas Vroom | Re :The two postulates in Special Relativity | Monday 5 december 2016 |
> | We NOW know this is NOT what relativity says. In relativity, all clocks tick at their usual rates, regardless of how they might move or where they might be located (e.g. in a gravitational field). |
In the book "Subtle is the Lord..." by Abraham Pais at page 140
and 141 we read:
The two postulates:
1. The laws of physics take the same form in all inertial frames.
2. In any given inertial system the velocity of light c is the same
whether the light be emitted by a body at rest or by a body in uniform
motion.
At page 138 we read: "By definition, any two of these (inertial frames) are in uniform motion with respect to each other"
Consider the following three situations: 1. a light at rest which emits a flash at position p1 at t1. 2. an uniform moving light which also emits a flash at p1 at t1. 3. an accelerating moving light which does the same. Question: for any observer at a certain distance are this one or three distinquished physical events? IMO: It is one physical event. From a frequency point of view this is a different story.
[[Mod. note -- Assuming that when you say "at rest" or "uniformly moving" or "accelerating" you really mean "... with respect to some specified inertial frame", then you're correct: neglecting any doppler shift of the light, a distant observer can't distinguish between situation 1, situation 2, and situation 3. (This remains true regardless of the distant observer's state of motion with respect to the inertial frame.) -- jt]]
When I study postulate 1 immediate certain some thoughts pop up: Which type of physical processes are we discussing here? Are this all physical processes or only some (i.e. subset)? Laws are descriptions of physical processes. That means (if my interpretation is correct) that all physical processes are indepent of uniform movement until the speed of light. This sounds "too optimistic" specific if you consider these clocks which inner working uses light signals to operate (i.e. counts)
The following article is very interesting: http://www.nist.gov/pml/div689/20150421_strontium_clock.cfm. It writes: "Precision refers to how closely the clock approaches the true resonant frequency at which the strontium atoms oscillate between two electronic energy levels." Also here the question arises to which extend these oscillations are independent of the speed of the clock and does not influence the ticking rate.
A whole different thought is: why are accelarations not discussed?
Nicolaas Vroom Click here to Reply
> |
In the book "Subtle is the Lord..." by Abraham Pais at page 140 and 141 we read: The two postulates: 1. The laws of physics take the same form in all inertial frames. 2. In any given inertial system the velocity of light c is the same whether the light be emitted by a body at rest or by a body in uniform motion. |
this doesn't seem to be widely accepted (not sure why), but i've always felt that postulate #2 comes directly from postulate #1. if the laws of physics are the same for all inertial frames of reference, every observer has the same epsilon_0 and mu_0 in their laws of physics. so c=(epsilon_0*mu_0)^(-1/2) is the same for every inertial observer hanging around in a vacuum.
and all postulate #1 says is that if a vacuum is physically nothing, you can't tell if a vacuum is whizzing past you at a speed of c/2 or not. the relative speed of a physical nothing is meaningless. so you could be whizzing past me at a constant relative speed of c/2, but there is no aether wind blowing in your face nor in mine. we both have equal claim to being "at rest". when we look at the **same** flash or beam of light, since we both have the same physics (because we're *both* "at rest"), then we both measure the speed of that flash of light to be the same speed. the only way for that to happen is if we both observe the other's clock as ticking more slowly than our own.
so, in my opinion, there is only one necessary postulate to special relativity and it is the first postulate.
> |
At page 138 we read: "By definition, any two of these (inertial frames)
are in uniform motion with respect to each other"
Consider the following three situations: 1. a light at rest which emits a flash at position p1 at t1. 2. an uniform moving light which also emits a flash at p1 at t1. 3. an accelerating moving light which does the same. Question: for any observer at a certain distance are this one or three distinquished physical events? IMO: It is one physical event. From a frequency point of view this is a different story. |
once the EM wave departs the mechanism that created it (the emitter), all we have is a changing electric field which causes a changing magnetic field which, in turn, causes a changing electric field which causes another changing magnetic field, etc.
the light is a propagating EM field and, once emitted, has no idea about the emitter including what the velocity or motion the emitter had.
--
r b-j r...@audioimagination.com
"Imagination is more important than knowledge."
> | On 5/5/15 9:24 PM, Nicolaas Vroom wrote: |
> > |
In the book "Subtle is the Lord..." by Abraham Pais at page 140 and 141 we read: The two postulates: 1. The laws of physics take the same form in all inertial frames. 2. In any given inertial system the velocity of light c is the same whether the light be emitted by a body at rest or by a body in uniform motion. |
> |
this doesn't seem to be widely accepted (not sure why), but i've always felt that postulate #2 comes directly from postulate #1. if the laws of physics are the same for all inertial frames of reference, every observer has the same epsilon_0 and mu_0 in their laws of physics. so c=(epsilon_0*mu_0)^(-1/2) is the same for every inertial observer hanging around in a vacuum. |
The first postulate doesn't tell us what the limiting velocity, if any, is. Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it.
- Gerry Quinn
--- This email has been checked for viruses by Avast antivirus software. http://www.avast.com
> | [Einstein's postulates for SR] When I study postulate 1 immediate certain some thoughts pop up: Which type of physical processes are we discussing here? |
All types.
> | Laws are descriptions of physical processes. That means (if my interpretation is correct) that all physical processes are indepent of uniform movement until the speed of light. This sounds "too optimistic" specific if you consider these clocks which inner working uses light signals to operate (i.e. counts) |
Instead of inertial frames, consider this proposition: all physical phenomena are independent of coordinates. This must be true if physics is possible, because coordinates are arbitrary human constructs; they are part of the model, not the world. Once you accept this, then it's easy to see that inertial frames are just a subset of possible coordinates.
So this is not "too optimistic".
> | Also here the question arises to which extend these oscillations are independent of the speed of the clock and does not influence the ticking rate. |
Assuming Einstein's first postulate is valid, then the physics that governs the clock's ticking is the same regardless of which inertial frame it finds itself at rest in. So the "speed of the clock" (relative to any coordinates one might choose) does not affect its ticking rate.
> | A whole different thought is: why are accelarations not discussed? |
In 1905 Einstein did not get that far. Modern textbooks on SR certainly do discuss acceleration. Many experiments have shown that acceleration does not affect a clock's ticking rate, as long as the clock is not damaged. Commercial clocks come with a specification of how large an acceleration they can sustain without damage.
Tom Roberts
> | On 5/5/15 5/5/15 - 8:24 PM, Nicolaas Vroom wrote: |
> > | Which type of physical processes are we discussing here? |
> |
All types. |
> > | Laws are descriptions of physical processes. That means that all physical processes are indepent of uniform movement until the speed of light. This sounds "too optimistic" specific if you consider these clocks which inner working uses light signals to operate (i.e. counts) |
> |
Instead of inertial frames, consider this proposition: all physical phenomena are independent of coordinates. |
> | Once you accept this, then it's easy to see that inertial frames are just a subset of possible coordinates. |
> | So this is not "too optimistic". |
[[Mod. note -- Pendulum clocks and hourglasses both have the property that they depend on the local "little g" acceleration with respect to an inertial frame, and *don't* work in an inertial frame. Thus for present purposes, they're not good clocks. -- jt]]
https://books.google.be/books?id=Z7chuo4ebUAC&pg=PA61&sig=r7PLMbI4rhAgfGkfBS-MCJEBkVs&hl=nl#v=onepage&q&f=false This document at page 64 raises the question: Can we always build a better clock?
> > | Also here the question arises to which extend these oscillations are independent of the speed of the clock and does not influence the ticking rate. |
> |
Assuming Einstein's first postulate is valid, then the physics that governs the clock's ticking is the same regardless of which inertial frame it finds itself at rest in. So the "speed of the clock" (relative to any coordinates one might choose) does not affect its ticking rate |
The issue is the ticking rate (tr) of two clocks (as measured by the final clock count = fcc) relative to each other.
Consider two identical clocks.
A) IMO if both clocks are not "moved" the fcc will be the same
B) IMO if both clocks are moved from A to B following the same
path the fcc will be the same.
C) IMO if both clocks are moved from A to B following a different path
there are two options:
C1) The fcc is the same. IMO this has a low chance.
C2) The fcc is different. IMO this has a high chance.
C2 IMO implies that the ticking rate is different.
> > | A whole different thought is: why are accelarations not discussed? |
> |
In 1905 Einstein did not get that far. |
> | Modern textbooks on SR certainly do discuss acceleration. Many experiments have shown that acceleration does not affect a clock's ticking rate, as long as the clock is not damaged. |
[[Mod. note -- The standard way to assess this is to make comparisons amongst an ensemble of similar clocks, some of which have been accelerated and some not. If all the clocks are statistically "similar", then they're probably all undamaged. The Allen variance http://en.wikipedia.org/wiki/Allen_variance is a common way of characterizing the performance of (undamaged) clocks. -- jt]]
Nicolaas Vroom
*only* dimensionless constants are fundamental.
all c needs to be is real, positive, and finite. no matter how "God" (or whatever hypothetical immortal being not governed by the laws of nature) perceives the speed of instantaneous interactions (EM, gravity, strong force) meditated by massless particles, we mortals would continue to perceive it as moving 299792456 of our meters in the time elapsed by one of our seconds. (we would also measure the same epsilon_0 and define the same mu_0.)
cut c in half (from the POV of the god-like being) and the rest of us get our length and time scaled in such a manner that c remains the same.
c will always be 1 Planck Length per Planck Time. and if none of the dimensionless fundamental constants change, then the number of Planck Lengths per meter will remain the same and the number of Planck Times per second will remain the same. - show quoted text -
> | It would be interesting to study a hourglas inside a spacecraft. |
Why? An hourglass is NOT a clock. Only hourglass+earth is a (modestly accurate) clock, and you cannot possibly put that into a spacecraft.
Ditto for pendulum clocks and sundials (etc.).
> | The question is: what is the influence on the accuracy of a pendulum clock when you move such a clock (fast?) from A to B. |
That question is useless, because you cannot move the earth with it.
> |
The issue is the ticking rate (tr) of two clocks (as measured by the
final clock count = fcc) relative to each other.
Consider two identical clocks. |
No to this last -- you DID NOT MEASURE the tick rate of either clock, and therefore cannot make any conclusion about it.
In relativity this difference is modeled as being the difference in the "length of the paths", where "length" for such timelike paths is really the elapsed proper time.
When cars' odometers indicate different distances for different paths between A and B, do you really think the odometers' tick rates are different? OF COURSE NOT! The odometers increment 1 mile for every mile traveled -- that is their (intrinsic) tick rate. The clocks increment 1 second for every second of elapsed proper time -- that is their (intrinsic) tick rate.
Note your implicit assumption hidden in your conclusion: you are assuming your personal appreciation of "time" is important. That is, you have added a HIDDEN third clock, your mind, and you are really assessing "tick rate" relative to it, WITHOUT MENTIONING IT. Yes, if you measured the tick rates of those clocks RELATIVE TO A CLOCK CO-LOCATED and CO_MOVING WITH YOURSELF, then you could conclude their tick rates RELATIVE TO THAT CLOCK are different.
But as I have said before, when you just discuss the "tick rate of a clock", that phrase inherently refers to the INTRINSIC tick rate of the clock, because that is how words behave. The intrinsic rate of the clock never changes; only tick rates RELATIVE TO OTHER CLOCKS can change (really relative to other coordinate systems).
Bottom line: your "common sense" is insufficient to understand what is happening in relativity. The world is more complicated than your common sense can capture. Relativity models it well, "common sense" does not.
>>> | A whole different thought is: why are accelarations not discussed? |
>> | In 1905 Einstein did not get that far. |
> | IMO all experiments with moving clocks imply acceleration |
>> |
Modern textbooks on SR certainly do discuss acceleration. Many experiments have shown that acceleration does not affect a clock's ticking rate, as long as the clock is not damaged. |
> | What is the definition of damaged? |
A clock is not damaged if it continues ticking at its intrinsic tick rate.
> | When you first perform test C and than test A and the fcc is different than at least one clock is damaged. |
No. Had you measured each clock's (intrinsic) tick rate, you would have found them to be correct.
There is more going on here than you understand, and you keep making assumptions based on your personal experience, which is woefully inadequate because you have no personal experience with speeds approaching c. You need to study relativity, and its underlying geometry.
Tom Roberts
> | On 5/9/15 3:21 AM, Gerry Quinn wrote: |
> > | The first postulate doesn't tell us what the limiting velocity, if any, is. Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it. |
> |
but that doesn't matter. (well, "if any" matters. but even in 1900, we already had a finite speed for c, so the point doesn't count.) |
So why write down ANY laws or postulates that are known to be true?
In any case, it's not obvious from first principles that c is the limiting speed, even if we haven't found anything that goes faster. Sure, you can deduce that based on observations too. But ultimately, you must state enough postulates to describe the physics that you want to describe.
> |
*only* dimensionless constants are fundamental.
all c needs to be is real, positive, and finite. no matter how "God" (or whatever hypothetical immortal being not governed by the laws of nature) perceives the speed of instantaneous interactions (EM, gravity, strong force) meditated by massless particles, we mortals would continue to perceive it as moving 299792456 of our meters in the time elapsed by one of our seconds. (we would also measure the same epsilon_0 and define the same mu_0.) cut c in half (from the POV of the god-like being) and the rest of us get our length and time scaled in such a manner that c remains the same. |
I can agree that the second postulate could have been stated as "there is a limiting speed", leaving it open to be deduced from observation that the speed of light fits the bill. [Assuming it does - it is not actually proven that the photon has zero mass, although numerous arguments constrain any photon mass to be extremely small.] - show quoted text -
> | So why write down ANY laws or postulates that are known to be true? |
Postulates are not any laws.
These are the supplementary assumptions only, and of a special type; for example, in the model of the collisions there are used two assumption usually: ideal elastic collision, or ideal inelastic.
And we know very well these both are false in any practical case. But this not a problem - the models works well... in some limited conditions, which are known commonly.
And the same rule applies to every postulate - to these of SR too.
Especially: the 'light speed is invariant' is not any discovery, but a modeled-assumption only, on which the SR is based (or on the assumption of the relativity principle, which is equivalent, or maybe a superior, to the invariance of a light speed).
> | In any case, it's not obvious from first principles that c is the limiting speed, even if we haven't found anything that goes faster. Sure, you can deduce that based on observations too. But ultimately, you must state enough postulates to describe the physics that you want to describe. |
No. The postulates are suplementary always, therefore these are present in the models only, never in a theory itself.
There is none of postulates in a real theory, but just axioms only! And an axiom is not a postulate.
So, what is a difference between an axiom and postulate? It should be rather obvious...
> |
> |
There is none of postulates in a real theory, but just axioms only! And an axiom is not a postulate. So, what is a difference between an axiom and postulate? It should be rather obvious... |
it's not to me. seems to me that, operationally, postulates and axioms are the same. they are initial statements that are taken as true without proof and other substantive conclusions are made from those postulates or axioms. - show quoted text -
> | On 5/23/15 10:30 PM, al...@interia.pl wrote: |
>> |
> |
... |
>> |
There is none of postulates in a real theory, but just axioms only! And an axiom is not a postulate. So, what is a difference between an axiom and postulate? It should be rather obvious... |
> |
it's not to me. seems to me that, operationally, postulates and axioms are the same. they are initial statements that are taken as true without proof and other substantive conclusions are made from those postulates or axioms. |
There are no axioms in physics exept the axiom of "use logic and numbers, make an experiment and adapt the mathematical model to its outcomes".
Axioms can be formulated in an axiomatic theory as a mathematical framework to serve as a specific model describing the measurable observables of a given system.
Postulates are more general: They fomulate model independent features which all mathematical models of a physical reality have to incorporate, like use of a space-time universe, Poincare invariance, probabilistic interpretation, gauge invariance, locality, causality, determinism aof system states by a given set of starting conditions at the time of preparation of experiments.
These postulates drive the development in quite different models like relativistic mechanics, cosmology, quantum theory, field theory or classical and quantum statistical mechanics.
--
Roland Franzius
> |
There are no axioms in physics exept the axiom of "use logic and numbers, make an experiment and adapt the mathematical model to its outcomes". |
Indeed, because the whole physics is not a theoretical domain in fact.
The physics is just about the models.
> | Axioms can be formulated in an axiomatic theory as a mathematical framework to serve as a specific model describing the measurable observables of a given system. |
No, axioms are just of a theory basis... a model is besed on a theory, of course, because there is nothig more to start!
> | Postulates are more general: They fomulate model independent features which all mathematical models of a physical reality have to incorporate, like use of a space-time universe, Poincare invariance, probabilistic interpretation, gauge invariance, locality, causality, determinism aof system states by a given set of starting conditions at the time of preparation of experiments. |
Yes. Maybe a postulate can be a something more than an axiom.
But it's only because we have more freedom in this case... any axiom are independent of any our decision - it's just a fact, an obvious truth.
Finally: there are unlimited postulates possible, but an axioms set is very limited.
> | These postulates drive the development in quite different models like relativistic mechanics, cosmology, quantum theory, field theory or classical and quantum statistical mechanics. |
These all 'theories' are just the models only, in fact, because: the relativity, quantum, ect. are based on the general theory - the math itself, what is evident... and sametime on a specfic theory, like in the case of relativity: the Lorentz - Poincare's Theory.
> | Am 25.05.2015 um 10:02 schrieb robert bristow-johnson: |
>> | On 5/23/15 10:30 PM, al...@interia.pl wrote: ... |
>>> |
There is none of postulates in a real theory, but just axioms only!
And an axiom is not a postulate.
So, what is a difference between an axiom and postulate? It should be rather obvious... |
>> |
it's not to me. seems to me that, operationally, postulates and axioms are the same. they are initial statements that are taken as true without proof and other substantive conclusions are made from those postulates or axioms. |
> |
There are no axioms in physics exept the |
> | Postulates are more general: They fomulate model independent features |
There isn't much support for giving them different meanings:
(Although stackexchange is of course less authoritative than sci.physics.research, let's postulate that first!)
-- Jos
> | W dniu poniedziaLek, 25 maja 2015 15:45:18 UTC+2 uLLytkownik Roland Franzius |
>> |
There are no axioms in physics exept the axiom of "use logic and numbers, make an experiment and adapt the mathematical model to its outcomes". |
> |
Indeed, because the whole physics is not a theoretical domain in fact. The physics is just about the models. |
>> |
Axioms can be formulated in an axiomatic theory as a mathematical framework to serve as a specific model describing the measurable observables of a given system. |
> |
No, axioms are just of a theory basis... a model is besed on a theory, of course, because there is nothig more to start! |
You will find two unique truly axiomatic theories in physics and both have no working model, that proves its existence in the mathematical sense for a faily general rich set of observables and their time development:
1) Analytical Lagrangian mechanics: Plainly wrong physical, mathematical not existent because of lack of predictability for many point-particle systems with interaction.
2) Axiomatic Quantum field theory: While starting with beautiful results in the 1950 after the work of Wigner, Wightman, Haag, Kastler there was little physical progress later on. Now it is a branch of pure mathematics applied to an physical motivated axiomatic setting.
Again there exists no mathematical realisation beyond free fields could be established in a physical acceptable number of space-time dimensions.
Of course this is symptomatic for theoretical physics:
Physics is about time development of 3d-geometric systems with an indefinite bilinear form invariant under the local families of representations of the Poincare group.
The general lack of a unique canonical euclidean norm for systems in space-time makes convergency theorems in relativistic mechanics and field theories extremely hard to prove.
In most cases one has to introduce smoothness conditions on series solutions in some much too rich taylored solution spaces that are by no means capable to select a unique mathematical model.
So finally the best thing one gets as an aximotic setting in physics is the selection of some interesting categories like continuous representations of Lie-groups over tensor products.
In axiomatic field theories like General Relativity and QED and Quantum Field Theory it is not known until today if the choosen set of axioms is consistent and free of contradictions except perhaps for the toy theories of free test systems in external backgrounds.
--
Roland Franzius
Op woensdag 13 mei 2015 10:21:35 UTC+2 schreef Tom Roberts:
> | On 5/5/15 5/5/15 - 8:24 PM, Nicolaas Vroom wrote: |
> > | Which type of physical processes are we discussing here? |
> |
All types. |
> > | Laws are descriptions of physical processes. That means that all physical processes are indepent of uniform movement until the speed of light. This sounds "too optimistic" specific if you consider these clocks which inner working uses light signals to operate (i.e. counts) |
> |
Instead of inertial frames, consider this proposition: all physical phenomena are independent of coordinates. |
That is correct, but it does not say anything about (the inner working) of the processes them self
> | Once you accept this, then it's easy to see that inertial frames are just a subset of possible coordinates. |
Again that is correct, but etc (see above)
> | So this is not "too optimistic". |
When you study http://en.wikipedia.org/wiki/Clock you can see that it is a continuous struggle to make better, more accurate, clocks. It would be interesting to study a hourglas inside a spacecraft. The question is what is the influence on the accuracy of a pendulum clock when you moved.
https://books.google.be/books?id=Z7chuo4ebUAC&pg=PA61&sig=r7PLMbI4rhAgfGkfBS-MCJEBkVs&hl=nl#v=onepage&q&f=false This document at page 64 raises the question: Can we always build a better clock?
> > | Also here the question arises to which extend these oscillations are independent of the speed of the clock and does not influence the ticking rate. |
> |
Assuming Einstein's first postulate is valid, then the physics that governs the clock's ticking is the same regardless of which inertial frame it finds itself at rest in. So the "speed of the clock" (relative to any coordinates one might choose) does not affect its ticking rate |
The issue is the ticking rate (tr) of two clocks (as measured in the final clock count = fcc) relative to each other.
Consider two identical clocks.
A) IMO if both clocks are not "moved" the fcc will be the same
B) IMO if both clocks are moved from A to B following the same
path the fcc will be the same.
C) IMO if both clocks are moved from A to B following a different path
there are two options:
C1) The fcc is the same. IMO this has a low chance.
C2) The fcc is different. IMO this has a high chance.
C2 IMO implies that the ticking rate is different.
> > | A whole different thought is: why are accelarations not discussed? |
> |
In 1905 Einstein did not get that far. |
> | Modern textbooks on SR certainly do discuss acceleration. Many experiments have shown that acceleration does not affect a clock's ticking rate, as long as the clock is not damaged. |
Nicolaas Vroom
W dniu sroda, 27 maja 2015 13:19:32 UTC+2 uzytkownik Jos Bergervoet napisal:
> | On 5/25/2015 3:45 PM, Roland Franzius wrote: |
>> | Am 25.05.2015 um 10:02 schrieb robert bristow-johnson: |
>>> | On 5/23/15 10:30 PM, al...@interia.pl wrote: ... |
>>>> |
There is none of postulates in a real theory, but just axioms only!
And an axiom is not a postulate.
So, what is a difference between an axiom and postulate? It should be rather obvious... |
>>> |
it's not to me. seems to me that, operationally, postulates and axioms are the same. they are initial statements that are taken as true without proof and other substantive conclusions are made from those postulates or axioms. |
>> |
There are no axioms in physics exept the |
> | ... ... |
>> | Postulates are more general: They fomulate model independent features |
> |
There isn't much support for giving them different meanings: (Although stackexchange is of course less authoritative than sci.physics.research, let's postulate that first!) -- Jos |
Any postulate is some trick math trick in fact, which leads to more simplicity... of the equations... so, any model is based just on such trick.
The great example is the c = inv in the SR model: it's evident that: c' = c - v, due to the strict math: a gemetry principles, logics, ect.
But it's to poor fact, because a speed can't be measured directly, but omly indirect: by a time and a distance measure.
Therefore if there is in fact: c' = c-v, then we still can assume it's: c = inv, but then we must transform a time or a distance adecuatelly, to cancel the obvious change of the speed of light.
A distance is rather hard to transform, because if we have some rod with a fixed length, say L = 1m, then we assume it's preserved unconditionaly (in any local system).
Thus we must transform a time - it's the one real possibility!
Therefore the relativity model, which is based on the postulate: c = inv, postulates in fact just that: a transformation of a light speed = tr. of a time.
And it's all obout this model, because such convention lands directly on the well known transformation:
x' = k(x - vt) and t' = k(t - xv)
>> | No, axioms are just of a theory basis... a model is besed on a theory, of course, because there is nothig more to start! |
> |
You will find two unique truly axiomatic theories in physics and both have no working model, that proves its existence in the mathematical sense for a faily general rich set of observables and their time development: 1) Analytical Lagrangian mechanics: Plainly wrong physical, mathematical not existent because of lack of predictability for many point-particle systems with interaction. |
This is just a model, which is based explicityly on some postulates; and the model gives very good predictions... for example: a simulation of the Solar System, basing on this model, is possible, and rather easy, and the final results are quite good.
> | Again there exists no mathematical realisation beyond free fields could be established in a physical acceptable number of space-time dimensions. |
The whole space-time concempt is just a model-specific postulate... and it depends totaly on an abstract mathematical space theory.
> | In axiomatic field theories like General Relativity and QED and Quantum Field Theory it is not known until today if the choosen set of axioms is consistent and free of contradictions except perhaps for the toy theories of free test systems in external backgrounds. |
There is no axioms in the GR, nor QM... similarily the hiperbolic geometry is not of SR domain at all, nor the complex algebra is a part of the waves theory.
> | On 5/18/15 5/18/15 - 9:35 PM, Nicolaas Vroom wrote: |
> > | It would be interesting to study a hourglas inside a spacecraft. |
> |
Why? An hourglass is NOT a clock. |
That is the question. What is a clock and what is not a clock. If SR describes all processes and all clocks and if that is the case than it should also describe a hourglass and a pendulum.
> | That question is useless, because you cannot move the earth with it. |
Than you cannot perform any experiment with any clock ? (because of the earth)
> > |
The issue is the ticking rate (tr) of two clocks (as measured by the
final clock count = fcc) relative to each other.
Consider two identical clocks. C2) The fcc is different. IMO this has a high chance. C2 IMO implies that the ticking rate is different. |
> |
No to this last -- you DID NOT MEASURE the tick rate of either clock, and therefore cannot make any conclusion about it. |
I agree, but I did not write that. I specific use the word "implies". The issue is that the final clock counts are different. If you agree that that is possible, than the Q is: how do you explain that.
> | Note your implicit assumption hidden in your conclusion: you are assuming your personal appreciation of "time" is important. That is, you have added a HIDDEN third clock, your mind, and you are really assessing "tick rate" relative to it, WITHOUT MENTIONING IT. |
I'm comparing the result (counts) of an experiment with two clocks. My mind has nothing to do with this. You can add a third clock, (and call each count of that clock 1 second) but that does not really makes a difference.
> | But as I have said before, when you just discuss the "tick rate of a clock", that phrase inherently refers to the INTRINSIC tick rate of the clock, because that is how words behave. |
Exactly what is your definition of the INTRINSIC (tick rate)
> | The intrinsic rate of the clock never changes. |
Even in the case when you perform experiment C/C2 and the fcc is different?
> | Bottom line: your "common sense" is insufficient to understand what is happening in relativity. |
I would never use the words "common sense". Generally you should perform experiments without any (directly) people involved.
> | A clock is not damaged if it continues ticking at its intrinsic tick rate. |
I will come back to this remark when the meaning of the word intrinsic is clear.
> > | When you first perform test C and than test A and the fcc is different than at least one clock is damaged. |
> |
No. Had you measured each clock's (intrinsic) tick rate, you would have found them to be correct. |
The issue is the definition of damaged. When you supposedly have two identical clocks and when you perform experiment A (both clocks are not "moved") and the fcc is different than at least one clock is damaged.
Nicolaas Vroom
> |
Op donderdag 21 mei 2015 19:01:17 UTC+2 schreef Tom Roberts: |
> > |
On 5/18/15 5/18/15 - 9:35 PM, Nicolaas Vroom wrote: |
> > > |
It would be interesting to study a hourglas inside a spacecraft. |
> > |
Why? An hourglass is NOT a clock. |
> |
That is the question. What is a clock and what is not a clock. If SR describes all processes and all clocks and if that is the case than it should also describe a hourglass and a pendulum. |
Nick, Tom has explained to you that pendulum clocks by themselves are not clocks because they operate only in an acceleration field. Hourglasses are the same. Ideal clocks keep perfect time within their range of operation. Pendulum clocks and hourglasses are far from perfect even in their range of operation and don't work at all in free fall. The best clocks we have are atomic clocks.
> > | That question is useless, because you cannot move the earth with it. |
> |
Than you cannot perform any experiment with any clock ? (because of the earth) |
The earth, or rather its acceleration field, is PART of hourglasses and pendulum clocks. The earth is NOT part of an atomic clock. That's why they keep excellent time even in orbit.
Gary
> |
In article |
> > | On 5/5/15 9:24 PM, Nicolaas Vroom wrote: |
> > > |
In the book etc. we read: The two postulates: 1. The laws of physics take the same form in all inertial frames. 2. In any given inertial system the velocity of light c is the same whether the light be emitted by a body at rest or by a body in uniform motion. |
> |
The first postulate doesn't tell us what the limiting velocity, if any, is. |
> | Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it. |
The above two postulates are not the total picture. In the same book at page 142 is written: Einstein spells out three additional assumptions which are made in this reasoning (See volume 7 doc 50) 3) Homogeneity: the properties of rods and clocks depend neither on position nor on the time at which they move, but only on the way in which they move. 4) Isotropy: the properties of rods and clocks are independent of direction. 5) these properties are also independent of their history. (in the text the 3 assumptions are idicated as 1. 2. and 3.)
Accordingly to Websters a postulate is a statement that is assumed and as such requires no proof of its validity. As such IMO relativity is based on 5 assumptions. The next step is to make testable (observable) predictions using a a common set of "logical" reasoning.
One important issue is that the assumptions should be clear.
IMO all the words or concepts: inertial system, at rest, in (uniform)
motion and properties require a clear definition.
As such assumption 3 should be divided in two assumptions:
3a) the properties of rods depend on the way in which they move.
3b) the properties of clocks depend on the way in which they move.
What does the word property in each instant mean?
Does "on the way in which clocks move" imply that clock count if two
identical clocks move from A to B (at a different path) could be
different?
Assumption 2 can be used to make the following prediction (?):
The speed of light in any inertial sytem is the same in (any)
two opposite directions.
Can this prediction being tested?
Nicolaas Vroom
> |
Nick, Tom has explained to you that pendulum clocks by themselves are not clocks because they operate only in an acceleration field. Hourglasses are the same. Ideal clocks keep perfect time within their range of operation. Pendulum clocks and hourglasses are far from perfect even in their range of operation and don't work at all in free fall. The best clocks we have are atomic clocks. |
Gary. I (almost) 100% agree with you. However the real question is what are ideal clocks. How do you know that they keep perfect time? That is why I raised the 3 question/experiments using two identical clocks. The assumption is that both clocks keep the same time when 1) not moved or 2) both moved together from A to B. The third possibility is that both are moved from A to B accordingly to a different path. The Q is: Do they both keep perfect time? IMO even when you use atomic clocks that is not always the case. IMO when both clocks meet and the time (count) is different than at least one clock does not indicate the perfect time.
If you agree than the next question is: How come? When your answer depents about "range of operation" then you have to explain what you mean. IMO when both clocks meet and the time (count) is different than always different accelerations are involved. (Those different accelerations are the cause that the clocks behave differently)
Nicolaas Vroom
> |
Op maandag 1 juni 2015 13:22:20 UTC+2 schreef Gary Harnagel: |
> > |
Nick, Tom has explained to you that pendulum clocks by themselves are not clocks because they operate only in an acceleration field. Hourglasses are the same. Ideal clocks keep perfect time within their range of operation. Pendulum clocks and hourglasses are far from perfect even in their range of operation and don't work at all in free fall. The best clocks we have are atomic clocks. |
> |
Gary. I (almost) 100% agree with you. However the real question is what are ideal clocks. How do you know that they keep perfect time? |
Hi Nick,
Well, there's no such thing as a perfect clock. USNO provides the time standard and NIST has a bank of atomic clocks. A large number is needed because atomic clocks have a tendency to randomly jump a nanosecond from time to time, and real clocks do have failure modes so you can't count on one particular clock.
> | That is why I raised the 3 question/experiments using two identical clocks. The assumption is that both clocks keep the same time when 1) not moved or 2) both moved together from A to B. |
The standard clocks are indeed "moving together" since the earth is moving. That should take care of that question.
> | The third possibility is that both are moved from A to B accordingly to a different path. The Q is: Do they both keep perfect time? IMO even when you use atomic clocks that is not always the case. IMO when both clocks meet and the time (count) is different than at least one clock does not indicate the perfect time. |
If two clocks travel different paths and then meet, they certainly will not indicate the same elapsed time. You seem to believe that there is some "universal time" a la Newton, but there is only proper time. If you took one bank of clocks (say, 100 of them) down one path and another bank down another path, all the clocks in one bank would agree among themselves but they would disagree with all the clocks in the other bank.
"Perfect" time is nonexistent, unless you want to define that as far from the influence of any gravitational field and "motionless" (whatever that means), but there is no such place.
> | If you agree than the next question is: How come? |
Relativity explains that.
> | When your answer depents about "range of operation" then you have to explain what you mean. |
That has been explained. Atomic clocks work as long as they aren't accelerated beyond 2g. This is a technological problem involving the atomic beam hitting the wall of the clock body instead of remaining in free fall.
> | IMO when both clocks meet and the time (count) is different than always different accelerations are involved. |
That is correct (unless, of course, they never parted from each other).
> |
(Those different accelerations are the cause that the clocks behave
differently)
Nicolaas Vroom |
But that's part of the cause but not the whole story. Half correct is not correct. In SR, distance between clocks when the acceleration occurs affects the outcome. If the distance is zero, there is no time dilation regardless of the acceleration.
Concerning your post to Gerry Quinn, you are correct about assumptions 3, 4 and 5. You might, in fact, add another: v = delta_x/delta_t, but that's more of a definition.
However, I must disagree with Websters. That may be true in mathematics but in physics everything is subject to experimental verification.
Gary
> | Op zaterdag 9 mei 2015 09:21:11 UTC+2 schreef Gerry Quinn: |
> > |
In article |
> > > | On 5/5/15 9:24 PM, Nicolaas Vroom wrote: |
> > > > |
In the book etc. we read: The two postulates: 1. The laws of physics take the same form in all inertial frames. 2. In any given inertial system the velocity of light c is the same whether the light be emitted by a body at rest or by a body in uniform motion. |
> > |
The first postulate doesn't tell us what the limiting velocity, if any, is. |
> | I agree. |
> > | Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it. |
> | I do not expect that Newton makes any statement about the speed of a massless particle. |
Sure he does: F = MA. A massless particle subject to a finite force will undergo infinite acceleration. If you integrate the motion of a particle over a finite distance you will find that the terminal velocity rises proportional to the square root of the acceleration, so in the limiting case of infinite acceleration, the velocity would be infinite.
> | Also IMO newton's physics is independent about the speed of light. IMO his assumption is that gravity acts instantaneous. |
Yes. Newton actually knew well that there were problems with instantaneous gravity, but he could not see a way to avoid it.
> |
The above two postulates are not the total picture.
In the same book at page 142 is written: Einstein spells out three
additional assumptions which are made in this reasoning (See volume 7 doc 50) 3) Homogeneity: the properties of rods and clocks depend neither on position nor on the time at which they move, but only on the way in which they move. 4) Isotropy: the properties of rods and clocks are independent of direction. 5) these properties are also independent of their history. (in the text the 3 assumptions are idicated as 1. 2. and 3.) Accordingly to Websters a postulate is a statement that is assumed and as such requires no proof of its validity. As such IMO relativity is based on 5 assumptions. The next step is to make testable (observable) predictions using a a common set of "logical" reasoning. One important issue is that the assumptions should be clear. IMO all the words or concepts: inertial system, at rest, in (uniform) motion and properties require a clear definition. As such assumption 3 should be divided in two assumptions: 3a) the properties of rods depend on the way in which they move. 3b) the properties of clocks depend on the way in which they move. What does the word property in each instant mean? |
What it always means in relativity theory: the result of a measurement that could be made.
> | Does "on the way in which clocks move" imply that clock count if two identical clocks move from A to B (at a different path) could be different? |
Clearly it is intended to allow for that, since Einstein would have noticed if the consequences of his theory were in complete contradiction to one of his postulates!
> | Assumption 2 can be used to make the following prediction (?): The speed of light in any inertial sytem is the same in (any) two opposite directions. Can this prediction being tested? |
Seems reasonably testable. You can set up a coordinated system of clocks at two separate positions, and then fire light beams to and fro, comparing the clock readings for sent and received signals at your leisure. You will find that you measure the same speed whichever way the beam is going.
- Gerry Quinn
--- This email has been checked for viruses by Avast antivirus software. https://www.avast.com/antivirus
> | On Saturday, June 6, 2015 at 5:24:12 AM UTC-6, Nicolaas Vroom wrote: |
> > |
Gary. I (almost) 100% agree with you. However the real question is what are ideal clocks. How do you know that they keep perfect time? |
> |
Hi Nick, Well, there's no such thing as a perfect clock. |
Gary, I agree with you. Science should not use the wording perfect. In that sense "everything" is relatif because you are comparing either different working clocks under the same conditions or "identical" clocks under different conditions.
> > | The third possibility is that both are moved from A to B accordingly to a different path. The Q is: Do they both keep perfect time? IMO even when you use atomic clocks that is not always the case. IMO when both clocks meet and the time (count) is different than at least one clock does not indicate the perfect time. |
> | If two clocks travel different paths and then meet, they certainly will not indicate the same elapsed time. You seem to believe that there is some "universal time" a la Newton, but there is only proper time. If you took one bank of clocks (say, 100 of them) down one path and another bank down another path, all the clocks in one bank would agree among themselves but they would disagree with all the clocks in the other bank. |
which one is correct? Next I perform a test with three banks all going from A to B, accordingly to a different path and I get 1100, 1000 and 900 counts. Which one is "correct"? (or the best) Of course you can answer they are all correct because each behaves as it should behave. IMO the bank (of clocks) which the highest count is the best. All the other clocks are running behind.
> > | If you agree than the next question is: How come? |
> |
Relativity explains that. |
Which do you mean SR or GR? IMO inorder to understand the behaviour of clocks (pendulums) you can use
Newton's Law. IMO to fully understand the behaviour of clocks you should use GR. IMO when you can only use SR to do the same under a rather strict set of limitations i.e. lineair motion.
> > | (Those different accelerations are the cause that the clocks behave differently) |
> | But that's part of the cause but not the whole story. |
> | In SR, distance between clocks when the acceleration occurs affects the outcome. |
> | If the distance is zero, there is no time dilation regardless of the acceleration. |
> |
Concerning your post to Gerry Quinn, you are correct about assumptions
3, 4 and 5. You might, in fact, add another: v = delta_x/delta_t, but
that's more of a definition.
However, I must disagree with Websters. That may be true in mathematics but in physics everything is subject to experimental verification. |
In the book Newton's law by 's Chandrasekbar Chapter 2 Basic Concepts explains 8 definitions and 3 Laws. Law 3 can be stated as: Action is reaction. The text is: This Law is central to proving the important Corollaries IV and V etc. IMO it is not directly necessary to prove the assumptions but it is important that these assumptions lead to predictions which can be verified by means of observations.
Nicolaas Vroom
> | In article <87d4e9b8-2dc3-4621-a772-b5879f88824e@googlegroups.com>, nicolaas.vroom@pandora.be says... |
> > > | Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it. |
> > | I do not expect that Newton makes any statement about the speed of a massless particle. |
> |
Sure he does: F = MA. A massless particle subject to a finite force will undergo infinite acceleration. etc |
Studying the book Newton's Principia by s'Chandrasekhar I can not find any mentioning of this. The issue is why should Newton study massless particles ?
> > | Also IMO newton's physics is independent about the speed of light. IMO his assumption is that gravity acts instantaneous. |
> |
Yes. Newton actually knew well that there were problems with instantaneous gravity, but he could not see a way to avoid it. |
> > |
One important issue is that the assumptions should be clear.
IMO all the words or concepts: inertial system, at rest, in (uniform)
motion and properties require a clear definition.
As such assumption 3 should be divided in two assumptions: 3a) the properties of rods depend on the way in which they move. 3b) the properties of clocks depend on the way in which they move. What does the word property in each instant mean? |
> |
What it always means in relativity theory: the result of a measurement that could be made. |
> > | Does "on the way in which clocks move" imply that clock count if two identical clocks move from A to B (at a different path) could be different? |
> |
Clearly it is intended to allow for that, since Einstein would have noticed if the consequences of his theory were in complete contradiction to one of his postulates! |
> > | Assumption 2 can be used to make the following prediction (?): The speed of light in any inertial sytem is the same in (any) two opposite directions. Can this prediction being tested? |
> |
Seems reasonably testable. You "C" can set up a coordinated system of clocks at two separate positions "A" and "B", and then fire light beams to and fro, comparing the clock readings for sent and received signals at your leisure. You "C" will find that you measure the same speed whichever way the beam is going. |
Assuming the observer C is half way between the two clocks at A and B, that means the distance AC and BC is the same and stays the same during the whole experiment. The speed in both (opposite) directions is the same when the arrival times of the two beams is the same at A and B. That means the counts of the clocks at A and B should be the same. In order to do that you first have to synchronise the clocks at A and B. How do you that? by using light signals. That means you use the same strategy to synchronise as to measure the speed, which ofcourse gives the same value in both directions.
The problem this test depents about the position and speed of "C". IMO you should perform a test indepent of "C"
Nicolaas Vroom.
> | Op zaterdag 6 juni 2015 17:21:05 UTC+2 schreef Gerry Quinn: |
> > | In article <87d4e9b8-2dc3-4621-a772-b5879f88824e@googlegroups.com>, nicolaa...@pandora.be says... |
> |
> > > > |
Newtonian physics, in which the velocity of a massless particle is infinite, would be compatible with it. |
> > > | I do not expect that Newton makes any statement about the speed of a massless particle. |
> > |
Sure he does: F = MA. A massless particle subject to a finite force will undergo infinite acceleration. etc |
> |
Studying the book Newton's Principia by s'Chandrasekhar I can not find any mentioning of this. The issue is why should Newton study massless particles ? |
Does he say anywhere that M should be greater than zero?
> > > | One important issue is that the assumptions should be clear. IMO all the words or concepts: inertial system, at rest, in (uniform) motion and properties require a clear definition. As such assumption 3 should be divided in two assumptions: 3a) the properties of rods depend on the way in which they move. 3b) the properties of clocks depend on the way in which they move. What does the word property in each instant mean? |
> > |
What it always means in relativity theory: the result of a measurement that could be made. |
> | For example the length of a rod? But why mention this as an assumption? |
Because in other theories properties could be defined differently. For example, in ether-based theories, the actual length of a rod is reduced when it is in motion with respect to the ether. But this actual length, although it is a property of the object, cannot be measured by any known method.
> > > | Does "on the way in which clocks move" imply that clock count if two identical clocks move from A to B (at a different path) could be different? |
> > |
Clearly it is intended to allow for that, since Einstein would have noticed if the consequences of his theory were in complete contradiction to one of his postulates! |
> | Again also here: Why mention clocks? Newton studies pendulums as a mechanical object, subject of gravity. |
You were the one to mention clocks!
> > > | Assumption 2 can be used to make the following prediction (?): The speed of light in any inertial sytem is the same in (any) two opposite directions. Can this prediction being tested? |
> > |
Seems reasonably testable. You "C" can set up a coordinated system of clocks at two separate positions "A" and "B", and then fire light beams to and fro, comparing the clock readings for sent and received signals at your leisure. You "C" will find that you measure the same speed whichever way the beam is going. |
There were no A, B and C in what I wrote. Please note when posting edited versions of what I say. I did not place A, B and C in equivalent statuses. A and B can be considered measuring devices. C is a scientist, not a measuring device. C studies the results of measurements made at A and B.
> |
Assuming the observer C is half way between the two clocks at A and B,
that means the distance AC and BC is the same and stays the same during
the whole experiment.
The speed in both (opposite) directions is the same when the arrival
times of the two beams is the same at A and B.
That means the counts of the clocks at A and B should be the same.
In order to do that you first have to synchronise the clocks
at A and B. How do you that? by using light signals.
That means you use the same strategy to synchronise as to measure
the speed, which ofcourse gives the same value in both directions.
The problem this test depents about the position and speed of "C". IMO you should perform a test indepent of "C" |
Unless you can find a way to synchronise them with does not ultimately depend on such signals, or other signals which also obey the Lorentz symmetries, then according to relativity theory, your point is irrelevant, because things that can't be measured are not physical properties.
- Gerry Quinn
--- This email has been checked for viruses by Avast antivirus software. https://www.avast.com/antivirus
W dniu pitek, 5 czerwca 2015 14:59:20 UTC+2 uytkownik Nicolaas Vroom napisa:
> | In the same book at page 142 is written: Einstein spells out three additional assumptions which are made in this reasoning (See volume 7 doc 50) 3) Homogeneity: the properties of rods and clocks depend neither on position nor on the time at which they move, but only on the way in which they move. 4) Isotropy: the properties of rods and clocks are independent of direction. 5) these properties are also independent of their history. (in the text the 3 assumptions are idicated as 1. 2. and 3.) |
These are not any postulates, but a trivial facts, deduced from math directly, ie. from a theory.
> | Does "on the way in which clocks move" imply that clock count if two identical clocks move from A to B (at a different path) could be different? |
Yes. It is independent on the path. The experimantal data show this explicitly, a logics - theory also.
In the SR model it depends on path... because thes model is based on: c = inv, and on some other simplifications/idealisations.
> | Assumption 2 can be used to make the following prediction (?): The speed of light in any inertial sytem is the same in (any) two opposite directions.> Can this prediction being tested? |
Yes, it can be tested, but still superflous because Lorentz theory predicts this: c'(f) = k(c - vcosf) = c/k(1-v/c cosf');
therefore the measured two-way speed of light, in the vacuum, is constant: c = inv.
And it's due to the first Lorentz's equation only: x' = k(x - vt); So, we catch at once the whole experimental data, from the 20 century without any superfluous postulates... the strict ans strong math is good enought.
> > | Studying the book Newton's Principia by s'Chandrasekhar I can not find any mentioning of this. The issue is why should Newton study massless particles ? |
> |
Does he say anywhere that M should be greater than zero? |
Newton at page 18 defines the notion of mass as a quantity of matter. Newton defines: quantity of motion = mass * velocity. (IMO) When mass = 0 the body or object does not exist.
> > > | What it always means in relativity theory: the result of a measurement that could be made. |
> > | For example the length of a rod? But why mention this as an assumption? |
> |
Because in other theories properties could be defined differently. For example, in ether-based theories, the actual length of a rod is reduced when it is in motion with respect to the ether. But this actual length, although it is a property of the object, cannot be measured by any known method. |
You make it even more complex. IMO assumption 3 is not very clear. Why not rewrite assumption 3 that the length? and mass? depend on the way in which they move. Of course the last part of this sentence is also not clear.
> | You were the one to mention clocks! |
> > > | You "C" will find that you measure the same speed whichever way the beam is going. |
> |
There were no A, B and C in what I wrote. |
> | Please note when posting edited versions of what I say. I did not place A, B and C in equivalent statuses. A and B can be considered measuring devices. C is a scientist, not a measuring device. C studies the results of measurements made at A and B. |
> > |
Assuming the observer C is half way between the two clocks at A and B,
that means the distance AC and BC is the same and stays the same during
the whole experiment.
The speed in both (opposite) directions is the same when the arrival
times of the two beams is the same at A and B.
That means the counts of the clocks at A and B should be the same.
In order to do that you first have to synchronise the clocks
at A and B. How do you that? by using light signals.
That means you use the same strategy to synchronise as to measure
the speed, which ofcourse gives the same value in both directions.
The problem this test depents about the position and speed of "C". IMO you should perform a test indepent of "C" |
> |
Unless you can find a way to synchronise them with does not ultimately depend on such signals, or other signals which also obey the Lorentz symmetries, then according to relativity theory, your point is irrelevant, because things that can't be measured are not physical properties. |
The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. Of course if this can not be measured than this becomes a whole different story. You could also claim that this is true by definition i.e. that the speed of light is (physical) the same in both directions. But if that is the case why mention: "in any inertial system".
Nicolaas Vroom
Am 20.06.2015 um 05:41 schrieb Nicolaas Vroom:
> | Op donderdag 11 juni 2015 09:00:42 UTC+2 schreef Gerry Quinn: |
>> |
Does he say anywhere that M should be greater than zero? |
> |
Newton at page 18 defines the notion of mass as a quantity of matter. Newton defines: quantity of motion = mass * velocity. (IMO) When mass = 0 the body or object does not exist. |
Thats the question.
It originated with detection of the duality of the two mathematical concepts of waves and point particles as the possible nature of light.
Fermat Huyghens, Newton, Kirchhoff and even people like Goethe and Schopenhauer engaged in that widely philosophically shaped academic discussion.
The two generic Newtonian equations of motion of point particles m x'' = K = m g for acceleration in static gravity and m x'' = e E for charged particles clearly have simple limits m->0. The first equation is stating universality of gravitation independent of mass, the second aimes to conclude that classes of charged point particles in the limit m->0 should have constant specific charge per mass density.
That idea was the starting point of quantum theory and the redetection of Demokritos' and Leibniz' fundamental concept of the atomism of matter, where the atoms represent the smallest unit having the same physical and chemical identity as a pure macroscopic body composed of them.
In the times of the glorius physical revolution between Maxwell and Heisenberg/Schroedinger the idea of a point particle disappeared together with its velocity and acceleration.
The first doubt was raised by H.A. Lorentz who showed the impossibility to make the relativistic limit for charged point particles to diameter -> 0 at fixed e/m.
Today we are left now with a widely algebraically equivalent Hamiltonian canonical picture of position and momentum variables in a quantised wave theory where the mass m is a fixed parameter in the relativistic Einstein wave dispersion relation
(E/c)^2 - p^2 == (m c)^2
to be fulfilled at every space time point where E/c and p are the local frequency and wave number in units of hbar.
In this Q-theory mass m (and charge e and spin s) are fixed parameters of a group representation and the limit m->0 cannot be taken on representation spaces.
But representations with m=0, e=0 exist (scalar bosons, neutrinos, photons, gravitons). The limits to be taken are mathematically involved and notoriously difficult to understand.
--
Roland Franzius
> |
The problem is my question: how can you test or measure the speed of
light in any inertial system in both directions and come to the
conclusion that this speed is always the same.
Of course if this can not be measured than this becomes a whole
different story.
You could also claim that this is true by definition i.e. that the speed
of light is (physical) the same in both directions.
But if that is the case why mention: "in any inertial system".
Nicolaas Vroom |
There is no problem with a lightspeed, because it's: c' = c - v due to the fact: x' = x - vt;
But in a moving frame we measure a different quantity, due to the physical contraction, in a moving system, which rescale the unit of distance, like this: d' = kd, where k = gamma;
hence the Lorentz transform: x' = k(x-vt); thus the light =velocity= must be rescaled in the same way: c'_vec = k(c - v)
thus a speed is: c'(f) = k(c - vcosf)
where the angle f is measured in a stationary frame; but we should use f' - the angle in the moving frame, which is: cosf' = ...
and finally the light speed (measured in a moving frame) is eq.: c'(f') = c/k(1-v/c cosf'); ... so, we can measure just that quatnity only.
The two-way speed of light, ie. a harmonic mean of the: c'(f') and c'(f'+180) is constant, of course... therefore the SR model - as a very simplified version of the Lorentz's theory.
> | The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. |
The measurements leading up to the redefinition of the meter in 1983 did precisely that, for all inertial frames occupied by laboratories on earth. As they are rotating and orbiting with the earth, a large number of different inertial frames were sampled, and the accuracy of the measurements was ~ 60,000 times better than the variations in velocities of the frames relative to the solar system rest frame.
Today (post 1983) standards organizations are not interested in measuring the speed of light, as it is a constant used to define the meter.
You may argue that those were all round-trip measurements. True, but unimportant, because one-way measurements are conventional in that they require one to select an ARBITRARY convention for synchronizing clocks, and the result depends on your ARBITRARY choice.
Using pre-1983 standards and modern equipment, direct measurements of the one-way speed of light suffer from large systematic errors, but there are many measurements of the isotropy of the one-way speed of light that are far more accurate; they use slow clock transport for synchronization. The combination of isotropy of one-way propagation and accurate measurements of the round-trip speed is sufficient to test the various fundamental theories of physics, and the only theories that survive are SR and the other theories that are experimentally indistinguishable from it (none of which are useful or interesting other than historically).
Tom Roberts
> | Op donderdag 11 juni 2015 09:00:42 UTC+2 schreef Gerry Quinn: |
> > > | Studying the book Newton's Principia by s'Chandrasekhar I can not find any mentioning of this. The issue is why should Newton study massless particles ? |
> > |
Does he say anywhere that M should be greater than zero? |
> |
Newton at page 18 defines the notion of mass as a quantity of matter. Newton defines: quantity of motion = mass * velocity. (IMO) When mass = 0 the body or object does not exist. |
We certainly consider that entities with zero mas exist nowadays. I don't know what Newton thought about the issue, though perhaps we could get some clue from considering his various tyhoughts regarding infinitesimals etc. But in any case, it is clearly implicit in his equations that an object of zero mass would gain infinite velocity if impelled by a force. And even if zero mass objects cannot exist, there is no obvious limit on the velocities attainable by objects of very low mass subjected to large forces.
> > > > | What it always means in relativity theory: the result of a measurement that could be made. |
> > > | For example the length of a rod? But why mention this as an assumption? |
> > |
Because in other theories properties could be defined differently. For example, in ether-based theories, the actual length of a rod is reduced when it is in motion with respect to the ether. But this actual length, although it is a property of the object, cannot be measured by any known method. |
> |
You make it even more complex. IMO assumption 3 is not very clear. Why not rewrite assumption 3 that the length? and mass? depend on the way in which they move. Of course the last part of this sentence is also not clear. |
I would see assumption 3 as just partial. To say that length and mass do not depend on position or time is not to imply that they must necessarily vary with velocity.
> > > | The problem this test depents about the position and speed of "C". IMO you should perform a test indepent of "C" |
> > |
Unless you can find a way to synchronise them with does not ultimately depend on such signals, or other signals which also obey the Lorentz symmetries, then according to relativity theory, your point is irrelevant, because things that can't be measured are not physical properties. |
> |
The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. Of course if this can not be measured than this becomes a whole different story. |
If you adopt the philosophy that what cannot be measured is not real, then there is no difference. My view is that the philosophy is justified by what we know of quantum theory. [That is not to imply that quantum theory says that the vacuum in principle cannot have a state of motion; our failure so far to find a way to detect any such motion is a matter of observation rather than theory.] - show quoted text -
> | We certainly consider that entities with zero mas exist nowadays. I don't know what Newton thought about the issue, though perhaps we could get some clue from considering his various thoughts regarding infinitesimals etc. But in any case, it is clearly implicit in his equations that an object of zero mass would gain infinite velocity if impelled by a force. And even if zero mass objects cannot exist, there is no obvious limit on the velocities attainable by objects of very low mass subjected to large forces. |
Reading the previous mentioned book objects of zero mass are no issue for Newton. At page 236 we read: "If the masses m1,m2,m3 etc are sufficiently tiny (compared to M) then the center of gravity will not be sensibly different from the location of M, which may, then, be considered to be at rest or moving uniformly forward in a right line; and about which the lesser bodies will revolve."
One of the most amazing chapters is #10 "On revolving orbits" In this chapter he discusses different "Laws of force". In example 1 (page 194) the situation close to the movement of the planet Mercury is discussed. Truly amazing.
> > | The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. Of course if this can not be measured than this becomes a whole different story. |
> |
If you adopt the philosophy that what cannot be measured is not real, then there is no difference. |
> | My view is that the philosophy is justified by what we know of quantum theory. |
Nicolaas Vroom
> | On 6/19/15 6/19/15 10:41 PM, Nicolaas Vroom wrote: |
> > | The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. |
> |
The measurements leading up to the redefinition of the meter in 1983 did precisely that, for all inertial frames occupied by laboratories on earth. |
How did they measure the speed in one direction ? I think it is rather difficult to measure the speed of light in a laboratory accurately, with the emphasis on accurate.
> | Today (post 1983) standards organizations are not interested in measuring the speed of light, as it is a constant used to define the meter. |
I can understand that you define the speed of light as a constant. However that is only a part of the problem. The first question is: is the speed of individual photons everywhere the same? Is the speed the same at "my" position as near a blackhole? The second question is when you draw a space time diagram, Is the space diagram the same at "my" position as on a moving train from the position of an observer on the moving train. See: https://en.wikipedia.org/wiki/Relativity_of_simultaneity#Spacetime_diagrams or: https://en.wikipedia.org/wiki/Relativity_of_simultaneity#/media/File:TrainAndPlatformDiagram1.svg
To be more specific: Is it always correct to draw the light lines at the same angle in both directions.
> | Using pre-1983 standards and modern equipment, direct measurements of the one-way speed of light suffer from large systematic errors, but there are many measurements of the isotropy of the one-way speed of light that are far more accurate; they use slow clock transport for synchronization. |
As I wrote before there are three types of tests with identical clocks
in relation to their clock counts:
1) They both stay at the same position A (IMO the counts are the same)
2) They both are moved together from A to B (IMO the counts are the same)
3) They both are moved along different paths (length) from A to B
(IMO the clock counts (in general) are different)
4) A specific case is when the points A and B are the same and when
one clock stays at home.
(IMO the clock counts of the moving clock will be the least)
5) There is also a fifth test.
One clock #1 stays at point A.
A second clock is moved from point A to point B and back to A along
the same path at high speed. (the counts of #1 and #2 will be different)
A third clock follows exactly the same path as #2 but very slowly.
The issue are the counts of clock #1 and #3 the same or different.
(at point A)
The problem is even when the clock counts are the same, you are not sure if that is the case for the whole trip nor what the clock count is of clock #1 (at point A) when clock #3 is at point B. (is this correct ?)
Nicolaas Vroom
> | Op zaterdag 20 juni 2015 21:45:03 UTC+2 schreef Tom Roberts: |
>> | On 6/19/15 6/19/15 10:41 PM, Nicolaas Vroom wrote: |
>>> | The problem is my question: how can you test or measure the speed of light in any inertial system in both directions and come to the conclusion that this speed is always the same. |
>> | The measurements leading up to the redefinition of the meter in 1983 did precisely that, for all inertial frames occupied by laboratories on earth. |
> |
How did they measure the speed in one direction ? |
They didn't. They measured the speed over a round-trip laboratory path (in vacuum), and verified isotropy in many different OTHER experiments. The many different round-trip measurements were accurate to better than 1 m/s, and did not vary significantly over the location, year, month, or day.
> | I think it is rather difficult to measure the speed of light in a laboratory accurately, with the emphasis on accurate. |
Not at all. The accuracy back then was a few parts per billion; could do better today, but:
>> | Today (post 1983) standards organizations are not interested in measuring the speed of light, as it is a constant used to define the meter. |
> |
I can understand that you define the speed of light as a constant. However that is only a part of the problem. |
WHAT "problem"??? The definitions as of 1983 have proven to be robust and useful.
OK, YOU seem to have a problem understanding this. The only cure is to STUDY. Your "20 questions" approach here is USELESS. Get a good textbook; I recommend: Misner, Thorne, and Wheeler, _Gravitation_.
> | The first question is: is the speed of individual photons everywhere the same? |
If you actually knew what photons are, you would know that this question is meaningless. We measure the speed of LIGHT PULSES, not "individual photons".
In our best theory of all this, GR, the LOCAL speed of LIGHT PULSES (in vacuum) is indeed everywhere the same. And in all places we have managed to measure it, the measurements are consistent with this prediction.
> | Is the speed the same at "my" position as near a blackhole? |
Nobody has ventured near a black hole to measure. But in our only theory that describes black holes, GR, the LOCAL speed of light is equal to c EVERYWHERE, including near and even inside a black hole.
> | The second question is when you draw a space time diagram, Is the space diagram the same at "my" position as on a moving train from the position of an observer on the moving train. |
The diagrams themselves are of course the same, but the objects depicted in them can be displayed in different places, with different orientations. This is no different from "left" to you being "right" to me as we face different directions -- remember that in relativity, relative motion is a change in orientation (in spaceTIME) as well as a (time-dependent) change in (relative) position.
> | Is it always correct to draw the light lines at the same angle in both directions. |
Yes, as long as the diagram is drawn from the perspective of an inertial frame, and as long as the diagram is no larger than the domain of validity of that frame's coordinates.
> | [... more questions too complicated to parse] |
Tom Roberts
> | Op zaterdag 27 juni 2015 22:26:39 UTC+2 schreef Gerry Quinn: |
> > | If you adopt the philosophy that what cannot be measured is not real, then there is no difference. |
> | If you cannot measure what the proposition describes than you cannot validate the proposition. |
Not relevant if from your philosophical perspective the proposition (a 'true' each-way velocity that cannot be measured by any means) is meaningless! Meaningless propositions are neither susceptible to validation, nor needful of it.
It is perfectly legitimate to adopt another perspective in which the proposition is meaningful - this leads us to ether-like interpretations along the lines proposed by Lorentz and Poincare. If our physical intuitions invoke a pre-quantum world, in which every phenomenon must be explicable in terms of the workings of constituent local mechanisms, and counterfactual definiteness is a given, this approach is very attractive. For example, in this approach there is no such thing as the 'twin paradox' - regardless of the twins' motions, the aging of each twin is controlled at all times simply by his velocity with respect to the ether, and no other factor need be considered at all.
Unfortunately it's rather clear that we do not in fact live in such a world. In the world we live in, it has been demonstrated that quantities we choose not to measure are not meaningful, even if we could have measured them had we wanted to. For example, when we set up a two slit experiment, "the slit the particle goes through" is something we can measure if we choose, by monitoring one or both slits. But if we don't choose to monitor that, and we send a large number of particles through, the resulting distribution will be consistent only with the idea that each particle in some sense goes through both slits. Because we did not measure which slit, the question of 'which slit' has become meaningless.
In such a world, the existential status of something that we not only do not measure, but do not know how to measure, is precarious!
> > | My view is that the philosophy is justified by what we know of quantum theory. |
> | Certain aspects of the quantum theory are also different to measure i.e. to validate, but that is not the subject here. |
What parts of the quantum theory are asserted to be measureable, but cannot be measured? - show quoted text -
On Monday, July 6, 2015 at 1:56:45 AM UTC-4, Gerry Quinn wrote:
> > > | My view is that the philosophy is justified by what we know of quantum theory. |
> |
> > |
Certain aspects of the quantum theory are also different to measure i.e. to validate, but that is not the subject here. |
> |
What parts of the quantum theory are asserted to be measureable, but cannot be measured? |
Hi Gerry
"Meaningless propositions are neither susceptible to validation, nor needful of it."
Well said.
Would like to touch on developmental psychology with respect to the 2 postulates.
There are two general types in science. A Faraday and an Oppenheimer.
A Faraday will compare the postulate with the math to verify the math. The postulates are of greater importance. I will venture a guess at 12 he required cloves tied to coat sleeves to keep them from being lost. Forgetful is the key leading to an intuitive thinker later in life.
An Oppenheimer will compare the math with the postulates to verify the postulates. The math is of greater importance. Oppy has no need for cloves tied to sleeves as they are in a draw organize chronologically. A well organized mind that is not forgetful is the key.
I would put myself in the Faraday camp. The postulates are heart of special relativity. If it turned out the math in SR is wrong then one simply corrects the math somewhat like a spelling mistake. It is the postulates that may not be violated.
This placers a greater burden on us. Dr Einstein could not violate Newtonian physics in 1905 as he would no longer have a floor to stand on. When the last dot was put on SR Newtonian physics was not violated with regards to energy and arrival times for a given frame of reference. Both theories render the same answer. This makes SR foundational to Newtonian physics. From a physics foundational position we today can not violate the two postulates as we will no longer have a floor to stand on in the same way Dr Einstein could not violate Newtonian physics.
> |
My understanding is that when there is curvature involved there
is also mass involved implying that you come in the region which
is described by GR and where light rays do not follow straight lines.
IMO to calculate the speed of light under such conditions is tricky. |
It's much worse than merely "tricky", it is AMBIGUOUS and therefore not well defined.
Consider a simple one-way measurement of the speed of light from a mountaintop to the adjacent valley, using two (ideal) clocks, neglecting air. The clocks must be synchronized, so imagine you do that using a light ray. Obviously if you make the measurement immediately thereafter, you will obtain c. Wait a while, and you will obtain a value smaller than c (due to the relative drift of the clocks due to "gravitational redshift"). Wait long enough, and you will obtain a NEGATIVE result! Use the same endpoints but measure in the other direction, and you can obtain an arbitrarily large answer!
That is why when physicists measure a speed, they always intend the measurement to be made in a locally inertial frame. The size of that frame, of course, depends on both the local curvature of spacetime and the measurement accuracy. For marathons and auto races this doesn't matter; for measuring the speed of light it can.
Note, however, if the two endpoints are on earth's geoid, then the measurement will be independent of time, even though the path is the same length as before. It would be disingenuous to claim this uses SR -- one must apply GR, and for this case it predicts the constant value c.
But if one measures in a lab over a horizontal path of a few meters, then one CAN apply SR -- a locally inertial (free- falling) frame that is at rest with the apparatus when the measurement begins will fall much less than the measurement accuracy during the few nanoseconds of the measurement.
> | Of course the simplest solution is to declare the speed of light constant. |
HUH??? That is no "solution" at all.
Of course physicists don't do that -- the constancy of the speed of light applies to SR, not GR, and SR is only APPROXIMATELY valid, and only in a locally inertial frame; the maximum size of that frame, of course, depends on both the local curvature of spacetime and the measurement accuracy.
> | If you cannot use GR what than? |
Then YOU must find another hobby.... Those of us who do this sort of thing for a living can and will use GR. Most likely in an appropriate approximation, of course.
Tom Roberts
> | On 8/4/15 8/4/15 7:48 AM, Nicolaas Vroom wrote: |
> > | IMO to calculate the speed of light under such conditions is tricky. |
> |
It's much worse than merely "tricky", it is AMBIGUOUS and therefore not well defined. Consider a simple one-way measurement of the speed of light from a mountaintop to the adjacent valley, using two (ideal) clocks, neglecting air. The clocks must be synchronized, so imagine you do that using a light ray. |
Just some thoughts. IMO this synchronisation process is already rather complex. IMO the mountaintop should issue a light signal at regular intervals. You get than a string like 6, 8, 10, 12 and 14. The next step is to record the arrival times of these signals at the valley clock. You could get than a string like 11, 13, 15, 17 and 19. (A) But also You could get than a string like 11, 12.9, 14.8, 16.7 and 18.6 (B) In case B the valley clock runs faster, which have to adjusted to take care that both clocks run at the same rate. After this adjustment the time to go from top to valley is always the same, which it physical should be. The next step consists of two parts: You must first reflect the received valley signals back to the top. You get a string like 10, 12, 14, 16 and 18 Secondly you must adjust the valley clocks such that their readings are a string like: (6+10)/2 = 8, 10, 12, 14 and 16 Now the clocks are synchronised?
However you do not know if the speed is constant during the whole trip. To test that you have to repeat the same process half way between top and valley.
> | That is why when physicists measure a speed, they always intend the measurement to be made in a locally inertial frame. |
But if you perform such a test at a locally inertial frame at the top and a second time at a locally inertial frame at the valley and the speeds are different what is the point of declaring the speed of light constant?
See also you posting at 20 June 2015: "Today (post 1983) standards organizations are not interested in measuring the speed of light, as it is a constant used to define the meter."
> > | Of course the simplest solution is to declare the speed of light constant. |
> |
HUH??? That is no "solution" at all. |
I agree
> | Of course physicists don't do that -- the constancy of the speed of light applies to SR, not GR, and SR is only APPROXIMATELY valid, and only in a locally inertial frame; the maximum size of that frame, of course, depends on both the local curvature of spacetime and the measurement accuracy. |
The problem is what I want to do is to simulate the movements of the planets around the sun, specific the planet Mercury. Also I want to calculate a Galaxy Rotation Curve. In both cases I want to see what is involved when I use GR. Apperently SR is out of the question, including the two (five) postulates on which it is based. The question than remains: what is the purpose of SR?
> > | If you cannot use GR what than? |
> |
Then YOU must find another hobby.... |
> | Those of us who do this sort of thing for a living can and will use GR. Most likely in an appropriate approximation, of course. |
If you start from one mutual agreed reference frame and if you do not use moving clocks (after synchronisation) things are becoming simpler.
IMO one important question to answer is what is the function of the speed of light (ie photons) in relation to the laws of nature i.e. GR. This question is specific important in relation to dark matter.
Nicolaas Vroom
Nicolaas Vroom wrote:
> | Just some thoughts. IMO this synchronisation process is already rather complex. IMO the mountaintop should issue a light signal at regular intervals. You get than a string like 6, 8, 10, 12 and 14. The next step is to record the arrival times of these signals at the valley clock. You could get than a string like 11, 13, 15, 17 and 19. (A) But also You could get than a string like 11, 12.9, 14.8, 16.7 and 18.6 (B) In case B the valley clock runs faster, which have to adjusted to take care that both clocks run at the same rate. After this adjustment the time to go from top to valley is always the same, which it physical should be. |
What do you mean with "time to go from top to valley"? The time a signal takes to run from top to valley? In GR, this time can mean the proper time of the signal (what is zero in the case of a light signal) or the coordinate time interval in some coordinate system. The coordinate time interval is, assumed the coordinate system is time translation invariant like Schwarzschild coordinates are, always the same, fully independent from adjustments of the valley clock.
> | The next step consists of two parts: You must first reflect the received valley signals back to the top. You get a string like 10, 12, 14, 16 and 18 Secondly you must adjust the valley clocks such that their readings are a string like: (6+10)/2 = 8, 10, 12, 14 and 16 Now the clocks are synchronised? |
The clocks are synchronized in Schwarzschild coordinates if both run with the same running speed with respect to Schwarzschild coordinate time and show the same clock time at the same Schwarzschild coordinate time. I.e. on any spacelike hypersurface defined by t = const, where t is Schwarzschild coordinate time, they must show the same clock time.
The division by 2 in your procedure sounds as if you want to apply SR clock synchronization that assumes a constant speed of light. Since the speed of light with respect to Schwarzschild coordinates is not constant, your procedure will probably fail.
> | However you do not know if the speed is constant during the whole trip. |
Applying the Schwazschild solution, you know that the speed of light is not constant with respect to Schwarzschild coordinates.
>> | That is why when physicists measure a speed, they always intend the measurement to be made in a locally inertial frame. |
> |
But if you perform such a test at a locally inertial frame at the top and a second time at a locally inertial frame at the valley and the speeds are different |
No, they are not. The speeds measured in the particular local inertial frame are the same, namely c. Only the speeds indicated in a coordinate like Schwarzschild coordinates are different.
More mathematically: take two clocks A and B that are radially free falling. For each clock, you take a small spacetime region, so small that you can approximate each clock as resting in Schwarzschild coordinates, i.e. dr/dt = 0, where r ist Schwarzschild radial coordinate. So, in the particular spacetime region, you can imagine clock A as resting at radial coordinate rA, clock B at rB.
Now take a light ray passing clock A radially. In Schwarzschild coordinates, the speed of the light ray is
dr/dt = (1 - rs/rA) c (1)
Now let's calculate the speed of that light ray in the local inertial frame of clock A. To do so, we at first have to calculate the proper time interval d(tauA) elapsing for clock A during the Schwarzschild coordinate time interval dt. We get
d(tauA) = sqrt(g_tt(rA)) = sqrt(1 - rs/rA) dt
with g_tt(rA) = 1 - rs/rA being the tt-component of the metric tensor in Schwarzschild coordinates at r = rA. Next, we need to calculate the spatial distance d(lA) in clock A's local inertial frame between the points rA and rA + dr between which the light ray is travelling during the Schwarzschild coordinate time interval dt. We get
d(lA) = sqrt(-g_rr(rA)) = dr / sqrt(1 - rs/rA)
with g_rr(rA) = -1/(1 - rs/rA) being the rr-component of the metric tensor in Schwarzschild coordinates at r = rA. For dr, we insert (1):
dr = (1 - rs/rA) c dt
=> d(lA) = (1 - rs/rA) c dt / sqrt(1 - rs/rA)
= sqrt(1 - rs/rA) c dt
To get now the speed of light in the local inertial frame of clock A, we need to calculate
d(lA) / d(tauA) = sqrt(1 - rs/rA) c dt / sqrt(1 - rs/rA) dt
= c
So, in the local inertial frame of clock A, the speed of that light ray is c.
The procedure we apply to clock B: the speed of a light ray passing clock B radially is in Schwarzschild coordinates:
dr/dt = (1 - rs/rB) c (2)
The elapsing proper time on clock B is
d(tauB) = sqrt(g_tt(rB)) = sqrt(1 - rs/rB) dt
and the spatial distance in clock B's local inertial frame
d(lB) = sqrt(-g_rr(rB)) = dr / sqrt(1 - rs/rB)
We again insert (2):
d(lB) = sqrt(-g_rr(rB)) = (1 - rs/rB) c dt / sqrt(1 - rs/rB)
= sqrt(1 - rs/rB) c dt
and calculate the speed of the light ray in clock B's local inertial frame:
d(lB) / d(tauB) = sqrt(1 - rs/rB) c dt / sqrt(1 - rs/rB) dt
= c
We again get c as speed.
In other words: the speed of light slows down in Schwarzschild coordinates when r is decreasing, but clocks of local inertial frames are slowing down, too, with respect to Schwarzschild coordinate time, and in combination with the effects of spatial curvature, expressed by g_rr, this provides that the speed of light remains the same, namely c, in all local inertial frames.
In fact, the causality of GR is the other way round: the constancy of the speed of light in all local inertial frames is the fundamental principle, and the slowing down of the speed of light with respect to Schwarzschild coordinates in Schwarzschild solution is derived from that.
And it is important to note, that the speed of light in local inertial frames is, compared to the speed of light in Schwarzschild coordinates, the more fundamental one. Schwarzschild coordinates are just an arbitrarily chosen coordinate system, one could as well chose various different coordinate systems, like one does in the case of black holes, e.g. Eddingtin-Finkelstein coordinates, free-falling coordinates, or Kruskal coordinates, that yield totally different speeds of light.
>> | Of course physicists don't do that -- the constancy of the speed of light applies to SR, not GR, and SR is only APPROXIMATELY valid, and only in a locally inertial frame; the maximum size of that frame, of course, depends on both the local curvature of spacetime and the measurement accuracy. |
> |
The problem is what I want to do is to simulate the movements of the planets around the sun, specific the planet Mercury. Also I want to calculate a Galaxy Rotation Curve. In both cases I want to see what is involved when I use GR. Apperently SR is out of the question, including the two (five) postulates on which it is based. |
In GR, the postulate of the constancy of the speed of light remains valid in that way that the speed of light measured in local inertial frames is constant.
> | The question than remains: what is the purpose of SR? |
Describing situation where gravity can be neglected.
>>> | If you cannot use GR what than? |
>> |
Then YOU must find another hobby.... |
> | I'm too old to learn fishing. |
>> |
Those of us who do this sort of thing for a living can and will use GR. Most likely in an appropriate approximation, of course. |
> | Of course if you remove too much, is it than still GR or does it become Newton+ |
That depends on how much too much is.
> | If you start from one mutual agreed reference frame and if you do not use moving clocks (after synchronisation) things are becoming simpler. |
If you want to use reference frames in a regime ruled by gravity, then you cannot use GR. But why don't you simply use GR and accept that you have to use coordinate systems instead of inertial frames?
And: your desire to use reference frames but not to use moving clocks, seems a little strange. Usually, using reference frames is combined with using moving clocks.
> | IMO one important question to answer is what is the function of the speed of light (ie photons) in relation to the laws of nature i.e. GR. |
I'm not sure whether I can make any sense in this question. In coordinate systems in which the speed of light is not constant, e.g. Schwarzschild coordinates in Schwarzschild solution, you can write the speed of light as function of some parameters, like r in the case of Schwarzschild coordinates:
v(r) = (1 - rs/r) c
Or did you rather want to ask in what way the postulate of the constancy of the speed of light from SR remains valid in GR?
> | Op woensdag 5 augustus 2015 21:38:22 UTC+2 schreef Tom Roberts: |
>> | On 8/4/15 8/4/15 7:48 AM, Nicolaas Vroom wrote: when physicists measure a speed, they always intend the measurement to be made in a locally inertial frame. |
> |
But if you perform such a test at a locally inertial frame at the top and a second time at a locally inertial frame at the valley and the speeds are different what is the point of declaring the speed of light constant? |
If the speeds were measurably different then you would have refuted GR in a rather big way. To date that has not happened, and most physicists would give rather long odds that this sort of refutation won't ever happen.
> | The problem is what I want to do is to simulate the movements of the planets around the sun, specific the planet Mercury. |
Using Newtonian gravitation (NG) this is simple if you ignore the other planets, but quite complicated if you include them (and you must include them if you want accuracy [#]).
[#] e.g. sufficient accuracy to see the difference between NG and GR.
> | Also I want to calculate a Galaxy Rotation Curve. |
Let's not discuss this now, there's too much else on the table. (But this is VERY different from the solar system calculations.)
> | In both cases I want to see what is involved when I use GR. |
Using NG for the solar system is already quite complicated; AFAIK nobody has used GR for this, as that is far too complicated. What people actually do is use the post-Newtonian (or post-post-Netonian) approximation to GR. This is more complicated than using NG alone, but is tractable. Note, however, that programs to calculate the solar system at this level have been developed over many staff-years by experts; you have a long and arduous road ahead.... And a lot to learn....
> | what is the purpose of SR? |
It was a VERY important step on the road to GR. And since GR is so complicated to apply, SR remains quite useful in situations in which gravitation can be neglected.
Consider the LHC experiments. Each is in a cavern less than 100 meters large, and all the particles of interest travel with speed > 0.99 c relative to the cavern. So let's apply SR in the locally inertial frame that is at rest relative to the cavern at the instant of the crossing (the interaction that produces the particles of interest). Within 300 ns all the particles have left the cavern and can no longer be observed by the detector. During 300 ns that locally inertial frame falls 0.5 g t^2 = 4.4E-12 meters. The detectors have resolutions on the order of a micron or more, so the error in assuming the detector is at rest in an inertial frame is FAR below the experimental resolution -- SR can be used without problem. (A calculation for the rotation of the earth yields an error that's even smaller than this.)
> | IMO one important question to answer is what is the function of the speed of light (ie photons) in relation to the laws of nature... |
I suspect it has essentially no role at all in fundamental physical phenomena. That's because all such phenomena appear to be LOCAL (<< 1E-6 meters), so the propagation of light is just irrelevant.
> | ... i.e. GR. |
Most physicists doubt very much that GR is a "law of nature". It seems MUCH more likely that it is merely an approximation to something more fundamental. But the jury is still out....
Tom Roberts
> |
Nicolaas Vroom wrote: |
> > |
Just some thoughts. IMO this synchronisation process is already rather complex. IMO the mountaintop should issue a light signal at regular intervals. You get than a string like 6, 8, 10, 12 and 14. |
Skip
> | What do you mean with "time to go from top to valley"? The time a signal takes to run from top to valley? In GR, this time can mean the proper time of the signal (what is zero in the case of a light signal) or the |
Skip
It is important to remember that my posting is a reply on the following posting by Tom Roberts:
> | Op woensdag 5 augustus 2015 21:38:22 UTC+2 schreef Tom Roberts: |
>> | On 8/4/15 8/4/15 7:48 AM, Nicolaas Vroom wrote: |
>> > | IMO to calculate the speed of light under such conditions is tricky. |
>> |
It's much worse than merely "tricky", it is AMBIGUOUS and therefore not well defined. Consider a simple one-way measurement of the speed of light from a mountaintop to the adjacent valley, using two (ideal) clocks, neglecting air. The clocks must be synchronized, so imagine you do that using a light ray. |
What I try to do is answer the question is the speed of light constant. To do that let me first define a simple experiment. The experiment consists of dropping a ball from the Tower of Pisa, which bounches back. The objective is to measure the time when the ball reaches its highest point. In order to measure this time I use a small ball which bounces between two horizontal plates. The total number of counts (bounces) is 10. Next I perform the same experiment but I use half the distance. The total number of counts is 7. That means for the first part the number of counts is 7 and for the second part 3. My reasoning the speed of the ball is not constant. Is this correct?
The second experiment is physical identical as above but instead of a ball I use a light ray which is reflected. To measure the time I also use a light ray between two mirrors. The results are totally different but suppose I get for the total count 2000 and for the first part 1001. That means for the second part 999. Is this feasible? My conclusion is the same: The speed of light is not constant. Is this correct?
> > | The question than remains: what is the purpose of SR? |
> |
Describing situation where gravity can be neglected. |
Interesting. My impression is that in all (?) experiments in the realm of SR gravity is involved. (moving clocks in airplane) That means (My impresion) you can describe each of these experiments also without SR and only solely with GR. or is this wrong reasoning?
Nicolaas Vroom
> | On 8/12/15 8/12/15 5:05 AM, Nicolaas Vroom wrote: |
> > |
The problem is what I want to do is to simulate the movements of the planets around the sun, specific the planet Mercury. |
> |
Using Newtonian gravitation (NG) this is simple if you ignore the other planets, but quite complicated if you include them (and you must include them if you want accuracy [#]). |
[[Mod. note -- Note that as well as "all" the planets, you probably want lots of moons and asteroids, too. -- jt]]
The problem is the perihelion shift of Mercury of 43 arc sec. You can also use NG as a bassis to solve that, but than you have to modify NG and take into account that gravity does act instantaneous.
> > | Also I want to calculate a Galaxy Rotation Curve. |
> |
Let's not discuss this now, there's too much else on the table. (But this is VERY different from the solar system calculations.) |
See for example: https://www.nicvroom.be/VB%20Gal%20Mond%20operation.htm The purpose of the Visual Basic "VB Gal MOND" is to simulate a Galaxy starting from the Galaxy Rotation Curve. That means first the mass distribution is calculated and than the Galaxy is simulated.
The purpose of the program is primarily to compare NG with MOND. What the program shows that with MOND there is no mass in the disc in that part where the rotation curve is flat. That you cannot use MOND to simulate our Solar system.
> > | In both cases I want to see what is involved when I use GR. |
> |
Using NG for the solar system is already quite complicated; |
> | AFAIK nobody has used GR for this, as that is far too complicated. |
> | What people actually do is use etc. |
[[Mod. note -- What people actually do use is a very good approximation to GR called the Parameterized Post-Newtonian (PPN) Formalism. This is basically a Taylor-series expansion of GR about the flat metric. This is described in detail in sections 3 and 4 of Clifford M. Will's article "The Confrontation between General Relativity and Experiment" (Living Reviews in Relativity, 2014, free online at http://relativity.livingreviews.org/Articles/lrr-2014-4/fulltext.html
Another very good description, with lots of details on how the actual tests are done, is an old-but-very-good conference paper, Ronald W Hellings "Testing Relativity with Solar System Dynamics" p.365-385 in... B Bertotti, F. de Felice, and A. Pascolini "General Relativity and Gravitation" [Invited Papers and Discussion Reports of the 10th International Conference on General Relativity and Gravitation, Padua (Italy), 3-8 July 1983] Reidel, Dordrecht (Holland), 1984 ISBN 90-277-1819-9 -- jt]]
> > | what is the purpose of SR? |
> |
It was a VERY important step on the road to GR. And since GR is so complicated to apply, SR remains quite useful in situations in which gravitation can be neglected. |
My question is specific in relation to the simulation of the solar system, a galaxy, the universe in total.
> > | IMO one important question to answer is what is the function of the speed of light (ie photons) in relation to the laws of nature... |
> |
I suspect it has essentially no role at all in fundamental physical phenomena. That's because all such phenomena appear to be LOCAL (<< 1E-6 meters), so the propagation of light is just irrelevant. |
Again in relation to the simulation of the Solar system, a galaxy the Universe
A different document to study is this: https://www.nicvroom.be/galaxy%20simulation.htm
> > | ... i.e. GR. |
> |
Most physicists doubt very much that GR is a "law of nature". It seems MUCH more likely that it is merely an approximation to something more fundamental. But the jury is still out.... |
and what about SR, Newton's Law and MOND
> | Tom Roberts |
thanks.
Nicolaas Vroom
> | What I try to do is answer the question is the speed of light constant. |
This question is not precise enough. When talking about a speed in GR, you have to distinguish between the speed measured in a local inertial frame and the speed measured in a coordinate system. The description you provide below indicates that you refer to the speed measured in a coordinate system (for more details see below). For the speed of light, this indeed implies that it is not constant, unlike the speed of light measured in a local inertial frame that remains constant in GR.
> | To do that let me first define a simple experiment. The experiment consists of dropping a ball from the Tower of Pisa, which bounches back. The objective is to measure the time when the ball reaches its highest point. In order to measure this time I use a small ball which bounces between two horizontal plates. The total number of counts (bounces) is 10. Next I perform the same experiment but I use half the distance. The total number of counts is 7. That means for the first part the number of counts is 7 and for the second part 3. My reasoning the speed of the ball is not constant. |
Your descrption implies that you define a coordinate system, with the following properties:
(1) The top and the ground of the Tower have fixed spatial coordinates
(2) The elapsing coordinate time is proportional to the number of bounces of the bouncing ball between the plates.
(3) Time translation invariance applies: the coordinate time interval that the ball takes for the trip from top to ground is the same as the coordinate time interval the ball takes for the back-trip from ground to top.
The speed of the ball measured in that coordinate system is not constant, that is correct.
> | The second experiment is physical identical as above but instead of a ball I use a light ray which is reflected. To measure the time I also use a light ray between two mirrors. The results are totally different but suppose I get for the total count 2000 and for the first part 1001. That means for the second part 999. Is this feasible? My conclusion is the same: The speed of light is not constant. |
Measured with respect to the coordinate system that you apply here, which is the same coordinate system as in the ball version of the experiment, the speed of light is not constant, that is correct.
However, that speed of light is not "the speed of light". It is just the speed of light *in the coordinate system you have chosen*. In GR, the choice of the coordinate system is arbitrary, instead of the coordinate system that you applied above you could as well choose any other coordinate system, e.g. one in which the speed of light turns out to be constant for your experiment. Due to this, the speed of light in the currently chosen coordinate system is an arbitrary quantity in GR and therefore not very meaningful.
A rather meaningful indication of the speed of light is the indication with respect to a local inertial frame. That speed of light is always constant in GR. In your experiment, you can apply a local inertial frame at the top of the Towever, and you will find the speed of light constant. You can apply a different local inertial frame at the middle of the tower, and you will find the speed of light constant again. Finally, you can apply another local inertial frame at the bottom of the tower, and you will find the speed of light constant another time.
What is not possible, though, is to apply the same local inertial frame for the whole trip from top to bottom, since the corresponding spacetime region is not sufficiently limited.
>>> | The question than remains: what is the purpose of SR? |
>> |
Describing situation where gravity can be neglected. |
> |
Interesting. My impression is that in all (?) experiments in the realm of SR gravity is involved. (moving clocks in airplane) |
The Hafele-Keating experiment to which you seem to be referring indeed did not test the effects of SR on their own, but rather the combined effects of SR and GR.
However, there have been different experiments where GR effects were not relevant. Take e.g. experiments in particle accelerators. Since all parts of an accelerator are at the same height with respect to the ground, differences in gravitational field are out of relevance. Or take muon experiments. The muons are changing in height, though, but the gravitational time dilation effects are neglectible compared to the SR time dilation due to the high speed of the muons.
> | Nicolaas Vroom wrote: |
> > |
What I try to do is answer the question is the speed of light constant. |
> |
This question is not precise enough. |
I think that my question is rather simple ? Is the speed of light (the speed of the photons) in the universe everywhere the same and if not what is the physical cause.
> | When talking about a speed in GR, you have to distinguish between the speed measured in a local inertial frame and the speed measured in a coordinate system. |
> | The description you provide below indicates that you refer to the speed measured in a coordinate system (for more details see below). For the speed of light, this indeed implies that it is not constant, unlike the speed of light measured in a local inertial frame that remains constant in GR. |
My suggestion is to define your experiment which demonstrates that the speed of light is constant. By preference you should not include any moving clock.
> > | My reasoning the speed of the ball is not constant. |
> |
skip
> | The speed of the ball measured in that coordinate system is not constant, that is correct. |
In fact you can also make the coordinate system much larger. You can easily include the earth in total.
> > | The second experiment is physical identical as above etc My conclusion is the same: The speed of light is not constant. |
> |
Measured with respect to the coordinate system that you apply here, which is the same coordinate system as in the ball version of the experiment, the speed of light is not constant, that is correct. |
It is something more: the speed of light increases when it travels towards the earth. However also in reverse sense: The speed of light decreases when the distance from the earth increases. (Within limits of the solar system)
> | instead etc. you could as well choose any other coordinate system, e.g. one in which the speed of light turns out to be constant for your experiment. |
My same suggestion: Supply me the details.
> | In your experiment, you can apply a local inertial frame at the top of the Towever, and you will find the speed of light constant. |
The same as above
> | You can apply a different local inertial frame at the middle of the tower, and you will find the speed of light constant again. |
IMO why should I do that it makes a simulation of the solar system of a galaxy terrible complicated (I think)
> | What is not possible, though, is to apply the same local inertial frame for the whole trip from top to bottom, since the corresponding spacetime region is not sufficiently limited. |
What is wrong in using one coordinate system for our whole galaxy?
[[Mod. note -- The issue is that you can't use a single (global) *inertial* coordinate system for the whole trip -- the whole message of GR is that no such coordinate system can exist, i.e., that no coordinate system can have the property of being global-inertial (i.e., flat) *and* cover a large region of a spacetime with significant gravitational effects. -- jt]]
> | The Hafele-Keating experiment to which you seem to be referring indeed did not test the effects of SR on their own, but rather the combined effects of SR and GR. |
But why not solely using GR for the whole experiment?
[[Mod. note -- Since GR is a superset of SR, you *could* analyse the whole experiment in the framework of GR. However, some (though not all) of the effects in this experiment (= flying atomic clocks around the world) are already present in an SR model, and it's useful to analyses these effects from the perspective of SR. -- jt]]
Nicolaas Vroom
>>> | What I try to do is answer the question is the speed of light constant. |
>> |
This question is not precise enough. |
> |
I think that my question is rather simple ? Is the speed of light (the speed of the photons) in the universe everywhere the same |
Within the framework of a theory in which the term "speed of light" has a clear, unique meaning (e.g. SR), your question might be simple. But in GR, the term "speed of light" does not have such a clear meaning. "Speed of light" can either mean the speed of light measured in a local inertial frame, or the speed of light measured in a coordinate system.
> | and if not what is the physical cause. |
What is in general not constant in GR is the speed of light in a coordinate system. However, this does not have a physical cause, since it is just a property of the chosen coordinate system. At best, one can ask for the physical cause why one cannot apply inertial frames like in SR, but is obliged to come along with more general coordinate systems. The physical cause for that is the curvature of spacetime: in a curved spacetime, inertial frames can only be constructed locally, not globally for the complete spacetime.
Take for illustration the surface of sphere. That is a curved two-dimensional space. It's easy to seen that it's impossible to construct a Cartesian (x,y) coordinate system that covers the complete surface. A Cartesian coordinate system can only be constructed locally around a chosen point on the surface, in an environment that is small compared to the sphere's radius. The same applies for inertial frames in a curved spacetime.
>> | When talking about a speed in GR, you have to distinguish between the speed measured in a local inertial frame and the speed measured in a coordinate system. |
> | Ofcourse if you want to measure the speed of light you have to quantify the distance and time you use which implies a coordinate system. That is not what I have done. The speed is in counts of one counter. |
If we follow your description, the counts of the counter are nothing but a number that is proportional to the coordinate time of a coordinate system you apply. That means that you are using a coordinate system and measure speeds with respect to it.
>> | The description you provide below indicates that you refer to the speed measured in a coordinate system (for more details see below). For the speed of light, this indeed implies that it is not constant, unlike the speed of light measured in a local inertial frame that remains constant in GR. |
> |
My suggestion is to define your experiment which demonstrates that the speed of light is constant. |
Since the term "the speed of light" does not have a clear meaning in GR, this requirement is not well-formulated. Let's assume that your requirement was instead to define an experiment that demonstrates that the speed of light *in a local inertial frame* is constant.
This can e.g. be done by performing three experiments, one at the top of the tower, one at the middle, and one at the bottom. In each experiment, you measure the speed of light in the following way:
Put two clocks that are synchronized to two positions that are close to each other, where close means that the distance between both positions is much smaller than the height of the tower. Let a light ray run from the first clock to the second one. Not the clock time the first clock shows when the light ray starts, and the clock time the second clock shows when the light ray arrives. Divide the distance between the two clocks by the difference between the noted clock times.
The resulting quantity is the speed of light measured in a local inertial frame that is momentarily resting relative to the particular stage of the tower (top, middle, bottom). According to GR, that quantity is the same in all three experiments.
>> | The speed of the ball measured in that coordinate system is not constant, that is correct. |
> |
In fact you can also make the coordinate system much larger. You can easily include the earth in total. |
Different coordinate systems are not constructed by making a given coordinate system larger, but rather by attaching different coordinates to the same spacetime points.
Take the coordinate system that you defined in the description of your experiment. In that coordinate system, top and bottom of the tower have fixed spatial coordinates, i.e. the spatial coordinates are always the same for all values of the coordinate time. In a different coordinate system, the spatial coordinates of these two positions may be changing by time. Or they may be fixed, too, but time translation invariance does not apply, i.e. the time coordinate is different in that way that the trip from top to bottom takes a different coordinate time interval than the back-trip from bottom to top.
More in detail: the coordinate system that you are using can be easily identified with Schwarzschild coordinates. These coordinates are very useful to describe situations in the gravitational field of an ordinary celestial body, like a star or planet. However, they become impractical if you want to describe a black hole, since they have a coordinate singularity at the event horizon. Therefore, one has to apply alternative coordinate systems. Two examples are Eddington-Finkelstein coordinates and free-falling coordinates. In both, top and bottom of your tower have fixed spatial coordinates like in Schwarzschild coordinates, but time coordinates of events are different.
As you can read e.g. here:
http://casa.colorado.edu/~ajsh/schwp.html
the time coordinate t_ff of free-falling coordinates can by calculated from Schwarzschild coordinate time t_SS by
t_ff = t_SS + 2 r^(1/2) + ln|(r^(1/2) - 1)/(r^(1/2) + 1)|
where r is the radial spatial coordinate, that both coordinate systems share. For the coordinate time t_EF of Eddington-Finkelstein coordinates, the formula is
t_EF = t_SS + ln|r-1|
Let's use Eddington-Finkelstein coordinates for your ball experiment. Let the radial coordinate of the top of the tower be r = r_top, the radial coordinate of the bottom r = r_bottom. The Schwarzschild coordinate time when the ball starts to fall is t_SS = t_SS_1, the Schwarzschild coordinate time when the ball reaches the bottom is
t_SS = t_SS_2 = t_SS_1 + T
and the Schwarzschild coordinate time when the ball turns back to the top is
t_SS = t_SS_3 = t_SS_1 + 2T
where T is the Schwarzschild coordinate time interval the ball takes from top to bottom. So, the worldline of the ball passes through three spacetime points that have the following coordinates in Schwarzschild coordinates:
(t_SS_1, r_top), (t_SS_1 + T, r_bottom), (t_SS_1 + 2T, r_top)
Now, let's calculate the Eddington-Finkelstein coordinate times of the three events:
t_EF_1 = t_SS_1 + ln|r_top + 1|
t_EF_2 = t_SS_2 + ln|r_bottom + 1| = t_SS_1 + T + ln|r_bottom + 1|
t_EF_3 = t_SS_3 + ln|r_top + 1| = t_SS_1 + 2T + ln|r_top + 1|
Next, we calculate the coordinate time intervals. From the trip from top to bottom, the ball takes the Eddington-Finkelstein coordinate time interval
T_EF_12 = t_EF_2 - t_EF_1 = T + ln|r_bottom + 1| - ln|r_top + 1|
For the back-trip from bottom to top:
T_EF_23 = t_EF_3 - t_EF_2 = T + ln|r_top + 1| - ln|r_bottom + 1|
So, we see, the two coordinate time intervals are different in Eddington-Finkelstein coordinates, unlike in Schwarzschild coordinates where both intervals are equal, namely T. That means that there is no time translation invariance in Eddington-Finkelstein coordinates.
There is another coordinate system, that is also useful for black holes, Kruskal-Szekeres coordinates (often simply called Kruskal coordinates). In these coordinates, there is no time-translation invariance, too, and in addition, the top and bottom of your tower do not have fixed spatial coordinates. However, the speed of light in these coordinates is constant, at least for radially propagating light rays.
One could now be temptated to argue that as long as we do not consider black holes, there is no need for Eddington-Finkelstein coordinates, free-falling coordinates or Kruskal coordinates, so that we come along with Schwarzschild coordinates, especially since Schwarzschild coordinates have the nice property of time translation invariance and that bodies that are obviously resting in a gravitational field, like the Tower of Pisa, have fixed spatial coordinates.
However, when considering the question whether the speed of light is constant in GR, we must take into account the full symmetries of GR. GR is not only about ordinary celestial bodies, but also about black holes, and in addition, not only about Schwarzschild solution (that describes the gravitational fields of both, ordinary celestial bodies and black holes), but about arbitrary spacetime metrics. Therefore, we must not restrict ourselves to consider Schwarzschild coordinates, and to imagine the speed of light in Schwarzschild coordinates as being specially meaningful.
GR is generally covariant, i.e. the chosen coordinate system is arbitrary, and thefore the speed of light in the actual coordinate system little meaningful, no matter how useful that coordinate system is in special cases.
>>> | The second experiment is physical identical as above etc My conclusion is the same: The speed of light is not constant. |
>> |
Measured with respect to the coordinate system that you apply here, which is the same coordinate system as in the ball version of the experiment, the speed of light is not constant, that is correct. |
> |
It is something more: the speed of light increases when it travels towards the earth. |
No. The sentence is not well-formulated, seen from the viewpoint of GR. The speed of light *in Schwarzschild coordinates* increases.
>> | instead etc. you could as well choose any other coordinate system, e.g. one in which the speed of light turns out to be constant for your experiment. |
> |
My same suggestion: Supply me the details. |
See above: Kruskal-Szekeres coordinates. Also see:
https://en.wikipedia.org/wiki/Kruskal%E2%80%93Szekeres_coordinates
Take the diagram to the right, we the numbers I, II, III and IV in different colors. Imagine the top of the Tower having the hyperbola r=1.6 as wordline, the middle r=1.4 and the bottom r=1.2. Radial light ray follow diagonal lines in the diagram, i.e. their speed (in that coordinate system) is constant.
>> | You can apply a different local inertial frame at the middle of the tower, and you will find the speed of light constant again. |
> |
IMO why should I do that it makes a simulation of the solar system of a galaxy terrible complicated (I think) |
Your question to which I answered was not "How can I keep my simulation simple?". It was rather "Is the speed of light constand in GR?".
If you prefer an answer to the question "How can I keep my simulation simple?": just use Schwarzschild coordinates. Concerning the speed of light: that is not constant in these coordinates.
>> | What is not possible, though, is to apply the same local inertial frame for the whole trip from top to bottom, since the corresponding spacetime region is not sufficiently limited. |
> |
What is wrong in using one coordinate system for our whole galaxy? |
I did not say that there would be something wrong in using one coordinate system for our whole galaxy. What I said is that it is not possible to construct an inertial frame that covers a spacetime region that is not small compared to scales on which the spacetime curvature becomes relevant. To understand the reason just try to construct a Cartesian (x,y) coordinate system on a sphere's surface.
>> | The Hafele-Keating experiment to which you seem to be referring indeed did not test the effects of SR on their own, but rather the combined effects of SR and GR. |
> |
But why not solely using GR for the whole experiment? |
One solely uses GR for the whole experiment. However, in GR, one can distinguish between effects that also exist in SR, and effects that are special to GR. The latter category, I called "GR effects", and the first category "SR effects".
> | Nicolaas Vroom wrote: |
> >>> |
What I try to do is answer the question is the speed of light constant. |
> >> |
This question is not precise enough. |
> > |
I think that my question is rather simple ? Is the speed of light (the speed of the photons) in the universe everywhere the same |
> |
Within the framework of a theory in which the term "speed of light" has a clear, unique meaning (e.g. SR), your question might be simple. But in GR, the term "speed of light" does not have such a clear meaning. "Speed of light" can either mean the speed of light measured in a local inertial frame, or the speed of light measured in a coordinate system. |
Can you give me an idea what is the difference between measuring something in a local inertial frame versus in a coordinate system? I my opinion in practice when you perform an experiment there exists not such a difference.
> > | and if not what is the physical cause. |
> |
What is in general not constant in GR is the speed of light in a coordinate system. However, this does not have a physical cause, since it is just a property of the chosen coordinate system. At best, one can ask for the physical cause why one cannot apply inertial frames like in SR, but is obliged to come along with more general coordinate systems. The physical cause for that is the curvature of spacetime: in a curved spacetime, inertial frames can only be constructed locally, not globally for the complete spacetime. |
This gives me the impression that you can not use GR to simulate a complete galaxy. Using Newton's Law this is difficult in practice because you have to know the initial positions of all objects at the same instance. In order to calculate the initial speed for each object you need at least two specific instances. It is not so difficult to simulate starting from an artificial configuration. See https://www.nicvroom.be/galaxy%20simulation.htm
> >> | When talking about a speed in GR, you have to distinguish between the speed measured in a local inertial frame and the speed measured in a coordinate system. |
> > | Ofcourse if you want to measure the speed of light you have to quantify the distance and time you use which implies a coordinate system. That is not what I have done. The speed is in counts of one counter. |
> |
If we follow your description, the counts of the counter are nothing but a number that is proportional to the coordinate time of a coordinate system you apply. That means that you are using a coordinate system and measure speeds with respect to it. |
I performed two experiments: One with a ball and one with light. Both are reflected. In both cases each experiment consists of two parts: full distance and half distance. In each case starting point is the same. In order to "measure" I use a counter, one using a ball and the other one using light. The result in both cases (my prediction) that the speed is not constant. In the case of a ball this is in accordance with Newton's Law. For light I assume the same.
> | Since the term "the speed of light" does not have a clear meaning in GR, this requirement is not well-formulated. Let's assume that your requirement was instead to define an experiment that demonstrates that the speed of light *in a local inertial frame* is constant. |
What I am discussing is the result of experiments. First "we" have to agree about the outcome of the experiment. The second step is to agree which theories predict or describe these experiments.
> |
This can e.g. be done by performing three experiments, one at the top of
the tower, one at the middle, and one at the bottom. In each experiment,
you measure the speed of light in the following way:
Put two clocks that are synchronized to two positions that are close to each other, where close means that the distance between both positions is much smaller than the height of the tower. Let a light ray run from the first clock to the second one. Not the clock time the first clock shows when the light ray starts, and the clock time the second clock shows when the light ray arrives. Divide the distance between the two clocks by the difference between the noted clock times. |
No this is not the way I propose. I try as simple as possible. In each experiment there is only one sort of clock used (counter), which is at rest.
> | Different coordinate systems are not constructed by making a given coordinate system larger, but rather by attaching different coordinates to the same spacetime points. |
IMO this makes everything very complex.
> | These coordinates are very useful to describe situations in the gravitational field of an ordinary celestial body, like a star or planet. However, they become impractical if you want to describe a black hole, since they have a coordinate singularity at the event horizon. |
In the simulations I have done you can insert at the center a BH. In our Galaxy we are lucky because "we" can observe induvidual stars which are rotating around the BH. This allows you to calculate the mass of the BH. However that is not the topic of this discussion.
> | Therefore, we must not restrict ourselves to consider Schwarzschild coordinates, and to imagine the speed of light in Schwarzschild coordinates as being specially meaningful. |
IMO opinion the speed of light is specific important in order to process measurement data ie positions and speeds. In order to predict future positions I doubt if the speed of light is important.
> > | It is something more: the speed of light increases when it travels towards the earth. |
> |
No. The sentence is not well-formulated, seen from the viewpoint of GR. The speed of light *in Schwarzschild coordinates* increases. |
The result of the experiment show in both cases that the number of counts in each half distance is different. To be more specific the number of counts in the second part is smaller than the first part. This means that the speed is different. This means that the speed in the second part is larger.
> |
See above: Kruskal-Szekeres coordinates. Also see:
https://en.wikipedia.org/wiki/Kruskal%E2%80%93Szekeres_coordinates Take the diagram to the right, we the numbers I, II, III and IV in different colors. Imagine the top of the Tower having the hyperbola r=1.6 as wordline, the middle r=1.4 and the bottom r=1.2. Radial light ray follow diagonal lines in the diagram, i.e. their speed (in that coordinate system) is constant. |
In that article they discuss physical singularity. IMO singualrities only "exist" in mathematical sense.
The important thing is that in order to discuss or perform experiments related to the speed of light you should not use clocks which are affected by your experiment. As such I'am not measuring the speed of light quantitative, but only demonstrate that the speed is not constant.
See also paragraph 7.3 in the book Gravitation which discusses an experiment I try to perform a simpler experiment.
Albert Einstein's used thought experiments to "demonstrate" SR and GR (my impression) He used thought experiments to demonstrate or explain that the path of lightrays are bended around mass. IMO that is very tricky. Page 13 in the book Gravitation states: "In each case one is following a natural track through spacetime". That maybe true, but what does it mean? See also: https://www.nicvroom.be/ScientificAm%20September%202015%20Reality.htm
Nicolaas Vroom
Nicolaas Vroom wrote:
>>>>> | What I try to do is answer the question is the speed of light constant. |
>>>> |
This question is not precise enough. |
>>> |
I think that my question is rather simple ? Is the speed of light (the speed of the photons) in the universe everywhere the same |
>> |
Within the framework of a theory in which the term "speed of light" has a clear, unique meaning (e.g. SR), your question might be simple. But in GR, the term "speed of light" does not have such a clear meaning. "Speed of light" can either mean the speed of light measured in a local inertial frame, or the speed of light measured in a coordinate system. |
> |
Can you give me an idea what is the difference between measuring something in a local inertial frame versus in a coordinate system? I my opinion in practice when you perform an experiment there exists not such a difference. |
As far as the procedure is concerned, there is no difference. In both, local inertial frames and general coordinate systems, a speed measurement for some body can be performed by the following procedure:
- Take two points P and Q on the worldline of the body - Determine the coordinates xP^mu = (tP, xP^i), mu=0,1,2,3, i=1,2,3, of point P - Determine the coordinates xQ^mu = (tQ, xQ^i) of point Q - Divide the difference in spatial coordinates by the difference in time coordinate: v^i = (xQ^i - xP^i) / (tQ - tP)
What makes the difference is that the general coordinate system is a general coordinate system whereas the local inertial frame is a local inertial frame. The result in the general coordinate system is arbitrary, since the coordinate system itself is arbitrary. The result in the local inertial frame, however, is meaningful, because the local inertial frame is very special.
For a better understanding of this fact, consider a two-dimensional space. Let's first assume the this space is flat, i.e. not curved, and has a Euklidian metric. In this space, you can construct various coordinate systems. However, there is a very special class of coordinate systems, the Cartesian coordinate systems. In such a Cartesian coordinate system, you have two coordinates (x,y), and the coordinate system has two crucial properties:
- x and y coordinate lines are perpendicular to each other everywhere
- x and y coordinate lines are straight everywhere
You can construct non-Cartesian coordinate systems, that violate at least one of these properties. For example, you can construct an oblique-angled coordinate system. The coordinate lines are still straight then, but not perpendicular to each other. Or you can construct polar coordinates (r,phi). The coordinate lines are perpendicular to each other then, but the phi coordinate lines are not straight.
No let's assume that the two-dimensional space is no longer flat, but is curved. One the first things you will found out is that it is no longer possible to construct a Cartesian coordinate system globally. You can try to construct a coordinate system with straight coordinate lines, but you will soon find out that the coordinate lines are not perpendicular to each other everywhere. Or you can try to construct a coordinate system with coordinate lines that are perpendicular everywhere, but the coordinate lines are not straight everywhere. Only locally, in a region small compared to the curvature radius of the space, a coordinate system can be construct that matches the properties of a Cartesian coordinate system in good approximation.
Now let's return to the four-dimensional spacetime of Relativity. In SR, where the spacetime is flat, things are similar to the flat two-dimensional space discussed above. As you can construct global Cartesian coordinate systems (x,y) in flat two-dimensional space, you can construct inertial frames (t,x,y,z) in flat spacetime. You can imagine inertial frames as generalization of Cartesian coordinate systems: all four coordinate lines, the three spatial ones and the time coordinate line, are straight, and all four coordinate lines are orthogonal to each other ("orthogonal" means something like "perpendicular", but is more general, in mathematics, one uses the term "perpendicular" only for special spaces).
As you can construct non-Cartesian coordinate systems in flat two-dimensional space, you can as well construct general coordinate systems in flat SR spacetime that are no inertial frames, e.g. coordinate systems in which the time coordinate line is not orthogonal to the three spatial coordinate lines. In such a coordinate system, the SR postulate of constant speed of light does NOT apply. Only in inertial frames, that postulate applies generally. Analogously, in flat two-dimensional space, there are rules that apply in Cartesian coordinate systems only, not in general coordinate systems.
Finally, let's come to the curved spacetime of GR. As we cannot construct global Cartesian coordinate systems in curved two-dimensional space, we cannot construct global inertial frames here. Trying to construct a global inertial frame would either result in non-orthogonal coordinate lines or in coordinate lines not being straight.
Take e.g. Schwarzschild coordinates (t,r,phi,theta) that are similar to the coordinates you used in your Pisa Tower thought experiment: the coordinate lines are orthogonal, but not straight. As far as the angle coordinates (phi,theta) are concerned, this is trivial, however, the same is true for time coordinate t and radial coordinate r: a body resting at fixed spatial coordinates, i.e. travelling on a time coordinat line, is not free-falling, implying that the body's wordline is not a geodesic. In turn, this means that the time coordinate line is no geodesic, too, and thefore not straight.
And as in SR, the postulate of constant speed of light applies in inertial frames only, but not in general coordinate systems, the analog is true in GR: the postulate of constant speed of light applies in local inertial frames only, not in general coordinate systems. So, it is even wrong to say the postulate of constant speed of light is less valid in GR than in SR. It is valid in GR as much as in SR: in SR, it applies in inertial frames only, and analogously, in GR, the postulate applies in local inertial frames only.
>>> | and if not what is the physical cause. |
>> |
What is in general not constant in GR is the speed of light in a coordinate system. However, this does not have a physical cause, since it is just a property of the chosen coordinate system. At best, one can ask for the physical cause why one cannot apply inertial frames like in SR, but is obliged to come along with more general coordinate systems. The physical cause for that is the curvature of spacetime: in a curved spacetime, inertial frames can only be constructed locally, not globally for the complete spacetime. |
> |
This gives me the impression that you can not use GR to simulate a complete galaxy. |
Why this? Do you maybe presume that one needs to use an inertial frame to simulate a galaxy? There is no reason why this should be true - one can use a general coordinate system as well.
> | Using Newton's Law this is difficult in practice because you have to know the initial positions of all objects at the same instance. |
The same is true in GR. It's even worse in GR: since the gravitational field has own dynamical degrees of freedom, you need to know the initial configuration of the gravitational field.
>>>> | When talking about a speed in GR, you have to distinguish between the speed measured in a local inertial frame and the speed measured in a coordinate system. |
>>> | Ofcourse if you want to measure the speed of light you have to quantify the distance and time you use which implies a coordinate system. That is not what I have done. The speed is in counts of one counter. |
>> |
If we follow your description, the counts of the counter are nothing but a number that is proportional to the coordinate time of a coordinate system you apply. That means that you are using a coordinate system and measure speeds with respect to it. |
> |
I performed two experiments: One with a ball and one with light. Both are reflected. In both cases each experiment consists of two parts: full distance and half distance. In each case starting point is the same. In order to "measure" I use a counter, one using a ball and the other one using light. The result in both cases (my prediction) that the speed is not constant. |
No, this is not the result. Primarily, the result is that there is a quantity with the dimension of a speed ([length]/[time]) that is not constant. To interpret this result as "the speed" not being constant, you at first would have to apply a theory that allows you for interpreting the measured quantity as "the speed".
Newtonian Gravity as well as a special-relativistic theory of gravity (if there were any) would allow you for interpreting the quantity as the speed in an inertial frame, which can be imagined meaningfully as "the speed". GR, however, does not allow you for that. In GR, the quantity you measured can only be interpreted as the speed in a general coordinate system, which is an arbitrary and therfore not very meaningful quantity, since the choice of the coordinate system is arbitrary.
>> | Since the term "the speed of light" does not have a clear meaning in GR, this requirement is not well-formulated. Let's assume that your requirement was instead to define an experiment that demonstrates that the speed of light *in a local inertial frame* is constant. |
> |
What I am discussing is the result of experiments. First "we" have to agree about the outcome of the experiment. The second step is to agree which theories predict or describe these experiments. |
In your "first step", i.e. without referring to a theory like GR or Newtonian Gravity, all you know about the outcome of the experiment you described is that it is a quantity with the dimension of a speed ([length]/[time]) and that it is not constant. To find out whether and how far you can identify this quantity with a meaningful speed, you need to refer to a theory, i.a. proceed to your "second step".
>> |
This can e.g. be done by performing three experiments, one at the
top of the tower, one at the middle, and one at the bottom. In each
experiment, you measure the speed of light in the following way:
Put two clocks that are synchronized to two positions that are close to each other, where close means that the distance between both positions is much smaller than the height of the tower. Let a light ray run from the first clock to the second one. Not the clock time the first clock shows when the light ray starts, and the clock time the second clock shows when the light ray arrives. Divide the distance between the two clocks by the difference between the noted clock times. |
> |
No this is not the way I propose. |
You asked me for an experiment that demonstrates that the speed of light in a local inertial frame is constant. My description answers your question, no matter if it matches what you propose.
>> | Different coordinate systems are not constructed by making a given coordinate system larger, but rather by attaching different coordinates to the same spacetime points. |
> |
IMO this makes everything very complex. |
Maybe. But in GR, you are obliged to take into account that the particular coordinate system you are actually using is not the only one that can be used, what makes the results that you gain in this coordinate system arbitrary if they turn out to be coordinate-dependent.
>>> | It is something more: the speed of light increases when it travels towards the earth. |
>> |
No. The sentence is not well-formulated, seen from the viewpoint of GR. The speed of light *in Schwarzschild coordinates* increases. |
> |
The result of the experiment show in both cases that the number of counts in each half distance is different. To be more specific the number of counts in the second part is smaller than the first part. This means that the speed is different. This means that the speed in the second part is larger. |
No, is does not mean that. It does not mean anything concerning any speed as long as you do not apply a special coordinate system with the three properties I alreay mentioned:
(1) The top and the ground of the Tower have fixed spatial coordinates
(2) The elapsing coordinate time is proportional to the number of bounces of the bouncing ball between the plates.
(3) Time translation invariance applies: the coordinate time interval that the ball takes for the trip from top to ground is the same as the coordinate time interval the ball takes for the back-trip from ground to top.
The speed *in this special coordinate system* is larger in the second part. But since this coordinate system is arbitrary, this result is arbitrary, too.
>> |
See above: Kruskal-Szekeres coordinates. Also see:
https://en.wikipedia.org/wiki/Kruskal%E2%80%93Szekeres_coordinates Take the diagram to the right, we the numbers I, II, III and IV in different colors. Imagine the top of the Tower having the hyperbola r=1.6 as wordline, the middle r=1.4 and the bottom r=1.2. Radial light ray follow diagonal lines in the diagram, i.e. their speed (in that coordinate system) is constant. |
> |
In that article they discuss physical singularity. IMO singualrities only "exist" in mathematical sense. |
That does not change in any way the fact that Kruskal-Szekeres coordinates are an example for what you asked me, namely an example for a coordinate system in which the speed of light turns out to be constant for your experiment.
Or did you intend to reject the concept of black holes because of their central singularities and therefore the usage of Kruskal coordinates that can be used to describe the interior of a black hole? Then you would reject GR at all, and then it wouldn't make sense for you to ask whether the speed of light is constant in GR.
> | The important thing is that in order to discuss or perform experiments related to the speed of light you should not use clocks which are affected by your experiment. As such I'am not measuring the speed of light quantitative, but only demonstrate that the speed is not constant. |
No, you do not demonstrate that. You demonstrate that the speed of light *in the special coordinate system you are using* is not constant. Seen from GR, this result is arbitrary, though, since your choice of coordinate system is arbitrary.
> | See also paragraph 7.3 in the book Gravitation which discusses an experiment I try to perform a simpler experiment. |
You mean figure 7.1B? In this figure, however, a special coordinate system was used, namely Schwarzschild coordinates, or at least a coordinate system in which the two observers have fixed spatial coordinates and time translation invariance applies. The variable speed of light to see in figure 7.1B is valid in that special coordinate system only.
> | Albert Einstein's used thought experiments to "demonstrate" SR and GR (my impression) He used thought experiments to demonstrate or explain that the path of lightrays are bended around mass. IMO that is very tricky. Page 13 in the book Gravitation states: "In each case one is following a natural track through spacetime". That maybe true, but what does it mean? |
That means that the worldline of a free-falling body is a geodesic in spacetime. Let a stone fall from your hand. The stone falls towards the ground and touches the ground after some seconds. The segment of the stone's wordline between your hand and the ground is a geodesic. Unlike your own worldline that is no geodesic since you are not free falling.
Thanks.
> | Nicolaas Vroom wrote: |
> > |
Can you give me an idea what is the difference between measuring something in a local inertial frame versus in a coordinate system? I my opinion in practice when you perform an experiment there exists not such a difference. |
> |
As far as the procedure is concerned, there is no difference. In both, local inertial frames and general coordinate systems, a speed measurement for some body can be performed by the following procedure: - Take two points P and Q on the worldline of the body |
And how do you do that in practice? The same for next sentences.
> | The result in the general coordinate system is arbitrary, since the coordinate system itself is arbitrary. |
> | The result in the local inertial frame, however, is meaningful, because the local inertial frame is very special. |
An coordinate system should be unambigeous. The same for people overhere as overthere. In a different galaxy.
> | For a better understanding of this fact, consider a two-dimensional space. |
Skip.
> | As you can construct non-Cartesian coordinate systems in flat two-dimensional space |
Sorry I'm lost.
> | Take e.g. Schwarzschild coordinates (t,r,phi,theta) that are similar to the coordinates you used in your Pisa Tower thought experiment: the coordinate lines are orthogonal, but not straight. |
The Tower of Pisa experiment is not a thought experiment. It is a description of an actual experiment. It is something like: You put a camera at a large distance from the tower. You drop an apple from the tower. You take a picture with the camera each second. When you compare the pictures you will see that the speed of the apple is not constant but increases.
The problem with this experiment is that you need a clock.
In the experiment I propose there is no clock. In the experiment I use a bouncing ball and the clock becomes a counter which is also a bouncing ball. Using that scenenario and performing the experiment from two different hights, the result is that the speed of the ball is not constant.
In stead of a ball in principle I can also use a light signal. Of course to perform this experiment from the Tower of Pisa is not realistic. However what I expect that the result of the experiment is the same: that the speed of light is not constant. The question of course is if this conclusion is correct.
> |
As far as the angle
coordinates (phi,theta) are concerned, this is trivial, however, the
same is true for time coordinate t and radial coordinate r: a body
resting at fixed spatial coordinates, i.e. travelling on a time
coordinat line, is not free-falling, implying that the body's wordline
is not a geodesic. In turn, this means that the time coordinate line is
no geodesic, too, and thefore not straight.
And as in SR, the postulate of constant speed of light applies in inertial frames only, but not in general coordinate systems, the analog is true in GR: the postulate of constant speed of light applies in local inertial frames only, not in general coordinate systems. So, it is even wrong to say the postulate of constant speed of light is less valid in GR than in SR. It is valid in GR as much as in SR: in SR, it applies in inertial frames only, and analogously, in GR, the postulate applies in local inertial frames only. |
Do I really need of all this to answer my question?
> > | This gives me the impression that you can not use GR to simulate a complete galaxy. |
> |
Why this? Do you maybe presume that one needs to use an inertial frame to simulate a galaxy? There is no reason why this should be true - one can use a general coordinate system as well. |
See next.
> > | Using Newton's Law this is difficult in practice because you have to know the initial positions of all objects at the same instance. |
> |
The same is true in GR. It's even worse in GR: since the gravitational field has own dynamical degrees of freedom, you need to know the initial configuration of the gravitational field. |
That means you agree with my previous remark: GR is "tricky"
> > | I performed two experiments: One with a ball and one with light. Both are reflected. In both cases each experiment consists of two parts: full distance and half distance. In each case starting point is the same. In order to "measure" I use a counter, one using a ball and the other one using light. The result in both cases (my prediction) that the speed is not constant. |
> |
No, this is not the result. Primarily, the result is that there is a quantity with the dimension of a speed ([length]/[time]) that is not constant. To interpret this result as "the speed" not being constant, you at first would have to apply a theory that allows you for interpreting the measured quantity as "the speed". |
The first conclusion is that the number of counts to travel (fall) over the two identical distances (first part and second part) is not identical. This is "translated" that the speed is not constant and that there is acceleration involved.
> | Newtonian Gravity as well as a special-relativistic theory of gravity (if there were any) would allow you for interpreting the quantity as the speed in an inertial frame, which can be imagined meaningfully as "the speed". GR, however, does not allow you for that. In GR, the quantity you measured can only be interpreted as the speed in a general coordinate system, which is an arbitrary and therfore not very meaningful quantity, since the choice of the coordinate system is arbitrary. |
The first question to answer if you agree with the outcome of the two experiments. The next question is if the outcome is in agreement with Newton's Law. The same for GR.
> > | The result of the experiment show in both cases that the number of counts in each half distance is different. To be more specific the number of counts in the second part is smaller than the first part. This means that the speed is different. This means that the speed in the second part is larger. |
> |
No, is does not mean that. It does not mean anything concerning any speed as long as you do not apply a special coordinate system with the three properties I alreay mentioned: (1) The top and the ground of the Tower have fixed spatial coordinates (2) The elapsing coordinate time is proportional to the number of bounces of the bouncing ball between the plates. (3) Time translation invariance applies: the coordinate time interval that the ball takes for the trip from top to ground is the same as the coordinate time interval the ball takes for the back-trip from ground to top. The speed *in this special coordinate system* is larger in the second part. But since this coordinate system is arbitrary, this result is arbitrary, too. |
I would agree with you if you call this a local experiment, in the sense that the speed of the ball in this local experiment is not constant. The same should than also be true for the speed of light.
But if you agree that the speed of light is not constant in this local experiment why should than this also not to be true in a much broader sense?
Why should the speed of light be physical constant if you transmit a light signal from the earth to the moon?
> > | Page 13 in the book Gravitation states: "In each case one is following a natural track through spacetime". That maybe true, but what does it mean? |
> |
That means that the worldline of a free-falling body is a geodesic in spacetime. |
Is that a natural track through spacetime?
GR is "tricky"
Nicolaas Vroom
>>> | Can you give me an idea what is the difference between measuring something in a local inertial frame versus in a coordinate system? I my opinion in practice when you perform an experiment there exists not such a difference. |
>> |
As far as the procedure is concerned, there is no difference. In both, local inertial frames and general coordinate systems, a speed measurement for some body can be performed by the following procedure: - Take two points P and Q on the worldline of the body |
> |
And how do you do that in practice? |
Attach two clocks to two different spatial positions with known spatial coordinates. Ensure that the two clocks are synchronous with the coordinate time. Note the displayed clock times at which the body passes each of the two clocks.
>> | The result in the general coordinate system is arbitrary, since the coordinate system itself is arbitrary. |
> | That means should not be used ? |
You can use it if you want, but you have to be aware that it is arbitrary.
>> | The result in the local inertial frame, however, is meaningful, because the local inertial frame is very special. |
> |
An coordinate system should be unambigeous. |
A coordinate system is unambigeous, or unique, in that sense that every spacetime point is assigned to a unique set of coordinates. A general coordinate system is not unambigeous, though, in that sense that the choice of the coordinate system is arbitrary, i.e. that one could choose a different coordinate system as well. An inertial frame (in Newtonian Mechanics or SR) is more unambigeous in this sense: if you choose an observer, e.g. yourself, then you already fix the inertial frame to be used.
>> | For a better understanding of this fact, consider a two-dimensional space. |
> | Two dimensional SPACE does not exist. Sorry I'm lost. |
The two-dimensional space was just to make the understanding easier. We can of course do all consideration in four-dimensional spacetime if you prefer that. It's just a little more complicated.
>> | Take e.g. Schwarzschild coordinates (t,r,phi,theta) that are similar to the coordinates you used in your Pisa Tower thought experiment: the coordinate lines are orthogonal, but not straight. |
> |
The Tower of Pisa experiment is not a thought experiment. It is a description of an actual experiment. It is something like: You put a camera at a large distance from the tower. You drop an apple from the tower. You take a picture with the camera each second. When you compare the pictures you will see that the speed of the apple is not constant but increases. |
No, I don't see that. And you don't see that, too. You may conclude that from what you see, but to draw this conclusion, you have to make some assumptions. Those assumptions contain the usage of a coordinate system, and that quantities measured with respect to this coordinate systems are in some way meaningful.
More in detail:
- Primarily, you have a collection of pictures. You then emumerate the
pictures (1,2,3,...).
- Then you assume that you can apply a coordinate system to a spacetime
region that contains the wordline of the apple, the worldlines of the
light signals that travel from the apple to the camera, and the wordline
of the camera itself.
- Then you assume that the coordinate time interval for a light signal
to travel from the apple to the camera is the same for all light
signals, so that you can identify the coordinate time interval between
two light signals reaching the camera with the interval between two
light signals emitted by the apple.
- Then you identify the number of each picture with the coordinate time
at which the particular light signal reached the camera.
- Then you identify the apple's position on the particular picture with
the spatial coordinates of the apple at the particular coordinate time
minus the coordinate time the light signal took from the apple to the
camera.
After doing this, you can draw the conclusion that the speed of the apple in the coordinate system you have chosen increases. Then you assume that this coordinate system is very special, so that you can interpret the speed of the apple in this coordinate system as "the" speed of the apple.
> |
The problem with this experiment is that you need a clock.
In the experiment I propose there is no clock. |
In the one experiment, the role of the clock is undertaken by the bouncing ball, in the other experiment, the role of the clock is undertaken by the enumeration of the picture photographed by the camera. I don't see a great difference. In both cases, you use a number (count of ball bounces, index of picture) as a replacement for the coordinate time.
> | Using that scenenario and performing the experiment from two different hights, the result is that the speed of the ball is not constant. |
No, the result is not that the speed of the ball is not constant. The result is that in the one case, the round trip of the ball takes more bounces than in the other case.
To draw any conclusions from this result that concern the speed of the ball, you again have to construct a coordinate system. Then you have the speed of the ball in the particular coordinate system. To interpret this speed as "the" speed of the ball, you again have to assume that this coordinate system is specially meaningful.
> | In stead of a ball in principle I can also use a light signal. Of course to perform this experiment from the Tower of Pisa is not realistic. However what I expect that the result of the experiment is the same: that the speed of light is not constant. The question of course is if this conclusion is correct. |
The answer is: no. The conclusion would be correct if the assumptions you make would be correct. In Newtonian Gravity, they would: the coordinate system you are using could be considered as an inertial frame (of an observer resting with respect to the Tower, or of the Tower itself). In GR, however, they do not: the coordinate system you are using for your conclusion is arbitrary there.
>> |
As far as the angle
coordinates (phi,theta) are concerned, this is trivial, however, the
same is true for time coordinate t and radial coordinate r: a body
resting at fixed spatial coordinates, i.e. travelling on a time
coordinat line, is not free-falling, implying that the body's wordline
is not a geodesic. In turn, this means that the time coordinate line is
no geodesic, too, and thefore not straight.
And as in SR, the postulate of constant speed of light applies in inertial frames only, but not in general coordinate systems, the analog is true in GR: the postulate of constant speed of light applies in local inertial frames only, not in general coordinate systems. So, it is even wrong to say the postulate of constant speed of light is less valid in GR than in SR. It is valid in GR as much as in SR: in SR, it applies in inertial frames only, and analogously, in GR, the postulate applies in local inertial frames only. |
> |
Do I really need of all this to answer my question? |
To answer your question whether the SR postulate of constant light speed applies in GR, yes.
>>> | This gives me the impression that you can not use GR to simulate a complete galaxy. |
>> |
Why this? Do you maybe presume that one needs to use an inertial frame to simulate a galaxy? There is no reason why this should be true - one can use a general coordinate system as well. |
> |
See next. |
>>> |
Using Newton's Law this is difficult in practice because you have to know the initial positions of all objects at the same instance. |
>> |
The same is true in GR. It's even worse in GR: since the gravitational field has own dynamical degrees of freedom, you need to know the initial configuration of the gravitational field. |
> |
That means you agree with my previous remark: GR is "tricky" |
Your previous remark was: "See next". And now, when I see next, you suggest me your previous remark again?
Or do you want to say that you cannot GR to simulate a galaxy because a simulation based on GR would be more complicated than one base on Newtonian Gravity? This, however, has little to do with inertial frames not being applicable in GR.
>>> | I performed two experiments: One with a ball and one with light. Both are reflected. In both cases each experiment consists of two parts: full distance and half distance. In each case starting point is the same. In order to "measure" I use a counter, one using a ball and the other one using light. The result in both cases (my prediction) that the speed is not constant. |
>> |
No, this is not the result. Primarily, the result is that there is a quantity with the dimension of a speed ([length]/[time]) that is not constant. To interpret this result as "the speed" not being constant, you at first would have to apply a theory that allows you for interpreting the measured quantity as "the speed". |
> |
The first conclusion is that the number of counts to travel (fall) over the two identical distances (first part and second part) is not identical. |
For this conclusion, you already need to apply a coordinate system that tells you that the spatial distances of the two parts are identical. This property of the two distances is coordinate-dependent.
> | This is "translated" that the speed is not constant and that there is acceleration involved. |
For this translation, you need to apply a theory that tells you whether the coordinate system you are using is specially meaningful (e.g. an inertial frame) and therefore the speed in this coordinate system considerable as "the" speed.
>> | Newtonian Gravity as well as a special-relativistic theory of gravity (if there were any) would allow you for interpreting the quantity as the speed in an inertial frame, which can be imagined meaningfully as "the speed". GR, however, does not allow you for that. In GR, the quantity you measured can only be interpreted as the speed in a general coordinate system, which is an arbitrary and therfore not very meaningful quantity, since the choice of the coordinate system is arbitrary. |
> |
The first question to answer if you agree with the outcome of the two experiments. |
No, I don't. What you call the outcome of the experiments is not the outcome of the experiments, but a conclusion from the outcome that is based on wrong assumptions.
> | The next question is if the outcome is in agreement with Newton's Law. The same for GR. |
To gain what you call the outcome of the experiments, but which is rather a conclusion from the outcome and not the outcome itself, you apply assumptions that are in contradiction to GR (namely that the coordinate system you are using would be specially meaningful). So, you already presume that GR is wrong. To ask whether results are in agreement with GR does not make sense any more then. - show quoted text - No, I do not call your experiment a local experiment, in that sense that this experiment would be local whereas an experiment that involves a broader spatial region that include Earth and Moon would not be local. Your experiment as well as a comparable experiment that involve Earth and Moon are not local, in that sense that they both involve spacetime regions that are not sufficiently limited to apply the concept of an inertial frame. A local experiment would be one that involves a spacetime region that is sufficiently limited, e.g. one that involves a small region around the top (or the bottom) of the Towor.
In other words: the postulate of constant speed of light does not apply in a spatially *broader* sense in GR, but in a spatially *narrower" sense, namely in that sense that the speed of light is constant in a local inertial frame. The region where a local inertial frame can be applied is not broader, it is narrower.
One could explain this quite easy using a two-dimensional space, but since you reject such a consideration, you'll have to come along with the more complicated consideration of four-dimensional spacetime.
>>> | Page 13 in the book Gravitation states: "In each case one is following a natural track through spacetime". That maybe true, but what does it mean? |
>> |
That means that the worldline of a free-falling body is a geodesic in spacetime. |
> |
Is that a natural track through spacetime? |
Yes. Like moving in a straight line with constant speed is the natural track in a flat, uncurved spacetime.
Remember Newton's first law: a body remains in the state of rest or uniform motion unless it is enforced to change its state by acting forces. In a flat spacetime, this means that a force-free body moves along a straight worldline. In a curved spacetime, it means that a force-free body moves along a geodesic worldline.
Again: this could be very easiely illustrated in a two-dimensional space, but you reject that.
> |
The Tower of Pisa experiment is not a thought experiment. It is a
description of an actual experiment.
It is something like:
You put a camera at a large distance from the tower.
You drop an apple from the tower.
You take a picture with the camera each second.
When you compare the pictures you will see that the speed of
the apple is not constant but increases.
The problem with this experiment is that you need a clock. In the experiment I propose there is no clock. In the experiment I use a bouncing ball and the clock becomes a counter which is also a bouncing ball. |
A remark to this experiment: the bouncing ball that is used as clock bounces do to gravitational effects. So, by definition, this experiment necessarily involves a spacetime region that is not sufficiently limited to apply SR. Therefore, an experiment of this kind cannot be performed within a local inertial frame. In other words: to perform measurements with respect to a local inertial frame (for which you asked me), this type of experiment is impractical.
> | The Tower of Pisa experiment is not a thought experiment. It is a description of an actual experiment. |
The difference between those two types of experiment are merely time, effort an money ;)
> |
It is something like:
You put a camera at a large distance from the tower.
You drop an apple from the tower.
You take a picture with the camera each second.
When you compare the pictures you will see that the speed of
the apple is not constant but increases.
The problem with this experiment is that you need a clock. In the experiment I propose there is no clock. In the experiment I use a bouncing ball and the clock becomes a counter which is also a bouncing ball. |
A 'clock' in the sense of a time-measuring device is any device that allows to count well-defined time intervals. It is for convenience that usually these time intervalls are of identical length, i.e. the device counts the cycles of a periodic system like the oscillations between two electronic states of an atom or the swinging of a pendulum.
So your bouncing ball *is* a clock. A lousy one, but a clock nevertheless.
-- Space - The final frontier
> |
Nicolaas Vroom |
> > |
The Tower of Pisa experiment is not a thought experiment. It is a description of an actual experiment. |
> |
The difference between those two types of experiment are merely time, effort an money ;) |
I think it is something more. See below.
> > | In the experiment I propose there is no clock. In the experiment I use a bouncing ball and the clock becomes a counter which is also a bouncing ball. |
> |
A 'clock' in the sense of a time-measuring device is any device that allows to count well-defined time intervals. It is for convenience that usually these time intervalls are of identical length, i.e. the device counts the cycles of a periodic system like the oscillations between two electronic states of an atom or the swinging of a pendulum. So your bouncing ball *is* a clock. A lousy one, but a clock nevertheless. |
What I do is to compare the outcome of two identical physical experiments. In the first experiment I use two balls. Ball #1 bounces between two plates and services as an oscillator. Ball #2 bounces only once in two different cases. In case 1 the ball starts at the top, bounces at the bottom. The experiment finishes when the ball is back at its highest position. In case 2 the ball bounces back halfway between top and bottom. The object of the experiment is to count the number of bounces/counts of the oscillator. The results of the experiment show (as an example) that the number of counts when you drop ball #2 in case 1 is 17 and 10 in case 2 (first half) The strategy of the experiment is that the oscillator does not move! The first question is if you agree that the number of counts from in-between to the bottom is 7? (second half) The second question is if you agree that the speed is increasing when the ball drops from top to in-between to the bottom? Speed defined as distance divided by counts.
The whole purpose of this experiment to perform the same experiments but now not with balls but with two light signals. The oscillator in this case becomes light signal #1. Again also in this case the first question is if you agree that there is a difference in counts in the first half compared with the second half. The second question is if you agree that when the counts are different that the speed of light is not constant but has increased,
The whole idea behind each experiment is to use in each case only one physical concept. In the first experiment this is a falling ball #2 which is influenced by the gravitational field of the earth. In the second experiment this is a lightsignal #2 which is also supposed to be influenced by the gravitational field of the earth.
IMO this is identical from a physical point of view if you shoot a bullet horizontal or if you shine a lightsignal horizontal. Both the path of the bullet and of the lightsignal are bended.
To call each of the two oscillators ie ball #1 and light signal #1, a clock is only in the name. The issue is that both oscillators are physical processes and are influenced by the same physical phenomena as their counter parts.
To perform experiment #1 with the bouncing balls is rather simple The biggest problem that the bouncing should be perfect. This means the two distances (down and up) should be the same.
Experiment #2 is extremely difficult and IMO is much more like a thought experiment, but requires an honnest investigation. The experiment becomes more tricky when the movement of the earth around the Sun, and more global in our Galaxy is included. Still the two lightsignals behave the same. Experiment #2 is different from the Pound and Rebka experiment and from the concept of Gravitational redshift.
Nicolaas Vroom
>> | And as in SR, the postulate of constant speed of light applies in inertial frames only, but not in general coordinate systems, the analog is true in GR: the postulate of constant speed of light applies in local inertial frames only, not in general coordinate systems. So, it is even wrong to say the postulate of constant speed of light is less valid in GR than in SR. It is valid in GR as much as in SR: in SR, it applies in inertial frames only, and analogously, in GR, the postulate applies in local inertial frames only. |
> |
Do I really need of all this to answer my question? |
A remark: maybe you are not really interested in the question whether the SR postulate of constant speed of light applies in GR, but rather in the question whether you can consider the speed of light as being variable in the coordinate system you are using for a galaxy simulation? That is question is very much simpler, and very easy to answer: yes, you can do that.
> | Nicolaas Vroom wrote: |
> >> |
And as in SR, the postulate of constant speed of light applies in inertial frames only, but not in general coordinate systems, the analog is true in GR: the postulate of constant speed of light applies in local inertial frames only, not in general coordinate systems. So, it is even wrong to say the postulate of constant speed of light is less valid in GR than in SR. It is valid in GR as much as in SR: in SR, it applies in inertial frames only, and analogously, in GR, the postulate applies in local inertial frames only. |
> > |
Do I really need of all this to answer my question? |
> |
A remark: maybe you are not really interested in the question whether the SR postulate of constant speed of light applies in GR, but rather in the question whether you can consider the speed of light as being variable in the coordinate system you are using for a galaxy simulation? That is question is very much simpler, and very easy to answer: yes, you can do that. |
I would add that Einstein himself gave serious consideration to the consistency of the speed of light being relative not absolute. That is to say the speed of light is constant for a given frame of reference. The speed of light being constant to all frames of reference is not the same as saying the speed of light is constant in a absolute sense. If someone very close to a black hole and time dilated to the point that their voice is notably 1 octave lower do you trust their judgement when they tell they measure the speed of light to be c ? With a clock running at half speed I would not trust that voice in the dark. More likely the speed is 1/2 c but they measure it to be c with a clock that is ticking at 1/2 its normal rate.
[[Mod. note -- Many of the questions you pose are (in their present form) insufficiently precise to be answered.
For example, "If someone very close to a black hole and time dilated to the point that their voice is notably 1 octave lower" doesn't specify (the spacetime worldline of) the observer who measures that time dialation. And simply saying "1 octave lower" leaves unanswered the question of "1 octave lower than what?". (The standard answer to this latter question is, "with respect to a recording of the now-close-to-the-BH speaker, made when she was far from the BH, and coincident with and at rest with respect to the recorder". In other words, adiabatic clock transport, treating the speaker's vocal cords as a clock. Is this what you mean?)
And when that observer "measure[s] the speed of light", we need to know just how that measurement is made. For example, it might be a local measurement made in a free-falling local Lorenz frame... [n.b. "local" here means "small enough that we can approximate spacetime as flat within this region"] ... but then within that frame special relativity applies, and the answer of that measurement MUST be 299792458 m/s. So I guess you mean some other sort of measurement... which needs to be specified. -- jt]]
> | I would add that Einstein himself gave serious consideration to the consistency of the speed of light being relative not absolute. That is to say the speed of light is constant for a given frame of reference. The speed of light being constant to all frames of reference is not the same as saying the speed of light is constant in a absolute sense. If someone very close to a black hole and time dilated to the point that their voice is notably 1 octave lower do you trust their judgement when they tell they measure the speed of light to be c ? With a clock running at half speed I would not trust that voice in the dark. More likely the speed is 1/2 c |
In GR, you have to distinguish between local inertial frames and general coordinate systems, like e.g. Schwarzschild coordinates in Schwarzschild solution. Considered in Schwarzschild coordinates, the clock of the observer near the black hole is running at half speed (compared to Schwarzschild coordinate time), and the speed of light is 1/2 c. However, choosing Schwarzschild coordinates is an arbitrary choice, one could as well choose Eddington-Finkelstein coordinates, free-falling coordinates or Kruskal coordinates. In each of those coordinate systems, you'll gather different results for the clock running speed and for the speed of light. Therefore, the speed of light measured with respect to a general coordinate system is arbitrary, and due to that, little meaningful.
The only meaningful speed measurements in GR are those that are performed with respect to a local inertial frame. According to GR, the observer near the black hole will measure c for the speed of light, and since he performed his measurement with respect to a local inertial frame, one can trust his result.
Good point. I made the measurement leaving earth with a calibrated 1 meter stick and an atomic clock. I reported to you from near a black hole that the speed of light is c as I measure it with my 1 meter stick and atomic clock. The gravitational time dilation from this location near a black hole caused my atomic clock to run at 1/2 its normal speed compared with earth. When talking to you on my intergalactic cell phone you noted my voice was one octave lower than normal suggesting my clock has been compromised running at only 1/2 its normal rate caused by gravitational time dilation. With these conditions I put the question to you on earth. Is the speed of light in my location near a black hole , c or 1/2 c ? Keep in mind I should have said 2 c not c if the speed of light is absolute with a time dilated clock but I do not want to bias your thoughts. In your mind in the broader sense is the consistency of the speed of light absolute or relative in the big picture. It is all relative so you may use the earth as the as an arbitrary reference point to make this judgement and assume idea conditions of the earth not changing.
> | Good point. I made the measurement leaving earth with a calibrated 1 meter stick and an atomic clock. I reported to you from near a black hole that the speed of light is c as I measure it with my 1 meter stick and atomic clock. The gravitational time dilation from this location near a black hole caused my atomic clock to run at 1/2 its normal speed compared with earth. When talking to you on my intergalactic cell phone you noted my voice was one octave lower than normal suggesting my clock has been compromised running at only 1/2 its normal rate caused by gravitational time dilation. |
That I noted your voice one octave lower is primarily due to the gravitational redshift which the electromagnetic waves emitted by your cell phone undergo on their towards me.
To conclude that this gravitational redshift is caused by gravitational time dilation, you need to apply Schwarzschild coordinates, in which we both have fixes spatial positions (wordlines with r = const, where r is the Schwarzschild radial coordinate) and time translation invariance applies, so that the waves emitted by your cell phone propagate on wordlines that are equivalent, except a coordinate time shift.
However, instead of Schwarzschild coordinates, we can as well apply a coordinate system with a time coordinate tau that relates to Schwazschild coordinates by
tau = (1 - rs/r) t
so that
d(tau) = (1 - rs/r) dt - rs t dr / r^2
On our worldlines, r = const applies so that dr = 0, resulting in
d(tau) = (1 - rs/r) dt
In this coordinate system, there is no gravitational time dilation. Of course, we again observe the gravitational redhift, since it is coordinate-independent, but in this coordinate system, we do not conclude that is is caused by gravitational time dilation, but rather by differences in propagation of subsequently emitted waves: the later a wave is emitted from your cell phone, the longer is the coordinate time interval the wave takes to reach me (there is no time-translation invariance like in Schwarzschild coordinates).
Or let use apply Kruskal coordinates. Then our is result is that we both are moving (our worldlines are hyperbolas in a Kruskal spacetime diagram), and that the gravitational redshift is mainly due to our different movements.
So, we see: the gravitational redshift is coordinate-independent, but its relation to a gravitational time dilation depends on the applied coordinate system.
Due to the general covariance of GR, all three mentioned coordinate systems are in the same way valid, there is none of them more valid than the other ones. Therefore, the result you gather in Schwarzschild coordinates, namely that the gravitational redshift is caused by a gravitational time dilation only, is arbitrary and therefore little meaningful.
The only coordinate systems in GR that are valid in a greater measure are the local inertial frames, and in those, there is neither a gravitational time dilation nor a gravitational redshift, since they are limited to spacetime regions that too small to recognize gravitational effects.
To get a better impression of different coordinate systems for Scharzschild geometry, have a look on the spacetime diagrams on this page:
http://casa.colorado.edu/~ajsh/schwp.html
> | With these conditions I put the question to you on earth. Is the speed of light in my location near a black hole , c or 1/2 c ? |
By this formulation, the question is ambigous, since you do not indicate whether you refer to a local inertial frame or to a general coordinate system.
As we have seen above, you obviously refer to Schwarzschild coordinate, and in those, the speed of light indeed is c / 2 in you location. But since Schwarzschild coordinates are arbitrary, this result is little meaningful. The most meaningful indication of the speed of light is with respect to your local inertial frame.
> | Keep in mind I should have said 2 c not c if the speed of light is absolute with a time dilated clock but I do not want to bias your thoughts. In your mind in the broader sense is the consistency of the speed of light absolute or relative in the big picture. It is all relative |
Sad to say, I do not really understand what you try to say here. Assumed, you wanted to claim that the speed of light is not absolute in GR, but rather relative: in GR, the speed of light is always the same in local inertial frames, namely c, whereas in general coordinate systems (Schwarzschild, Eddington-Finkelstein, Kruskal...), it may vary, like it becomes c / 2 near a black hole in Schwarzschild coordinates. The situation is already similar in SR, though: the invariance of the speed of light applies in inertial frames only there, not in e.g. accelerated frames of reference.
> | so you may use the earth as the as an arbitrary reference point to make this judgement |
When saying "reference point", you obviously refer to the SR concept of a frame of reference. However, this concept is not applicable in GR, except in its SR limit, i.e. in spacetime regions suffiently limited.
In SR, when you choose an observer, you automatically declare a frame of reference, that provides a method to compare any clock in the universe to the observer's clock. In GR, however, things are different. By choosing an observer far away from a black hole, you do NOT declare a frame of reference, and you do NOT have a distinct method to compare clocks near the black hole to the observer's clock.
You may, if you want, choose Schwarzschild coordinates, yielding the result, that a clock at radial coordinate r runs by factor sqrt(1 - rs/r) slower than the clock of the far away observer, e.g. by factor 1/2 for r = 4/3 rs. But as well, you can choose a different coordinate system, yielding a different ratio for the running speeds of the same two clocks, e.g. the coordinate system with coordinate time tau from above, in which both, the clock near the black hole and the clock of the far aways observer, run at the same speed.
So, by choosing the far away observer as "reference point", you do not fix the clock near the black hole to run with half speed. You need to choose to apply Schwarzschild coordinates in addition. And that choice is arbitrary.
> | So, by choosing the far away observer as "reference point", you do not fix the clock near the black hole to run with half speed. You need to choose to apply Schwarzschild coordinates in addition. And that choice is arbitrary. |
Really now! If the experiment were actually performed, there would be only ONE result. This "arbitrariness" makes no sense and sounds like obfuscation to me.
Gary
> | John Heath wrote: |
> > |
Good point. I made the measurement leaving earth with a calibrated 1 meter stick and an atomic clock. I reported to you from near a black hole that the speed of light is c as I measure it with my 1 meter stick and atomic clock. The gravitational time dilation from this location near a black hole caused my atomic clock to run at 1/2 its normal speed compared with earth. When talking to you on my intergalactic cell phone you noted my voice was one octave lower than normal suggesting my clock has been compromised running at only 1/2 its normal rate caused by gravitational time dilation. |
> |
That I noted your voice one octave lower is primarily due to the gravitational redshift which the electromagnetic waves emitted by your cell phone undergo on their towards me. To conclude that this gravitational redshift is caused by gravitational time dilation, you need to apply Schwarzschild coordinates, in which we both have fixes spatial positions (wordlines with r = const, where r is the Schwarzschild radial coordinate) and time translation invariance applies, so that the waves emitted by your cell phone propagate on wordlines that are equivalent, except a coordinate time shift. However, instead of Schwarzschild coordinates, we can as well apply a coordinate system with a time coordinate tau that relates to Schwazschild coordinates by tau = (1 - rs/r) t so that d(tau) = (1 - rs/r) dt - rs t dr / r^2 On our worldlines, r = const applies so that dr = 0, resulting in d(tau) = (1 - rs/r) dt In this coordinate system, there is no gravitational time dilation. Of course, we again observe the gravitational redhift, since it is coordinate-independent, but in this coordinate system, we do not conclude that is is caused by gravitational time dilation, but rather by differences in propagation of subsequently emitted waves: the later a wave is emitted from your cell phone, the longer is the coordinate time interval the wave takes to reach me (there is no time-translation invariance like in Schwarzschild coordinates). Or let use apply Kruskal coordinates. Then our is result is that we both are moving (our worldlines are hyperbolas in a Kruskal spacetime diagram), and that the gravitational redshift is mainly due to our different movements. So, we see: the gravitational redshift is coordinate-independent, but its relation to a gravitational time dilation depends on the applied coordinate system. Due to the general covariance of GR, all three mentioned coordinate systems are in the same way valid, there is none of them more valid than the other ones. Therefore, the result you gather in Schwarzschild coordinates, namely that the gravitational redshift is caused by a gravitational time dilation only, is arbitrary and therefore little meaningful. The only coordinate systems in GR that are valid in a greater measure are the local inertial frames, and in those, there is neither a gravitational time dilation nor a gravitational redshift, since they are limited to spacetime regions that too small to recognize gravitational effects. To get a better impression of different coordinate systems for Scharzschild geometry, have a look on the spacetime diagrams on this page: |
> > |
With these conditions I put the question to you on earth. Is the speed of light in my location near a black hole , c or 1/2 c ? |
> |
By this formulation, the question is ambigous, since you do not indicate whether you refer to a local inertial frame or to a general coordinate system. As we have seen above, you obviously refer to Schwarzschild coordinate, and in those, the speed of light indeed is c / 2 in you location. But since Schwarzschild coordinates are arbitrary, this result is little meaningful. The most meaningful indication of the speed of light is with respect to your local inertial frame. |
> > |
Keep in mind I should have said 2 c not c if the speed of light is absolute with a time dilated clock but I do not want to bias your thoughts. In your mind in the broader sense is the consistency of the speed of light absolute or relative in the big picture. It is all relative |
> |
Sad to say, I do not really understand what you try to say here. Assumed, you wanted to claim that the speed of light is not absolute in GR, but rather relative: in GR, the speed of light is always the same in local inertial frames, namely c, whereas in general coordinate systems (Schwarzschild, Eddington-Finkelstein, Kruskal...), it may vary, like it becomes c / 2 near a black hole in Schwarzschild coordinates. The situation is already similar in SR, though: the invariance of the speed of light applies in inertial frames only there, not in e.g. accelerated frames of reference. |
> > |
so you may use the earth as the as an arbitrary reference point to make this judgement |
> |
When saying "reference point", you obviously refer to the SR concept of a frame of reference. However, this concept is not applicable in GR, except in its SR limit, i.e. in spacetime regions suffiently limited. In SR, when you choose an observer, you automatically declare a frame of reference, that provides a method to compare any clock in the universe to the observer's clock. In GR, however, things are different. By choosing an observer far away from a black hole, you do NOT declare a frame of reference, and you do NOT have a distinct method to compare clocks near the black hole to the observer's clock. You may, if you want, choose Schwarzschild coordinates, yielding the result, that a clock at radial coordinate r runs by factor sqrt(1 - rs/r) slower than the clock of the far away observer, e.g. by factor 1/2 for r 4/3 rs. But as well, you can choose a different coordinate system, yielding a different ratio for the running speeds of the same two clocks, e.g. the coordinate system with coordinate time tau from above, in which both, the clock near the black hole and the clock of the far aways observer, run at the same speed. So, by choosing the far away observer as "reference point", you do not fix the clock near the black hole to run with half speed. You need to choose to apply Schwarzschild coordinates in addition. And that choice is arbitrary. |
Nice link , I bookmarked it. And thanks for taking the time for a long response. I can see I have failed to set the conditions of the test in a clear way. Perhaps I should state the condition instead of creating the condition . I will state the conditions.
A] Alice is on earth with a 1 meter stick and a atomic clock to measure the speed of light.
B] Bob is gravity time dilated 50 percent. His clock is ticking at 1/2 its rate relative to Alice's clock.
C] There is no Doppler effect or SR effects. Assume ideal conditions of no movement between Alice and Bob.
If Bob measures the speed of light to be 2c then we can assume that the speed of light is absolute at c and it is his slow clock that is causing him to think it is 2c. If Bob measures the speed of light to be c then we can assume the speed of light will always measure c and is not absolute but relative to the observer. This would require the speed of light to be variable in the larger picture to guarantee that all observers measure the speed of light to be c. It should be noted that Alice on earth is the observer. If Bob is the observer then Alice should say the measured speed of light is 1/2 c caused by her fast clock relative to Bob if light speed is absolute. If light speed is relative then Alice will measure it to be c and therefore speed of light is variable in the larger picture , god's view.
The Schwarzschild model requires a more complicated setup of a copper wire link between Alice and Bob to demonstrate causality concerns with multiple time lines. For this reason I have set it aside for now in the interest of clarity of thought. I would enjoy going there but for now it will confuse the issue at hand with too many variables on the table.
To return to the burning question. In your mind is the speed of light absolute or variable. It is a given light will always measure c but is it constant in the larger picture of god looking down at Alice and Bob from a great distance?
[[Mod. note -- Once again, many of these questions are insufficiently precise to have well-defined answers.
For example, you write "If Bob measures the speed of light to be 2c". But any (correct) *local* measurement [i.e., a measurement made entirely within a (freely-falling) local inertial reference frame] of the speed of light gives c (independendent of the details of how the measurement is made). So your description must refer to some sort of *non-local* measurement. You need to specificy precisely how that measurement is made.
-- jt]]
>> | So, by choosing the far away observer as "reference point", you do not fix the clock near the black hole to run with half speed. You need to choose to apply Schwarzschild coordinates in addition. And that choice is arbitrary. |
Gary Harnagel
The problem is that you (Gary harnagel) haven't specified the experiment
in sufficient detail. There are many possible experiments which would be
consistent with your description, and (in general) these experiments will
give different answers.
For example, here are four possible experiments consisten with your
description:
(a) The far-away observer is a rest with respect to the black hole (BH).
She drops a clock into the BH; that clock sends out a sequence of
radio-wave "ticks" at uniform time intervals as measured by the
falling clock; each "tick" also encodes the falling clock's
current position (areal radial coordinate) with respect to the
BH. The far-away observer measures the arrival frequency of
the radio-wave "ticks" as a function of the encoded position.
(b) Same thing as (a), but change "areal radial coordinate" to
"isotropic radial coordinate".
(c) The far-away observer is a rest with respect to the BH. She
releases a clock which is just like the clock in (a), but is
also equipped with a rocket engine. The rocket-engine-clock is
programmed to fly down to a specific position (areal radial coordinate)
with respect to the BH, hold itself at that position for a while,
then fly to a new position (areal radial coordinate) with respect
to the BH, hold itself at that position for a while, then fly to
another position, etc etc. The far-away observer measures the
arrival frequency of the radio-wave "ticks" at each rocket-engine-clock
position, as a function of the encoded radius.
(d) Same thing as (c), but change "areal radial coordinate" to
"tortise radial coordinate".
[there are many other possibilities as well]
As I suggested above, experiments (a), (b), (c), and (d) will
(in general) give four different answers to the question "at what rate
do the clock-near-the-BH ticks arrive at the far-from-the-BH clock when
the clock-near-the-BH is at the position r=3M?". You haven't specified
which of these is the experiment which you're asking about, and nature
doesn't single out any of these as "the natural or obvious way to do
this experiment".
The fact that there are these multiple possibilities, all of them equally
physically meaningful and all of them plausible operational definitions
of "the gravitational redshift at a distance r=3M from the BH", is a
consequence of the arbitrariness which Gregor Scholten was referring to.
--
-- "Jonathan Thornburg [remove -animal to reply]"
A] Alice is on earth with a 1 meter stick and a atomic clock to
measure the speed of light.
B] Bob is gravity time dilated 50 percent. His clock is ticking at
1/2 its rate relative to Alice's clock.
According to GR, this statement is ambigous. You missed indicating what
coordinate system you applied to compare Bob's clock to Alice's clock.
In SR, you would be finished by just stating "relative to Alice's clock"
because that would define a frame of reference. In GR, however, you are
not finished, you in addition need to indicate what coordinate system
you are applying.
Let's assume you are applying Schwarzschild coordinates.
If Bob measures the speed of light to be 2c then we can assume that
the speed of light is absolute at c and it is his slow clock that
is causing him to think it is 2c. If Bob measures the speed of light
to be c then we can assume the speed of light will always measure
c and is not absolute but relative to the observer.
According to GR, this is another ambigous statement. When talking about
Bob measuring a speed, you have to indicate with respect to what
coordinate systems he is performing his measurement.
Let's assume he measures the speed of light to a local inertial frame.
If he then measures the speed of light to be 2c, he has falsified GR and
we can immediately skip this discussion about statements of GR. If he,
instead, measures to speed of light to be c, we can assume that GR
remains applicable, and that with respect to Schwarzschild coordinates,
the speed of light at Bob's position is c/2.
What we cannot assume then, though, is that the speed of light would be
relative to the observer. Because being relative to an observer is a
concept from SR that implies that choosing an observer defines a frame
of reference. In GR, there is no concept of frames of reference - except
in SR limit - and therefore no concept of being relative to an observer.
Assumed, you mean Schwarzschild coordinates when saying "in the larger
picture", you are right. This "larger picture", however, is arbitrary,
since one could as well apply different coordinates that yield a
different running speed ratio between Bob's clock and Alice's clock than
1/2.
In GR, it does not make sense to say that Bob is "the" observer or that
Alice is "the" observer. Defining someone as "the" observer makes sense
in SR only, where one can apply the concept of a frame of reference. In
SR, one could assign a frame of reference to Alice and one to Bob, and
by choosing one of both frames, one would choose either Alice or Bob as
"the" observer. In GR, however, there's no frame of reference. One can
consider each of both, Alice and Bob, as "an" observer, but none of them
as "the" observer.
When talking about "relative" or "absolute", you seem to SR's concept of
relative and absolute: relative means "depending on the frame of
reference" and absolute means "not depending on the frame of reference".
In GR, this concept is obsolete, since there's no frame of reference.
In my mind, your question is based on assumptions that aren't valid in
GR. When asking for being absolute or relative/variable, you seem to
refer to SR concepts that are obsolete in GR. Therefore, your question
cannot be answered meaningfully.
Really now! If the experiment were actually performed, there would be
only ONE result.
This one result, however, would be a result for gravitational redshift,
not for gravitational time dilation. You CAN, if you want, apply
Schwarzschild coordinates, and based on that, interpret the result as
caused by gravitational time dilation. This interpretation, however, is
arbitrary, since applying Schwarzschild coordinates is arbitrary.
Or you can modifiy the experiment's prescription by explicitly
specifying that Schwarzschild coordinates are to be applied and that
observed redshift is to be interpreted as time dilation with respect to
Schwarzschild coordinates. This, however, would make the experiment's
prescription arbitrary, since one could as well define a prescription
specifying the application of a different coordinate system.
The problem is that you (Gary harnagel) haven't specified the experiment
in sufficient detail. There are many possible experiments which would be
consistent with your description, and (in general) these experiments will
give different answers.
For example, here are four possible experiments consisten with your
description:
(a) The far-away observer is a rest with respect to the black hole (BH).
This specification, however, isn't sufficiently detailed, too. "At rest
with respect to the blach hole" does not have a disctinct meaning in GR,
since there is no such thing like a frame of reference of the black
hole. To specify the observer as being resting, you need to specify a
coordinate system with respect to which the observer is resting. If you
want, you can take Schwarzschild coordinates, like John and Gary
obviously do.
As far as John specified the experiment, thise case (c) is presumed,
with "holding itself at that position" meaning holding at a fixed
Schwarzschild radial coordinate r = const.
What makes the experiment's outcome for gravitational time dilation
arbitrary is NOT that there also the cases (a), (b) and (d), but rather
that choosing Schwarzschild coordinates for conclusions about the
apperaring time dilation is arbitrary.
No, they will give many more different answers, since for each of them,
one can apply different coordinate systems. Only for the gravitational
redshift, they yield only four different results.
But John had done this before.
[[Mod. note --
I agree with all of Gregor Scholten's points. Mea culpa for trying
to post about GR when tired and in a rush. :)
-- jt]]
[--]
I would argue that there are two reasonably consistent ways of
describing 'what's actually going on'. One is the GR model, in which
spacetime is curved, and light (and other energy) travels along those
curves at c everywhere. The other is a model in which gravity is a kind
of force that causes light (and other energy) to bend and slow. In this
way of describing things, light slows down in gravitational fields, and
the background spacetime is considered flat just as in your 'god's eye'
view.
When I say 'what's actually going on' I mean descriptions that connect
or could possibly connect with deeper or separated areas of physics.
Descriptions that are not necessarily great for solving specific
problems, but better for understanding fundamentals. Each of these
descriptions naturally suggests a particular type of coordinate system,
but neither is really 'about' coordinate systems.
So, does light *really* slow down or not? Pick one of the above, and
you have chosen the answer you prefer. No further measurement required,
as we already understand the implications quite well. These two
descriptions are the ones we can reasonably offer at present when the
question of "what really happens" is asked. (Maybe there are 'deeper'
options, but in the current context there are only these two.)
However, much of physics involves discussions of particular physical
situations which in the context of gravity tend to involve various
carefully selected curved coordinate systems. Because even if the
'gravity as force' model is the best fundamental description, its
effects are often most easily described in terms of geometry. Anyway,
all these ad hoc coordinate systems are essentially arbitrary as Gregor
was saying - or more precisely, they are chosen to fit a particular
problem. For example, Schwarzschild coordinates are useful in
describing the gravitational field surrounding a star or a black hole.
Hope that is some help.
- Gerry Quinn
---
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Gary Harnagel wrote:
I understand that choosing an experiment where r is constant for Bob leaves
out how that condition can be maintained. Specifying that phi and theta
are also constant, all wrt a distant observer, means that either Bob is
standing on a surface or he is in a rocket. Specifying that the derivative
of phi or theta is constant means that he maintains r = constant by orbital
motion. Different experimental conditions. But it appears to me that
either case can be addressed using Schwarzschild coordinates. One may get
different results for the two cases, but the results must agree regardless
of the coordinate system used.
Also, there seems to be some conflation about gravitational red shift versus
time dilation. Just use an atomic clock to measure the difference in time.
Then the change in the wavelength of the carrier is irrelevant.
Gary
Jonathan did not bring up such an explanation. Jonathan described
different experiment, though, but those experiments are not defined by
different choices of coordinates. As I pointed out in my reply to
Jonathan, the experiments were are talking about here are of (c) type.
And as I pointed out, one can choose different coordinate types for
experiment (c).
This depends on the experiment's prescription. If the prescrition
defines that the experiment just measures the gravitational redshift,
then the result is just a gravitational redshift, not a gravitational
time dilation. Conclusions that the resulting redshift may be caused by
gravitational time dilation are not part of the experiment then, and an
eventually concluded time dilation is not part of the result then.
Choosing different coordinates does not change the experiment then.
If, on the other hand, the experiment's prescription explicitly
specifies that Schwarzschild coordinates are to be used, and that
gravitational redshift is to be interpreted as gravitational time
dilation, then choosing different coordinates changes the experiment,
since it changes its prescription.
These are out of interest, though, since John's experiment definition
specified that both, the far distant observer and the observer near the
black hole, are resting with respect to Schwarzschild coordinates, i.e.
for both apply r = const, theta = const and phi = const.
Of course. But as well, each case can be addressed different
coordinates. And due to that, using Schwarzschild coordinates is arbitrary.
That depends on the experiment's prescription, as explained above. A
prescription that defines the experiment as measuring a
coordinate-independent quantity, like the gravitational redshift, then
the result is coordinate-independent. If, however, the prescription
defines the experiment as measuring a coordinate-dependent quantity,
like gravitational time dilation, and specifies a coordinate system to
measure that quantity, like Schwarzschild coordinates, the result may be
different for different coordinate systems.
However, one single atomic clock cannot be used to measure a
gravitational time dilation. You need at least two of them, and they
must the spatially separated. To measure the gravitational time dilation
in Schwarzschild coordinates, one could e.h. the following experiment:
Attach two clocks to two different spatial positions, the first at r = r1,
the second at r = r2 > r1. For both clocks apply theta = const and
phi = const. Now let the first clock emit a light signal to the second
one. Note the proper time tau2_1 displayed by the second clock when the
light signals arrives it. After some proper time interval Delta tau1 on
the first clock, e.g. 1 second, let this clock emit another light signal
to the second clock. Note again ther proper time tau2_2 the second
clocks displays when this second signals arrives.
You will find out that the proper time interval on the second clock,
Delta tau_2 = tau2_2 - tau2_1
is different from the proper interval Delta tau1 on the first clock,
namely that Delta tau2 is longer: Delta tau_2 > Delta tau1. Since the
propagation of both light signals is equivalent in Schwarzschild
coordinate due to time translation invariance, you will conclude that
this difference in the proper time interval is caused by gravitational
time dilation.
This result, however, is coordinate-dependent. Instead of Schwarzschild
coordinates (t, r, theta, phi), you could instead use a coordinate
system (T, R, Theta, Phi), that transforms from Schwarzschild coordinates by
T = (1 - rs/r) t
R = r
Theta = theta
Phi = phi
Applying these coordinates, wou will NOT conclude that the difference in
proper time interval is due to gravitational time dilation, but rather
by different propagation of the two light signals (there is no time
translation invariance in these coordinates): the second signal took a
longer coordinate time interval to reach the second clock.
You can define different experiments than this one to measure the
gravitational time dilation, but as long as the two uses clocks always
remain in their fixed different spatial positions, you will be obliged
to use some kind of signals travelling between them to perform the
experiment, and this makes necessary to take the propagation of these
signals into account.
Alternatively, you can use clocks that are initially close together and
encounter again finally. Then you do not need signals. You can assume,
the both clocks start at r = r2, and that the first clocks moves from r2
to r1 then, stays at r1 for a long proper time interval, and then return
to r2 finally. When the first clocks returns to r2, you can compare the
different elapsed proper time intervals of the to clocks.
However, also in this experiment, conclusions from the result that
concern gravitational time dilation are coordinate-dependent again: in
Schwarzschild coordinates, you will conclude that during the most
elapsed coordinate time, the first clocks stayed at r = r1, and that the
time intervals the clock took to transit from r2 to r1 and from r1 to r2
again were neglectably short, so that the difference in elapsed proper
time obviously came from the time when the fist clock stayed at r1.
Applying the coordinate (T, R, Theta, Phi) I described above, on the
other hand, your conclusions are completely different: the difference in
elapsed proper time comes from the phases where the clock was travelling
from r2 to r1, and back from r1 to r2, not from the phase where it
stayed at r1.
Now, one could be temptated to claim that Schwarzschild coordinates are
more valid than the coordinates (T, R, Theta, Phi) since in
Schwarzschild coordinates, time translation invariance applies, making
these coordinates specially meaningful. As far as the Schwarzschild
solution is considered on its own, one could indeed think that this
argumentation would be valid.
However, in any solutions of the field equations of GR, one always has
to keep in mind the full symmetries of GR, and these include general
covariance which implies that coordinate systems without time
translation invariance are as good as coordinate systems with time
translation invariance. Keep in mind that there are solutions of field
equations where you cannot construct coordinate systems with translation
invariance at all, e.g. cosmological solutions that describe an
expanding universe. Therefore, GR cannot ascribe a special validity to
time translation invariant coordinate systems, and this remains valid
even for solution where such coordinate systems can be concstructed.
The only special coordinate systems in GR are the local inertial frames,
since they can be constructed in any arbitrary solution of the field
equations.
[...]
Others have given good answers to this, but let me
try to say it in slightly different words. I'll
avoid referring to coordinate systems, since strictly
speaking, no physical result should depend on a choice
of coordinate system -- the problem is that unless
you're very careful, different coordinates push you
toward different hidden assumptions. (Conversely,
hidden assumptions about things like simultaneity
can often be converted to statements about choices
of coordinates.)
There's a slogan that all misunderstandings about
relativity come from a failure to appreciate the
relativity of simultaneity. This is an exaggeration,
of course, but there's some truth to it. It's very
easy to forget that there's no single "right" way to
compare clocks or meter sticks at different locations,
and that different choices can lead to different
conclusions.
In particular:
Here, you're implicitly assuming that the two "meter
sticks" are the same length. How do you determine that?
How can you tell? For this to mean something, you
need a method to compare clocks at two different
locations. Different choices give different results.
How do you tell? To say that Alice and Bob are at rest
relative to each other, you need a way to compare their
velocities. How do you do that? One way would be to
look for Doppler shift, but how would you propose to
disentangle that from gravitational red shift?
Consider the first question, the length of Alice's and
Bob's meter sticks. It may be tempting to say that if
Alice and Bob start with identical meter sticks at the
same place and then move apart, their meter sticks stay
the same. But would you say that about their clocks
as well? If so, then if Bob and Alice started with
identical atomic clocks, Bob's clock is still measuring
time at the same rate as Alice's not "ticking at half
its rate."
Or are you saying you want the length of a meter
stick to remain constant when its location changes,
but the speed of a clock to change? You *can*
make such a choice -- actually in infinitely many
ways -- but you have to specify a precise method.
Another way to compare the meter sticks would be
to have Alice and Bob each time a pulse of light as
it moves from one end of a stick to the other. If
it takes about 3.336 nanoseconds, then each stick is
one meter long. This is a nice, consistent method,
and it's pretty much the "standard" choice. But of
course with this definition, the speed of light is
automatically the same for both Alice and Bob.
[...]
It depends on how god is synchronizing clocks and
determining lengths. Te key lesson of relativity is
that there is no "right" answer, no choice that is
a "god's-eye view."
Steve Carlip
I wish to convey the simultaneity of time to a class using the
classic train and lightening strikes. A hand goes up in the back
of the class wanting to know if it is a steam powered train or a
diesel powered train. How do I respond? Jumping out the window to
just end it all is one option.
This specification, however, isn't sufficiently detailed, too. "At rest
with respect to the blach hole" does not have a disctinct meaning in GR,
But when does "at rest" have a meaning, then? Being at
rest w.r.t. empty space has no meaning, so at least we
need one particle in it and how is a black hole different
from a particle? (OK, it's mass might be of a different
scale, but what is essentially different?)
--
Jos
[[Mod. note -- In the context of general relativity:
For an asymptotically-flat spacetime (this includes Schwarzschild and
Kerr black holes) we can define a notion of the total 4-momentum of
the spacetime, as measured far from the BH (either at spatial infinity
or at future null infinity). This then lets us define "at rest"
(choose a far-from-the-BH observer, then Lorentz-boost her until she
measures no spatial component to the total 4-momentum).
-- jt]]
[--]
To return to the burning question. In your mind is the speed of
light absolute or variable. It is a given light will always measure
c but is it constant in the larger picture of god looking down at
Alice and Bob from a great distance?
I would argue that there are two reasonably consistent ways of
describing 'what's actually going on'. One is the GR model, in which
spacetime is curved, and light (and other energy) travels along those
curves at c everywhere. The other is a model in which gravity is a kind
of force that causes light (and other energy) to bend and slow. In this
way of describing things, light slows down in gravitational fields, and
the background spacetime is considered flat just as in your 'god's eye'
view.
When I say 'what's actually going on' I mean descriptions that connect
or could possibly connect with deeper or separated areas of physics.
Descriptions that are not necessarily great for solving specific
problems, but better for understanding fundamentals. Each of these
descriptions naturally suggests a particular type of coordinate system,
but neither is really 'about' coordinate systems.
So, does light *really* slow down or not? Pick one of the above, and
you have chosen the answer you prefer. No further measurement required,
as we already understand the implications quite well. These two
descriptions are the ones we can reasonably offer at present when the
question of "what really happens" is asked. (Maybe there are 'deeper'
options, but in the current context there are only these two.)
However, much of physics involves discussions of particular physical
situations which in the context of gravity tend to involve various
carefully selected curved coordinate systems. Because even if the
'gravity as force' model is the best fundamental description, its
effects are often most easily described in terms of geometry. Anyway,
all these ad hoc coordinate systems are essentially arbitrary as Gregor
was saying - or more precisely, they are chosen to fit a particular
problem. For example, Schwarzschild coordinates are useful in
describing the gravitational field surrounding a star or a black hole.
Hope that is some help.
- Gerry Quinn
---
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https://www.avast.com/antivirus
[[Mod. note -- Please limit your text to fit within 80 columns,
preferably around 70, so that readers don't have to scroll horizontally
to read each line. I have manually reformatted this article, making
an educated guess at paragraph breaks. -- jt]]
Well said. If memory serves your last post was the same in that you
understood the point being made the first time. If I were smart I
would leave at that on a high note but it is not in my nature:<).
I would like to demonstrate from a philosophical position that
gravitational red shift could be in violation of causality provided
ideal conditions of Doppler and SR effects are set aside. The way
to do this is to state ahead of time that there is no movement
between A and B therefore there can not be a Doppler or SR effect.
Now that the clutter of too many variables on the table has cleared
we have only gravitation time dilation and gravitational red shift
of B atomic clock observed by A that is not time dilated. The exact
amount of time dilation is not relevant other than being consistent
so I leave it to the read to assume then set ideal condition for
it to be so. If Schwarzschild coordinates are useful then a toss
of dice could set the exact time dilation and then reverse construct
the Schwarzschild coordinates. I am kidding of course :<). Clock B
may have missing ticks without violating causality as it is time
dilated therefore justified to have missing ticks as observed by
A. However if gravitational red shift were in any way effect the B
clock rate as observed by A then there is a violation to causality.
Where are the missing ticks? There is no longer a Doppler effect
to continuously hide them in space. Where did they go? From this I
conclude that gravitational red shift is simply the observation of
gravity time dilation.
There in is the rub. From energy conservation laws the frequency
of a photon must go down caused by G red shift. From a causality
position the frequency can not go down as it violates causality.
Where are you going to hide the missing tick . Only gravity time
dilation is allowed to have missing ticks not gravitational red
shift as it is only a carrier of information. I do not have an
answer for this.
On 12/11/15 12/11/15 - 6:00 AM, Gary Harnagel wrote:
If one specifies the experiment sufficiently well, then GR predicts a single
result. For a basic redshift measurement of an electromagnetic signal, a
sufficient specification consists of:
1) the metric of spacetime at all events of interest
2) the position and 4-velocity of the emitter when the signal is emitted
3) the position and 4-velocity of the detector when the signal is detected
4) the path of the EM signal between emission and detection
5) the proper period of the emitted EM signal; it must be very much smaller
than any other timescale in the problem
Without all that, one cannot calculate the redshift. But with all that one can
calculate the redshift in a coordinate-independent way:
A) Form the displacement 4-vector between two successive wavecrests
of the emitted wave. This is necessarily parallel to the
emitter's 4-velocity, with norm (5).
B) Parallel propagate that displacement 4-vector along the signal
path to the detector.
C) Compute the dot product of the result of (B) with the detector's
4-velocity. This is the measured period of the detected wave.
Note this algorithm is quite general and works in any manifold of GR (including
Minkowski spacetime of SR, and non-static/non-stationary manifolds). It depends
on the metric at the emission event, everywhere along the signal path, and at
the detection event.
Note also it does not distinguish among "gravitational time dilation",
"gravitational redshift", "redshift due to relative velocity", and "Doppler
shift" -- all it does is give you the predicted numerical result; what label one
chooses to apply does not really matter.
Tom Roberts
Instead of Schwarzschild coordinates, you can e.g. choose coordinates in
which time translation invariance does not apply. In such coordinates,
the light signals propagating from clock B to clock A may propagate
differently: the later a signal is emitted by clock B, the more
coordinate time takes it to reach clock A. Due to the symmetry of GR,
such a coordinate is as valid as Schwarzschild coordinates are.
I made two spacetime diagrams that illustrate this:
http://fs5.directupload.net/images/151215/ny7cjhue.png
The left diagram is based on Schwarzschild coordinates. Since time
translation invariance applies there, the light signals from clock B to
A are equivalent, except the second one being shifted by some coordinate
time interval. The right diagram is in coordinates without time
translation invariance. The second light signal takes longer (i.e. a
longer coordinate time interval) to reach clock A.
But differences in light propagation due to time translation invariance
not applying.
Your conclusion is based on the presumption that a coordinate system in
which time translation invariance applies is more valid than a
coordinate system in which there is no time translation invariance.
According to GR, this presumption must be considered as wrong.
Although Schwarzschild solution has special properties that may temptate
one to make this wrong presumption, one has to keep in mind that the
full symmetry of GR, i.e. general covariance, applies in any solution of
the field equations, even in those with special properties.
To a coordinate system without time translation invariance. According to
the symmetries of GR, such a coordinate system is as valid as one with
time translation invariance like Schwarzschild coordinates.
Once again: this conclusion is based on the presumption that time
translation invariance is obliged to apply. This presumption is wrong in GR.
You are wrong, you have one, since I indicated it to you several times:
instead of Schwarzschild coordinates, you can as well apply coordinates
in which time translation invariance does not apply.
This specification, however, isn't sufficiently detailed, too. "At rest
with respect to the blach hole" does not have a disctinct meaning in GR,
But when does "at rest" have a meaning, then? Being at
rest w.r.t. empty space has no meaning, so at least we
need one particle in it and how is a black hole different
from a particle?
In GR, a particle is even not sufficient to define being at rest, since
unlike in SR, the particle does not define a frame of reference. So, in
addition to a particle, you need a coordinate system.
In SR, a particle would be sufficient, but not in GR.
More in detail: an inertial frame, like it is constructable in SR, is
like a four-dimensional Cartesian coordinate systems: the coordinate
lines of it four coordinates (t,x,y,z) are straight lines and orthogonal
to each other. In the flat spacetime of SR, such an inertial frame can
be defined in a distinct way by choosing a uniformly moving particle:
the wordline of that particle is a straight line, and all the t
coordinate lines of the inertial frame are parallel to the particle's
worldline, while the spatial coordinate lines are orthogonal to the so
defined t coordinate lines. In the curved spacetime of GR, however,
there is no such procedure to define an inertial frame or any other type
of coordinate system from just choosing a particle. You won't be able to
construct a coordinate system where all coordinate lines are straight
(i.e. geodesic) everywhere and at the same time orthogonal to each other
everywhere.
Take e.g. Schwarzschild coordinates, those are orthogonal, but their
coordinate lines are not straight (proof: a particle with a worldline on
which r = const, theta = const, phi = const applies, i.e. with a
wordline that matches a t coordinate line, is not free-falling, so the
wordline is not goedesic, and by this, the t coordinate line is not
geodesic, too). Therefore, choosing Schwarzschild coordinates is
arbitrary. Instead, one could as well choose coordinates where the
coordinate lines are geodesic, but not orthogonal to each other. In
those coordinates, being at rest will probably have a different meaning
than in Schwarzschild coordinates (e.g. a free falling particle might
have a wordline that matches a t coordinate line, implying it is at rest
in these coordinates, whereas it is surely not at rest in Schwarzschild
coordinates.).
Different to a particle in the flat spacetime of SR? The spacetime
curvature generated by the black hole that destroys to applicability of
frames of reference.
However if gravitational red shift were in any way effect the B
clock rate as observed by A then there is a violation to causality.
Where are the missing ticks?
Instead of Schwarzschild coordinates, you can e.g. choose coordinates in
which time translation invariance does not apply. In such coordinates,
the light signals propagating from clock B to clock A may propagate
differently: the later a signal is emitted by clock B, the more
coordinate time takes it to reach clock A. Due to the symmetry of GR,
such a coordinate is as valid as Schwarzschild coordinates are.
I made two spacetime diagrams that illustrate this:
http://fs5.directupload.net/images/151215/ny7cjhue.png
The left diagram is based on Schwarzschild coordinates. Since time
translation invariance applies there, the light signals from clock B to
A are equivalent, except the second one being shifted by some coordinate
time interval. The right diagram is in coordinates without time
translation invariance. The second light signal takes longer (i.e. a
longer coordinate time interval) to reach clock A.
There is no longer a Doppler effect
to continuously hide them in space.
But differences in light propagation due to time translation invariance
not applying.
Where did they go? From this I
conclude that gravitational red shift is simply the observation of
gravity time dilation.
Your conclusion is based on the presumption that a coordinate system in
which time translation invariance applies is more valid than a
coordinate system in which there is no time translation invariance.
According to GR, this presumption must be considered as wrong.
Although Schwarzschild solution has special properties that may temptate
one to make this wrong presumption, one has to keep in mind that the
full symmetry of GR, i.e. general covariance, applies in any solution of
the field equations, even in those with special properties.
There in is the rub. From energy conservation laws the frequency
of a photon must go down caused by G red shift. From a causality
position the frequency can not go down as it violates causality.
Where are you going to hide the missing tick .
To a coordinate system without time translation invariance. According to
the symmetries of GR, such a coordinate system is as valid as one with
time translation invariance like Schwarzschild coordinates.
Only gravity time
dilation is allowed to have missing ticks not gravitational red
shift as it is only a carrier of information.
Once again: this conclusion is based on the presumption that time
translation invariance is obliged to apply. This presumption is wrong in GR.
I do not have an
answer for this.
You are wrong, you have one, since I indicated it to you several times:
instead of Schwarzschild coordinates, you can as well apply coordinates
in which time translation invariance does not apply.
I appreciate the effort you are making to get your point across and
I would add Tom as well for taking the time to make the counter
argument as clear as possible. I know from experience that it takes
a good hour if not more to word it just right , for myself anyways
, so I appreciate the time taken to conveying these thoughts. l
hear you.
Founding principles of physics are not to be played with. Energy
conservation , momentum conservation , causality. This is our candle
of light to navigate this wonderful subject of physics. These
principles can not be set aside if it is inconvenient. On another
note one can have 1 variable on the table and be okay. You can have
2 variables on the table and still be okay provided one is willing
to pace the floor a few nights to sort out all the possible
alternatives. If there are 3 variables on the table it is unlikely
anything productive can come out as there are just too many roads
to explore. If there are 4 variables on the table forget it as it
not going to happen. Maybe a computer but not the human mind with
a clock rate of 25 Hz at best.
I have made what I consider a valid argument from a philosophical
position that gravitational red shift can not change rate of ticks
, amount of time dilation , without being in conflict with causality
within the limitations of no SR effects and no Doppler effects.
The only two variables are gravitational time dilation and
gravitational red shift. If new variables are introduce such as
this coordinate system vs that then we have 3 or 4 variables on
the table to consider. This is beyond human capacity and will lead
to nothing more than dogs barking at the moon into the wee hours.
Surely we are better than dogs barking at the moon into the wee
hours. Please restrict your self to gravitational time dilation
and gravitational red shift only to proceed in a productive way.
For clarification a photon leaving earth must be reduced in frequency
to satisfy energy concentration laws. If the frequency of the photon
is reduced within a medium , medium between earth and space , there
will be a violation to causality.
To understand why think of a rigid hollow rod between A and B with
information of atomic clock ticks being conveyed by a laser in the
middle of the rigid rod. With the rigid rod there can not be Doppler
effects. With this in place make sure the rod is not rotating
relative to the stars so that there can not be a SR effects within
that local area. This leavers us with only 2 variables of G time
dilation and G red shift between A and B. I do not think it is
possible for G red shift to change time dilation without being in
violation of causality. However if photon energy therefore frequency
is not adjusted for G red shift then energy conservation will be
violated. Either way it is dead end road. Where is the compromise
for both causality and energy conservation to be satisfied under
these conditions?
Always good to describe a problems two ways to best communicate a
thought. B sends a sample of 1000 pules to A from his atomic clock
to test for time dilation caused by G time dilation. There is not
a violation to causality here. However for G red shift to change
measurements of time dilation it must change 1000 pulses to 999 or
1001 pulses which is a clear violation to causality. Keep in mind
G red shift is information on a laser beam of light that can not
go back in time to change the atomic clock as it is just a wave of
information of 1000 pulses. There is no Doppler effect to hide
pulses. Only G time dilation can change atomic tick rates. G red
shift does not have the means to effect clock rate other than delayed
in time but it will still be 1000 pulses only at a rate consistent
with the rate pulses are leaving B. If not there will be too many
or not enough pulses in the information channel which will be
unmanageable over a period of time if 1000 pulses is changed to 1
10^10 pulses. Where can one hide these pulses in a G red shift as
it is just a medium that conveys information from A to B.
[[Mod. note -- Energy and momentum conservation are nice principles,
but they're very tricky in a curved spacetime. Notably, it's very
hard to even *define* the total energy/momentum in some finite volume:
You can (fairly) easily define the energy/momentum in an infinitesimal
volume, but in a generic curved spacetime there's no unique way to
add up (volume-integrate) the contributions from all the different
infinitesimal regions.
-- jt]]
[--]
- show quoted text -
I'm not precisely clear as to your exact thought experiment, but it
seems to me that you can start by looking at things through 'god's eye'
coordinates, a.k.a. coordinates natural to an observer in a low
gravitational far from the system of interest. In these flat spacetime
coordinates, light slows and bends in gravitational fields. But so long
as you consider only regions outside event horizons, you can describe
any physical system in a way that is consistent with any system of GR
curved coordinates.
There is no causality violation in either description. If B moves in
close to a black hole for a while and comes back again, he will have
aged less than A, according to either formulation. But there are no
'missing ticks'. In the flat spacetime formulation, that's because
light and time slowed down where he was. In the curved spacetime
formulation, light and time go at the same speed everywhere, but
spacetime is distorted. So when he meets up again with A, he finds less
time passed on the route he took. And when they meet, the number of
ticks observed by both parties will be identical.
Remember, in relativity it's very important to talk only about local
measurements - so you can't safely add the ticks until A and B meet, nor
can you claim that there is no relative movement. In the flat spacetime
formulation, that's still technically the case if we are talking about
relative movement and invoking special relativity, but where there is no
relative movement [and no acceleration - this doesn't apply in a
rotating system!] we can assert the fact without tripping ourselves up.
In the discussion of the general relativistic formulation of this
thought experiment, we can't really do that. You can't claim a paradox
in a theory based on non-measureable entities that aren't considered
meaningful in that theory.
Also, note that energy conservation applies in asymptotically flat
spacetimes in GR, but is not necessarily applicable when only part of
such a spacetime is considered.
- Gerry Quinn
---
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[[Mod. note -- Your description doesn't tell me how to define your
"god's eye" (GE) coordinates.
Let's be specific. What's your operational definition of GE
coordinates for Schwarzschild spacetime, and why should we believe
that these are unique (i.e., that they're the *only* coordinates
"natural to an observer in a low gravitational far from the system
of interest")?
And, how do we know that the GE coordinates cover all "interesting"
regions of spacetime. For example, can you prove that GE coordinates
don't have any coordinate singularities outside the event horizon?
-- jt]]
To understand why think of a rigid hollow rod between A and B with
information of atomic clock ticks being conveyed by a laser in the
middle of the rigid rod. With the rigid rod there can not be Doppler
effects.
You have to keep in mind, though, that according to Relativity, there is
no such thing like an ideal rigid rod. Any real rod is deformable.
Imagine a rod consisting of atoms. The atoms are bound together by
interatomic forces. With the rod exposed to a gravitational field, the
position of each atom is determined by an equilibrium of the
gravitational forces (the rod and its atoms are not free-falling, so
each atom experiences a gravitational force) and the interatomic forces
from the other atoms.
Now consider things in Schwarzschild coordinates. The gravitational
field is static there (in the sense that the derivatives to coordinate
time vanish), so the equilibrium positions of the atoms of the rod are
static, too, making the rod not stretching or shrinking.
But now consider things in e.g. Kruskal coordinates. With passing
Kruskal coordinate time v, a rod with two ends for which r = const
applies each is shrinking more and more. This is in full compliance with
the rod atoms' positions being determined by equilibrium between
gravitational force and interatomic forces: the gravitational field is
not static in Kruskal coordinates, but rather changing by coordinate
time v. So, the equilibrium positions of the rod atoms are changing,
too, making the rod being shrinking.
Therefore, your argument that there cannot be a Doppler effect - or
let's say: a redshift due to movement - is wrong.
In principle, this rod examples shows what I said in a parallel post in
this thread, namely that in a curved spacetime, there is no distinct
procedure to construct a frame of reference. With the assumption of a
rigid rod, one could be temptated to claim that such a rod should
provide such a procedure: namely that the wordlines of the rod atoms
might define the t coordinate lines of a frame of reference. But this is
wrong: there is no reason why a rod had to be rigid, and therefore no
reasong to prefer coordinate systems in which both ends of the rod are
resting.
You are again making the wrong assumption that time translation
invariance had to apply. In Schwarzschild coordinates, time translation
invariance applies, making all 1000 pulses take the same coordinate time
interval to propagate from B to A. So that redshift only can be
explained by different ratios of the proper times of the two clocks to
coordinate time.
However, in GR, there is no reason why not to apply coordinates without
time translation invariance. Take again the following coordinates:
T = sqrt(1 - rs/r) t
R = r
Theta = theta
Phi = phi
You will see that the second pulse from B to A takes a little more
coordinate time T to propagate than the first pulse, the third pulse
takes again a little more coordinate time than the second one, and so
on. Let Delta T_B denote the coordinate time interval it takes to emit
all 1000 pulses from clock B. And let Delta T_A denote the coordinate
time interval it takes to receive all 1000 pulses at clock A. Then the
relation is
Delta T_A = 1.001 * Delta T_B
So, in a coordinate time interval of length Delta T_B, clock A receives
only 999 pulses, not 1000. The 1000th pulse comes a little later.
A further analysis shows up that when we consider pulses propagating in
the opposite direction, namely inwards from clock A to clock B, the
propagation time interval of those pulses becomes shorter and shorter,
and after a finite coordinate time T, it hits zero. In other words: the
radial coordinate R becomes timelike. This simply means that the
coordinates (T, R, Theta, Phi) have a coordinate singularity in future
direction, outside the black hole. This implies that their range of
validity (their "map") is even more limited than the one of
Schwarzschild coordinates (which is limited to r > rs). But within this
range, the coordinates (T, R, Theta, Phi) are - according to GR - as
good as any other coordinate system.
But there is a lack of time translation invariance (in the coordinates
(T, R, Theta, Phi)) that allows the 1000 pulses to stretch, from Delta
T_B to
Delta T_A = 1.001 * Delta T_B
....
[[Mod. note -- Your description doesn't tell me how to define your
"god's eye" (GE) coordinates.
Let's be specific. What's your operational definition of GE
coordinates for Schwarzschild spacetime,
Wouldn't that be r = infinity?
There should be an infinite number of coordinates that are at r < infinity
but still large enough to be insignificantly different from r = infinity
by our measurement techniques.
But the GE coordinates are essentially where WE are, and we're in peril
if we aren't there.
What about a circular orbit at r = 1.5*r_schw?
Gary
On 12/18/15 12/18/15 1:14 AM, Gerry Quinn wrote:
This is just plain not true. You cannot apply such "flat coordinates"
to any manifold of GR containing mass or energy, as such manifolds
are not flat. Remember "flat" is a property of the metric, not the
coordinates, and the metric is a tensor (field) and therefore
independent of coordinates.
What you seem to be thinking of is a completely different formulation
of gravity as a spin-2 field on a flat manifold. This is a MUCH
bigger difference than mere selection of coordinates as you say.
This model can account for many properties of GR, but in particular
it can be compared to GR only in regions in which gravitation is
weak (so you can put the manifolds of the two models into 1-to-1
correspondence with negligible error, and thus compare them). This
comparison fails wherever gravity is not weak, and that can happen
well outside any event horizons.
This depends IN DETAIL on what one means by "causality". The casual
notion of "this caused that" is both hopelessly naive and completely
useless. So what do you mean?
In relativity, causality is the property that at any given
event in the manifold, the fields depend only their values
at events within the past lightcone of the event in question.
How they depend is an aspect of the specific fields being
discussed, and their properties and interactions.
It OUGHT to be obvious that mere coordinate choice cannot possibly
do that -- it requires a physical process to make "light and time
[be] slowed down".
Note that in neither model are there any "missing ticks". In GR the
integrated proper time (= tick count) over the two paths is different;
in the other model B's clock physically ticked slower for much of
his path. But nobody could possibly notice that some ticks were
"missing".
I think you meant to say that A and B can have different tick counts
(elapsed proper times) when they meet, but the two models agree on
what those counts are.
Hmmm. One can discuss non-local "measurements" as long as one
specifies how they are performed with sufficient clarity and
precision. Of course the actual act of measurement takes place at
a single event and is thus inherently "local", so by "non-local
measurement" one really means combining measurements performed at
different events.
I think you mean "count the ticks on clocks A and B, ending when
they meet". One can certainly compare the clock readings of two
clocks, but then, one must specify HOW they are compared; this is
simple when the clocks are co-located, but when they aren't this
would be a "non-local measurement" that must be specified in more
detail. Note this applies to both the beginning and the end of the
interval over which they are to be compared.
Energy conservation in GR is subtle and complicated. But if you
follow your own dictum above, "talk only about local measurements",
then it is easy: energy and momentum are locally conserved at every
event in the manifold.
He intends the "GE" coordinates to be "flat", which simply is not
possible in Schw. spacetime.
Tom Roberts
Another remark: considering the Schwarzschild solution in Kruskal
coordinate is similar to considering a uniformly accelerating rocket in
SR. Instead of Kruskal coordinates (u,v), there are the coordinates of
the inertial frame (X,T) where the rocket is initially resting in, and
instead of the Schwarzschild coordinates (r,t), there the so-called
Rindler coordinates (x,t) that can be imagined as defining the
accelerated frame of reference of the rocket:
https://en.wikipedia.org/wiki/Rindler_coordinates#Relation_to_Cartesian_chart
The front and back of the rocket can be thought as having constant
spatial Rindler coordinate x (e.g. x = 1 for the front and x = 0.6 for
the back). Now, when the rocket accelerates more and more, the front and
back of the rocket come closer and closer together seen from the
inertial frame (X,T), due to Lorentz contraction.
In the inertial frame (X,T), this Lorentz contraction can also be
interpreted as being caused by the interatomic forces of the rocket's
material: assumed, the forces are of electromagnetic nature, it follows
that they can be described by Lineard-Wiechert potentials, resulting in
electric fields being Lorentz-contracted due to the movement of the
electric charges in the rocket atoms (seen from the inertial frame
(X,T)). Those Lorentz-contracted electric fields can be thought as
causing the rocket atoms to be Lorentz-contracted, and finally, the
rocket itself.
Returning to Kruskal coordinates in Schwarzschild coordinates, we can
conclude that your "rigid" rod, which is of constant length in
Schwarzschild coordinates, is contracted by an analogous mechanism: it's
not only the gravitational field that causes the atoms' equilibriums
positions to evolve in a way that the rod is contracted, there are also
the interatomic forces behaving in a way that yields a contraction
effect on the rod (in Kruskal coordinates).
On 12/18/15 12/18/15 1:14 AM, Gerry Quinn wrote:
This is just plain not true. You cannot apply such "flat coordinates"
to any manifold of GR containing mass or energy, as such manifolds
are not flat. Remember "flat" is a property of the metric, not the
coordinates, and the metric is a tensor (field) and therefore
independent of coordinates.
What you seem to be thinking of is a completely different formulation
of gravity as a spin-2 field on a flat manifold. This is a MUCH
bigger difference than mere selection of coordinates as you say.
And indeed I indicated clearly that this was what I meant two posts
upstream. It should be obvious here in any case, since I state in the
above paragraph that in this model light slows and bends in
gravitational fields. Only one viable class of models exist in which
the gravitational force has such effects.
Completely untrue. It models GR in strong fields too (or why do you
think anyone would bother with it?). What you are missing, perhaps, is
that the graviton field acts on gravitons as well as photons (it acts on
all energy, as I noted more than once in the thread). Due to this self-
coupling, the end result is exactly the same math we get from the
geometric model, but without any need for a fundamental concept of
spacetime curvature.
Now it is true that the match-up is not absolutely perfect. To make the
graviton theory match GR perfectly everywhere would require a perfectly
fundamental spin-2 field, but only an effective field (low-energy) can
be made consistent with quantum theory. It should also be obvious that
a model with a flat background isn't going to be able to be made
consistent with GR anywhere the latter predicts non-simple topologies.
This means that at some point the theories must diverge significantly,
but that most likely requires a very strong field indeed. (In this
context, "low-energy" means up to 10^30 K or more!)
The debate is not rendered less contentious by the fact that at the
Schwarzshield radius, one model sees strong fields, and the other does
not!
[What seems strange to me, given GR's problems with singularities etc.,
is how long it has taken for this imperfect match-up to be begun to be
seen as a feature, not a bug...]
Regarding the rest, I think if you read previous posts in the thread for
context, and do not instantly assume that I am making jejune errors such
as thinking that coordinate choices have physical effects, you won't
have any difficulty understanding the points I was making.
- show quoted text -
[[Mod. note -- Your description doesn't tell me how to define your
"god's eye" (GE) coordinates.
Let's be specific. What's your operational definition of GE
coordinates for Schwarzschild spacetime, and why should we believe
that these are unique (i.e., that they're the *only* coordinates
"natural to an observer in a low gravitational far from the system
of interest")?
The techniques used to choose them would be the same as those used by
astronomers on Earth to underpin Coordinated Universal Time. Basically,
observation and correlation of various distant objects that display
periodic behaviour. Of course, there's a real possibility that the
entire measured region could be in a huge gravitational well, but in any
case we would still have a better approximation to the 'ultimate'
universal time than would someone in a microcosm of our space in which
we observe the presence of a gravitational field.
Nothing in this discussion requires very strong or even strong fields.
Except for the drama associated with numerically large red shifts,
everything under debate could be analysed in an Earth-based laboratory,
with experimenter A remaining on the ground floor while experimenter B
makes a daring excursion to the basement.
As regards uniqueness aside from the obvious arbitrary choice of origin
and velocity, I am not clear what it would mean for two observers in
communication in an asymptotically flat region of space to disagree. It
would be as if Martian astronomers were unable to make their
observations of Halley's comet consistent with those of Earthlings. It
would break numerous laws of physics.
They don't have any coordinate singularities *anywhere*. They are just
universal background Minkowski spacetime. Gravity is treated as just
another force that does what it does, bending and slowing light (and all
known energy). It must be assumed that GR breaks down inside black
holes - and when it does, high-energy clocks of some kind will in
principle be available. (Though it might not be possible to make
measurements inside one and convey them out in any reasonable external
timeframe. It is enough that time can be measured in principle.)
Again, this is not really germane. When I said there were two
reasonably consistent models, I did not intend to ignite a debate about
which one is better, or more consistent. Both will stand up well enough
in regard to the issues raised by the OP.
- Gerry Quinn
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[[Mod. note --
It's impossible to set up "universal background Minkowski" coordinates
in a curved spacetime: *any* coordinates you set up are going to fail
to have some of the key properties of coordinates in Minkowski spacetime,
namely that all the components of the Reimann tensor (computed in those
coordinates) vanish.
Also, If you set up coordinates far from a black hole,
and use ingoing light rays to extend those coordinates inwards, the
ingoing rays will often cross (forming coordinate caustics where the
coordinates are singular) long before reaching the black hole. In
fact, the coordinates will often cross when they're still in the
weak-field region.
This problem is well-known to people trying to use such "ingoing null"
coordinates to do numerical calculations in general relativity. The
usual solution is to start with coordinates chosen near to the black
hole, and extend those *outwards* via light rays -- that works and
doesn't produce caustics.
-- jt]]
[[Mod. note -- Your description doesn't tell me how to define your
"god's eye" (GE) coordinates.
Let's be specific. What's your operational definition of GE
coordinates for Schwarzschild spacetime, and why should we believe
that these are unique (i.e., that they're the *only* coordinates
"natural to an observer in a low gravitational far from the system
of interest")?
The techniques used to choose them would be the same as those used by
astronomers on Earth to underpin Coordinated Universal Time. Basically,
observation and correlation of various distant objects that display
periodic behaviour. Of course, there's a real possibility that the
entire measured region could be in a huge gravitational well, but in any
case we would still have a better approximation to the 'ultimate'
universal time than would someone in a microcosm of our space in which
we observe the presence of a gravitational field.
[--]
Also, If you set up coordinates far from a black hole,
and use ingoing light rays to extend those coordinates inwards, the
ingoing rays will often cross (forming coordinate caustics where the
coordinates are singular) long before reaching the black hole. In
fact, the coordinates will often cross when they're still in the
weak-field region.
It can't be impossible because we do it all the time. The space in the
solar system is curved, and we still use flat coordinates for most
purposes.
Why are you talking about extending coordinates using light rays? Where
there is a gravitational field, light rays have bent trajectories in
flat coordinates, and obviously cannot be used to extend them. Light
rays can only be used directly for extending coordinates in the GR
model, in which spacetime is curved. We're not talking about that,
except to see how it compares now and again.
Let's put the extreme case. We have a big laboratory containing a black
hole. We'll pretend that the lab is big enough that we can come to some
reasonable agreement that the walls are X, Y and Z metres long. And
we'll assume a plane of simultaneity based on the inertial frame of the
lab. Now what I mean by flat coordinates is that every point in the
lab, including points inside the black hole, can be assigned a
coordinate (x,y,z,t) such that (0..x..X, 0..y..Y, 0..z..Z), and t = current
lab clock time.
Now obviously light rays won't be much use to extend such coordinates;
we certainly can't use them to probe the black hole. But I'm asserting
that we can nevertheless model the syatem in terms of such coordinates.
At a given point (x,y,z,t) inside the black hole, there is *something* -
probably very hot stringy stuff. There's no conversion of spsce into
time or anything like that to be considered. I assume the GR black hole
interior solutions are irrelevant because according to this hypothesis
GR must break down completely around the Schwarzschield radius.
If you don't like the above, replace the black hole by a small neutron
star. Does that change anything? You *still* can't get light rays into
the interior, regardless of whether you describe it in Minkowski or
Schwarzschild coordinates, so why does it matter from a practical
perspective whether the coordinates correspond to the paths of light
rays?
What about replacing the neutron star by an ordinary rock? You can't
tell me we don't use such coordinates every day!
In short, I'm using radically flat coordinates, in which you can say
"one inch inside the Schwarzschild radius" just as easily and
unambiguously as you can say "one inch inside this concrete wall".
Since I'm talking about coordinates, a human invention, I'm making no
specific claims about physics, although the *usefulness* of different
coordinate concepts does obviously depend somewhat on physics.
Of course, you may argue that the coordinates are useful for discussing
wall interiors because they are a reasonable approximation to the true
geometry, but useless for black hole interiors, because the true
geometry is different. But then it is *you* who are asserting without
proof that so-far unobserved physics must correspond to your coordinate
system!
I don't doubt that they have very good reasons for doing as they do, but
the coordinates they are using are not the same as those I was talking
about.
- show quoted text -
A(nother) problem with this argument is the use of the phrase
"gravitational red shift" as if it were unique. Let's suppose we
specify a pair of observers A and B, with A close to a black hole and
B far away, and have A send out time-tagged once-per-second radio
pulses. If B receives A's once-per-second pulses at a rate of one
pulse per 2 seconds, I think you're arguing that (we should defined)
the gravitational redshift from A to B is (to be) a factor of 2.
The problem is, what if B receives each pulse more than once... and
the different arrival times are associated with different arrival rates?
For example, consider the following scenario (times in hh:mm:ss):
What would you say is the gravitational redshift from A to B?
(If this scenario seems implausible, consider that there can be
multiple propagation paths from A to B, e.g., going clockwise vs
counterclockwise around a spinning black hole. In general each path
will have its own time-delay.)
As noted by another poster earlier in this thread, to uniquely define
gravitational redshift requires specifying not a pair of *observers*,
but rather a pair of *events* AND a propagation path between them.
This means that "gravitational redshift" is NOT an attribute of a
position or event.
- show quoted text -
We use them for most engineering purposes, with accuracy tolerances which
are loose enough that we can ignore the curved-spacetime effects. But
if we want high accuracy, we can't ignore those effects, and we can't
use GE coordintes (or even *define* coordinates with the GE properties).
Let's put the extreme case. We have a big laboratory containing a black
hole. We'll pretend that the lab is big enough that we can come to some
reasonable agreement that the walls are X, Y and Z metres long. And
we'll assume a plane of simultaneity based on the inertial frame of the
lab. Now what I mean by flat coordinates is that every point in the
lab, including points inside the black hole, can be assigned a
coordinate (x,y,z,t) such that (0..x..X, 0..y..Y, 0..z..Z), and t = current
lab clock time.
Now obviously light rays won't be much use to extend such coordinates;
we certainly can't use them to probe the black hole. But I'm asserting
that we can nevertheless model the syatem in terms of such coordinates.
At a given point (x,y,z,t) inside the black hole, [[...]]
The problem is, how do we measure (operationally define) that (x,y,z,t)?
In fact, let's consider the simpler "model problem" of determining
(operationally defining) a "sample point"'s (x,y) given that z=0 and t
is known.
[This simplifies the exposition, but doesn't change the
underlying issues.]
To further simplify things, let's consider the simpler-still case where
instead of a BH in the middle of our lab, there's just a non-BH massive
object there. For example, our "lab" might be some part of solar system,
with a single massive body (the Sun) surrounded by (what we can for present
purposes approximate as) empty space.
There are plenty of ways to measure (operationally-define) our sample
point's (x,y), but your desire to not use light rays (or, I presume, other
propagating electromagnetic signals) rules out some of them.
For example:
(a) We could place meter sticks across the lab floor and throughout
the lab's volume. Since we don't want to use light rays (to sight
along the meter sticks to lay them in "straight" lines), we'll lay
the meter sticks out in a (rigid) triangular lattice, using Euclidian
geometry to figure out the (x,y) of the nearest vertex in the
lattice to the sample point. By using a finer lattice (e.g.,
use 10cm-sticks instead of meter-sticks) this approximation can
be made arbitrarily good.
But (how) do we know that it's possible to fill the lab with a
triangular lattice of meter sticks? That is, what (do we do) if
the 6 meter sticks which are supposed to meet at a lattice point,
don't meet? Which meter stick(s) do we cut short or lengthen
to make them all meet, and how do we define that lattice point's
(x,y)? Any choice we make would be arbitrary, causing this
procedure to fail as a "universal" operational definition
of GE coordinates.
(b) We could first prepare a long reel of strong cable with length
markings, then stretch two lengths of cable from the sample point
to two corresponding suspension points along the lab walls (separated
by a known distance), measure the cable lengths, and use Euclidian
geometry to figure out (x,y).
Since we don't want to sight along the cables to make sure they're
"straight", we can just stretch them tight (i.e., among all possible
cable paths, choose the one(s) with minimum length).
But what do we do if our results for (x,y) depend on which pair
of suspension points we choose? Equivalently, if we try to use 3
or more cables for redundancy, what do we do if there's no consistent
solution for (x,y)? In this case this procedure also fails as an
operational definition of GE coordinates.
(c) Same as (b), but imagine the cable ends freely *falling* from the
lab walls into the sample point. (Let's suppose we use the lab's
plane of simultaneity to make the length measurements at precisely
the same time that the cable ends cross the sample point.)
What will we do (i.e., how should we define GE coordinates) if this
method gives a different (x,y) from method (b)?
(d) We could set up a pair of theodolites along the lab walls, separated
by a known baseline ("known" in terms of the lab-wall coordinates),
measure the apparent angular position of the sample point as seen
from each theodolite, and (again) use Euclidean geometry to figure
out (x,y). But this method is ruled out -- it uses propagating
light (the theodolites are observing *light* from the sample point).
If we did try to use this method, what would we do (how would we
define the GE coordinates) if the resulting (x,y) turned out to
depend on where along the lab walls we put the pair of theodolites?
Equivalently, if we tried to use 3 or more theodolites for redundancy,
would we do if there were no consistent solution for (x,y)?
(e) We could set up two radar sets along the lab walls, put a radar
reflector at the sample point, time how long it takes for radar
echos to bounce back from the reflector to the transmitters, and
again use Euclidean geometry to figure out (x,y).
But this has the same sort of problems as (d): it uses propagating
radio signals. If we did try to use this method, what would we do
if we got differing results depending on where along the lab walls
we put the pair of theodolites? Equivalently, what would we do if
we tried to use 3 or more radar sets for redundancy, and failed to
find a consistent solution for (x,y)?
If our lab satisfies the axioms of Euclidean geometry, then the
"what if" situations I've outline above won't happen, all the above
procedures will give the *same* (x,y), and any of them are a reasonable
operational definition of (x,y).
But the central message of GR is that in the real world in which we
live, our lab (a.k.a. the solar system) does *not* satisfy the axioms
of Euclidean geometry, i.e., those "what if" situations *do* actually
arise in practice.
In other words, GR asserts that the meter sticks of our lattice will
*not* meet at the vertex where they were supposed to meet, that there
is *not* an (x,y) consistent with the suspension-cable lengths when
we have a redundant set of suspension points, that (a) and (b) will
in general give different (x,y), etc etc.
If we put our lab walls near the Earth's orbit, the inconsistencies
will be on the order of a centimeter near the Sun's surface. This is
small enough that for many purposes we can do as you suggested:
In other words, there's no consistent way to define your GE coordinates
close to a massive body.
In terms of the above argument, no.
In astrophysics our standards of proof often depend on inferences about
objects of which we have only limited observations. It would be really
nice to (say) be able to go look at the nucleus of M87 from the other
side, but we don't have the technology to do that (nor would the results
be available in either of our lifetimes). :(
You seem to be arguing that GR is valid outside a BH
[where we have a great deal of experimental evidence,
from things like observations of planetary and spacecraft
orbits in the solar system -- see (e.g.)
http://www.livingreviews.org/lrr-2014-4/
http://www.livingreviews.org/lrr-2010-7/
http://www.livingreviews.org/lrr-2003-1/
for some beautifully-written reviews, and section 6 of
http://www.livingreviews.org/lrr-2008-9
for some tests involving neutron stars]
but breaks down inside a BH. Perhaps the burden of proof should be on
you to propose a self-consistent theory of gravitation which agrees with
all known observations (including the presense of "things" which are very
massive, and accrete matter without showing any luminosity from that matter
hitting a surface), but which has "nicer" properties inside BHs?
ciao,
- show quoted text -
We use them for most engineering purposes, with accuracy tolerances which
are loose enough that we can ignore the curved-spacetime effects. But
if we want high accuracy, we can't ignore those effects, and we can't
use GE coordintes (or even *define* coordinates with the GE properties).
Why not? So long as the topology is the same, changing coordinates is
just changing the numbers we assign to any point in spacetime.
In fact, let's consider the simpler "model problem" of determining
(operationally defining) a "sample point"'s (x,y) given that z=0 and t
is known.
[This simplifies the exposition, but doesn't change the
underlying issues.]
To further simplify things, let's consider the simpler-still case where
instead of a BH in the middle of our lab, there's just a non-BH massive
object there. For example, our "lab" might be some part of solar system,
with a single massive body (the Sun) surrounded by (what we can for present
purposes approximate as) empty space.
There are plenty of ways to measure (operationally-define) our sample
point's (x,y), but your desire to not use light rays (or, I presume, other
propagating electromagnetic signals) rules out some of them.
There's no rule against using them - we can't do much without using the
electromagnetic force! What I cannot assume is that light rays travel
in straight lines where there is a gravitational field present - I must
take the effects of gravity into account. Once I have detected and
measured the strength and shape of the field, I can estimate its bending
and slowing effects on light, and correct my light ray measurements
accordingly. At worst I might have to do a series of iterations to
reduce the error below any desired limit. But really, there's nothing
unusual, difficult or complex about this - it is a process similar to
many that are used all the time in all areas of science.
Or if you are happy that coordinates can be measured using Schwarzschild
coordinates, you could just do that in any fashion you prefer, and
transform them to the coordinates of an observer in asymptotically flat
spacetime.
[Snip ingenious but unnecessary attempts at making measurements without
the use of light or any knowledge of the effects of gravity - the last
part being the more problematic. We are not obliged to develop a theory
of gravity simultaneously with our making of measurements!]
But the central message of GR is that in the real world in which we
live, our lab (a.k.a. the solar system) does *not* satisfy the axioms
of Euclidean geometry, i.e., those "what if" situations *do* actually
arise in practice.
In other words, GR asserts that the meter sticks of our lattice will
*not* meet at the vertex where they were supposed to meet, that there
is *not* an (x,y) consistent with the suspension-cable lengths when
we have a redundant set of suspension points, that (a) and (b) will
in general give different (x,y), etc etc.
Not a problem - it is no more difficult in principle to assume that the
meter sticks change in length etc. depending on the gravitational
potential than to assume that spacetime is curved under the same
conditions.
In astrophysics our standards of proof often depend on inferences about
objects of which we have only limited observations. It would be really
nice to (say) be able to go look at the nucleus of M87 from the other
side, but we don't have the technology to do that (nor would the results
be available in either of our lifetimes). :(
Inference is okay for GR coordinates, but not for alternatives?
We do have such a theory, which as far as I can see is *more* consistent
that GR - e.g. it doesn't have pathology such as singularities. It is
the theory of a spin-2 effective field on a flat background.
Under all but the strongest fields, its differences from GR are
negligible - it can be assumed that the energy needed to probe the
breakdown of the effective field is at least 10^30 K, and probably more.
Near to and inside the Schwarzschild radius of a black hole, the
effective field will break down, and the physics will diverge from GR.
We can assume that matter reaching this region - at least in a well
established black hole - will encounter extremely high temperatures and
will break down (adding fuel to the 'fire'). Hawking radiation is
nothing more than gravitationally redshifted thermal radiation from this
'firewall'. (That's why it drains mass from the black hole, and gets
hotter as the black hole shrinks - no questionable 'heuristics' needed
to explain it! And of course it's obvious that the information content
of infalling matter will come out eventually, instead of falling into
some mysterious singularity and *still* somehow finding a way into the
Hawking radiation...)
I should note that the last paragraph is my own interpretation of what
physicists working on this model believe - if anyone knows better I am
sure we would all love to be informed!
- show quoted text -
A(nother) problem with this argument is the use of the phrase
"gravitational red shift" as if it were unique. Let's suppose we
specify a pair of observers A and B, with A close to a black hole and
B far away, and have A send out time-tagged once-per-second radio
pulses. If B receives A's once-per-second pulses at a rate of one
pulse per 2 seconds, I think you're arguing that (we should defined)
the gravitational redshift from A to B is (to be) a factor of 2.
The problem is, what if B receives each pulse more than once... and
the different arrival times are associated with different arrival rates?
What would you say is the gravitational redshift from A to B?
(If this scenario seems implausible, consider that there can be
multiple propagation paths from A to B, e.g., going clockwise vs
counterclockwise around a spinning black hole. In general each path
will have its own time-delay.)
As noted by another poster earlier in this thread, to uniquely define
gravitational redshift requires specifying not a pair of *observers*,
but rather a pair of *events* AND a propagation path between them.
This means that "gravitational redshift" is NOT an attribute of a
position or event.
--
-- "Jonathan Thornburg [remove -animal to reply]"
You are over thinking the problem. There is a rigid rod between A
and B . The rigid rod is hollow to provide a means for a laser light
within the hollow rigid rod to communicate clock pulses. This
hopefully eliminates all possible options to avoid a conflict with
causality. I would have a marked preference for saying "assume ideal
conditions" and leave it at that. However if the ideal condition
need to be spelled out then so be it. Please do not rotate the
system leading to SR effects.
With all this in place there is gravitational time dilation , 1/2
to B. This is fine and will not violate causality when A receives
clock pulses from B at 1/2 their normal rate. However we are obligated
to add gravitational red shift time dilation according to the
equivalence principle by an imperative Doppler effect that is
inherent in the equivalence principle. If there is a rigid rod
between A and B how can a Doppler effect be accommodated without
violating causality? Gravitational time dilated B is sending 1/2
rate pulses. Once B sends 1/2 pulses how can A hear 1/3 the pulses
to accommodate gravitational red shift in addition to gravitational
time dilation. How can one hide pulses inside a rigid hollow rod
without violating causality.
The only way I see out of this is to say use gravitational time
dilation or gravitational red shift but not both. In short gravitational
time dilation and gravitational red shift are the same and therefore
should not be added together as this would be redundant leading to
a violation of causality. Somewhat like adding simultaneity of time
to length contraction in special relativity leading to a double
gamma. A mistake I have noticed more than once.
John Heath
I'll assume that you meant that the rigid rod should be "straight",
i.e., [this is my operational definition of "straight"] that with a
suitable alignment of the laser, the laser light does NOT touch the
inside walls of the rod.
My question is, why should there be only ONE such rod between A and B?
Or more precisely, what if we can place (say) TWO such rods (both rigid
and "straight" by the definition I just gave) between A and B... and
the redshift of the light arriving at B from A through rod #1 differs
from the redshift of the light arriving at B from A through rod #2.
My argument is that such a situation shows that we can't (uniquely)
define such a quantity: gravitational redshift is (in general) *not*
an attribute of a pair of observers, but rather of a pair of *events*
*and* a particular (light-) propagation path between them.
Hmm. If A is close to a spinning black hole and B is far away, it's
a bit tricky to define what you mean by "do not rotate the system".
But we can certainly say that the observer who is far from the black
hole isn't rotating with respect to a (local) inertial reference frame.
--
-- "Jonathan Thornburg [remove -animal to reply]"
The curvature of spacetime near the earth is quite small: only about a part per
million (i.e. the trajectories of the moon and other satellites deviate from
straight lines by about 1 part per million).
What do I mean by "a part per million from a straight line",
when these objects obviously follow geodesic paths? I mean
that in earth-fixed coordinates their path is a helix
with radius about a million times smaller than the length
of its period (coordinates with c=1).
Why not? So long as the topology is the same, changing coordinates is just
changing the numbers we assign to any point in spacetime.
It is in general not possible to apply your GE coordinates to a curved manifold,
regardless of topology. They can only be applied to a "small" region, where
"small" is defined by the error acceptable to your application.
For instance, in 2 dimensions, it is not possible to cover the sphere with ANY
coordinate system, much less the 2-d analog of your GE coordinates. Indeed, on
the surface of the earth, the errors inherent in using GE coordinates are
quite noticeable for regions only a few miles in size (in Chicago, wherever
surveyor's regions meet along a main street, all the cross streets are offset by
20-30 feet).
I doubt this very much. Elsewhere I have posted the algorithm for computing the
redshift of an EM signal. Given a curved metric of spacetime, it is
straightforward (albeit tedious) to do the calculation. I doubt you could do it
at all by assuming that rulers change length and clocks change tick rates.
In particular, how could you ever determine or verify that
spacetime is flat (as you assume), when rulers and clocks
cannot be trusted?
Indeed, if I construct a 3-d latticework of 1-meter rods,
and they don't meet up at the corners, it seems simplest
to take this as an indication that space is curved, not
that rods constructed to be 1 meter long are not.
It seems to me that you are taking an "armchair" attitude here, and have never
actually tried to apply your GE coordinates and varying rulers and clocks to the
Schwarzschild manifold of GR. I think that if you try, you will find it MUCH
more difficult than you imagine -- Chicago streets seem to me to be a strong
indication of that: imagine trying to survey what was back then a trackless
wilderness, using rulers that vary in length....
Singularities are not really "pathological". They merely represent places where
the theory breaks down (does not apply). EVERY theory has limits to its domain;
GR is one of the few that can compute at least some of those limitations (most
theories are mute on the subject of where/when they don't apply; usually one
must go outside the theory to determine this).
For instance, in 3-d Euclidean space we don't reject cylindrical and spherical
coordinates merely because they have singularities -- rather, we simply don't
apply them there. Ditto for the curvature singularities of GR.
Tom Roberts
Imagine flat creatures living on the surface of a sphere, unaware of a
third dimension. They might hypothesise that their space is curved. Or
they might hypothesise that it is embedded in a higher dimensional
space, and some force causes their meter sticks to bend to conform to a
sphere. If they believed in the latter, they could still define a two
parameter coordinate system (e.g. latitude and longitude), and there is
no reason why they could not convert such coordinates to 3D coordinates,
make calculations, convert them back again, and build roads with perfect
accuracy.
Or they might use the same coordinates as their friends who believe in
curved space when it is convenient, but point out that their system is
just as accurate in principle, and that the inconvenience of using it is
not a relevant argument when it comes to debating what underlies the
physics of their world.
I doubt this very much. Elsewhere I have posted the algorithm for computing the
redshift of an EM signal. Given a curved metric of spacetime, it is
straightforward (albeit tedious) to do the calculation. I doubt you could do it
at all by assuming that rulers change length and clocks change tick rates.
In particular, how could you ever determine or verify that
spacetime is flat (as you assume), when rulers and clocks
cannot be trusted?
Indeed, if I construct a 3-d latticework of 1-meter rods,
and they don't meet up at the corners, it seems simplest
to take this as an indication that space is curved, not
that rods constructed to be 1 meter long are not.
It seems to me that you are taking an "armchair" attitude here, and have never
actually tried to apply your GE coordinates and varying rulers and clocks to the
Schwarzschild manifold of GR. I think that if you try, you will find it MUCH
more difficult than you imagine -- Chicago streets seem to me to be a strong
indication of that: imagine trying to survey what was back then a trackless
wilderness, using rulers that vary in length....
An armchair attitude is appropriate, given that we are discussing
theory, not the taking of measurements. The curved space enthusiasts on
my planet of flat creatures could make the same arguments that you have
made. And yet, if they live in our universe, those arguments are wrong.
There really IS a force bending their meter sticks. (Or if it is
geometry, it is at least geometry at one remove - the geometry of
general relativity as it applies to our world is not relevant to their
current scientific concerns.)
As for verification that spacetime is flat, the only sure way I know at
present is to jump into a very large black hole, and find out whether
you get incinerated near the Schwarzschild radius, or progress further
only to be spaghettified at some point inside. Failing that, we can only
argue on the basis of what is consistent, including what is consistent
with the rest of physics such as quantum theory and thermodynamics. In
my view, the geometric theory of gravity cannot easily be made
consistent with these.
Singularities are not really "pathological". They merely represent places where
the theory breaks down (does not apply). EVERY theory has limits to its domain;
GR is one of the few that can compute at least some of those limitations (most
theories are mute on the subject of where/when they don't apply; usually one
must go outside the theory to determine this).
For instance, in 3-d Euclidean space we don't reject cylindrical and spherical
coordinates merely because they have singularities -- rather, we simply don't
apply them there. Ditto for the curvature singularities of GR.
I don't disagree that singularities are not necessarily more than an
indication of where a theory breaks down. However I strongly disagree
with the second part. It seems to me that GR is actually a theory which
has allowed singularities to be wished away. I believe the
Schwarzschild singularity is actually the breakdown point of GR - and if
we accept this, we do not have any particularly fundamental problems
about black holes in terms of thermodynamics etc. But the geometric
theory has allowed the Schwarzschild singularity to be defined away as a
coordinate singularity, and solutions continued inward from it. The end
result, though, is an intractable central singularity that makes no
sense whatsoever in terms of thermodynamics, or physics in general.
This should be taken as a sign that the interpretation of the
Schwarzschild singularity as a coordinate singularity is incorrect, and
that conditions there are such that the symmetries of GR, which allow
the extension to interior solutions, no longer apply.
"But how can that be", you ask? "GR predicts that conditions at the
Schwarzschild radius of a large black hole are nothing special. So
obviously GR cannot break down there. Your alternative hypotheses are
unimaginable!"
And therein lies the problem. Internal consistency is not truth, and
powerful theories of symmetry cannot imagine their symmetries broken.
I think "going outside the theory" is something that proponents of the
geometric view of gravity should practice more!
- show quoted text -
John Heath
I'll assume that you meant that the rigid rod should be "straight",
i.e., [this is my operational definition of "straight"] that with a
suitable alignment of the laser, the laser light does NOT touch the
inside walls of the rod.
My question is, why should there be only ONE such rod between A and B?
Or more precisely, what if we can place (say) TWO such rods (both rigid
and "straight" by the definition I just gave) between A and B... and
the redshift of the light arriving at B from A through rod #1 differs
from the redshift of the light arriving at B from A through rod #2.
[For example, the two rods might pass on either side
of a massive body (say a star, galaxy, or black hole)
which is acting as a gravitational lens. And that
massive body might be spinning.]
How then should we define "the gravitational redshift from A to B"?
My argument is that such a situation shows that we can't (uniquely)
define such a quantity: gravitational redshift is (in general) *not*
an attribute of a pair of observers, but rather of a pair of *events*
*and* a particular (light-) propagation path between them.
Please do not rotate the
system leading to SR effects.
Hmm. If A is close to a spinning black hole and B is far away, it's
a bit tricky to define what you mean by "do not rotate the system".
But we can certainly say that the observer who is far from the black
hole isn't rotating with respect to a (local) inertial reference frame.
--
-- "Jonathan Thornburg [remove -animal to reply]"
Dr Thornburg please allow my words to trap you in a corner. If you
resist a delicate point of a possible violation to causality when
adding gravitational red shift to gravitational time dilation could
be lost. You need to be trapped in the same corner as I am to stand
in my shoes to see a possible violation to causality. With this in
mind allow my words to trap in a corner willingly without resistance.
A is time dilated sending 10 pulses per second. B receives 9 pulses
per second as B is not time dilated. We are fine as causality is
not violated as gravitational time dilation justifies this. However
when we are required to add gravitational red shift to gravitational
time dilation a problem pops up with causality. B must now hear 8
pulses per second not 9. Where can 1 pulse per second be hiding if
the distance between A and B is fixed. A is sending 10 pulses per
second , 9 pulses per second according to Bs clock , but B is hearing
8 pulses per when grt5avitational red shift is added to gravitational
time dilation. How can this happen without violating causality?
Why do you think anything breaks down if particles
simply keep following a nice continuous trajectory
when thy cross the Schwarzschild radius? (And waves
likewise.) There is nothing special happening to
anything at that radius (nor at a 10% smaller radius).
Do you have anything to offer as an indication of
"break down" except for the accidental choice of
some coordinate function?
And why *would* we have such problems if we define
the "breakdown" at a 10% smaller radius? So again,
what do you have to offer as special behavior of
physics near the Schwarzschild radius?
But the coordinate theory *also* allows you to take
slightly (or radically) different coordinates for
which the coordinate functions are defined further
inwards. It is exactly a shortcoming of your cherished
coordinates that they break down at all kind of
arbitrary points where nothing strange happens to
the laws of physics at all.
And whether you "believe" that GR breaks down is
uninteresting if you fail to mention any indication
that the laws of physics change at that point (i.e.
they should start to differ from GR).
...
So then why don't you call a spade a spade and say
that *there* is the point where GR breaks down? And
if you don't want to, why do you bring up this fact?
It actually weakens your case! Your post tells us that:
1) Inside the Schwarzschild radius GR is still consistent.
2) Things become intractable at a central singularity
3) But according to you GR breaks down not at 2) but at 1)
You are not just forgetting to give arguments for your
claim, it seems more like you give counter-arguments!
--
Jos
Why do you think anything breaks down if particles
simply keep following a nice continuous trajectory
when thy cross the Schwarzschild radius? (And waves
likewise.) There is nothing special happening to
anything at that radius (nor at a 10% smaller radius).
Do you have anything to offer as an indication of
"break down" except for the accidental choice of
some coordinate function?
Obviously I don't believe they keep following such a trajectory.
"There is nothing special happening to anything..." I believe I pointed
out the circularity of that argument in the post you are responding to.
If GR breaks down at the Schwarzschild radius, then GR's prediction that
nothing special is happening there doesn't mean very much.
The choice of coordinates is nothing to do with the breakdown, except
insofar as GR allows coordinate choices that in its own terms allow
patching of interior solutions (which in my view are spurious,
corresponding to no physical reality) to external ones.
I don't believe in any special behaviour of physics anywhere. I think
gravity can be described - like the other forces - in terms of a field
on a flat background (albeit an effective field, which cannot be
fundamental). At the Schwarzschild radius, this becomes topologically
incompatible with the geometric theory of gravity, so one of them (at
least) must be wrong.
I suppose in a sense I'm saying that both are wrong, as the effective
field must itself break down here. The effective field acts like
geometric gravity. But unlike geometric gravity, it has a way to fail
gracefully, as high-energy underlying processes become observable.
As to the actual mechanics of how such forces might become observable,
there are several angles. We can say that ordinary 'low-energy' clocks
become time dilated to the point of stopping, so only high-energy clocks
remain. We can argue that the intense gravitational time dilation means
that the absorption of Hawking radiation by distant observers
corresponds to high-energy events at the Schwarzschild radius. And we
can argue that decay processes catalysed by high-energy interactions
eventually 'start a fire' so to speak, which brings the Schwarzschild
region up to a temperature where we'd expect the breakdown of the
effective field theory anyway (the so-called 'firewall').
[--]
So then why don't you call a spade a spade and say
that *there* is the point where GR breaks down? And
if you don't want to, why do you bring up this fact?
It actually weakens your case! Your post tells us that:
1) Inside the Schwarzschild radius GR is still consistent.
2) Things become intractable at a central singularity
3) But according to you GR breaks down not at 2) but at 1)
You are not just forgetting to give arguments for your
claim, it seems more like you give counter-arguments!
You are misundertanding my argument. I am saying that the central
singularity that arises if the equations of geometric gravity are
extended into the black hole interior is a monstrosity that doesn't make
sense even as the breakdown point of a theory. What sort of new physics
can you imagine that will take the place of general relativity there?
If we did not have quantum mechanics, we might imagine that matter is
somehow crushed out of existence entirely, leaving only its
gravitational field as a kind of ghost. But if we hope to be compatible
with quantum theory, even this in untenable.
So we must have made a mistake - the breakdown point must have been
earlier. And there is only one other distinctive place where it could
be - the Schwarzschild radius, which must not have been a mere
coordinate singularity after all...
(As to whether the patching of interior to exterior solutions is really
consistent, to be honest I'm not certain that it is, but I don't think
either side would have their views affected by argument on the subject.)
- show quoted text -
..
Why do you think anything breaks down if particles
simply keep following a nice continuous trajectory
when thy cross the Schwarzschild radius? (And waves
likewise.) There is nothing special happening to
anything at that radius (nor at a 10% smaller radius).
Do you have anything to offer as an indication of
"break down" except for the accidental choice of
some coordinate function?
Obviously I don't believe they keep following such a trajectory.
Again you talk about your "belief". It is not interesting.
Your homework is:
1) Give observational proof.
2) Explain how you remove the inconsitencies.
About the second point: how can GR breakdown if there
is nothing indicating where the Schwarzschild radius
is? It cannot be the curvature of space, because at
the Schwarzschild radius of a large black hole that
is completely different from a small one. Also the
presence of other gravitating objects would create
asymmetry. You really would not *believe* that for a
black hole binary GR breaks down exactly in two
spherical regions around each of them without the
slightest influence of the other, or do you?
...
GR isn't needed for that prediction. Also without GR
(or *even more so* without GR) there is no criterion
possible that gives you the position of the Schwarzschild
radius based on the physical situation of the point where
you believe it to be. There is not a specific value of
any physical quantity that can serve to position it.
You write that you *believe* that something special is
happening at certain boundaries in space but in fact you
are fooling yourself because you evade any definition
of what those special boundaries are.
Of course not. But you also fail to give us anything
else that could have something to do with it. Therefore
there cannot be a breakdown.
Your *believe* is extremely flexible. You just argued
against "There is nothing special happening to
anything" being used by others, but now you seem to
believe exactly that yourself.
But you "don't believe in any special behaviour of physics
anywhere" so your choice will be that the field on the flat
background would be wrong and GR correct.
Why? It is on a flat background, you say! So it doesn't
have any problem.
But there are no high energy processes activated if you
approach the Schwarzschild radius. NB: there also is no
large gavitational force field if it is a large black hole
(the larger it is, the *weaker* its gravitational field
at the Schwarzschild radius.)
Yes, the mechanism is what you leave out. In everything you
wrote until now.
Those are all meaningless words, especially since you denounce
GR. Write down a well-defined theory for what you want to say
and perhaps we can discuss it further.
...
So then why don't you call a spade a spade and say
that *there* is the point where GR breaks down? And
if you don't want to, why do you bring up this fact?
It actually weakens your case! Your post tells us that:
1) Inside the Schwarzschild radius GR is still consistent.
2) Things become intractable at a central singularity
3) But according to you GR breaks down not at 2) but at 1)
You are not just forgetting to give arguments for your
claim, it seems more like you give counter-arguments!
You are misundertanding my argument. I am saying that the central
singularity that arises if the equations of geometric gravity are
extended into the black hole interior is a monstrosity that doesn't make
sense even as the breakdown point of a theory.
Here your words are *not even meaningless* I would say.
If the singularity doesn't make sense in an existing theory
then by the accepted meaning of these words this is
synonymous to the theory breaking down.
You are now descending into the rather pointless game of
stripping words of there ordinary meaning!
On the contrary, things that are classically a singular point,
could become manageable in quantum theory. Even in other
theories, there might be some region where the theory changes
gradually. This could be just outside the classical point of
singularity, but far inside the Schwarzschild radius.
So that could be just outside the classical point of singularity,
but still far inside the Schwarzschild radius.
That is not distinctive at all! You failed miserably until
now to define what distinguishes the Schwarzschild radius
from any other point in space.
--
Jos
On 1/15/2016 8:51 AM, Gerry Quinn wrote:
So that could be just outside the classical point of singularity,
but still far inside the Schwarzschild radius.
And there is only one other distinctive place where it could
be - the Schwarzschild radius,
That is not distinctive at all! You failed miserably until
now to define what distinguishes the Schwarzschild radius
from any other point in space.
--
Jos
Work by Samir Mathur and others suggest that the Schwarzschild radius
points (or just outside them) have structure:
https://www.quantamagazine.org/20150623-fuzzballs-black-hole-firewalls/
http://arxiv.org/pdf/1207.3123.pdf
Very interesting stuff.
Gary
Why do you think anything breaks down if particles
simply keep following a nice continuous trajectory
when thy cross the Schwarzschild radius? (And waves
likewise.) There is nothing special happening to
anything at that radius (nor at a 10% smaller radius).
The coordinate "r" in the Schwarzschild solution is essentially the
radial distance from the center of the (uncollapsed) spherical mass WHEN
r is sufficiently large, and "t" is the time coordinate when r is
greater than 1. But for r < 1, r becomes the time coordinate, and t
becomes one of the three spatial coordinates. So when r is 10% smaller
that 1, it is NOT a "radius", it is a time. And r = 0 is NOT the
"center" of the blackhole.
I'm one of the few people who believe that the r < 1 solution to the
quadratic equation obtained in the Schwarzschild derivation is just a
spurious mathematical result, with no physical significance in our
universe. The "center" of the blackhole is at r = 1, and there is
nothing "inside" of that ... there IS no "inside" of that.
I realize I'm a member of a tiny minority holding this view, but I'm in
very good company: some years ago (after I had arrived at my view), I
found out that Dirac had the same view. Made my day!
--
https://sites.google.com/site/cadoequation/cado-reference-frame
"Accelerated Observers in Special Relativity", PHYSICS ESSAYS,
December 1999, p629.
All you ever need to know about the twin "paradox".
You attempt to make a distinction without a difference.
"Gravitational redshift" and "gravitational time dilation" are the same
phenomenon, and nobody in their right mind would "add" them.
See my earlier post on how to compute them -- one uses exactly the same
algorithm for both, which is why I say they are the same phenomenon. You
just apply different words as labels to a single phenomenon. The
physics, of course, is completely independent of your labels.
Tom Roberts
So that could be just outside the classical point of singularity,
but still far inside the Schwarzschild radius.
And there is only one other distinctive place where it could
be - the Schwarzschild radius,
That is not distinctive at all! You failed miserably until
now to define what distinguishes the Schwarzschild radius
from any other point in space.
Work by Samir Mathur and others suggest that the Schwarzschild radius
points (or just outside them) have structure:
https://www.quantamagazine.org/20150623-fuzzballs-black-hole-firewalls/
They want the "firewall" to be located at some "horizon"
(p. 13, "Conclusions") but they write that is is: "not
determined by any local feature but by a global property."
They even admit that: (p. 14)
"..we pass through Rindler horizons all the time and do
not burn up or experience obvious new physics."
So then the burden is on the authors to show that there can
be a consistent definition of where we will, and where we
*will not* see this new physics happening.
It must in particular be applicable to combined Rindler-
Schwarzschild situations for multiple black holes and
masses with all kind of accelerations. And it must
explain *why* this should happen despite the absence
of "any local feature" (a fact that they admit.)
Their answer, "We believe that this is due to an essential
difference.." (p. 14) is not accompanied by any explanation.
It doesn't look much better than the "we believe" arguments
that people in this thread are making.
--
Jos
Why do you think anything breaks down if particles
simply keep following a nice continuous trajectory
when thy cross the Schwarzschild radius? (And waves
likewise.) There is nothing special happening to
anything at that radius (nor at a 10% smaller radius).
The coordinate "r" in the Schwarzschild solution is essentially the
radial distance from the center of the (uncollapsed) spherical mass WHEN
r is sufficiently large, and "t" is the time coordinate when r is
greater than 1. But for r < 1, r becomes the time coordinate, and t
becomes one of the three spatial coordinates.
Those are the coordinate functions used in that case.
So how does that prove that anything strange is the
matter with space? You mention only a peculiarity of
your chosen coordinates. So I could elaborate:
"There is nothing special happening to anything at
the Schwarzschild radius, nor at a 10% smaller
r in those coordinates, nor in the region going
further inwards (which is another direction than
decreasing r)."
A region "further in" should be in the direction
following the space-like coordinate that goes
further in. You can draw a curve going in space-like
direction regardless of the coordinates you have
chosen.
So where do you see anything that blocks you from
drawing the curve further inwards?
..
Why would it matter what the coordinates do? You
do not answer the question what would be preventing
us from constructing a space-like curve inwards.
--
Jos
You seem to not understand the difference between coordinates and the geometry
or physics -- neither geometry nor physics can depend on the coordinates used.
Your statements are inextricably bound to the usual Schwarzschild coordinates,
and simply do not apply to the manifold itself. The physics and geometry are in
the manifold, not the coordinates.
Technically the Schw. solution clearly has no relevance to the universe we
inhabit (the world we inhabit is nowhere close to being static and spherically
symmetric). But it is not unreasonable to expect that solution to approximate
certain regions of our universe -- indeed we observe that it does apply to our
solar system outside the solar surface. I see no reason to think this would not
apply to isolated objects smaller than their Schw. radius -- certainly GR
remains valid for such objects (within the approximation of applying GR to just
a region of the universe). Indeed there are many objects observed that are
consistent with being black holes, and for which no alternative description has
been found.
This is just not so. The manifold extends inside the horizon, and the physics
and geometry are in the manifold. Yes, the coordinates you use do not extend
inside, but that does not AND CAN NOT affect the manifold, the physics, or the
geometry.
I'll bet that was an opinion that he formed long before the complete geometry
was known.
Tom Roberts
Thank you.
On 1/12/16 1/12/16 4:56 PM, Gerry Quinn wrote:
For instance, in 2 dimensions, it is not possible to cover the sphere with ANY
coordinate system, much less the 2-d analog of your GE coordinates. Indeed, on
the surface of the earth, the errors inherent in using GE coordinates are
quite noticeable for regions only a few miles in size (in Chicago, wherever
surveyor's regions meet along a main street, all the cross streets are offset by
20-30 feet).
Those errors arise from using them incorrectly.
No. The surveyors correctly applied Euclidean geometry. The errors
arise from the MISMATCH between their assumption of Euclidean
geometry and the actual curved geometry of the surface of the earth.
Your "GE coordinates" will have the same problem.
If you don't say that, at least locally and at every point, then
you don't understand what a manifold is. A manifold is BY DEFINITION
locally equivalent to a Euclidean space. And in Euclidean space
orthogonal straight lines do form a rectangular grid.
Sure. But those coordinates are not your "GE coordinates", because
latitude and longitude do NOT yield geodesics. If they try to use
geodesics ("straight lines"), they will find inconsistencies and
problems in sufficiently large regions.
An armchair attitude is appropriate, given that we are discussing
theory, not the taking of measurements.
I meant "armchair" not in the sense of thinking mathematically, but
in the sense of NOT applying mathematics. Because you haven't tried
to apply your "GE coordinates" on Schw. spacetime. You ASSERT it
is "no more difficult in principle", but you have not actually
TRIED. I strongly suspect your assertion is false, and it would be
MUCH more difficult to use your approach.
You are mixing metaphors -- that is not at all "flat".
The issue of whether GR fails at the Schwarzschild radius of a Schw.
black hole has been resolved for many decades: GR is valid at the
horizon and inside it until the singularity at the "center" is
approached.
Whether there exist such objects in the world we inhabit is a
completely different issue. As is the issue of whether other physics
applies (e.g. some as-yet-unknown quantum theory).
Yes, consistency of GR and QM is a major current topic.
You are wrong on both points. GR is _KNOWN_ to be well behaved at
the horizon of a Schw. black hole. There is no "wishing away of
singularities, BECAUSE THERE IS NO SINGULARITY THERE.
It may be that other physics becomes important at or near the
horizon, rendering GR only an approximation, or even invalid. But
GR itself does not "breakdown" there at all.
This is not "defined away", it is rather the correction of an old
mistake. I repeat: THERE IS NO SINGULARITY THERE. It's just that
historically people made a poor choice of coordinates that made
them THINK there was a singularity there, WHEN THERE WASN'T.
Hmmmm. Other theories of physics may indeed need to be modified to
be consistent with GR, or GR may need to be modified to be consistent
with them. At present, nobody has done so. This is a major area of
research.
I see no reason to expect that.
Remember that "all physics is local" [Einstein and others]. Locally,
the horizon is no different from any other point in the manifold.
There is no possible local experiment or measurement that can
identify the horizon.
And therein lies the problem. Internal consistency is not truth, and
powerful theories of symmetry cannot imagine their symmetries broken.
I think "going outside the theory" is something that proponents of the
geometric view of gravity should practice more!
I think you greatly overstate the case. I think not enough is known
about how GR relates to other theories of physics, and until more
is known about that this will have to remain unresolved.
Tom Roberts
I realize I'm a member of a tiny minority holding this view, but I'm in
very good company: some years ago (after I had arrived at my view), I
found out that Dirac had the same view. Made my day!
I'll bet that was an opinion that he formed long before the complete geometry
was known.
I THINK the paper in which Dirac stated those conclusions was published
around 1965 or so. And as I recall, it was the moderator of the
sci.physics.foundations newsgroup who told me about Dirac's conclusions
(after I had expressed my conclusions on that newsgroup, and
acknowledged that I knew I was in a tiny minority with that opinion),
and he gave me an on-line link to that paper. I've got that link (and
perhaps a printout of the paper) around here somewhere, but I don't know
where ... it's probably been about 10 years since I found out about it.
- show quoted text -
Hi Nicolaas!
Einstein's two postulates aren't enough on their own to uniquely define
the physics of special relativity. We also seem to need a third,
"geometrical", postulate, the assumption that spacetime is and remains
"flat" and that the presence or introduction of stationary or moving
matter doesn't affect the propagation of light, or the resulting
lightbeam geometry.
The physics of how relatively-moving bodies interact in real life is
//never// conducted in totally empty space (because the space under
consideration has to contain the bodies!), so our third postulate should
probably be that the "mathematical" lightbeam geometry derived by SR for
empty space is still correct in the presence of physically-real moving
masses and observers.
If we don't apply this third postulate, we can imagine a different
physics that still obeys the principle of relativity and the law of
local lightspeed constancy, without being the 1905 theory.
For instance, we could take Fresnel's early C19th idea of local
light-dragging as the basis of a relativistic dragged-light model,
eliminate the "aether" terminology and restate it as a geometrical
theory where the dragging is a gravitoelectromagnetic effect, use GEM to
regulate local lightspeeds and use W.K. Clifford's late C19th concept of
"all physics as curvature" to reject the idea of moving-body physics
having a valid flat-spacetime solution. We'd then have a different
theory of relativity that'd seem to agree with the physical evidence
available in 1905, but which wouldn't be Einstein's special theory.
Physicists in 1905 may have believed that two postulates were sufficient
to make SR inevitable, but we now have a broader and more sophisticated
conceptual vocabulary, which opens up other possibilities. This means
that defining SR's position within "theory-space" and distinguishing it
from its neighbours requires more parameters.
Eric Baird
https://www.researchgate.net/profile/Eric_Baird
Tom Roberts
5 Mar
On 2/28/16 2/28/16 2:39 AM, erkd...@gmail.com wrote:
Much of this is subsumed in the definition of "inertial frame", which Einstein
phrased in 1905 as "a system of coordinates in which the equations of Newtonian
mechanics hold good". A modern definition is more complicated, but is absolutely
required to derive the equations of SR.
One also needs the "hidden postulates" Einstein described in a 1907 paper: a)
clocks and rulers have no memory, b) space is homogeneous and isotropic, and c)
time is homogeneous. Plus one he didn't mention: d) light follows a null
geodesic in the spacetime geometry. Note (b) and (c) are part of the definition
of inertial frames, and (d) can be derived from that and the second postulate.
Note also that it is the instantaneous tick rate of a clock
that has no memory, not the counter or indicated time (which
is clearly a type of memory).
Physics is never exact. All that is required is that other effects are small
enough to be neglected. Here on earth that is so (see below).
But the key theoretical characteristic of SR is Lorentz invariance; local
lightspeed constancy is required for that, but is itself not very important,
theoretically. Without your "third postulate" (or equivalent) you don't have
Lorentz invariance, and arrive at an essentially useless theory (examples of
other useless theories below).
I don't think that any of this leads anywhere useful, for the simple reason that
here on earth spacetime curvature is quite small (on the order of 1
part-per-million). Of course some experiments are sensitive enough to detect
that, but the great majority are not.
This is easy to compute: in coordinates fixed to the earth,
the moon follows a helical path with radius 1.3 light-sec
and period 27.3 light-days. That helix differs from a
straight line by about 0.5 ppm. Somewhat larger values
apply to falling rocks near the surface.
Hmmmm. I don't think those "neighbors" are useful at all.
You did not mention the infinite set of aether theories which are experimentally
indistinguishable from SR. These are theories in which the round-trip vacuum
speed of light is isotropically c in every inertial frame, but the one-say speed
of light differs from c; how it differs distinguishes these theories from one
another. This set includes Lorentz Ether Theory (LET), the Tangherlini
transforms, and an infinite number of even less well known theories. Except for
SR, none of them are useful theoretically, as they do not obey Lorentz invariance.
These are discussed by Zhang, were he calls them "Edwards frames".
Zhang, _Special_Relativity_and_its_Experimental_Foundations_.
Tom Roberts
Much of this is subsumed in the definition of "inertial frame", which
Einstein phrased in 1905 as "a system of coordinates in which the
equations of Newtonian mechanics hold good". A modern definition is more
complicated, but is absolutely required to derive the equations of SR.
Yes, the two standard postulates, plus the concept of the
"inertial frame" gives special relativity. The "frame"
approach assumes that the global lightspeed across a region
is the same as the local lightspeed measured anywhere
within it, providing SR's required third postulate of flat
spacetime.
If we don't make this additional assumption, then there
is at least one other way of implementing the principle
of relativity for inertial physics. Globally flat geometry
plus the principle of relativity gives SR, but a
//locally//-constant c pus the principle of relativity
seems to lead //either// to special relativity or to a
relativistic acoustic metric.
Note also that it is the instantaneous tick rate of a clock
that has no memory, not the counter or indicated time (which
is clearly a type of memory).
The physics of how relatively-moving bodies interact in real life is
//never// conducted in totally empty space (because the space under
consideration has to contain the bodies!), so our third postulate should
probably be that the "mathematical" lightbeam geometry derived by SR for
empty space is still correct in the presence of physically-real moving
masses and observers.
Physics is never exact. All that is required is that other effects are small
enough to be neglected. Here on earth that is so (see below).
Mmm ... according to Einstein's description of the effects
that appear under GR, rotational motion and forcibly
accelerated motion both create significant deviations from
flat spacetime. The calculated magnitude of those effects
for circling bodies was the same as the magnitude of SR
effects, leading to the assumption that we could describe
the time dilation of a circling clock either as an SR time-
dilation effect due to speed, or as a gravitational time-
dilation effect due to the apparent radial ("Machian")
gravitational field due to rotation. It was assumed that
if a central observer didn't rotate with the centrifuge
then they could blame the effect on relative motion and SR,
but if they rotated with the centrifuge, so that there was
no relative motion between the two, they could explain
exactly the same result by blaming spacetime curvature.
In 1960, those two arguments were found to be in apparent
conflict, because if we allowed the gravitational calculation,
the associated intrinsic curvature would be present for both
the rotating and the non-rotating observers. This suggested
that the gravitational interpretation had priority and that
the SR interpretation wasn't fundamental, but was providing a
sort of rough "flat approximation" of effects that were
intrinsically curved-spacetime phenomena.
In late 1960 the community apparently decided that losing SR
wasn't acceptable, and standardised on the "SR" explanation
rather than the "curvature-based" one.
If we'd taken the other path and given the GPoR priority
over SR, then we'd have lost special relativity and would
have had to implement a curved-spacetime replacement, with
curvature effects being fundamental not only to relative
acceleration and relative rotation, but also to relative
velocity.
Nowadays (post-1960), we "know" that gravitational/
distortional effects don't play a part in everyday physics
because we "know" that SR is correct and that the GPoR
isn't to be taken too seriously. Where the GPoR and SR
generate similar predictions for an effect, we say that
the SR version is correct and the GPoR version is wrong,
and that the success of the SR explanation means that
there's nothing left for the GPoR to explain, and
therefore no measurable effect due to acceleration
(see: "SR clock hypothesis").
But this "knowledge" is based on interpretation rather
than raw phenomenology. We believe it because we grew up
in a society where SR was the norm.
If in 1960 the community had decided to take the other
"fork in the road" and had decided to support the GPoR
rather than SR, we'd now be saying with similar certainty
that that we "know" that distortional effects are strong
in rotation and and acceleration, that we "know" that
particle lifetimes in accelerator storage rings support
the GPoR rather than SR, and that we "know" that SR isn't
correct core theory.
Until we have better reasons for selecting one or other of
these two interpretations, I don't think that we can safely
say that we "know" that curvature effects are vanishingly
weak and too small to worry about in Earth-based physics.
I think that people are certainly entitled to argue in favour
of that position, but I don't think that the issue has yet
been settled.
But the key theoretical characteristic of SR is Lorentz invariance; local
lightspeed constancy is required for that, but is itself not very important,
theoretically. Without your "third postulate" (or equivalent) you don't have
Lorentz invariance, and arrive at an essentially useless theory ...
IMO, The current concept of Lorentz invariance hasn't yet
been shown to be essential to relativity theory.
The principle of relativity seems to require that there
be a "Lorentzlike" factor involved, expressable as the ratio
[1 - vv/cc]^x, where the exponent has a value in the range
0.5 to 1 ... but it doesn't tell us what that exponent's value
ought to be.
* If we assume that the existence and motion of particles has
zero effect on the lightbeam geometry of a region, we can set
x=0.5 and get the unique flat-spacetime solution of special
relativity.
* If we assume that the recoverable kinetic energy of a system
is expressed as a physical spacetime distortion between moving
bodies, then we need a value of x that's greater than 0.5, but
no greater than 1.
* If we require the theory to also produce the classical
counterpart of Hawking radiation (for compatibility with QM),
we seem to require x to be equal to one.
Assuming flat spacetime gives a straightforward way of
immediately ruling out all possibilities apart from x=0.5
... which is certainly convenient ... , but that doesn't
necessarily mean that x=0.5 is the right answer.
For instance, we could take Fresnel's early C19th idea of local
light-dragging as the basis of a relativistic dragged-light model,
eliminate the "aether" terminology and restate it as a geometrical
theory where the dragging is a gravitoelectromagnetic effect, use GEM to
regulate local lightspeeds and use W.K. Clifford's late C19th concept of
"all physics as curvature" to reject the idea of moving-body physics
having a valid flat-spacetime solution. We'd then have a different
theory of relativity that'd seem to agree with the physical evidence
available in 1905, but which wouldn't be Einstein's special theory.
I don't think that any of this leads anywhere useful, for the simple
reason that here on earth spacetime curvature is quite small (on the
order of 1 part-per-million). Of course some experiments are sensitive
enough to detect that, but the great majority are not.
This is easy to compute: in coordinates fixed to the earth,
the moon follows a helical path with radius 1.3 light-sec
and period 27.3 light-days. That helix differs from a
straight line by about 0.5 ppm. Somewhat larger values
apply to falling rocks near the surface.
I think you've just produced an excellent argument for
why it can be dangerous to artificially set the strength
of "puny" effects to zero. If we tried to construct a
theory of gravity, and said that the moon's deviation
from a straight line was only about 0.5ppm, and that
the deviation was too small to be taken seriously, and
should be set to zero ... and we then based a
gravitational theory on the assumption that it //was//
zero ... we would be liable to get a very bad theory.
It's often the job of theoretical physics to fixate on
effects that are so small as to be undetectable or
nearly-undetectable, but which should (or might) exist,
and to calculate the consequences, not just of the
effects themselves, but of the design changes that we
make to theories to accommodate those imperceptibly-small
effects.
It's the job of theoretical physics to try to be ahead
of the experimental data. If we're operating in a region
where the theoretical inputs and outputs are all well
within the range that can be easily measured and
verified, then we're probably not doing theoretical
physics but engineering.
Hmmmm. I don't think those "neighbors" are useful at all.
Knowing which set of Lorentzlike equations is the correct
one impacts on some interesting issues, ranging from
horizon physics, to the problem of how to reconcile GR with
QM, to whether or not we can ever build a warp drive.
SR's "near neighbours" where the Lorentzlike difference
is small are probably not all that interesting (except
as a proofs of concept), but the solution at the farthest
end of the range from SR (x=1 rather than 0.5), with nominal
relationships that are redder and shorter than SR's by one
complete extra Lorentz factor, is IMO rather intriguing.
If future experiments turn out to confirm that this
"redder" solution is more accurate than the SR version, then
modifying GR to accept the revised equations would seem to
solve the black hole information paradox. That would be a
useful thing.
These are discussed by Zhang, were he calls them "Edwards frames".
Zhang, _Special_Relativity_and_its_Experimental_Foundations_.
You're right, I'm less interested in theories that are
completely identical to SR, or completely experimentally
indistinguishable from SR, and which don't obviously
lead to any new physics.
The switch from a flat SR approach to a relativistic
acoustic metric isn't in that category, though - it'd
seem to reinstate the GPoR as a proper principle, it'd
seem to fix most or all of the outstanding problems
with GR including the incompatibility with QM, it'd
lead to GR being extendable down to the realm of
particle physics, it'd change the way that we think
about gravitational horizons, and it'd allow
experimental verification (or disproof) using lab-scale
physics.
I had a look though as much of the relevant parts of
that Zhang book as I could using Google Books preview,
but I didn't see anything that seemed to me to be in
this league.
BTW, in the Zhang book, the term "SR test theory" seems
to be used to mean "a theory to be compared against SR",
whereas in all the papers I've seen, it usually means
"the principles and procedures of how we should go about
comparing SR against other theories".
I've always used this second definition - if you're more
familiar with the first, from Zhang's book, then some of
my older posts may seem rather confusing.
Eric
Aren't there at least three or four postulates to
begin with? Or, isn't there at least two or three
postulates entangled just in #1 above?
Something like:
0. Motion is not many-body, multiple-state or
multiple-field-field related but arises only
due to universe being composed of space
and time describable in terms as inertial frames.
2. The laws of physics take the same form in all
inertial frames (described in terms of increments,
and increments orf increments of the assumed
space and time).
3. In any given inertial system the velocity of light c
is the same whether the light be emitted by a body
at rest or by a body in uniform motion.
Ralph
Eric,
In order to unravel what you mean with GPoR (General Principle of
Relativity) I found this link (Search "Eric Baird GPoR")
Op dinsdag 10 mei 2016 12:07:07 UTC+2 schreef Eric Baird:
Yes, the two standard postulates, plus the concept of the
"inertial frame" gives special relativity. The "frame"
approach assumes that the global lightspeed across a region
is the same as the local lightspeed measured anywhere
within it, providing SR's required third postulate of flat
spacetime.
What is the purpose of Science?
IMO (very rough definition):
Based on the present (a small period) to predict the future
and the past. That means what will happen in the future
and what has happened in the past.
What is the purpose of the medical Science?
The same. The subjects are humans, but is only relevant for
a small period in total. The internal structure is considered.
What is the purpose of Newton's Law?
The same but for single objects. The time frame is long.
The internal structure of the objects is "not" considered.
What is the purpose of GR GPoR?
The same as Newton's Law but more accurate.
What is the purpose of SR?
IMO: ?
This reply seems negative, but I think that is the question
you try to answer.
This text raises the following question:
How important are observers related to the study of science?
IMO generally speaking zero. For medicine this is 100%.
The laws of "nature" are independent of humans.
What is important are the concepts of speed and acceleration.
What is also important that you first start from a fixed
reference coordination system. When that leads to contradiction
you can try something else.
When you start from a fixed frame all observers fixed to the frame
are the same and there are no moving clocks involved.
It is like placing the Sun in the center of the solar system
and not the earth.
This swings the pendulum into the SR camp.
Again this raises the question:
What is the practical importance of SR?
Which particular physical processes do you have in mind?
IMO accelerations are always involved in any physical process.
I do not agree with this.
My "background" is more that SR is "simple" and GR is "complex"
IMO the limited implication of SR is much more that it "only"
handles physical concepts like v/c along straight lines.
To calculate the particle lifetimes of different reactions
(after the collisions?) in LHC, using GR, I expect is extremely
difficult. Can you give me a glue how this is done?
snip
New physics is a misnomer. The point is how accurate can
you do science using an existing theory. If "your" predictions
don't match observations and a different theory is more
accurate than either "you" have to modify "your" theory
or switch to the other camp.
An interesting document to read is this:
http://arxiv.org/pdf/physics/0207109.pdf?origin=publication_detail
It gives an idea how difficult SR is.
[[Mod. note --
The official arxiv url for this (excellent) paper is
http://arxiv.org/abs/physics/0207109
-- jt]]
Nicolaas Vroom
Why is that? If SR worked as well as the other approach
you simply would have had the luxury to keep both of them!
Why the latter? Constant velocity can never transform
flat coordinates to a non-flat situation. So you would
not have had to implement that (nor even have been able
to do so, in fact).
--
Jos
Dne 16/05/2016 v 05:02 Nicolaas Vroom napsal(a):
This text raises the following question:
How important are observers related to the study of science?
IMO generally speaking zero. For medicine this is 100%.
The laws of "nature" are independent of humans.
What is important are the concepts of speed and acceleration.
What is also important that you first start from a fixed
reference coordination system. When that leads to contradiction
you can try something else.
When you start from a fixed frame all observers fixed to the frame
are the same and there are no moving clocks involved.
It is like placing the Sun in the center of the solar system
and not the earth.
As experimental information and feedback in science
is get from ( generalized ) observers,
the statement their importance is zero is ....
... interesting.
The consequence would be physics can be reduced
to the theoretical physics and no examination is needed.
--
Poutnik ( The Pilgrim, Der Wanderer )
Knowledge makes great men humble, but small men arrogant.
Yes, the two standard postulates, plus the concept of the
"inertial frame" gives special relativity. The "frame"
approach assumes that the global lightspeed across a region
is the same as the local lightspeed measured anywhere
within it, providing SR's required third postulate of flat
spacetime.
Again I would like to comment on this text but in a more general(?) way.
Consider the following experiment.
At point A you have a lightsource and a photon detector.
At point B a distance x away, there is a mirror.
With the lightsource you emit a flash at A which is reflected with the
mirror at B and detected with the photon detector at A.
All this sounds reasonable.
Next you place a second mirror at C. The distance A-B = B-C = x
You also place a mirror at A.
At A in stead of one flash you simultaneous emit two flashes.
The first flash goes from A to B back to A (reflection) to B and back to A.
The second flash goes from A to C (reflection) and back to A.
Question: Are the two flashes finally arriving at A simultaneous?
IMO because the distance is identical 4*(A-B) = 2*(A-C) they will arrive
simultaneous.
But there is more: you can move this setup in any direction horizontal
and the answer will be the same.
Ofcourse such an experiment in reality is extremely difficult
and the accuracy not very reliable.
Next we perform the same experiment but now in vertical direction.
Point A is at the top and point C at the bottom.
There are two possible outcomes in principle:
When the result is (1) the speed of light is constant and you can
describe the experiment using SR.
Any comments?
Nicolaas Vroom
Dne 20/05/2016 v 04:43 Poutnik napsal(a):
As experimental information and feedback in science
is get from ( generalized ) observers,
the statement their importance is zero is ....
Question: Are the two flashes finally arriving at A simultaneous?
Your description is incomplete, as you did not specify the distance A to C.
If I suppose that the distance A-C is twice A-B, then your description
is still incomplete; if I further suppose that all components are at
rest in an inertial frame in a region in which gravitation is
negligible, then the two flashes arrive at A simultaneously. [These
further suppositions permit me to apply SR in a simple and obvious
manner.]
Your description did not say this, but it is my first supposition in the
second paragraph above. Apparently you are assuming (but did not say)
that A, B, and C are lined up along a straight line, with B midway
between A and C. How the two flashes are kept separate and follow their
specified paths is not mentioned, but this is a detail we can ignore.
Perhaps. If the further suppositions above are valid this is true for
any meaning of "horizontal", but if they do not hold this might not,
either.
Let's keep this a gedanken.
If the further suppositions above are valid, then "vertical" has no real
meaning and is the same as "horizontal".
So I assume this means you don't want to make my further suppositions
above, and want to consider gravity to be important. This opens a very
large can of worms as one must apply GR.... As a simple example, there
is now no definite meaning to "distance A-B", and you must specify how
it is to be measured (i.e. along which spacelike geodesic; this is
directly related to choosing a time coordinate...). Remember that above
I had to suppose all components were at rest in some inertial frame,
which resolves this ambiguity for SR, but not for GR with non-negligible
gravity.
To proceed, let me make these further assumptions (which I suspect are
what you have in mind); remember this is a gedanken:
Explanation of this last: if two points have identical
altitudes, the (constant-time) spacelike geodesic along
which the distance between them is measured does not have
that altitude everywhere between them, and there is no
such thing as a "horizontal plane"; this assumption makes
the effect of that be negligible within the apparatus
and permits me to use a horizontal plane there.
[These deal with the major worms; I'll ignore any others.]
First let me consider a simpler physical situation: A still has a pulsed
light source and detector; there are mirrors at D and E which are always
a distance x from A, but their positions (orientations wrt A) can vary;
A can always send a pulse to both D and E and detect the two reflected
pulses (i.e. the mirrors are always adjusted to make this so, as is the
detector orientation).
If A, D, and E are all in a horizontal plane, then the pulses arrive at
A simultaneously. If they are not in a horizontal plane, then the pulses
in general do NOT arrive simultaneously at A (for certain specific
situations they can, such as D-A-E forming a vertical "V").
Consider A-D horizontal, and A-E vertical, with E above A. Remember the
distance A-D = A-E, and both distances are measured simultaneously in
the above coordinates. The pulse A->E->A will arrive before the pulse
A->D->A. If E is vertically below A, then A->E->A will arrive after
A->D->A.
For your physical situation with A, B, and C along a straight line with
B midway between A and C, and the light traverses A-B four times and A-C
twice: if the line is horizontal the pulses arrive simultaneously; if
A-C is vertically upward, A->C->A arrives before A->B->A->B->A; if A-C
is vertically downward, A->C->A arrives after A->B->A->B->A.
Note all these non-simultaneous arrivals come far too close together to
actually measure in a real experiment with x less than a km or so. So
this must remain a gedanken unless possibly an interferometer setup can
be invented; the basic problem is comparing horizontal and vertical
distances to the required accuracy without using light (use light and
the result is fore-ordained).
Not necessarily (see below).
If gravitation is not negligible, you cannot use SR and must use GR.
Even if you happen to luck out and the flashes arrive simultaneously.
Tom Roberts
I have to apoligize. I should have drawn a sketch
' E0------------->
' <--------------- From A to B to A to B
' --------------->
' E1<-------------
' E0---------------------------->
' E2<---------------------------- from A to C to A
Question: Are the two flashes finally arriving at A simultaneous?
Your description is incomplete, as you did not specify the distance A to C.
All is in horizontal plane on surface of the earth
I agree with you in the horizontal setup
IMO because the distance is identical 4*(A-B) = 2*(A-C) they will
arrive simultaneous.
Your description did not say this, but it is my first supposition in the
second paragraph above. Apparently you are assuming (but did not say)
that A, B, and C are lined up along a straight line, with B midway
between A and C. How the two flashes are kept separate and follow their
specified paths is not mentioned, but this is a detail we can ignore.
I agree.
Perhaps. If the further suppositions above are valid this is true for
any meaning of "horizontal", but if they do not hold this might not,
either.
I agree
If the further suppositions above are valid, then "vertical" has no real
meaning and is the same as "horizontal".
No that's not I have in mind.
The idea is that the whole set up is in a vertical direction
and that the light signal first travels towards the center of the earth.
To proceed, let me make these further assumptions (which I suspect are
what you have in mind); remember this is a gedanken:
Sorry SNIP
I like all the technical subtleties you bring into this discussion
but I do not know if they are necessary.
First let me consider a simpler physical situation: A still has a pulsed
light source and detector; there are mirrors at D and E which are always
a distance x from A, but their positions (orientations wrt A) can vary;
A can always send a pulse to both D and E and detect the two reflected
pulses (i.e. the mirrors are always adjusted to make this so, as is the
detector orientation).
If A, D, and E are all in a horizontal plane, then the pulses arrive at
A simultaneously.
Consider A-D horizontal, and A-E vertical, with E above A. Remember the
distance A-D = A-E, and both distances are measured simultaneously in
the above coordinates.
In this case gravity has to be considered. Tricky
IMO this example is much more complex than I have in mind.
The issue is that when you perform such an experiment gravity is involved
and SR is not sufficient.
I fully agree with you. Such an experiment is in practice very difficult
to perform.
The whole issue is that, no clock is involved.
However that is not totally true. The signal ABABA services as a clock
for the signal ACA.
Not necessarily (see below).
When the result is (2) the speed of light is not constant and you must
describe the experiment using GR.
If gravitation is not negligible, you cannot use SR and must use GR.
Even if you happen to luck out and the flashes arrive simultaneously.
Exactly. You have to use GR for the vertical set up.
That is what I have in mind to challenge that the speed of light is constant.
However there is more it places the importance of GR above SR.
And you can ask yourself the question how important is the third postulate
proposed by Eric Baird.
Nicolaas Vroom
All is in horizontal plane on surface of the earth
And we agree that light A->B->A->B->A arrives at A simultaneously with light
A->C->A. (Distance A-B = distance B-C.)
Not terribly tricky.
The trick is keeping FIRMLY IN MIND what one means by "speed". Remember that in
GR the LOCAL speed of light in vacuum is always c when measured in a locally
inertial frame. Remember also that the size of such a locally inertial frame
depends on the measurement accuracy with which one can make the relevant
measurements.
From that we can immediately conclude if the distance A-C is "small" enough, and
if the apparatus is in freefall, the two light pulses above will arrive
simultaneously at A, regardless of the orientation of the apparatus. (This
basically means that the measurement resolution is insufficient to observe the
difference in their arrival times.)
But you want to keep the apparatus at rest on earth's surface, and you want to
use essentially infinite accuracy. So the apparatus is not at rest in a locally
inertial frame. All is not lost, and we can make some conclusions (see below).
The issue is that when you perform such an experiment gravity is involved
and SR is not sufficient.
Yes. But very general things are known about GR. For this conclusion I simply
applied the analysis of the Shapiro time delay -- B-C is below A-B, and thus
from the perspective of an observer at A, light traversing B-C is delayed more
than light traversing A-B. Hence I can make this conclusion without performing a
detailed calculation.
But I would NOT claim "light travels slower B-C than A-B". That would be a PUN
on "speed", because we normally reserve that word for measurements in locally
inertial frames. And also because we did not measure it.
Interesting observation: as in QM, in GR it is usually not possible to discuss
quantities which were not measured. Here the delays of pulses are measured
(compared) and I can make definitive statements about them; but their speed is
NOT measured, and I cannot make definite statements. It is remarkable that the
two major revolutions in physics of the 20th century, quantum mechanics and
relativity, share this emphasis on measurements. But the reasons for this
similarity are QUITE different: in QM it is because such quantities have no
definite value, while in GR it happens because such statements invariably
involve a choice of coordinates, and such choices are arbitrary
(coordinate-dependent quantities need not reflect the underlying physical
processes as they also involve aspects of the coordinate choice).
Why are measurements so "special" in GR? -- because they are
necessarily independent of coordinates. That is, every
measurement projects the quantity being measured onto the
measuring instrument. As you were taught in kindergarten, the
ruler must be aligned with the object to measure its length
(the ruler projects onto itself, and if not aligned the
projection will not be the desired result); this is inherently
a very general aspect of measuring instruments.
Hmmmm. As I said above: keep FIRMLY IN MIND what you mean by "speed". When you
try to say "the speed of light is not constant" you are using a PUN on "speed".
The vacuum speed of light measured in a locally inertial frame is c, everywhere
and everywhen. But if you choose to divide a distance by a flight time and call
the result "speed", even when the measurements are not in a locally inertial
frame, then OF COURSE you can obtain a result not equal to c. Indeed GR predicts
this (c.f the Shapiro time delay -- if you insist on calling the result "speed"
then of course it is not equal to c; that's why it is termed a DELAY and not a
"reduction in speed").
Yes, of course. The only reasons SR is still taught are a) because it is the
local limit of GR, and b) is ENORMOUSLY less difficult to apply [#].
Moreover, most ordinary measurements are made in a locally
inertial frame in which SR can be applied with negligible error.
This includes every aspect of our daily lives, every elementary-
particle experiment, and almost all optical experiments performed
on a table.
[#] Remember the details I gave earlier in this thread, for the
horizontal situation where the light path does not correspond to
a spacelike geodesic between endpoints A-C -- so what does
"distance" mean when attempting to apply the definition of speed?
No matter what you do, you will have to CHOOSE coordinates (or at
least a foliation of spacetime into space and time), and the
result will depend on your choice.
He proposed adding "flat spacetime" -- that is inherent in applying SR and
presuming it to be exact. But as the local limit of GR it can be a very useful
and accurate approximation in many physical situations of interest.
Tom Roberts
Sorry I have to skip this part.
The issue is that when you perform such an experiment gravity is
involved and SR is not sufficient.
Yes. But very general things are known about GR. For this conclusion I
simply applied the analysis of the Shapiro time delay -- B-C is below A-B,
and thus from the perspective of an observer at A, light traversing B-C
is delayed more than light traversing A-B. Hence I can make this
conclusion without performing a detailed calculation.
In order to refresh my mind about the Spapiro effect I have studied
paragraph 15.6 (page 204) from the book 1:"Introducing Einstein's
Relativity" by Ray d'Inverno and page 1106 etc of the book
2:"Gravitation."
Consider dropping a ball A from the top of a tower with height h. The
ball is reflected completely without any friction. T1 is the moment when
the ball A is back at the top Consider dropping a second ball B
simultaneous with A from the top, however this ball is reflected at
height h/2. When ball B is back at the top the ball is immediate dropped
again. T2 is the moment when ball B is back at the top for the second
time. Question is T1=T2 or T1
But that is not what I want. I'am interested in the behavior of a light
signal with goes "undisturbed" straight towards to the (center of) the
earth. For example starting half way between the Moon and the Earth.
The initial speed can be "c". The first question is will this speed
increase or decrease or decrease when the photons travel towards the
earth.
I'am not that "strict". If you compare two light signals, which both
travel over the same distance and the first arrives before the second
than the speed of the first is higher than the second without any
indication what the actual speed is.
I agree with this, but I do not think this is particular
related to GR. IMO there is a hugh difference for the laws that are
relevent at macro niveau versus micro niveau. You "can not" use GR to
predict earthquakes.
This whole discussion is very tricky. Suppose you want to simulate a
whole galaxy. To do that you have to measure the position of the stars
involved over a series of intervals. In order to do that you need one
coordinate system. When the positions are known the next step is to
calculate the masses of the stars in the galaxy, using a certain model.
However in order to measure the position of a single star light signals
are involved which have to be corrected because the signals are bended
by masses of stars inbetween this single star and the measuring
instrument. In fact you have to take the behaviour of photons (QM?) into
account if you want to do this very accurate.
For me a much more important issue is the relation of a measurement
versus a calculation. Went you want to know the order of the runners in
a maraton this is a (direct) measurement. The first one arriving runs
the fastest. When you want to know the speed of each runner this is a
calculation because it depents on two measurements.
When you study Fig 15.13 book 1 the shortest distance is called D. In
fig 40.3 book 2 this is the distance slightly larger than b. For me the
important question is the speed of light constant from transmitter to
reflector? Is the speed the highest at the shortest distance near the
Sun? To answer that question IMO you have to divide the path in for
example 10 smaller parts with the same length and investigate each. In
the experiment I propose I try to answer that same question very close
to the earth by comparing two signals without the aid of a clock and
"no" mathematics.
Thanks Tom.
Nicolaas Vroom
Is the speed the highest at the shortest distance near the
Suppose there was self aware matter that could answer these questions?
I put it to you that we are self aware matter and if it does not
seem to be logical from our shoes then all efforts should be made
to make sense of it. Myself having lucked out as being self aware
matter for a brief period of time can say the consistency of the
speed of light is only true for measurements the observer not reality
in the larger picture. Your only obligation to fulfill the postulate
of SR is to measure the speed of light to be c. This is not the
same as saying the speed of light is constant at c. If one lived
in a hot air balloon it is never a windy day and one could conclude
that the speed of sound is constant at 1000 feet per second. If we
are a product of a vacuum we would be under the same illusion that
the speed of light is constant. However a hot air balloon Einstein
would never be noted as a hero in physics as every hot air balloon
person would be is aware that temperature effects time. A hot air
person , cloud in the sky , will know intuitively to leave earlier
to arrive on time on a cold day. Temperature effects time. What
seems obvious to a cloud in the sky could lead to misunderstanding
to us as solids so we celebrate Einstein as a hero in physics. A
vacuum sets time for us in the same way the temperature effects
time for a cloud in the sky. Both the cloud gas and ourselves solids
think the speed of sound for clouds and the speed of light is
constant by measurements made in both cases. In both cases we are
wrong for the same reasons. There is no way the speed of light is
c near a black hole as this would violate the postulate the laws
physics are the same for all Frames of reference. The speed of light
only measures c for the same reason the speed of sound always measure
1000 feet per second for a hot air balloon.
Nicolaas Vroom wrote:
Is the speed the highest at the shortest distance near the
Sun? To answer that question IMO you have to divide the path in for
example 10 smaller parts with the same length and investigate each.
In the experiment I propose I try to answer that same question very
close to the earth by comparing two signals without the aid of a
clock and "no" mathematics.
Suppose there was self aware matter that could answer these questions?
I put it to you that we are self aware matter and if it does not
seem to be logical from our shoes then all efforts should be made
to make sense of it.
The concept of "self aware matter" is out side the physical reality
which makes any discussion immediate tricky.
The current topic in the discussion is the speed of light.
What I try to answer is the question: is this speed always the same
or is this speed variable. Specific I want to find out "if" and "what"
the influence of matter or gravity is. The influence of vacuum should
also be considered.
What I presently do not want to discuss is the actual (average?) value
of the speed of light.
In order to study the behaviour of photons, I propose an experiment
(using light, a tower and mirrors). See previous postings. The current
discussion is to predict the outcome of this experiment.
My understanding is that the speed will increase when the photons
approach the earth. In fact when you send a light signal from the sun
towards the earth, first the speed will decrease and than increase.
The problem with this whole discussion is that it belongs more in the
newsgroup :Sci.physics.foundations. However at this moment this is
impossible, because the newsgroup is temporary "out of order".
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
What is important as part of this discussion: what is the definition of
a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
But that does not exist in outerspace. In fact the whole universe is
filled with photons, which makes any definition based on vacuum
misleading(?)
A different reason, why the issue is important, is the program "VB
light" See: https://www.nicvroom.be/VB%20Light%20operation.htm
In this program light rays around matter are simulated, specific to
study: "The bending of light around matter". What this simulation shows
(based on Newton's Law) that the speed of light (photons) is not
constant.
Nicolaas Vroom.
If the speed of light is not constant, there would be many other worries
besides problems with the definition of the metre!
No; you can always discuss the limit of a true vacuum.
You can't expect to learn anything based on Newton's laws. We know that
they are wrong. Yes, they are good approximations in some limits, but
you have to know what those are before you can safely use Newton's laws.
The point is that any LOCAL measurement of the speed of light always
gives the same value.
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
If the speed of light is not constant, there would be many other worries
besides problems with the definition of the metre!
Very few, actually. The speed of light is both a
*concept* (let's call it c0=1 for simplicity) and a measured quantity
'c' (though via the SI the latter has to be done indirectly).
The *experimentally* established mass of the photon is smaller than
10^-18 eV [1] - everything below that is simply terra incognita. It
could be that the photon had a mass of, say 4*10^-21 eV. That would lead
to not only to a speed of light different from c0 but also a *frequency
dependent* speed of light.
Not a problem there, obviously, as this might actually be the case for
all that we know.
Now, the *concept* of a finite speed limit in the Universe is fully
independent of any actual physical realisation or, indeed, experimental
proof.
If it turned out that 'real' light is not quite the 'conceptual light'
and that the photon has a mass, very few actual things would change. So
few, that with all our rather well developed measurement devices we are
currently not able to measure the effects of a massive photon, provided
the mass is smaller than said 10^-18 eV.
[1] Interestingly enough, the mass of the graviton (or in absence of a
quantum theory of gravity, the dispersion of gravitational waves) is
known better than that - m_g < 1.2e-22 eV. Still, we call it 'speed of
light' and not 'speed of gravity', because the for the ART, it is the
*concept* that matters, not so much the actual speed.
--
Space - The final frontier
If the speed of light is not constant, there would be many other worries
besides problems with the definition of the metre!
Very few, actually. The speed of light is both a
*concept* (let's call it c0=1 for simplicity) and a measured quantity
'c' (though via the SI the latter has to be done indirectly).
What I meant was that a non-constant speed of light, finite rest mass of
the photon, etc, would imply some sort of new physics. The metre is
defined by the speed of light, and relies on the second, which is
defined in terms of a specific wavelength of light. One could specify
that the metre should also use this wavelength.
If it turned out that 'real' light is not quite the 'conceptual light'
and that the photon has a mass, very few actual things would change. So
few, that with all our rather well developed measurement devices we are
currently not able to measure the effects of a massive photon, provided
the mass is smaller than said 10^-18 eV.
Right. Practical consequences would be almost none. It would mean a
lot conceptually, though.
A Wikipedia definition is not necessarily scientifically accurate,
unless it is an exact copy or translation of a definition agreed by the
relevant international body.
Any purely LOCAL error-free measurement of the speed of light in empty
flat space nowadays will give a result of 299792458 m/s, by tautology.
Any apparent discrepancy in an error-free imperfectly local measurement
must result from the local area used being not flat. Non-empty space
cannot be flat, although non-flatness is generally only a minor
consequence of non-emptiness.
--
(c) John Stockton, Surrey, UK. ¬@merlyn.demon.co.uk Turnpike v6.05 MIME.
Merlyn Web Site < > - FAQish topics, acronyms, & links.
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance
travelled by light in vacuum in 1/299792458 of a second."
The problem with this defintion is when the speed is not constant
the length of a metre also changes.
If the speed of light is not constant, there would be many other worries
besides problems with the definition of the metre!
What is physical wrong with the idea that the speed of light (radiation)
is not always the same? (can vary). The same with any particle?
The opposite would be amazing. Why should the speed be constant
As I said before this whole discussion belongs more in the newsgroup:
sci.physics.foundations.
When consider the above definition of a metre you must also define what
a second is and such a second must also be a physical constant process.
We know by experiment that that is also difficult to establish.
A whole different physical issue the speed of gravition. It is physical
possible that this speed is much more "fixed" (stable?) than the speed
of light. In principle such a speed (if constant) is a better starting
point to define a metre. (But is has its own problems)
No; you can always discuss the limit of a true vacuum.
The point is when you use the concept "vacuum" in a defintion than the
concept vacuum should also clearly be defined. I doubt it is.
A different issue is than also always when you consider the speed of light
in any discussion it should be in a vacuum. The point is when the physical
state between the Sun and the earth is not a vacuum than you cannot use
the definition in order to measure distance. (Of course for most
applications you can)
You can't expect to learn anything based on Newton's laws. We know that
they are wrong. Yes, they are good approximations in some limits, but
you have to know what those are before you can safely use Newton's laws.
I agree quantitatif that you are right. The point I want to make is
that using Newton's Law you can see that the speed is not always the same,
which raises an issue to be discussed.
As I stated before it is primarily not my strategy to calculate the speed
of light. What I want to challenge is the idea that this speed is not
always the same. To do that I use one observer, two light sources, a tower,
and two mirrors at different heights.
The question is what is the outcome of the two experiments.
Nicolaas Vroom.
You mean, you want to consider the combined gravitational field of Sun
and Earth. The first thing you have to note then is that there is no
known exact solution of GR field equations for a gravitational field
with more than one centre of gravity. For one single centre of gravity,
there is Schwarzschild solution, but for two or more centres of gravity,
there is no exact solution known. And due to non-linearity of GR, you
cannot simply construct such as solution by combining two Schwarzschild
solutions.
However, you could argue that an eventual solution for two centres of
gravity, like Sun and Earth, should in some way look similar to a
combination of two Schwarzschild solutions, at least in that way that
one should be able to find a coordinate system in which the speed of
light, measured with respect to that coordinate systems, shows the
behaviour you described.
Assumed, in spf would someone reply to you who has good knowledge in GR,
his answer might probably be similar to the answers you got here. So, it
wouldn't make any difference.
As far as the variability of the speed of light due to gravitational
effects is concerned, the metre definition is not touched in any way: to
define the metre, one uses the speed of light measured with respect in a
local inertial frame, which is applied in a small spacetime region
limited enough to neglect gravitational effects and to apply the
SR-limit of GR.
As far as an eventual variability of the speed of light is concerned
that might occur even in a local inertial frame due to an eventual
failure of GR and SR, the "problem" you described is not different from
the "problem" any other metre definition would cause, and the definition
of the unit of any other quantity causes. As you can read here:
https://en.wikipedia.org/wiki/History_of_the_metre#International_prototype_metre
one used the international prototype metre to define the metre from 1889
until 1960. At that time, the "problem" you describe was that changes in
the length of the prototype metre resultet in changes in the length of
the metre. They were even well aware of this fact: they knew that the
length of the prototype metre had an uncertainty of about 0.1
micrometers, causing a relative uncertainty of 10^-7. But this was a
much better precision than former definition for the metre or other
length unit could achieve. And as you can read here:
https://en.wikipedia.org/wiki/History_of_the_metre#Krypton_standard
from 1960 until 1983, the metre was defined as 1650763.73 wavelengths in
vacuum of the radiation corresponding to the transition between the
levels 2p10 and 5d5 of the krypton 86 atom. This caused again a
"problem" as you describe it: changes in the wavelength of the radiation
of krypton atoms resulted in changes in the length of the metre. At that
time, it was well known that wavelength of the radiation of krypton
atoms it not constant: like any other spectal line, the spectral line of
the 2p10 to 5d5 transition of krypton 86 atoms has a non-zero line
width, making the wavelength fluctuate. This fluctuation of the
wavelength caused a relative uncertainty in the metre definition of
10^-8. But this was by one order better than the relative uncertainty
yielded by the former metre definition by the prototype metre.
So, what we can see is that the aim of unit definitions is to achieve a
precision that is as high as possible. The krypton standard yielded a
relative uncertainty of 10^-8, what is a better precision than the
relativ uncertainty of 10^-7 that was formerly achieved using the
prototype metre. And the today's metre definition:
https://en.wikipedia.org/wiki/History_of_the_metre#Speed_of_light_standard
yields an even better precision, the relative uncertainty is only 10^-10.
So, if we assumed that the speed of light might vary, even in situations
where the SR limit of GR should be applicable, because GR and SR break
down, the consequence would be, that the relative uncertainty of the
metre definition is higher that assumed so far. Assumed, it turned out
that the uncertainty exceeds 10^-8, they would skip the speed of light
standard and e.g. return to the krypton standard.
A very general procedure in physics is to use idealizations and
approximations. One could e.g. reason that in a real vacuum (as is can
be created in a laboratory), the speed of light is in good approximation
equal to the speed of light in an ideal vacuum.
This isn't in any way special to relativistic physics. Take e.g. Newton
formula F=m*a. Rigorously, this formula applies in ideal inertial frames
only. However, there are to ideal inertial frames, because there is no
observer that is ideally force-free. There are only observer who can be
thought as being force-free in good approximation.
But even that is not really necessary. One could as well argue that
there should be a speed of light, let's call it c0, that would be the
speed of light in a hypothetical perfect vacuum. Then one could
postulate that this speed c0 is always the same, in all inertial frames,
and conclude that SR effects occur at velocities near this speed. Frome
the fact that we observe SR effects near the real speed of light that we
can factually measure in a real vacuum, let's call it c', we then can
conclude that both speeds, c0 and c', are very close to each other.
It shows that in Newtonian Gravity, the speed of light is variable. Or
more precisely: in Newtonian Gravity amended by some assumptions on how
light is influenced by gravity. However, since Newtonian Gravity is
known to be wrong, except in non-relativistic regime, this result shows
little about reality. At best, is *suggests* that also in a relativistic
theory of gravity, i.e. in GR, the speed of light should be variable in
some way.
And indeed, in GR, the speed of light turns out to be variable in some
way. Namely in that way, that the speed of light measured with respect
to a general coordinate system is variable. But not the speed of light
measured with respect to a local inertial frame.
My understanding is that the speed will increase when the photons
approach the earth. In fact when you send a light signal from the sun
towards the earth, first the speed will decrease and than increase.
You mean, you want to consider the combined gravitational field of Sun
and Earth. The first thing you have to note then is that there is no
known exact solution of GR field equations for a gravitational field
with more than one centre of gravity. For one single centre of gravity,
there is Schwarzschild solution, but for two or more centres of gravity,
there is no exact solution known.
This IMO raises an issue when you want to study the merging of two
black holes using GR.
As such we both agree.
As far as the variability of the speed of light due to gravitational
effects is concerned, the metre definition is not touched in any way: to
define the metre, one uses the speed of light measured with respect in a
local inertial frame, which is applied in a small spacetime region
limited enough to neglect gravitational effects and to apply the
SR-limit of GR.
I agree with you, however this becomes an issue when light years are
considered.
Sorry, I skipped a lot of your text but it is very worthwhile reading.
I fully agree with you. The problem is more or less that in SR we start
from the idea that the speed of light is constant (and in all directions
the same) and equal to c. In reality this picture is much more complex.
It shows that in Newtonian Gravity, the speed of light is variable. Or
more precisely: in Newtonian Gravity amended by some assumptions on how
light is influenced by gravity. However, since Newtonian Gravity is
known to be wrong, except in non-relativistic regime, this result shows
little about reality. At best, is *suggests* that also in a relativistic
theory of gravity, i.e. in GR, the speed of light should be variable in
some way.
I fully agree. Specific I like the subtleties in your comments.
I doubt how important the last is. What is the point when local implies
a very small region, while in general what we want is to study the
evolution of the universe.
Nicolaas Vroom.
If the speed of light is not constant, there would be many other worries
besides problems with the definition of the metre!
What is physical wrong with the idea that the speed of light (radiation)
is not always the same? (can vary). The same with any particle?
The opposite would be amazing. Why should the speed be constant
According to all our obversations, the speed of light is constant in
situations where the SR-limit of GR is applicable, i.e. where
gravitational effects can be neglected. So, obviously, it would be
physically wrong to say that the speed of light would vary in those
situations.
Or did you want to ask for a theoretical explaination for the constancy
of the speed of light? Within the framework of Relativity (no matter if
SR or GR), the constancy of the speed of light is a fundamental
postulate, i.e. it is considered as a fundamental property of nature.
So, it cannot be explained (in the sense that it could be derived from a
more fundamental principle).
This, however, is no lack of Relativity: every imaginable physical
theory is based on fundamental assumptions that are not explained
themselves. Take e.g. Newtonian Mechanics: there, the fundamental
assumptations are that the three Newtonian axioms apply and that
simultaneity is absolute (or in other world: Galilei invariance
applies). Newtonians Mechanics does not explain why the three axioms
apply or why simultaneity is absolute, it consider both as fundamental
properties.
Relativity instead makes the fundamental assumption that the speed of
light is constant and Lorentz invariance applies (globally in SR and
locally in GR). Before SR was founded it 1905, there was Lorentzian
Ether Theory (LET) that "explained" the constancy of the speed of light
by the ether influencing yardsticks and clocks when moving relative to
the ether. However, this wasn't a real explaination: this mechanism was
more complex than the assumption that the speed of light is constant,
and therefore did not match the requirement that explainations have to
be simple.
This is done:
https://en.wikipedia.org/wiki/Second#Based_on_caesium_microwave_atomic_clock
A second is the duration of 9192631770 periods of the radiation
corresponding to the transition between the two hyperfine levels of the
ground state of the caesium-133 atom.
What makes you think so?
But it would be much more difficult to measure this speed.
No; you can always discuss the limit of a true vacuum.
The point is when you use the concept "vacuum" in a defintion than the
concept vacuum should also clearly be defined. I doubt it is.
Remember, unit definitions are a matter of certainty. The speed of light
in a hypothetical perfect vacuum may be a little different from the
speed of light in a vacuum that can be created in a laboratory or that
exists in outer space. But that difference is probably very small, much
smaller than the known uncertainty in the metre definition of 10^-10
relatively. So, this does not affect the certainty of the metre definition.
You're wrong, you can, because the resulting contribution to the
uncertainty of the metre definition is neglectable.
Indeed. An this is why your argument is wrong.
As I stated before it is primarily not my strategy to calculate the speed
of light. What I want to challenge is the idea that this speed is not
always the same. To do that I use one observer, two light sources, a tower,
and two mirrors at different heights.
In other words: you consider a non-local set-up. And since it is
well-known that the speed of light is not constant in such a setup and
that this is in full agreement with GR (which claims that in a
gravitational field, the speed of light is constant only locally), you
do not challenge anything by this. Or at least no idea that is part of
today's physics.
You mean, you want to consider the combined gravitational field of Sun
and Earth. The first thing you have to note then is that there is no
known exact solution of GR field equations for a gravitational field
with more than one centre of gravity. For one single centre of gravity,
there is Schwarzschild solution, but for two or more centres of gravity,
there is no exact solution known.
This IMO raises an issue when you want to study the merging of two
black holes using GR.
This can be done only numerically, not analytically. Of course, you
could apply the same numerical methods for the Sun-Earth system.
As far as the variability of the speed of light due to gravitational
effects is concerned, the metre definition is not touched in any way: to
define the metre, one uses the speed of light measured with respect in a
local inertial frame, which is applied in a small spacetime region
limited enough to neglect gravitational effects and to apply the
SR-limit of GR.
I agree with you, however this becomes an issue when light years are
considered.
To consider great spatial distances, you just consider a sequence of a
high number of small yardsticks, each small enough to apply the SR-limit
locally.
I fully agree with you. The problem is more or less that in SR we start
from the idea that the speed of light is constant (and in all directions
the same) and equal to c.
There is no reason not to apply the described procedure: we just assume
as c0 as the quantity for which the property to be always constant applies.
I doubt how important the last is. What is the point when local implies
a very small region, while in general what we want is to study the
evolution of the universe.
If you restrict yourself to study the evolution of the universe, that
point is not very relevant, that's correct. GR, however, is not only
about the evolution of the universe.
Yes.
I disagree. In 1905 Einstein did indeed assume something close to this [#]. But
TODAY we have no need to do so. The equations of SR can be derived from:
[#] Of course he actually postulated that "Any ray of light
moves with the determined velocity c, whether the ray be emitted
by a stationary or by a moving body." But when combined with the
PoR this directly yields what you said.
In other words: you consider a non-local set-up. And since it is well-known
that the speed of light is not constant in such a setup and that this is in
full agreement with GR (which claims that in a gravitational field, the
speed of light is constant only locally), you do not challenge anything by
this. Or at least no idea that is part of today's physics.
Yes, assuming the measurement accuracy is sufficiently good to distinguish the
result from c -- that's not possible using current technology and any existing
tower. Boreholes are considerably "taller", but they are not straight enough
(not to mention the difficulty of lowering a vacuum pipe several km long into
one). I cannot even devise an experiment to compare a horizontal and vertical
path in an interferometer to sufficient accuracy, due to the impossibility of
measuring distances accurately enough without using light, and the inevitable
strains in a "rigid" rod rotated between horizontal and vertical.
Tom Roberts
Nicolaas Vroom wrote:
In other words: you consider a non-local set-up.
A whole different issue is, that I do not understand why GR claims that
the speed is constant locally when any practical application (for
example the forward movement of Mercury) is a global configuration?
The experiment I propose does not have a horizontal component.
The idea is to send a (two) light signals straight down.
The reflection is upwards.
Nicolaas Vroom
I disagree. In 1905 Einstein did indeed assume something close to this [#]. But
TODAY we have no need to do so. The equations of SR can be derived from:
Does that mean that you want to replace the postulate of the speed of
light being constant by the postulate that kilomer-long pion beams
exist? That wouldn't be very straight-forward: such a posulate would be
much more special than the postulate of the speed of light being
constant and therefore doesn't match the requirement that postulates
have to be as general as possible.
Or do you want to say that we do not need any postulate at all any more
because we have experimental facts? That would be completely wrong, due
to the general structure of physical theories: a theory has to postulate
fundamental statements, and those statements or the statements that can
be derived from them have to be in agreement with the observations.
And BTW: the existence of kilometer-long pion beams could be as well
explained by pions travelling 100 times faster than the light. A funny
thing: when I first read about the long distance that pions travel
before decaying many years ago, I thought this should be a proof for
superluminal pions. It was only years later that I realized that this
should rather be a proof for time dilation ;)
No, it does not have that advantage because the same is already true for
the postulate that the speed of light is constant: what we call the
"speed of light" is not a property of electrodynamics, but a general
quantity. It's only due to historical reasons that the name of that
quantity contains the name of an electrodynamic phenomenon (light).
Does that mean that you want to replace the postulate of the speed of light
being constant by the postulate that kilomer-long pion beams exist? That
wouldn't be very straight-forward: such a posulate would be much more special
than the postulate of the speed of light being constant and therefore doesn't
match the requirement that postulates have to be as general as possible.
One does not need (c) to be a postulate. (a) and (b) alone determine just three
potential theories, distinguished by their symmetry groups:
The postulate "the speed of light is constant" brings in a whole lot of
"baggage" you did not mention. In essence it brings in all of classical
electrodynamics (c.f. the title of Einstein's 1905 paper).
See above. This approach does that. It's just that the postulates (a) and (b) do
not determine a unique theory -- as usual, one needs experiments to determine
which theories are valid....
Tom Roberts
Yes.
My interpretation of this is that both of you agree that the speed of
light is constant in situations where SR applies and not where GR
applies. My understanding is that when GR applies gravitational effects
can not be neglected. Which raises the question if both of you agree
that when GR applies the speed of light is not constant.
This question is of practical importance for almost all experiments
because in reality always gravitational effects are involved, specific
if you want to discuss the movement of physical objects.
On Tuesday, 19 July 2016 01:13:50 UTC+2, Gregor Scholten wrote:
Or did you want to ask for a theoretical explaination for the constancy of
the speed of light? Within the framework of Relativity (no matter if SR or
GR), the constancy of the speed of light is a fundamental postulate, i.e.
it is considered as a fundamental property of nature. So, it cannot be
explained (in the sense that it could be derived from a more fundamental
principle).
I disagree. In 1905 Einstein did indeed assume something close to this [#].
But TODAY we have no need to do so. The equations of SR can be derived from:
What type of experiment do you have in mind?
Can you give a link where this is explained?
This discussion is difficult to follow. My first impression is that they
have "nothing" in common. Light is used to measure distance. Pion beams
are used for ?
Maybe see: https://en.wikipedia.org/wiki/Pion
Skip
Also this requires more detail (for most readers?)
I try to understand, but I do not.
Any way for me the most important question is why the claim that the
speed of light is constant.
A whole diferent issue the definition of what is a lightyear.
The distance is: 9460730472580800 metres (exactly) See:
https://en.wikipedia.org/wiki/Light-year
But that does not mean that the speed of light is always the same when
the distance between two objects is 1 lightyear (For a pulse which
travels that distance)
Nicolaas Vroom
In other words: you consider a non-local set-up.
In GR a local region is one in which the curvature of spacetime can be
neglected. The size of such a region depends directly on one's
measurement resolution. Note that if the curvature can be neglected for
a given resolution, then the vacuum speed of light will be equal to c
within that resolution.
Your experiment explicitly requires a measurement resolution that can
distinguish the measured value from c. So you must use a region that is
not local.
In a local region the resolution is insufficiently good to distinguish
the vacuum speed of light from c. So your experiment would be
hopeless/useless.
[Your experiment has two vertical light paths of length L and 2L, with
mirrors such that one light ray goes down-up-down-up over L, and the
other goes down-up over 2L. The two rays start together.]
Nobody disputes that they will not arrive simultaneously, when measured
with infinite precision. But in practice, on earth with current
technology, it is not possible to achieve the requisite resolution for
any practical paths (towers or boreholes).
I have considered very similar potential experiments. The limit
is not in measuring time differences between light rays, the
difficulty is in measuring the path lengths to the required
accuracy without using light.
Sure. Over NON-LOCAL paths the vacuum speed of light need not be c. But
one must be careful to define PRECISELY what one means by "speed" [#].
The postulate is that in the local limit SR applies -- that is essential
in deriving the field equation of GR. Yes, most applications of GR are
probing the effects of gravity, so they involve non-local regions.
Elementary calculations show that over non-local paths, the vacuum speed
of light can differ from c (sometimes by a lot) -- one MUST be careful
to define PRECISELY what one means by "speed" [#].
[#] Here there be dragons.
Tom Roberts
The speed of light, when measured locally, is constant. With
gravitation, one can interpret the speed as being constant and space
being stretched, or the speed slowing down. It doesn't matter how you
think about it as long as you get the correct result.
The difference is negligible in practice, though.
This is just the speed of light, which is defined exactly, times the
length of a year, which is also defined exactly.
No-one claims that it is. But, again, in practice the difference is
negligible.
In GR a local region is one in which the curvature of spacetime can be
neglected. The size of such a region depends directly on one's
measurement resolution. Note that if the curvature can be neglected for
a given resolution, then the vacuum speed of light will be equal to c
within that resolution.
Okay, I agree
Okay, I agree
In Scientific American August 2016 page 25 we read:
"As a paricle moves into the void, etc, it slows down like a ball rolling
up a hill; once it starts to move out of the void toward the dense area
it accelerates etc. CMB photons behave similary, although they do not
change speed (the speed of light is always constant)"
Do you agree with the final remark?
[Your experiment has two vertical light paths of length L and 2L, with
mirrors such that one light ray goes down-up-down-up over L, and the
other goes down-up over 2L. The two rays start together.]
Nobody disputes that they will not arrive simultaneously, when measured
with infinite precision. But in practice, on earth with current
technology, it is not possible to achieve the requisite resolution for
any practical paths (towers or boreholes).
I fully agree that "you" cannot perform such an experiment in practice.
The discussion is only in principle. My intention is primarily not
to calculate the speed of light.
I like such discussions because you "try to go to the limits".
Sure. Over NON-LOCAL paths the vacuum speed of light need not be c. But
one must be careful to define PRECISELY what one means by "speed"
I fully agree. That is why I try to define experiments, which are as simple
as possible.
(The same with length contraction and Schr=C3=B6dinger's Cat)
Thanks
Nicolaas Vroom
My interpretation of this is that both of you agree that the speed of
light is constant in situations where SR applies and not where GR
applies. My understanding is that when GR applies gravitational effects
can not be neglected. Which raises the question if both of you agree
that when GR applies the speed of light is not constant.
The speed of light, when measured locally, is constant.
It is possible that when you measure the speed of light (here on earth)
you always get the same value.
What I propose is an experiment and I ask the readers if they agree
with me about the outcome of the experiment. In my opinion what the
outcome of the experiment shows is that the speed of light is not always
the same. The cause is gravitation.
That means if you perform an experiment and no gravitation is involved
it is possible that the speed of light is always the same.
The experiment is such that the distances involved are the same.
To claim that the distances are changed when the results of the test shows
that the speeds are diferent is "tricky"
The difference is negligible in practice, though.
I agree that in many cases the differences are negligible, but that is
not the issue.
This is just the speed of light, which is defined exactly, times the
length of a year, which is also defined exactly.
I agree that the distances is mathematically defined exactly, but that
does not mean in practice that it is that simple, specific when
gravitation is involved.
No-one claims that it is. But, again, in practice the difference is
negligible.
I fully agree with you.
Thanks
Nicolaas Vroom
This is just the speed of light, which is defined exactly, times the
length of a year, which is also defined exactly.
One should perhaps add that the year is a Julian Year of 365.25 days;
those days contain 24*60*60 SI seconds and no leap seconds.
--
(c) John Stockton, Surrey, UK. ?merlyn.demon.co.uk Turnpike v6.05 MIME.
- show quoted text -
In other words: you consider a non-local set-up.
A local set-up is one that covers a spacetime region that is
sufficiently limited to neglect the curvature of spacetime. In your
experiment, you place two mirrors at different heights, with the
difference in height being big enough to detect gravitational effects,
i.e. effects caused by curvature of spacetime. So, obviously, the two
mirrors cover a spacetime region that is not sufficiently limited.
One can reason this by two arguments:
1) An important property of GR is that in the limit of weak
gravitational fields, it becomes equivalent to SR. And since GR
describes gravity as curvature of spacetime, this limit is equivalent to
the limit of small spacetime regions, because in the limit of small
spacetime regions, the curvature becomes neglectable, like in the limit
of weak gravitational fields. So, in the limit of small spacetime
regions, GR must become equivalent to SR, too.
2) GR is based on the equivalence principle according to which a
free-falling observer in a gravitational field is equivalent to a
uniformly moving observer in a spacetime without gravity. So, it must be
possible to describe a free-falling observer in a gravitational field by
the terms of SR in some way. GR implements this requirement by being
locally equivalent to SR.
And this fact makes your experiment being a thought experiment. And a
core property of a thought experiment is that you cannot ascertain its
outcome without referring to a theory.
As I stated before it is primarily not my strategy to calculate the
speed of light. What I want to challenge is the idea that this speed
is not always the same. To do that I use one observer, two light
sources, a tower, and two mirrors at different heights.
In other words: you consider a non-local set-up.
A local set-up is one that covers a spacetime region that is
sufficiently limited to neglect the curvature of spacetime. In your
experiment, you place two mirrors at different heights, with the
difference in height being big enough to detect gravitational effects,
i.e. effects caused by curvature of spacetime. So, obviously, the two
mirrors cover a spacetime region that is not sufficiently limited.
IMO the difference is very arbitrary.
When gravitational effects are considered, distance and light
are a non-local effect.
And this fact makes your experiment being a thought experiment. And a
core property of a thought experiment is that you cannot ascertain its
outcome without referring to a theory.
I agree that you can call this a thought experiment, but that does not
mean that we can not discuss what the outcome of this experiment could be.
The issue is that discussions about the speed of light in one direction
are very difficult. The same with experiments that are related with
the speed of light in one direction.
Anyway what I try to do is not to measure the speed of light, but only
to try to answer the question if the speed of light going from
object A to B is constant all the way down.
Nicolaas Vroom.
A local set-up is one that covers a spacetime region that is
sufficiently limited to neglect the curvature of spacetime. In your
experiment, you place two mirrors at different heights, with the
difference in height being big enough to detect gravitational effects,
i.e. effects caused by curvature of spacetime. So, obviously, the two
mirrors cover a spacetime region that is not sufficiently limited.
IMO the difference is very arbitrary.
When gravitational effects are considered, distance and light
are a non-local effect.
As such light bending around a star (or any object) is non-local issue.
When gravitational effects are not considered distance and light
are a local issue. In such a scenario it makes sense to declare
the speed of light a constant.
It is not a matter of considering or non considering gravitational
effects, but of considering spacetime regions sufficiently limited or
not sufficiently limited to neglect gravitational effects. In a
spacetime region that is sufficiently limited, you can, if you want,
consider gravitational effects. However, this consideration yields the
result that those effects are neglectable. It's like considering the
electric field inside a charged conducting body: you will see the field
being zero everyhwere inside the body.
In turn, you can consider a spacetime region that is not sufficiently
limited to neglect gravitational effects, and skip considering
gravitational effects. As long as you do not consider the behaviour of
light as a gravitational effect itself, you can consider the speed of
light in that region, and find out that it is variable, without
considering gravitational effects.
What is indeed in some way arbitrary is the threshold for considering a
spacetime region as sufficiently limited or as not sufficiently limited.
One could e.g. claim that gravitational effects are neglectable when the
deviation from Minkowski metric is < 10^-10, or one could as well claim
that gravitational effects are neglectable when the deviation is <
10^-15. However, this is a general issue for limits, and in no way
special to the SR limit of GR.
In fact, it is a matter of measurement precision: if your measurement
setup is precise enough to detect a deviation of 10^-10, then the
threshold is lower than 10^-10.
And this fact makes your experiment being a thought experiment. And a
core property of a thought experiment is that you cannot ascertain its
outcome without referring to a theory.
I agree that you can call this a thought experiment, but that does not
mean that we can not discuss what the outcome of this experiment could be.
But we cannot discuss that without referring to a theory that predicts
some outcome.
And this fact makes your experiment being a thought experiment. And a
core property of a thought experiment is that you cannot ascertain its
outcome without referring to a theory.
For a description of the experiment see:
https://www.nicvroom.be/wik_Lorentz_ether_theory.htm#ref1
But we cannot discuss that without referring to a theory that predicts
some outcome.
The theory is called gravity.
In the newsgroup sci,astro
In the post: "Link between dark matter and baryonic matter"
On Tuesday, 25 October 2016 20:30:27 UTC+2, Steve Willner wrote:
Standard physics says photons have momentum and energy but zero rest
mass. Photons react to gravity and (in principle, but I don't think
it has been measured) create gravity, but neither of those properties
requires rest mass.
That is also my opinion.
And if that is the case the speed of light cannot be called constant.
Nicolaas Vroom.
The statement "the [vacuum] speed of light is constant" is NOT universally
applicable. However when measured in a LOCALLY INERTIAL FRAME, the vacuum speed
of light is constant, and equal to c (here "local" means "over a distance small
enough that the effects of gravitation are too small to measure").
Yes, if you measure the vacuum speed of light over a distance long enough that
gravity is not negligible, you can obtain a value different from c. Ditto if you
use some non-inertial "frame". There is no question whatsoever that General
Relativity predicts this, and that experiments confirm it (c.f. the Shapiro time
delay). I remark that in such cases one must be VERY careful to specify
precisely what one means by "speed" (here there be dragons).
You keep bringing up an overly simplistic statement that comes from SPECIAL
relativity over a century ago. We have learned A LOT since then, including the
fact that the vacuum speed of light is not always c. But for most physical
situations of interest the difference between the actual speed and c is too
small to measure.
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
Tom Roberts
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
When I study https://en.wikipedia.org/wiki/Speed_of_light IMO they only
mention that: the speed of light in vacuum (=c) is a physical constant.
Should this document not be updated to reflect the opinion that the
(vacuum) speed of light is not always c, specific when gravitation is
important?
Nicolaas Vroom
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
1) What is the speed of light?
299792458 m/sec. Details see below.
Right.
Right.
It is constant in vacuum when measured locally. No serious person has
ever claimed anything else.
No, it is much more complex. The answer is: no, it is not.
Right. Or when there is no vacuum.
It's not a question whether you are willing; it is a fact.
Should this document not be updated to reflect the opinion that the
(vacuum) speed of light is not always c, specific when gravitation is
important?
Not everything in Wikipedia is correct.
There are three ways to think of this:
One can think of the constancy of the speed of light (when measured
locally in vacuum) as a POSTULATE. Since this leads to no
contradictions with observations, it seems to be true.
One can measure the speed of light locally in a vacuum. The answer is
always the same.
Something of a red herring: Because of the two statements above, the
meter is now defined as the length travelled by light in a specific
time, so today, by definition, the speed of light is constant. But this
is not a tautology, since it is merely a convenient and practical
definition which follows from the two statements above.
It's not worth thinking about this anymore until you understand all
three of these statements. And after that, you won't have a need to
think about this anymore.
1/c^2 d^2/t^2 = d^2/d(c t)^2
This means that the constant is universal but can be meaured locally
only in a space time area of some wavelengths and frequancy beats.
For a general geometry of space time with a metric G tensor the wave
equation is
1/sqrt(det G) (d/dct , d/x ) sqrt(det G) G(t,x)^-1 (d/ct, d/dx) f(t,x) =0
wich means that waves emanating from a point are filling space time by a
complicated process of mode decomposition at the sender and composition
somewhere else and later by the receptor.
Compare: An universal speed of a bunch of signals moving by packages
from one computer through the knots and cables in the internet to a
distant receptor computer is a completely senseless notion.
--
Roland Franzius
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
1) What is the speed of light?
The speed v of a body is defined in that way that within a time interval
Delta_t, the body crosses a spatial distance Delta_x = v * Delta_t. The
speed of light is the application of this concept for light.
No, surely not. Even to make the statement that the speed of light is
constant meaningful, a different definition is required.
Better say: it wouldn't be any answer at all.
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
That is correct. According to GR, the speed of light is locally
constant, i.e. measured be a free-falling observer within the
application range of his local inertial frame. On scales where gravity
becomes important and the concept of an inertial frames breaks down, the
speed of light is variable in general.
In what way is this statement different from the previous one?
They refer to the local speed of light.
Feel free to add a section "The speed of light in General Relativity".
You keep bringing up an overly simplistic statement that comes from
SPECIAL relativity over a century ago. We have learned A LOT since
then, including the
fact that the vacuum speed of light is not always c. But for most
physical situations of interest the difference between the actual
speed and c is too small to measure.
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
1) What is the speed of light?
The speed v of a body is defined in that way that within a time interval
Delta_t, the body crosses a spatial distance Delta_x = v * Delta_t. The
speed of light is the application of this concept for light.
But the essential part of it is to define what is moving,
as there is defined several light speeds for light waves,
like phase, group and energy propagation speed.
The phase and group speed can be higher than c.
Light beam propagation speed
can be lower than c even for vacuum,
if the beam has a special spatial structure
and nonzero orbital angular momentum.
For energies where photons can be tracked
then vacuum speed c as energy propagation speed can be observed.
--
Poutnik ( The Pilgrim, Der Wanderer )
A wise man guards words he says,
as they say about him more,
than he says about the subject.
I agree with the opinion that the experiment can not be performed
accurately in practice using light signals.
And this fact makes your experiment being a thought experiment.
And a core property of a thought experiment is that you cannot
ascertain its outcome without referring to a theory.
For a description of the experiment see:
https://www.nicvroom.be/wik_Lorentz_ether_theory.htm#ref1
That is nothing but yet another repition of the description you already
brought up here numerous times here. BTW: ASCII art is really old-
schooled today, maybe you should try some graphics format. OpenOffice
Draw is a nice program to draw diagrams with lines.
I agree that you can call this a thought experiment, but that does
not mean that we can not discuss what the outcome of this
experiment could be.
But we cannot discuss that without referring to a theory that
predicts some outcome.
The theory is called gravity.
There is no such theory. There are theories that describe gravity, like
Newtonian Gravity or General Relativity, making statements in what exact
way gravity acts on the movements of bodies or on the propagation of
light rays, but gravity on its own, i.e. the bare concept that there is
a general mutual attraction of bodies, does not make up a theory.
On Tuesday, 25 October 2016 20:30:27 UTC+2, Steve Willner wrote:
Standard physics says photons have momentum and energy but zero rest
mass. Photons react to gravity and (in principle, but I don't think
it has been measured) create gravity, but neither of those properties
requires rest mass.
That is also my opinion.
And if that is the case the speed of light cannot be called constant.
Why not?
If we follow General Relativity, we know that the speed of light is not
constant except on local scales, but this has little to do with the fact
that reacting to gravity and being a source of gravity does not require
rest mass.
So, we know that the speed of light is not constant on scales where
gravity is relevant, but not for the reason you claimed.
You keep bringing up an overly simplistic statement that comes from
SPECIAL relativity over a century ago. We have learned A LOT since
then, including the fact that the vacuum speed of light is not always
c. But for most physical situations of interest the difference between
the actual speed and c is too small to measure.
Stated differently: Special Relativity is not valid when
gravitation is important. This OUGHT to be obvious.
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
1) What is the speed of light?
299792458 m/sec. Details see below.
To define the speed of light as a constant and equal to 299792458 m/sec
is okay for normal applications,
but is not a complete answer on this question.
Right.
I'am well aware that the specific conditions (vacuum) and how the speed
is measured, should be mentioned.
Right.
2) Is the speed of light constant?
It is constant in vacuum when measured locally. No serious person has
ever claimed anything else.
I mean by that, going from A to B anywhere in the universe, is the speed
always the same. This question is simpler as question 1.
No, it is much more complex.
When we agree that the speed of light is not constant it is extremely
difficult to measure that in practice.
I think the only way to demonstrate this is mathematically by means of a
model. I have used Newton's Law.
See https://www.nicvroom.be/VB%20Light%20operation.htm
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
Right. Or when there is no vacuum.
I'am even willingly to conclude that the speed of light is not constant
when gravitation is involved.
It's not a question whether you are willing; it is a fact.
When I study https://en.wikipedia.org/wiki/Speed_of_light IMO they only
mention that: the speed of light in vacuum (=c) is a physical constant.
Should this document not be updated to reflect the opinion that the
(vacuum) speed of light is not always c, specific when gravitation is
important?
Not everything in Wikipedia is correct.
The Wikipedia document starts with a picture which shows the distance
between the Sun and the Earth to indicate a lightray which goes
from the Sun towards the Earth.
The interesting part is when the lightray approaches the earth the
speed is almost constant. Going the other way when the lightray
aproaches the Sun this is different. The speed increases.
However I also have a whole different question:
Why is it that people very often say: the speed of light c=1
I can understand that for some applications this seems handy.
But in general IMO you have to use this "equation" with care.
Nicolaas Vroom
The speed v of a body is defined in that way that within a time
interval Delta_t, the body crosses a spatial distance Delta_x = v *
Delta_t. The speed of light is the application of this concept for
light.
But the essential part of it is to define what is moving,
as there is defined several light speeds for light waves,
like phase, group and energy propagation speed.
All those speeds have in common that the described speed definition can be
applied. And in vacuum, all those speeds are equal.
Not in vacuum.
Really? Can you bring up some resource about this?
And even if that is true: when claiming that the speed of light is constant
in vacuum, one usually refers to plane waves.
But the essential part of it is to define what is moving,
as there is defined several light speeds for light waves,
like phase, group and energy propagation speed.
All those speeds have in common that the described speed definition can be
applied. And in vacuum, all those speeds are equal.
For monochromatic plain wave.
The phase and group speed can be higher than c.
Not in vacuum.
I have not said in vacuum.
Light beam propagation speed
can be lower than c even for vacuum,
if the beam has a special spatial structure
and nonzero orbital angular momentum.
Really? Can you bring up some resource about this?
And even if that is true: when claiming that the speed of light is constant
in vacuum, one usually refers to plane waves.
And exactly this is claimed by those resurces.
That c should be referred to plane wave propagation.
Said simplified, as I got it,
the light is slowed by propagation in spirale instead of a line.
http://www.iflscience.com/physics/physicists-slow-down-light-vacuum-twisting-it/
http://www.sciencealert.com/physicists-have-found-a-way-to-slow-light-down-by-twisting-it
[[Mod. note --
These articles describe the slower-than-c group velocity of certain
*finite-sized* light beams in a vacuum. The classical statement
"The speed of light is always 299792458 m/s"
refers to plane waves of *infinite* extent in a vacuum, so there's no
contradiction with relativity here (nor do the researchers claim any
such contradiction).
I also note that the scientific paper in question
Bareza & Hermosa
But the essential part of it is to define what is moving,
as there is defined several light speeds for light waves,
like phase, group and energy propagation speed.
All those speeds have in common that the described speed definition can
be applied. And in vacuum, all those speeds are equal.
For monochromatic plain wave.
You must be joking. Is it a wave or not? You cant have them both. You mean
EM which not propagate spherically or not diverges?
Not in vacuum.
I have not said in vacuum.
Where then. Of course that can be both in vacuum. Or is something you both
misunderstood completely.
2) Is the speed of light constant?
I mean by that going from A to B any where in the universe is the
speed always the same. This question is simpler as question 1.
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
That is correct. According to GR, the speed of light is locally
constant, i.e. measured be a free-falling observer within the
application range of his local inertial frame. On scales where gravity
becomes important and the concept of an inertial frames breaks down, the
speed of light is variable in general.
What does this specific say if you want to simulate the planets
around the sun or a small collections of star.
Is there a free-falling observer?
Is there a local inertial frame.?
IMO in both cases you should take one star as the center of your
coordinate system.
[[Mod. note --
Let's think about Newtonian gravity for a moment. Suppose my "small
collection of stars" is a binary star where the two stars have equal
masses M1 = M2 = M. And for simplicity, let's have the two stars in
circular orbits about each other. (I'm neglecting tidal-friction effects
that could cause the stars to gradually spiral in or out.) Then if I
choose Cartesian inertial xyz coordinates centered on the center-of-mass
point midway between the two stars, the stars are located at
Feel free to add a section "The speed of light in General Relativity".
I think if any we should first investigate this document:
http://math.ucr.edu/home/baez/physics/Relativity/SpeedOfLigh/speed_of_light.html
I have started a new discussion for this document.
Nicolaas Vroom
[[Mod. note -- The correct url is
http://math.ucr.edu/home/baez/physics/Relativity/SpeedOfLight/speed_of_light.html
]]
-- jt]]
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
That is correct. According to GR, the speed of light is locally
constant, i.e. measured be a free-falling observer within the
application range of his local inertial frame. On scales where
gravity becomes important and the concept of an inertial frames
breaks down, the speed of light is variable in general.
What does this specific say if you want to simulate the planets
around the sun or a small collections of star.
Is there a free-falling observer?
Yes. E.g. an observer that is co-moving with one of the planets.
Yes. The local inertial frame of the upper observer that is co-moving
with one of the planets. However, that local inertial frame is not
appropriate for being used in a simulation of the planet system since it
is only applicable in the local environment of the particular planet.
For the simulation, you should rather use a general coordinate system,
like you describe it on your own below:
Indeed. With respect to that coordinate system, the speed of light is
not constant according to GR.
[[Mod. note --
Let's think about Newtonian gravity for a moment. Suppose my "small
collection of stars" is a binary star where the two stars have equal
masses M1 = M2 = M. And for simplicity, let's have the two stars in
circular orbits about each other. (I'm neglecting tidal-friction effects
that could cause the stars to gradually spiral in or out.) Then if I
choose Cartesian inertial xyz coordinates centered on the center-of-mass
point midway between the two stars, the stars are located at
This is a tricky and too simple exercise.
In fact you describe object 1 with a sequence of observations:
(x10,y10), (x11,y11), (x12,y12), (x13,y13)
with x12 meaning x1(2*deltat) = + R * cos(omega*2*deltat)
That means you describe it as an exact circle.
For object 2 exactly the same logic applies.
You can only do that mathematically using Newton's Law, because Newton's
acts instantaneous.
(Infact when I do a simulation of the solar system using Newton's Law
I do the same, contrary what I have written above)
In reality I have never done a serious GR analysis for such a system.
What I have done in order to improve my simulations I use a modification
of Newton's Law which includes the speed of gravity and retarded positions.
Which such a modification you can simulate the 43 arc sec and calculate
the speed of gravity by trial and error.
In relation to GR I only have implemented the equations which
describe the movements of the planet Mercury.
See: https://www.nicvroom.be/VB%20Mercury%20numerical.htm
The issue that this exercise gives already many problems and is too
simple. It includes one object which has a mass and the other one
is massless. In your exercise atleast both objects have a mass.
When I do a simulation using the speed of gravity cg equal to c the two
objects will spiral outwards. When cg is larger they will become
more stable.
This a simulation is in conflict which a simulation using GR and masses
comparable to the Sun i.e. masses like 50*m0. In such cases
the masses should spiral inwards and collide. As in the case of LIGO.
What this means in order to simulate the above observations using
Newton's Law and the speed of gravity I have in some way or
another to make mass a variable i.e. smaller as a function of t.
In the case of GR I also have to make the mass variable, but larger.
I expect this is not the answer you have in mind.
Thanks
Nicolaas Vroom
Back to my home page Contents of This Document
>
Really now! If the experiment were actually performed, there would be
only ONE result. This "arbitrariness" makes no sense and sounds like
obfuscation to me.
62 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Saturday 12 december 2015
John Heath wrote:
>
Nice link , I bookmarked it. And thanks for taking the time for a
long response. I can see I have failed to set the conditions of the
test in a clear way. Perhaps I should state the condition instead
of creating the condition . I will state the conditions.
>
C] There is no Doppler effect or SR effects. Assume ideal conditions
of no movement between Alice and Bob.
>
This would
require the speed of light to be variable in the larger picture to
guarantee that all observers measure the speed of light to be c.
>
It should be noted that Alice on earth is the observer. If Bob is
the observer then Alice should say the measured speed of light is
1/2 c caused by her fast clock relative to Bob if light speed is
absolute.
>
If light speed is relative
>
To return to the burning question. In your mind is the speed of
light absolute or variable. It is a given light will always measure
c but is it constant in the larger picture of god looking down at
Alice and Bob from a great distance?
63 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Saturday 12 december 2015
Gary Harnagel wrote:
>>
So, by choosing the far away observer as "reference point", you do not
fix the clock near the black hole to run with half speed. You need to
choose to apply Schwarzschild coordinates in addition. And that choice
is arbitrary.
>
64 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 13 december 2015
Jonathan Thornburg wrote:
>>
Really now! If the experiment were actually performed, there would be
only ONE result. This "arbitrariness" makes no sense and sounds like
obfuscation to me.
>
>
She drops a clock into the BH; that clock sends out a sequence of
radio-wave "ticks" at uniform time intervals as measured by the
falling clock; each "tick" also encodes the falling clock's
current position (areal radial coordinate) with respect to the
BH. The far-away observer measures the arrival frequency of
the radio-wave "ticks" as a function of the encoded position.
(b) Same thing as (a), but change "areal radial coordinate" to
"isotropic radial coordinate".
(c) The far-away observer is a rest with respect to the BH. She
releases a clock which is just like the clock in (a), but is
also equipped with a rocket engine. The rocket-engine-clock is
programmed to fly down to a specific position (areal radial coordinate)
with respect to the BH, hold itself at that position for a while
>
As I suggested above, experiments (a), (b), (c), and (d) will
(in general) give four different answers to the question "at what rate
do the clock-near-the-BH ticks arrive at the far-from-the-BH clock when
the clock-near-the-BH is at the position r=3M?".
>
You haven't specified
which of these is the experiment which you're asking about
65 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Sunday 13 december 2015
In article <0fc9baa2-17e6-4b72-a050-fbc3f9988580@googlegroups.com>,
heath...@gmail.com says...
>
On Thursday, December 10, 2015 at 11:12:56 PM UTC-5, Gregor Scholten wrote:
>
To return to the burning question. In your mind is the speed of
light absolute or variable. It is a given light will always measure
c but is it constant in the larger picture of god looking down at
Alice and Bob from a great distance?
66 The two postulates in Special Relativity
From: Gary Harnagel
Datum: Sunday 13 december 2015
On Saturday, December 12, 2015 at 12:59:42 AM UTC-7, Gregor Scholten wrote:
- show quoted text -
I like Jonathon's explanation that choosing different coordinate types
means choosing a different experiment, to which you allude in your last
paragraph. The problem is that by calling out different coordinate
systems, the shift to a different experiment isn't made explicit, and this
is VERY confusing to neophytes like me.
>
67 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 13 december 2015
Gary Harnagel wrote:
>
I like Jonathon's explanation that choosing different coordinate types
means choosing a different experiment
>
to which you allude in your last
paragraph. The problem is that by calling out different coordinate
systems, the shift to a different experiment isn't made explicit, and this
is VERY confusing to neophytes like me.
>
I understand that choosing an experiment where r is constant for Bob leaves
out how that condition can be maintained. Specifying that phi and theta
are also constant, all wrt a distant observer, means that either Bob is
standing on a surface or he is in a rocket. Specifying that the derivative
of phi or theta is constant means that he maintains r = constant by orbital
motion. Different experimental conditions.
>
But it appears to me that
either case can be addressed using Schwarzschild coordinates.
>
One may get
different results for the two cases, but the results must agree regardless
of the coordinate system used.
>
Also, there seems to be some conflation about gravitational red shift versus
time dilation. Just use an atomic clock to measure the difference in time.
Then the change in the wavelength of the carrier is irrelevant.
68 The two postulates in Special Relativity
From: Steven Carlip
Datum: Monday 14 december 2015
In article <0fc9baa2-17e6-4b72-a050-fbc3f9988580@googlegroups.com>,
John Heath
>
I can see I have failed to set the conditions of the
test in a clear way. Perhaps I should state the condition
instead of creating the condition . I will state the
conditions.
>
A] Alice is on earth with a 1 meter stick and a atomic
clock to measure the speed of light.
>
B] Bob is gravity time dilated 50 percent. His clock is
ticking at 1/2 its rate relative to Alice's clock.
>
C] There is no Doppler effect or SR effects. Assume ideal
conditions of no movement between Alice and Bob.
>
To return to the burning question. In your mind is
the speed of light absolute or variable. It is a
given light will always measure c but is it constant
in the larger picture of god looking down at Alice
and Bob from a great distance?
69 The two postulates in Special Relativity
From: John Heath
Datum: Tuesday 15 december 2015
On Friday, December 11, 2015 at 3:25:01 PM UTC-5, John Heath wrote:
[[Mod. note -- 224 quoted lines of discussion snipped here. -- jt]]
70 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Tuesday 15 december 2015
On 12/13/2015 7:00 AM, Gregor Scholten wrote:
..
>
Jonathan Thornburg wrote:
>>
(a) The far-away observer is a rest with respect to the black hole (BH).
>
71 The two postulates in Special Relativity
From: John Heath
Datum: Tuesday 15 december 2015
On Sunday, December 13, 2015 at 1:19:20 AM UTC-5, Gerry Quinn wrote:
>
In article <0fc9baa2-17e6-4b72-a050-fbc3f9988580@googlegroups.com>,
heath...@gmail.com says...
> >
On Thursday, December 10, 2015 at 11:12:56 PM UTC-5, Gregor Scholten wrote:
>
> >
>
72 The two postulates in Special Relativity
From: Tom Roberts
Datum: Wednesday 16 december 2015
[This was originally posted on 12/11/15, but has not appeared. I think my final
paragraph is particularly pertinent to the discussion, as some posters are
attempting to distinguish among those labels.]
>
Really now! If the experiment were actually performed, there would be only
ONE result. This "arbitrariness" makes no sense and sounds like obfuscation
to me.
73 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Wednesday 16 december 2015
John Heath wrote:
>
However if gravitational red shift were in any way effect the B
clock rate as observed by A then there is a violation to causality.
Where are the missing ticks?
>
There is no longer a Doppler effect
to continuously hide them in space.
>
Where did they go? From this I
conclude that gravitational red shift is simply the observation of
gravity time dilation.
>
There in is the rub. From energy conservation laws the frequency
of a photon must go down caused by G red shift. From a causality
position the frequency can not go down as it violates causality.
Where are you going to hide the missing tick .
>
Only gravity time
dilation is allowed to have missing ticks not gravitational red
shift as it is only a carrier of information.
>
I do not have an
answer for this.
74 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Friday 18 december 2015
Jos Bergervoet wrote:
>>>
(a) The far-away observer is a rest with respect to the black hole (BH).
>>
>
>
(OK, it's mass might be of a different
scale, but what is essentially different?)
75 The two postulates in Special Relativity
From: John Heath
Datum: Friday 18 december 2015
On Wednesday, December 16, 2015 at 3:53:42 AM UTC-5, Gregor Scholten wrote:
>
John Heath wrote:
> >
>
> >
>
> >
>
> >
>
> >
>
> >
>
76 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Friday 18 december 2015
In article <886ac775-51eb-4301-b12c-48962182fd41@googlegroups.com>,
heath...@gmail.com says...
>
On Sunday, December 13, 2015 at 1:19:20 AM UTC-5, Gerry Quinn wrote:
77 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Saturday 19 december 2015
John Heath wrote:
>
For clarification a photon leaving earth must be reduced in frequency
to satisfy energy concentration laws. If the frequency of the photon
is reduced within a medium , medium between earth and space , there
will be a violation to causality.
>
Always good to describe a problems two ways to best communicate a
thought. B sends a sample of 1000 pules to A from his atomic clock
to test for time dilation caused by G time dilation. There is not
a violation to causality here. However for G red shift to change
measurements of time dilation it must change 1000 pulses to 999 or
1001 pulses which is a clear violation to causality.
>
Keep in mind
G red shift is information on a laser beam of light that can not
go back in time to change the atomic clock as it is just a wave of
information of 1000 pulses. There is no Doppler effect to hide
pulses.
78 The two postulates in Special Relativity
From: Gary Harnagel
Datum: Sunday 20 december 2015
On Friday, December 18, 2015 at 12:15:02 AM UTC-7, Gerry Quinn wrote:
>
>
and why should we believe
that these are unique (i.e., that they're the *only* coordinates
"natural to an observer in a low gravitational far from the system
of interest")?
>
And, how do we know that the GE coordinates cover all "interesting"
regions of spacetime.
>
For example, can you prove that GE coordinates
don't have any coordinate singularities outside the event horizon?
-- jt]]
79 The two postulates in Special Relativity
From: Tom Roberts
Datum: Sunday 20 december 2015
[[Mod. note -- I have manually rewrapped over-long lines. -- jt]]
>
[...] it seems to me that you can start by looking at things through 'god's
eye' coordinates, a.k.a. coordinates natural to an observer in a low
gravitational far from the system of interest. In these flat spacetime
coordinates, light slows and bends in gravitational fields. But so long as
you consider only regions outside event horizons, you can describe any
physical system in a way that is consistent with any system of GR curved
coordinates.
>
There is no causality violation in either description.
>
If B moves in close to a black hole for a while and comes back again, he
will have aged less than A, according to either formulation. But there are
no 'missing ticks'. In the flat spacetime formulation, that's because light
and time slowed down where he was.
>
In the curved spacetime formulation, light and time go at the same speed
everywhere, but spacetime is distorted. So when he meets up again with A,
he finds less time passed on the route he took.
>
And when they meet, the number of ticks observed by both parties will be
identical.
>
Remember, in relativity it's very important to talk only about local
measurements
>
so you can't safely add the ticks until A and B meet,
>
[... further discussion which I cannot decipher at all]
>
Also, note that energy conservation applies in asymptotically flat
spacetimes in GR, but is not necessarily applicable when only part of such a
spacetime is considered.
>
[[Mod. note -- Your description doesn't tell me how to define your "god's
eye" (GE) coordinates. Let's be specific. What's your operational
definition of GE coordinates for Schwarzschild spacetime, [...]
80 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 20 december 2015
Gregor Scholten wrote:
>
But now consider things in e.g. Kruskal coordinates. With passing
Kruskal coordinate time v, a rod with two ends for which r = const
applies each is shrinking more and more. This is in full compliance with
the rod atoms' positions being determined by equilibrium between
gravitational force and interatomic forces: the gravitational field is
not static in Kruskal coordinates, but rather changing by coordinate
time v. So, the equilibrium positions of the rod atoms are changing,
too, making the rod being shrinking.
81 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Sunday 20 december 2015
In article
>
[[Mod. note -- I have manually rewrapped over-long lines. -- jt]]
> >
[...] it seems to me that you can start by looking at things through 'god's
eye' coordinates, a.k.a. coordinates natural to an observer in a low
gravitational far from the system of interest. In these flat spacetime
coordinates, light slows and bends in gravitational fields. But so long as
you consider only regions outside event horizons, you can describe any
physical system in a way that is consistent with any system of GR curved
coordinates.
>
>
This model can account for many properties of GR, but in particular
it can be compared to GR only in regions in which gravitation is
weak (so you can put the manifolds of the two models into 1-to-1
correspondence with negligible error, and thus compare them). This
comparison fails wherever gravity is not weak, and that can happen
well outside any event horizons.
82 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Monday 21 december 2015
In article
>
>
And, how do we know that the GE coordinates cover all "interesting"
regions of spacetime. For example, can you prove that GE coordinates
don't have any coordinate singularities outside the event horizon?
-- jt]]
83 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Monday 21 december 2015
In article
>
In article
> >
>
>
[[Mod. note --
It's impossible to set up "universal background Minkowski" coordinates
in a curved spacetime: *any* coordinates you set up are going to fail
to have some of the key properties of coordinates in Minkowski spacetime,
namely that all the components of the Reimann tensor (computed in those
coordinates) vanish.
>
This problem is well-known to people trying to use such "ingoing null"
coordinates to do numerical calculations in general relativity. The
usual solution is to start with coordinates chosen near to the black
hole, and extend those *outwards* via light rays -- that works and
doesn't produce caustics.
84 The two postulates in Special Relativity
From: Jonathan Thornburg
Datum: Thursday 31 december 2015
>
I have made what I consider a valid argument from a philosophical
position that gravitational red shift can not change rate of ticks
, amount of time dilation , without being in conflict with causality
within the limitations of no SR effects and no Doppler effects.
The only two variables are gravitational time dilation and
gravitational red shift.
at B-clock-reading 15:15:00, B receives A's 12:00:00 pulse
at B-clock-reading 15:15:02, B receives A's 12:00:01 pulse
at B-clock-reading 15:15:04, B receives A's 12:00:02 pulse
at B-clock-reading 15:15:06, B receives A's 12:00:03 pulse
but B is a patient observer, and keeps listening. A bit later, ...
at B-clock-reading 19:38:00, B receives A's 12:00:00 pulse again
at B-clock-reading 19:38:05, B receives A's 12:00:01 pulse again
at B-clock-reading 19:38:10, B receives A's 12:00:02 pulse again
at B-clock-reading 19:38:15, B receives A's 12:00:03 pulse again
and still later, ...
at B-clock-reading 23:12:00, B receives A's 12:00:00 pulse again
from direction-on-the-sky #1
at B-clock-reading 23:12:11, B receives A's 12:00:01 pulse again
from direction-on-the-sky #1
at B-clock-reading 23:12:22, B receives A's 12:00:02 pulse again
from direction-on-the-sky #1
at B-clock-reading 23:12:33, B receives A's 12:00:03 pulse again
from direction-on-the-sky #1
while at the same time, ...
at B-clock-reading 23:12:00, B receives A's 12:00:00 pulse again
from direction-on-the-sky #2
at B-clock-reading 23:12:07, B receives A's 12:00:01 pulse again
from direction-on-the-sky #2
at B-clock-reading 23:12:14, B receives A's 12:00:02 pulse again
from direction-on-the-sky #2
at B-clock-reading 23:12:21, B receives A's 12:00:03 pulse again
from direction-on-the-sky #2
at B-clock-reading 23:12:28, B receives A's 12:00:04 pulse again
from direction-on-the-sky #2
85 The two postulates in Special Relativity
From: Jonathan Thornburg
Datum: Thursday 31 december 2015
Gerry Quinn
>
It can't be impossible because we do it all the time. The space in the
solar system is curved, and we still use flat coordinates for most
purposes.
>
Why are you talking about extending coordinates using light rays? Where
there is a gravitational field, light rays have bent trajectories in
flat coordinates, and obviously cannot be used to extend them. Light
rays can only be used directly for extending coordinates in the GR
model, in which spacetime is curved. We're not talking about that,
except to see how it compares now and again.
But that's merely a practical engineering approximation, and the
underlying inconsistency remains.
>
solar system is curved, and we still use flat coordinates for most
purposes.
>
If you don't like the above, replace the black hole by a small neutron
star. Does that change anything? [[...]]
>
Of course, you may argue that the coordinates are useful for discussing
wall interiors because they are a reasonable approximation to the true
geometry, but useless for black hole interiors, because the true
geometry is different. But then it is *you* who are asserting without
proof that so-far unobserved physics must correspond to your coordinate
system!
86 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Friday 1 january 2016
In article
>
Gerry Quinn
> >
It can't be impossible because we do it all the time. The space in the
solar system is curved, and we still use flat coordinates for most
purposes.
>
>
The problem is, how do we measure (operationally define) that (x,y,z,t)?
>
If our lab satisfies the axioms of Euclidean geometry, then the
"what if" situations I've outline above won't happen, all the above
procedures will give the *same* (x,y), and any of them are a reasonable
operational definition of (x,y).
> >
Of course, you may argue that the coordinates are useful for discussing
wall interiors because they are a reasonable approximation to the true
geometry, but useless for black hole interiors, because the true
geometry is different. But then it is *you* who are asserting without
proof that so-far unobserved physics must correspond to your coordinate
system!
>
>
You seem to be arguing that GR is valid outside a BH
[where we have a great deal of experimental evidence,
from things like observations of planetary and spacecraft
orbits in the solar system -- see (e.g.)
http://www.livingreviews.org/lrr-2014-4/
http://www.livingreviews.org/lrr-2010-7/
http://www.livingreviews.org/lrr-2003-1/
for some beautifully-written reviews, and section 6 of
http://www.livingreviews.org/lrr-2008-9
for some tests involving neutron stars]
but breaks down inside a BH. Perhaps the burden of proof should be on
you to propose a self-consistent theory of gravitation which agrees with
all known observations (including the presense of "things" which are very
massive, and accrete matter without showing any luminosity from that matter
hitting a surface), but which has "nicer" properties inside BHs?
87 The two postulates in Special Relativity
From: John Heath
Datum: Friday 1 january 2016
On Thursday, December 31, 2015 at 4:09:07 AM UTC-5, Jonathan Thornburg [remove -animal to reply] wrote:
> >
I have made what I consider a valid argument from a philosophical
position that gravitational red shift can not change rate of ticks
, amount of time dilation , without being in conflict with causality
within the limitations of no SR effects and no Doppler effects.
The only two variables are gravitational time dilation and
gravitational red shift.
- show quoted text -
>
>
88 The two postulates in Special Relativity
From: Jonathan Thornburg
Datum: Saturday 2 january 2016
I wrote:
| A(nother) problem with this argument is the use of the phrase
| "gravitational red shift" as if it were unique. Let's suppose we
| specify a pair of observers A and B, with A close to a black hole and
| B far away, and have A send out time-tagged once-per-second radio
| pulses. If B receives A's once-per-second pulses at a rate of one
| pulse per 2 seconds, I think you're arguing that (we should defined)
| the gravitational redshift from A to B is (to be) a factor of 2.
|
| The problem is, what if B receives each pulse more than once... and
| the different arrival times are associated with different arrival rates?
[[...]]
| What would you say is the gravitational redshift from A to B?
|
| (If this scenario seems implausible, consider that there can be
| multiple propagation paths from A to B, e.g., going clockwise vs
| counterclockwise around a spinning black hole. In general each path
| will have its own time-delay.)
|
|
|
| As noted by another poster earlier in this thread, to uniquely define
| gravitational redshift requires specifying not a pair of *observers*,
| but rather a pair of *events* AND a propagation path between them.
|
| This means that "gravitational redshift" is NOT an attribute of a
| position or event.
>
You are over thinking the problem. There is a rigid rod between A
and B . The rigid rod is hollow to provide a means for a laser light
within the hollow rigid rod to communicate clock pulses.
[For example, the two rods might pass on either side
of a massive body (say a star, galaxy, or black hole)
which is acting as a gravitational lens. And that
massive body might be spinning.]
How then should we define "the gravitational redshift from A to B"?
>
Please do not rotate the
system leading to SR effects.
89 The two postulates in Special Relativity
From: Tom Roberts
Datum: Monday 11 january 2016
On 1/1/16 1/1/16 - 8:45 AM, Gerry Quinn wrote:
>
In article
>>
Gerry Quinn
>>>
It can't be impossible because we do it all the time. The space in the
solar system is curved, and we still use flat coordinates for most
purposes.
>>
We use them for most engineering purposes, with accuracy tolerances which
are loose enough that we can ignore the curved-spacetime effects. But if
we want high accuracy, we can't ignore those effects, and we can't use GE
coordintes (or even *define* coordinates with the GE properties).
>
>
it is no more difficult in principle to assume that the meter sticks change
in length etc. depending on the gravitational potential than to assume that
spacetime is curved under the same conditions.
>
[...] pathology such as singularities.
90 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Tuesday 12 january 2016
In article
> >
it is no more difficult in principle to assume that the meter sticks change
in length etc. depending on the gravitational potential than to assume that
spacetime is curved under the same conditions.
>
> >
[...] pathology such as singularities.
>
91 The two postulates in Special Relativity
From: John Heath
Datum: Wednesday 13 january 2016
On Saturday, January 2, 2016 at 4:01:59 AM UTC-5, Jonathan Thornburg [remove
-animal to reply] wrote:
>
I wrote:
| A(nother) problem with this argument is the use of the phrase
| "gravitational red shift" as if it were unique. Let's suppose we
| specify a pair of observers A and B, with A close to a black hole and
| B far away, and have A send out time-tagged once-per-second radio
| pulses. If B receives A's once-per-second pulses at a rate of one
| pulse per 2 seconds, I think you're arguing that (we should defined)
| the gravitational redshift from A to B is (to be) a factor of 2.
|
| The problem is, what if B receives each pulse more than once... and
| the different arrival times are associated with different arrival rates?
[[...]]
| What would you say is the gravitational redshift from A to B?
|
| (If this scenario seems implausible, consider that there can be
| multiple propagation paths from A to B, e.g., going clockwise vs
| counterclockwise around a spinning black hole. In general each path
| will have its own time-delay.)
|
|
|
| As noted by another poster earlier in this thread, to uniquely define
| gravitational redshift requires specifying not a pair of *observers*,
| but rather a pair of *events* AND a propagation path between them.
|
| This means that "gravitational redshift" is NOT an attribute of a
| position or event.
> >
You are over thinking the problem. There is a rigid rod between A
and B . The rigid rod is hollow to provide a means for a laser light
within the hollow rigid rod to communicate clock pulses.
>
> >
>
92 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Wednesday 13 january 2016
On 1/12/2016 11:56 PM, Gerry Quinn wrote:
>
In article
..
>>
On 1/1/16 1/1/16 - 8:45 AM, Gerry Quinn wrote:
>
I believe the
Schwarzschild singularity is actually the breakdown point of GR
>
- and if
we accept this, we do not have any particularly fundamental problems
about black holes in terms of thermodynamics etc.
>
But the geometric
theory has allowed the Schwarzschild singularity to be defined away as a
coordinate singularity, and solutions continued inward from it.
>
The end
result, though, is an intractable central singularity that makes no
sense whatsoever in terms of thermodynamics,
93 The two postulates in Special Relativity
From: Gerry Quinn
Datum: Friday 15 january 2016
In article <56959110$0$23771$e4fe...@news.xs4all.nl>,
jos.ber...@xs4all.nl says...
>
On 1/12/2016 11:56 PM, Gerry Quinn wrote:
>
..
> >
I believe the
Schwarzschild singularity is actually the breakdown point of GR
>
> >
The end
result, though, is an intractable central singularity that makes no
sense whatsoever in terms of thermodynamics,
>
94 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Sunday 17 january 2016
On 1/15/2016 8:51 AM, Gerry Quinn wrote:
>
In article <56959110$0$23771$e4fe...@news.xs4all.nl>,
jos.ber...@xs4all.nl says...
>>
On 1/12/2016 11:56 PM, Gerry Quinn wrote:
>
>>
>>>
I believe the
Schwarzschild singularity is actually the breakdown point of GR
>>
>
>
"There is nothing special happening to anything..." I believe I pointed
out the circularity of that argument in the post you are responding to.
If GR breaks down at the Schwarzschild radius, then GR's prediction that
nothing special is happening there doesn't mean very much.
>
The choice of coordinates is nothing to do with the breakdown,
>
I don't believe in any special behaviour of physics anywhere.
>
I think
gravity can be described - like the other forces - in terms of a field
on a flat background (albeit an effective field, which cannot be
fundamental). At the Schwarzschild radius, this becomes topologically
incompatible with the geometric theory of gravity, so one of them (at
least) must be wrong.
>
I suppose in a sense I'm saying that both are wrong, as the effective
field must itself break down here.
>
The effective field acts like
geometric gravity. But unlike geometric gravity, it has a way to fail
gracefully, as high-energy underlying processes become observable.
>
As to the actual mechanics of how such forces might become observable,
>
there are several angles. We can say that ordinary 'low-energy' clocks
become time dilated to the point of stopping, so only high-energy clocks
remain.
>>>
The end
result, though, is an intractable central singularity that makes no
sense whatsoever in terms of thermodynamics,
>>
>
>
What sort of new physics
can you imagine that will take the place of general relativity there?
If we did not have quantum mechanics, we might imagine that matter is
somehow crushed out of existence entirely, leaving only its
gravitational field as a kind of ghost. But if we hope to be compatible
with quantum theory, even this in untenable.
>
So we must have made a mistake - the breakdown point must have been
earlier.
>
And there is only one other distinctive place where it could
be - the Schwarzschild radius,
95 The two postulates in Special Relativity
From: Gary Harnagel
Datum: Sunday 17 january 2016
On Sunday, January 17, 2016 at 3:16:31 AM UTC-7, Jos Bergervoet wrote:
>
> >
....
So we must have made a mistake - the breakdown point must have been
earlier.
>
> >
>
96 The two postulates in Special Relativity
From: Mike Fontenot
Datum: Sunday 17 january 2016
On 1/17/16 3:16 AM, Jos Bergervoet wrote:
>>>
97 The two postulates in Special Relativity
From: Tom Roberts
Datum: Sunday 17 january 2016
On 1/12/16 1/12/16 11:15 PM, John Heath wrote:
>
[...] a possible violation to causality when adding gravitational red shift
to gravitational time dilation [...]
98 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Monday 18 january 2016
On 1/17/2016 10:11 PM, Gary Harnagel wrote:
>
On Sunday, January 17, 2016 at 3:16:31 AM UTC-7, Jos Bergervoet wrote:
>>
On 1/15/2016 8:51 AM, Gerry Quinn wrote:
>>>
....
So we must have made a mistake - the breakdown point must have been
earlier.
>>
>>>
>>
>
99 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Monday 18 january 2016
On 1/17/2016 10:12 PM, Mike Fontenot wrote:
>
On 1/17/16 3:16 AM, Jos Bergervoet wrote:
>>>>
>
>
I'm one of the few people who believe that the r < 1 solution to the
quadratic equation obtained in the Schwarzschild derivation is just a
spurious mathematical result,
100 The two postulates in Special Relativity
From: Tom Roberts
Datum: Tuesday 19 january 2016
On 1/17/16 1/17/16 3:12 PM, Mike Fontenot wrote:
>
I'm one of the few people who believe that the r < 1 solution to the
quadratic equation obtained in the Schwarzschild derivation is just a
spurious mathematical result, with no physical significance in our
universe.
>
The "center" of the blackhole is at r = 1, and there is
nothing "inside" of that ... there IS no "inside" of that.
>
I realize I'm a member of a tiny minority holding this view, but I'm in
very good company: some years ago (after I had arrived at my view), I
found out that Dirac had the same view. Made my day!
101 The two postulates in Special Relativity
From: John Heath
Datum: Wednesday 20 january 2016
- show quoted text -
Spoken in succinct simple words that I can understand. They are not
added together. I knew Einstein would not leave an untied knot such
as causality on the table. I feel better now.
102 The two postulates in Special Relativity
From: Tom Roberts
Datum: Wednesday 20 january 2016
[[Mod. note -- I have manually rewrapped some over-long lines. -- jt]]
>
In article
>>
It is in general not possible to apply your GE coordinates to a curved manifold,
regardless of topology. They can only be applied to a "small" region, where
"small" is defined by the error acceptable to your application.
>
>
You are assuming, just
as Jonathan did, that I think that orthogonal straight lines, measured
according to your operational definition (which in the case of your
Chicago example presumably means great circles) must under all
conditions form a rectilinear grid. I do not say that.
>
Imagine flat creatures living on the surface of a sphere, unaware of a
third dimension. They might hypothesise that their space is curved. Or
they might hypothesise that it is embedded in a higher dimensional
space, and some force causes their meter sticks to bend to conform to a
sphere. If they believed in the latter, they could still define a two
parameter coordinate system (e.g. latitude and longitude), and there is
no reason why they could not convert such coordinates to 3D coordinates,
make calculations, convert them back again, and build roads with perfect
accuracy.
>>
It seems to me that you are taking an "armchair" attitude here, and have never
actually tried to apply your GE coordinates and varying rulers and clocks to the
Schwarzschild manifold of GR. [...]
>
>
As for verification that spacetime is flat, the only sure way I know at
present is to jump into a very large black hole, and find out whether
you get incinerated near the Schwarzschild radius, or progress further
only to be spaghettified at some point inside.
>
Failing that, we can only
argue on the basis of what is consistent, including what is consistent
with the rest of physics such as quantum theory and thermodynamics. In
my view, the geometric theory of gravity cannot easily be made
consistent with these.
>
It seems to me that GR is actually a theory which
has allowed singularities to be wished away. I believe the
Schwarzschild singularity is actually the breakdown point of GR
>
But the geometric
theory has allowed the Schwarzschild singularity to be defined away as a
coordinate singularity, and solutions continued inward from it.
>
The end
result, though, is an intractable central singularity that makes no
sense whatsoever in terms of thermodynamics, or physics in general.
>
This should be taken as a sign that the interpretation of the
Schwarzschild singularity as a coordinate singularity is incorrect, and
that conditions there are such that the symmetries of GR, which allow
the extension to interior solutions, no longer apply.
>
"But how can that be", you ask? "GR predicts that conditions at the
Schwarzschild radius of a large black hole are nothing special. So
obviously GR cannot break down there. Your alternative hypotheses are
unimaginable!"
103 The two postulates in Special Relativity
From: Mike Fontenot
Datum: Wednesday 20 january 2016
On 1/19/16 5:27 AM, Tom Roberts wrote:
>
On 1/17/16 1/17/16 3:12 PM, Mike Fontenot wrote:
>>
>
104 The two postulates in Special Relativity
From: erkd...@gmail.com
Datum: Sunday 28 february 2016
On Wednesday, May 6, 2015 at 2:24:19 AM UTC+1, Nicolaas Vroom wrote:
>
...
In the book "Subtle is the Lord..." by Abraham Pais at page 140
and 141 we read:
The two postulates:
1. The laws of physics take the same form in all inertial frames.
2. In any given inertial system the velocity of light c is the same
whether the light be emitted by a body at rest or by a body in uniform
motion.
...
>
Einstein's two postulates aren't enough on their own to uniquely define
the physics of special relativity. We also seem to need a third,
"geometrical", postulate, the assumption that spacetime is and remains
"flat" and that the presence or introduction of stationary or moving
matter doesn't affect the propagation of light, or the resulting
lightbeam geometry.
>
The physics of how relatively-moving bodies interact in real life is
//never// conducted in totally empty space (because the space under
consideration has to contain the bodies!), so our third postulate should
probably be that the "mathematical" lightbeam geometry derived by SR for
empty space is still correct in the presence of physically-real moving
masses and observers.
>
If we don't apply this third postulate, we can imagine a different
physics that still obeys the principle of relativity and the law of
local lightspeed constancy, without being the 1905 theory.
>
For instance, we could take Fresnel's early C19th idea of local
light-dragging as the basis of a relativistic dragged-light model,
eliminate the "aether" terminology and restate it as a geometrical
theory where the dragging is a gravitoelectromagnetic effect, use GEM to
regulate local lightspeeds and use W.K. Clifford's late C19th concept of
"all physics as curvature" to reject the idea of moving-body physics
having a valid flat-spacetime solution. We'd then have a different
theory of relativity that'd seem to agree with the physical evidence
available in 1905, but which wouldn't be Einstein's special theory.
>
Physicists in 1905 may have believed that two postulates were sufficient
to make SR inevitable, but we now have a broader and more sophisticated
conceptual vocabulary, which opens up other possibilities. This means
that defining SR's position within "theory-space" and distinguishing it
from its neighbours requires more parameters.
105 The two postulates in Special Relativity
From: Eric Baird
Datum: Tuesday 10 may 2016
On Saturday, 5 March 2016 15:12:33 UTC, Tom Roberts wrote:
>
On 2/28/16 2/28/16 2:39 AM, Eric Baird wrote:
> >
Einstein's two postulates aren't enough on their own to uniquely define
the physics of special relativity. We also seem to need a third,
"geometrical", postulate, the assumption that spacetime is and remains
"flat" and that the presence or introduction of stationary or moving
matter doesn't affect the propagation of light, or the resulting
lightbeam geometry.
>
>
One also needs the "hidden postulates" Einstein described in a 1907
paper: a) clocks and rulers have no memory, b) space is homogeneous and
isotropic, and c) time is homogeneous. Plus one he didn't mention: d)
light follows a null geodesic in the spacetime geometry. Note (b) and
(c) are part of the definition of inertial frames, and (d) can be
derived from that and the second postulate.
> >
>
> >
If we don't apply this third postulate, we can imagine a different
physics that still obeys the principle of relativity and the law of
local lightspeed constancy, without being the 1905 theory.
>
>
... (examples of
other useless theories below).
> >
>
> >
Physicists in 1905 may have believed that two postulates were sufficient
to make SR inevitable, but we now have a broader and more sophisticated
conceptual vocabulary, which opens up other possibilities. This means
that defining SR's position within "theory-space" and distinguishing it
from its neighbours requires more parameters.
>
>
You did not mention the infinite set of aether theories which are
experimentally indistinguishable from SR. These are theories in which
the round-trip vacuum speed of light is isotropically c in every
inertial frame, but the one-say speed of light differs from c; how it
differs distinguishes these theories from one another. This set includes
Lorentz Ether Theory (LET), the Tangherlini transforms, and an infinite
number of even less well known theories. Except for SR, none of them are
useful theoretically, as they do not obey Lorentz invariance.
106 The two postulates in Special Relativity
From: Ralph Frost
Datum: Friday 13 may 2016
On Tuesday, May 5, 2015 at 9:24:19 PM UTC-4, Nicolaas Vroom wrote:
..
>
Op zaterdag 2 mei 2015 20:50:53 UTC+2 schreef Tom Roberts:
(in thread "rigid rotating dics")
>
In the book "Subtle is the Lord..." by Abraham Pais at page 140
and 141 we read:
The two postulates:
1. The laws of physics take the same form in all inertial frames.
2. In any given inertial system the velocity of light c is the same
whether the light be emitted by a body at rest or by a body in uniform
motion.
107 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Monday 16 may 2016
[[Mod. note --
This discussion seems to be near the border between sci.physics.research
and sci.physics.foundations, but I'm allowing it in the interests of
encouraging discussion.
-- jt]]
>
>
In 1960, those two arguments were found to be in apparent
conflict, because if we allowed the gravitational calculation,
the associated intrinsic curvature would be present for both
the rotating and the non-rotating observers. This suggested
that the gravitational interpretation had priority and that
the SR interpretation wasn't fundamental, but was providing a
sort of rough "flat approximation" of effects that were
intrinsically curved-spacetime phenomena.
>
In late 1960 the community apparently decided that losing SR
wasn't acceptable, and standardised on the "SR" explanation
rather than the "curvature-based" one.
>
If we'd taken the other path and given the GPoR priority
over SR, then we'd have lost special relativity and would
have had to implement a curved-spacetime replacement, with
curvature effects being fundamental not only to relative
acceleration and relative rotation, but also to relative
velocity.
>
Nowadays (post-1960), we "know" that gravitational/
distortional effects don't play a part in everyday physics
because we "know" that SR is correct and that the GPoR
isn't to be taken too seriously. Where the GPoR and SR
generate similar predictions for an effect, we say that
the SR version is correct and the GPoR version is wrong,
and that the success of the SR explanation means that
there's nothing left for the GPoR to explain, and
therefore no measurable effect due to acceleration
(see: "SR clock hypothesis").
>
But this "knowledge" is based on interpretation rather
than raw phenomenology. We believe it because we grew up
in a society where SR was the norm.
>
If in 1960 the community had decided to take the other
"fork in the road" and had decided to support the GPoR
rather than SR, we'd now be saying with similar certainty
that that we "know" that distortional effects are strong
in rotation and and acceleration, that we "know" that
particle lifetimes in accelerator storage rings support
the GPoR rather than SR, and that we "know" that SR isn't
correct core theory.
>
You're right, I'm less interested in theories that are
completely identical to SR, or completely experimentally
indistinguishable from SR, and which don't obviously
lead to any new physics.
108 The two postulates in Special Relativity
From: Jos Bergervoet
Datum: Monday 16 may 2016
On 5/10/2016 12:07 PM, Eric Baird wrote:
>
On Saturday, 5 March 2016 15:12:33 UTC, Tom Roberts wrote:
...
- show quoted text -
Was this community able to to describe the in-spiraling of
two black holes and the ring-down after merger, by just
using SR? (And where in the universe is this community
located?)
>> >
On 2/28/16 2/28/16 2:39 AM, Eric Baird wrote:
>
If we'd taken the other path and given the GPoR priority
over SR, then we'd have lost special relativity
curvature effects being fundamental not only to relative
acceleration and relative rotation, but also to relative
velocity.
>
and would
have had to implement a curved-spacetime replacement, with
109 The two postulates in Special Relativity
From: Poutnik
Datum: Friday 20 may 2016
[[Mod. note --
1. I apologise for the delay in processing this article, which arrived
at my moderation inbox on monday 2016-05-16.
2. It's very important to distinguish between the following different
meanings of the word "observer":
- an inertial reference frame in the context of special relativity
- a *macroscopic* observer in the context of quantum mechanics
("an observation collapses the wave function")
- a worldline in general relativity
- a coordinate system in general relativity
-- jt]]
>
110 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Friday 20 may 2016
Op maandag 16 mei 2016 05:02:11 UTC+2 schreef Nicolaas Vroom:
>
Op dinsdag 10 mei 2016 12:07:07 UTC+2 schreef Eric Baird:
> >
1) The two final flashes arrive simultaneous.
2) The two final flashes do not arrive simultaneous.
The one which goes via the bottom first.
When the result is (2) the speed of light is not constant and you must
describe the experiment using GR. (GPoR)
111 The two postulates in Special Relativity
From: Poutnik
Datum: Saturday 21 may 2016
Thanks, yes, I am aware of that.
I was pointing out not to confuse
observers in physics with humans.
---------------------------------
>
[[Mod. note --
1. I apologise for the delay in processing this article, which arrived
at my moderation inbox on monday 2016-05-16.
2. It's very important to distinguish between the following different
meanings of the word "observer":
- an inertial reference frame in the context of special relativity
- a *macroscopic* observer in the context of quantum mechanics
("an observation collapses the wave function")
- a worldline in general relativity
- a coordinate system in general relativity
-- jt]]
>>
- show quoted text -
>
.... interesting.
112 The two postulates in Special Relativity
From: Tom Roberts
Datum: Sunday 22 may 2016
On 5/20/16 5/20/16 7:16 AM, Nicolaas Vroom wrote:
>
Consider the following experiment.
At point A you have a lightsource and a photon detector.
At point B a distance x away, there is a mirror.
With the lightsource you emit a flash at A which is reflected with the
mirror at B and detected with the photon detector at A.
All this sounds reasonable.
Next you place a second mirror at C. The distance A-B = B-C = x
You also place a mirror at A.
At A in stead of one flash you simultaneous emit two flashes.
The first flash goes from A to B back to A (reflection) to B and back to A.
The second flash goes from A to C (reflection) and back to A.
>
IMO because the distance is identical 4*(A-B) = 2*(A-C) they will arrive
simultaneous.
>
But there is more: you can move this setup in any direction horizontal
and the answer will be the same.
>
Ofcourse such an experiment in reality is extremely difficult
and the accuracy not very reliable.
>
Next we perform the same experiment but now in vertical direction.
* the experiment is performed on the surface of the earth
* the earth is a perfect sphere with its usual mass
* all other massive objects are ignored, as is the atmosphere
* all components are supported against gravity, on the surface
* horizontal means a constant altitude from the surface
* vertical means along a radius from the center of the earth
* the metric is static (follows from the above assumptions)
* the time coordinate is the timelike Killing vector
* all distance measurements are made along spacelike geodesics
orthogonal to the time coordinate
* All components are very close together compared to the radius
of the earth. In particular, within the apparatus the difference
between an initially horizontal spacelike geodesic and an
initially horizontal null geodesic is negligible (note that
neither is the "horizontal distance", but this assumption also
makes the difference to that be negligible).
>
There are two possible outcomes in principle:
1) The two final flashes arrive simultaneous.
2) The two final flashes do not arrive simultaneous.
When the result is (1) the speed of light is constant and you can
describe the experiment using SR.
>
When the result is (2) the speed of light is not constant and you must
describe the experiment using GR.
113 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Tuesday 24 may 2016
Op zondag 22 mei 2016 09:47:44 UTC+2 schreef Tom Roberts:
>
On 5/20/16 5/20/16 7:16 AM, Nicolaas Vroom wrote:
> >
Consider the following experiment.
At point A you have a lightsource and a photon detector.
At point B a distance x away, there is a mirror.
With the lightsource you emit a flash at A which is reflected with the
mirror at B and detected with the photon detector at A.
All this sounds reasonable.
Next you place a second mirror at C. The distance A-B = B-C = x
You also place a mirror at A.
' A--------------B--------------C
'Light Mirror Mirror
> >
At A in stead of one flash you simultaneous emit two flashes.
The first flash goes from A to B back to A to B and back to A.
The second flash goes from A to C (reflection) and back to A.
>
The two original lightflashes are at E0.
Via B the second detection at A is at E1
Via C the first detection at A is at E2
The question is are E1 and E2 simultaneous.
>
If I suppose that the distance A-C is twice A-B, then your description
is still incomplete; if I further suppose that all components are at
rest in an inertial frame in a region in which gravitation is
negligible, then the two flashes arrive at A simultaneously. [These
further suppositions permit me to apply SR in a simple and obvious
manner.]
>
> >
>
> >
But there is more: you can move this setup in any direction horizontal
and the answer will be the same.
>
> >
Next we perform the same experiment but now in vertical direction.
>
>
So I assume this means you don't want to make my further suppositions
above, and want to consider gravity to be important. This opens a very
large can of worms as one must apply GR.... As a simple example, there
is now no definite meaning to "distance A-B", and you must specify how
it is to be measured (i.e. along which spacelike geodesic; this is
directly related to choosing a time coordinate...). Remember that above
I had to suppose all components were at rest in some inertial frame,
which resolves this ambiguity for SR, but not for GR with non-negligible
gravity.
I agree
>
Explanation of this last: if two points have identical
altitudes, the (constant-time) spacelike geodesic along
which the distance between them is measured does not have
that altitude everywhere between them, and there is no
such thing as a "horizontal plane"; this assumption makes
the effect of that be negligible within the apparatus
and permits me to use a horizontal plane there.
I have difficulties in understanding this sentence.
>
If they are not in a horizontal plane, then the pulses
in general do NOT arrive simultaneously at A (for certain specific
situations they can, such as D-A-E forming a vertical "V").
In this case A is "high" above the surface of the earth and so is D
>
The pulse A->E->A will arrive before the pulse A->D->A.
In this case A is at the surface of the flat earth and so is D
>
If E is vertically below A, then A->E->A will arrive after A->D->A.
Both A-C and A-B are upward.
>
For your physical situation with A, B, and C along a straight line with
B midway between A and C, and the light traverses A-B four times and A-C
twice: if the line is horizontal the pulses arrive simultaneously;
if A-C is vertically upward, A->C->A arrives before A->B->A->B->A;
Both A-C and A-B are downward.
This is the situation I have in mind.
>
if A-C is vertically downward, A->C->A arrives after A->B->A->B->A.
The center idea is that incase of AB 4 times the same path (length) is
considered. In the case of AC this is also the situation.
However (downward) the difference is that in the case of AB
two times a path AB is considered and in the case of AC two times the path
BC is considered.
AB is rougly speaking high above the surface and BC low above the surface.
The issue is if this has any relation with the speed of light.
When the speed increases going from top to bottom this will mean that
light via C arrives earlier than light via B (at A)
When the speed decreases going from top to bottom this will mean that
light via C arrives later than light via B (at A)
>
Note all these non-simultaneous arrivals come far too close together to
actually measure in a real experiment with x less than a km or so. So
this must remain a gedanken unless possibly an interferometer setup can
be invented; the basic problem is comparing horizontal and vertical
distances to the required accuracy without using light (use light and
the result is fore-ordained).
> >
There are two possible outcomes in principle:
1) The two final flashes arrive simultaneous.
2) The two final flashes do not arrive simultaneous.
When the result is (1) the speed of light is constant and you can
describe the experiment using SR.
>
> >
>
Thanks
>
Tom Roberts
114 The two postulates in Special Relativity
From: Tom Roberts
Datum: Wednesday 1 june 2016
On 5/24/16 5/24/16 3:04 PM, Nicolaas Vroom wrote:
>
Op zondag 22 mei 2016 09:47:44 UTC+2 schreef Tom Roberts:
>>
[...]
' A--------------B--------------C
' Light Mirror Mirror
>>>
Next we perform the same experiment but now in vertical direction.
>
The idea is that the whole set up is in a vertical direction and that the
light signal first travels towards the center of the earth. [...] In this
case gravity has to be considered. Tricky
>>
if A-C is vertically downward, A->C->A arrives after A->B->A->B->A.
>
Both A-C and A-B are downward. This is the situation I have in mind.
>
You have to use GR for the vertical set up. That is what I have in mind to
challenge that the speed of light is constant.
>
However there is more it places the importance of GR above SR.
>
And you can ask yourself the question how important is the third postulate
proposed by Eric Baird.
115 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Sunday 5 june 2016
Op woensdag 1 juni 2016 07:04:42 UTC+2 schreef Tom Roberts:
>
On 5/24/16 5/24/16 3:04 PM, Nicolaas Vroom wrote:
> >>
if A-C is vertically downward, A->C->A arrives after A->B->A->B->A.
> >
Both A-C and A-B are downward. This is the situation I have in mind.
>
>
But I would NOT claim "light travels slower B-C than A-B". That would
be a PUN on "speed", because we normally reserve that word for measurements
in locally inertial frames. And also because we did not measure it.
>
Interesting observation: as in QM, in GR it is usually not possible to
discuss quantities which were not measured. Here the delays of pulses are
measured (compared) and I can make definitive statements about them;
but their speed is NOT measured, and I cannot make definite statements.
>
It is remarkable that the
two major revolutions in physics of the 20th century, quantum mechanics
and relativity, share this emphasis on measurements. But the reasons for
this similarity are QUITE different: in QM it is because such quantities
have no definite value, while in GR it happens because such statements
invariably involve a choice of coordinates, and such choices are
arbitrary
>
Why are measurements so "special" in GR? -- because they are
necessarily independent of coordinates. That is, every
measurement projects the quantity being measured onto the
measuring instrument. As you were taught in kindergarten, the
ruler must be aligned with the object to measure its length
(the ruler projects onto itself, and if not aligned the
projection will not be the desired result); this is inherently
a very general aspect of measuring instruments.
a constant this make certain things simpler and but also introduces
others: What is a meter or what is a second.
>
The vacuum speed of light measured in a locally inertial frame is c,
everywhere and everywhen. IMO this is a calculation. When you declare c
>
But if you choose to divide a distance by a flight time and call
the result "speed", even when the measurements are not in a locally
inertial frame, then OF COURSE you can obtain a result not equal to c.
Indeed GR predicts this (c.f the Shapiro time delay -- if you insist
on calling the result "speed" then of course it is not equal to c;
that's why it is termed a DELAY and not a "reduction in speed").
116 The two postulates in Special Relativity
From: John Heath
Datum: Wednesday 22 june 2016
[[Mod. note -- 141 excessively-quoted lines snipped here.
We can generally presume that readers have already read the previous
posts in this thread, so recapitulating it all merely burdens readers
with trying to find what's new. It's better to just quote the minimum
needed to establish the context of what you're going to say. -- jt]]
>
Sun? To answer that question IMO you have to divide the path in for
example 10 smaller parts with the same length and investigate each. In
the experiment I propose I try to answer that same question very close
to the earth by comparing two signals without the aid of a clock and
"no" mathematics.
117 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Thursday 30 june 2016
Op woensdag 22 juni 2016 03:23:17 UTC+2 schreef John Heath:
>
> >
>
>
Your only obligation to fulfill the postulate
of SR is to measure the speed of light to be c. This is not the
same as saying the speed of light is constant at c.
118 The two postulates in Special Relativity
From: Phillip Helbig
Datum: Friday 1 july 2016
In article <04c3fc41-22cb-43aa-b594-84fb25c038ae@googlegroups.com>,
Nicolaas Vroom
>
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
>
What is important as part of this discussion: what is the definition of
a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
But that does not exist in outerspace. In fact the whole universe is
filled with photons, which makes any definition based on vacuum
misleading(?)
>
A different reason, why the issue is important, is the program "VB
light" See: https://www.nicvroom.be/VB%20Light%20operation.htm
In this program light rays around matter are simulated, specific to
study: "The bending of light around matter". What this simulation shows
(based on Newton's Law) that the speed of light (photons) is not
constant.
119 The two postulates in Special Relativity
From: Oliver Jennrich
Datum: Saturday 2 july 2016
hel...@asclothestro.multivax.de (Phillip Helbig (undress to reply))
writes:
>
In article <04c3fc41-22cb-43aa-b594-84fb25c038ae@googlegroups.com>,
Nicolaas Vroom
>>
>
120 The two postulates in Special Relativity
From: Phillip Helbig
Datum: Saturday 2 july 2016
In article
>>>
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
>>
>
>
Now, the *concept* of a finite speed limit in the Universe is fully
independent of any actual physical realisation or, indeed, experimental
proof.
121 The two postulates in Special Relativity
From: Dr J R Stockton
Datum: Sunday 3 july 2016
In sci.physics.research message
>
In article <04c3fc41-22cb-43aa-b594-84fb25c038ae@googlegroups.com>,
Nicolaas Vroom
>>
...
>
...
>>
What is important as part of this discussion: what is the definition of
a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
>
The point is that any LOCAL measurement of the speed of light always
gives the same value.
122 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Sunday 3 july 2016
Op vrijdag 1 juli 2016 10:37:05 UTC+2 schreef Phillip Helbig:
>
In article <04c3fc41-22cb-43aa-b594-84fb25c038ae@googlegroups.com>,
Nicolaas Vroom
> >
>
> >
What is important as part of this discussion: what is the definition
of a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
But that does not exist in outerspace. In fact the whole universe is
filled with photons, which makes any definition based on vacuum
misleading(?)
>
> >
A different reason, why the issue is important, is the program "VB
light" See: https://www.nicvroom.be/VB%20Light%20operation.htm
In this program light rays around matter are simulated, specific to
study: "The bending of light around matter". What this simulation shows
(based on Newton's Law) that the speed of light (photons) is not
constant.
>
>
The point is that any LOCAL measurement of the speed of light always
gives the same value.
123 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 3 july 2016
Nicolaas Vroom wrote:
>
My understanding is that the speed will increase when the photons
approach the earth. In fact when you send a light signal from the sun
towards the earth, first the speed will decrease and than increase.
>
The problem with this whole discussion is that it belongs more in the
newsgroup :Sci.physics.foundations. However at this moment this is
impossible, because the newsgroup is temporary "out of order".
>
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
>
What is important as part of this discussion: what is the definition of
a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
But that does not exist in outerspace.
>
A different reason, why the issue is important, is the program "VB
light" See: https://www.nicvroom.be/VB%20Light%20operation.htm
In this program light rays around matter are simulated, specific to
study: "The bending of light around matter". What this simulation shows
(based on Newton's Law) that the speed of light (photons) is not
constant.
124 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Thursday 7 july 2016
Op zondag 3 juli 2016 15:41:50 UTC+2 schreef Gregor Scholten:
>
Nicolaas Vroom wrote:
> >
>
>
However, you could argue that an eventual solution for two centres of
gravity, like Sun and Earth, should in some way look similar to a
combination of two Schwarzschild solutions, at least in that way that
one should be able to find a coordinate system in which the speed of
light, measured with respect to that coordinate systems, shows the
behaviour you described.
> >
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
>
>
But even that is not really necessary. One could as well argue that
there should be a speed of light, let's call it c0, that would be the
speed of light in a hypothetical perfect vacuum. Then one could
postulate that this speed c0 is always the same, in all inertial frames,
and conclude that SR effects occur at velocities near this speed. From
the fact that we observe SR effects near the real speed of light that we
can factually measure in a real vacuum, let's call it c', we then can
conclude that both speeds, c0 and c', are very close to each other.
> >
A different reason, why the issue is important, is the program "VB
light" See: https://www.nicvroom.be/VB%20Light%20operation.htm
In this program light rays around matter are simulated, specific to
study: "The bending of light around matter". What this simulation shows
(based on Newton's Law) that the speed of light (photons) is not
constant.
>
>
And indeed, in GR, the speed of light turns out to be variable in some
way. Namely in that way, that the speed of light measured with respect
to a general coordinate system is variable. But not the speed of light
measured with respect to a local inertial frame.
125 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 10 july 2016
Nicolaas Vroom wrote:
>>>
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance
travelled by light in vacuum in 1/299792458 of a second."
The problem with this defintion is when the speed is not constant
the length of a metre also changes.
>>
>
>
As I said before this whole discussion belongs more in the newsgroup:
sci.physics.foundations.
When consider the above definition of a metre you must also define what
a second is
>
and such a second must also be a physical constant process.
We know by experiment that that is also difficult to establish.
>
A whole different physical issue the speed of gravition. It is physical
possible that this speed is much more "fixed" (stable?) than the speed
of light. In principle such a speed (if constant) is a better starting
point to define a metre.
>>>
What is important as part of this discussion: what is the definition
of a vacuum. Accordingly to: https://en.wikipedia.org/wiki/Vacuum :
"Vacuum is space void of matter"
But that does not exist in outerspace. In fact the whole universe is
filled with photons, which makes any definition based on vacuum
misleading(?)
>>
>
>
A different issue is than also always when you consider the speed of light
in any discussion it should be in a vacuum. The point is when the physical
state between the Sun and the earth is not a vacuum than you cannot use
the definition in order to measure distance.
>
(Of course for most
applications you can)
>>
The point is that any LOCAL measurement of the speed of light always
gives the same value.
>
126 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 10 july 2016
Nicolaas Vroom wrote:
>>>
My understanding is that the speed will increase when the photons
approach the earth. In fact when you send a light signal from the sun
towards the earth, first the speed will decrease and than increase.
>>
>
>>>
When you study: https://en.wikipedia.org/wiki/Speed_of_light you can
read: "the metre was redefined in the SI Units as the distance travelled
by light in vacuum in 1/299792458 of a second." The problem with this
defintion is when the speed is not constant the length of a metre also
changes.
>>
>
>>
But even that is not really necessary. One could as well argue that
there should be a speed of light, let's call it c0, that would be the
speed of light in a hypothetical perfect vacuum. Then one could
postulate that this speed c0 is always the same, in all inertial frames,
and conclude that SR effects occur at velocities near this speed. From
the fact that we observe SR effects near the real speed of light that we
can factually measure in a real vacuum, let's call it c', we then can
conclude that both speeds, c0 and c', are very close to each other.
>
>>
And indeed, in GR, the speed of light turns out to be variable in some
way. Namely in that way, that the speed of light measured with respect
to a general coordinate system is variable. But not the speed of light
measured with respect to a local inertial frame.
>
127 The two postulates in Special Relativity
From: Tom Roberts
Datum: Wednesday 13 july 2016
On 7/10/16 7/10/16 5:53 AM, Gregor Scholten wrote:
>
According to all our obversations, the speed of light is constant in
situations where the SR-limit of GR is applicable, i.e. where gravitational
effects can be neglected. So, obviously, it would be physically wrong to say
that the speed of light would vary in those situations.
>
Or did you want to ask for a theoretical explaination for the constancy of
the speed of light? Within the framework of Relativity (no matter if SR or
GR), the constancy of the speed of light is a fundamental postulate, i.e. it
is considered as a fundamental property of nature. So, it cannot be
explained (in the sense that it could be derived from a more fundamental
principle).
a) the Principle of Relativity
b) the definition of inertial frames (referenced in the PoR)
c) any experimental result that distinguishes SR from Newtonian physics,
such as: kilometer-long pion beams exist
In this approach, the constancy of the speed of light is not at all assumed, and
is due to an underlying symmetry of the world we inhabit. This approach has the
advantage of separating the geometry (SR) from electrodynamics, which is HIGHLY
desirable pedagogically.
>>
As I stated before it is primarily not my strategy to calculate the speed
of light. What I want to challenge is the idea that this speed is not
always the same. To do that I use one observer, two light sources, a tower,
and two mirrors at different heights.
>
128 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Monday 18 july 2016
On Wednesday, 13 July 2016 05:44:07 UTC+2, Tom Roberts wrote:
>
On 7/10/16 7/10/16 5:53 AM, Gregor Scholten wrote:
> >>
As I stated before it is primarily not my strategy to calculate the
speed of light. What I want to challenge is the idea that this speed
is not always the same. To do that I use one observer, two light
sources, a tower, and two mirrors at different heights.
Why do you call this a non-local set-up ?
What is the difference with a local set-up ?
> >
My prediction of the outcome is that the two reflections do not arrive
simultaneous. My question to the readers is if they agree with this.
If my prediction is correct than my interpretation is that the speed
of light is not always the same.
My question to the readers is, if they agree.
> >
And since it is well-known that the
speed of light is not constant in such a setup and that this is
in full agreement with GR (which claims that in a gravitational field,
the speed of light is constant only locally), you do not challenge
anything by this. Or at least no idea that is part of today's physics.
I agree with the opinion that the experiment can not be performed accurately
in practice using light signals.
>
Yes, assuming the measurement accuracy is sufficiently good to distinguish
the result from c -- that's not possible using current technology and any
existing tower. Boreholes are considerably "taller", but they are not
straight enough (not to mention the difficulty of lowering a vacuum pipe
several km long into one).
>
I cannot even devise an experiment to compare a horizontal and vertical
path in an interferometer to sufficient accuracy, due to the impossibility of
measuring distances accurately enough without using light, and the inevitable
strains in a "rigid" rod rotated between horizontal and vertical.
129 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Tuesday 19 july 2016
Tom Roberts wrote:
>>
Or did you want to ask for a theoretical explaination for the constancy of
the speed of light? Within the framework of Relativity (no matter if SR or
GR), the constancy of the speed of light is a fundamental postulate, i.e. it
is considered as a fundamental property of nature. So, it cannot be
explained (in the sense that it could be derived from a more fundamental
principle).
>
a) the Principle of Relativity
b) the definition of inertial frames (referenced in the PoR)
c) any experimental result that distinguishes SR from Newtonian physics,
such as: kilometer-long pion beams exist
>
In this approach, the constancy of the speed of light is not at all assumed, and
is due to an underlying symmetry of the world we inhabit. This approach has the
advantage of separating the geometry (SR) from electrodynamics
130 The two postulates in Special Relativity
From: Tom Roberts
Datum: Thursday 21 july 2016
On 7/18/16 7/18/16 - 6:13 PM, Gregor Scholten wrote:
>
Tom Roberts wrote:
>>
The equations of SR can be derived from: a) the Principle of Relativity b)
the definition of inertial frames (referenced in the PoR) c) any
experimental result that distinguishes SR from Newtonian physics, such as:
kilometer-long pion beams exist
>
* the Galilei group
* the Euclid group (in 4-d space+time)
* the Poincare' group
The first two are solidly refuted by literally zillions of experiments and
observations; the third is essentially SR.
>
Or do you want to say that we do not need any postulate at all any more
because we have experimental facts? That would be completely wrong, due to
the general structure of physical theories: a theory has to postulate
fundamental statements, and those statements or the statements that can be
derived from them have to be in agreement with the observations.
131 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Friday 22 july 2016
On Wednesday, 13 July 2016 05:44:07 UTC+2, Tom Roberts wrote:
>
On 7/10/16 7/10/16 5:53 AM, Gregor Scholten wrote:
> >
According to all our obversations, the speed of light is constant in
situations where the SR-limit of GR is applicable, i.e. where gravitational
effects can be neglected. So, obviously, it would be physically wrong to say
that the speed of light would vary in those situations.
>
>
Tom Roberts wrote:
> >>
> >
a) the Principle of Relativity
b) the definition of inertial frames (referenced in the PoR)
c) any experimental result that distinguishes SR from Newtonian physics,
such as: kilometer-long pion beams exist
>
Does that mean that you want to replace the postulate of the speed of
light being constant by the postulate that kilomer-long pion beams
exist?
>
That wouldn't be very straight-forward: such a posulate would be
much more special than the postulate of the speed of light being
constant and therefore doesn't match the requirement that postulates
have to be as general as possible.
>
And BTW: the existence of kilometer-long pion beams could be as well
explained by pions travelling 100 times faster than the light.
>
A funny
thing: when I first read about the long distance that pions travel
before decaying many years ago, I thought this should be a proof for
superluminal pions. It was only years later that I realized that this
should rather be a proof for time dilation ;)
132 The two postulates in Special Relativity
From: Tom Roberts
Datum: Friday 22 july 2016
On 7/18/16 7/18/16 11:44 AM, Nicolaas Vroom wrote:
>
On Wednesday, 13 July 2016 05:44:07 UTC+2, Tom Roberts wrote:
>>
On 7/10/16 7/10/16 5:53 AM, Gregor Scholten wrote:
>
Nicolaas Vroom wrote:
>>>>
As I stated before it is primarily not my strategy to calculate the
speed of light. What I want to challenge is the idea that this speed
is not always the same. To do that I use one observer, two light
sources, a tower, and two mirrors at different heights.
>>>
>
Why do you call this a non-local set-up ?
>
What is the difference with a local set-up ?
>
My prediction of the outcome is that the two reflections do not arrive
simultaneous. My question to the readers is if they agree with this.
>
If my prediction is correct than my interpretation is that the speed of
light is not always the same.
>
A whole different issue is, that I do not understand why GR claims that the
speed is constant locally when any practical application (for example the
forward movement of Mercury) is a global configuration?
133 The two postulates in Special Relativity
From: Phillip Helbig
Datum: Saturday 23 july 2016
Nicolaas Vroom
>
My interpretation of this is that both of you agree that the speed of
light is constant in situations where SR applies and not where GR
applies. My understanding is that when GR applies gravitational effects
can not be neglected. Which raises the question if both of you agree
that when GR applies the speed of light is not constant.
>
This question is of practical importance for almost all experiments
because in reality always gravitational effects are involved, specific
if you want to discuss the movement of physical objects.
>
A whole diferent issue the definition of what is a lightyear.
The distance is: 9460730472580800 metres (exactly) See:
https://en.wikipedia.org/wiki/Light-year
>
But that does not mean that the speed of light is always the same when
the distance between two objects is 1 lightyear (For a pulse which
travels that distance)
134 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Saturday 23 july 2016
On Friday, 22 July 2016 11:07:07 UTC+2, Tom Roberts wrote:
>
On 7/18/16 7/18/16 11:44 AM, Nicolaas Vroom wrote:
> >
On Wednesday, 13 July 2016 05:44:07 UTC+2, Tom Roberts wrote:
> >>
On 7/10/16 7/10/16 5:53 AM, Gregor Scholten wrote:
> >
Nicolaas Vroom wrote:
> >>>
In other words: you consider a non-local set-up.
> >
Why do you call this a non-local set-up ?
>
>
Your experiment explicitly requires a measurement resolution that can
distinguish the measured value from c. So you must use a region that is
not local.
>
From a principle point it only makes sense to discuss this situation.
> >
My prediction of the outcome is that the two reflections do not arrive
simultaneous. My question to the readers is if they agree with this.
>
>
I have considered very similar potential experiments. The limit
is not in measuring time differences between light rays, the
difficulty is in measuring the path lengths to the required
accuracy without using light.
> >
If my prediction is correct than my interpretation is that the speed of
light is not always the same.
>
135 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Monday 25 july 2016
On Saturday, 23 July 2016 22:21:36 UTC+2, Phillip Helbig wrote:
>
Nicolaas Vroom
> >
>
>
With
gravitation, one can interpret the speed as being constant and space
being stretched, or the speed slowing down. It doesn't matter how you
think about it as long as you get the correct result.
> >
This question is of practical importance for almost all experiments
because in reality always gravitational effects are involved, specific
if you want to discuss the movement of physical objects.
>
> >
A whole diferent issue the definition of what is a lightyear.
The distance is: 9460730472580800 metres (exactly) See:
https://en.wikipedia.org/wiki/Light-year
>
> >
But that does not mean that the speed of light is always the same when
the distance between two objects is 1 lightyear (For a pulse which
travels that distance)
>
136 The two postulates in Special Relativity
From: Dr J R Stockton
Datum: Sunday 31 july 2016
In sci.physics.research message
>
Nicolaas Vroom
>>
A whole diferent issue the definition of what is a lightyear.
The distance is: 9460730472580800 metres (exactly) See:
https://en.wikipedia.org/wiki/Light-year
>
137 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Sunday 7 augustus 2016
Nicolaas Vroom wrote:
>>>>
As I stated before it is primarily not my strategy to calculate the
speed of light. What I want to challenge is the idea that this speed
is not always the same. To do that I use one observer, two light
sources, a tower, and two mirrors at different heights.
>>>
>
Why do you call this a non-local set-up ?
What is the difference with a local set-up ?
>
A whole different issue is, that I do not understand why GR claims that
the speed is constant locally when any practical application (for
example the forward movement of Mercury) is a global configuration?
>>
Yes, assuming the measurement accuracy is sufficiently good to distinguish
the result from c -- that's not possible using current technology and any
existing tower. Boreholes are considerably "taller", but they are not
straight enough (not to mention the difficulty of lowering a vacuum pipe
several km long into one).
>
I agree with the opinion that the experiment can not be performed accurately
in practice using light signals.
138 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Monday 15 augustus 2016
On Sunday, 7 August 2016 07:32:41 UTC+2, Gregor Scholten wrote:
>
Nicolaas Vroom wrote:
> >>>>
> >>>
> >
Why do you call this a non-local set-up ?
What is the difference with a local set-up ?
>
As such light bending around a star (or any object) is non-local issue.
When gravitational effects are not considered distance and light
are a local issue. In such a scenario it makes sense to declare
the speed of light a constant.
> >>
Yes, assuming the measurement accuracy is sufficiently good to distinguish
the result from c -- that's not possible using current technology and any
existing tower. Boreholes are considerably "taller", but they are not
straight enough (not to mention the difficulty of lowering a vacuum pipe
several km long into one).
> >
I agree with the opinion that the experiment can not be performed accurately
in practice using light signals.
>
For more info: https://en.wikipedia.org/wiki/One-way_speed_of_light
What this means that one way speed of light experiments are IMO also
thought experiments.
139 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Monday 29 augustus 2016
Am 15.08.2016 um 09:28 schrieb Nicolaas Vroom:
>>>
Why do you call this a non-local set-up ?
What is the difference with a local set-up ?
>>
>
>>>>
Yes, assuming the measurement accuracy is sufficiently good to distinguish
the result from c -- that's not possible using current technology and any
existing tower. Boreholes are considerably "taller", but they are not
straight enough (not to mention the difficulty of lowering a vacuum pipe
several km long into one).
>>>
I agree with the opinion that the experiment can not be performed accurately
in practice using light signals.
>>
>
140 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Saturday 29 october 2016
On Monday, 29 August 2016 22:46:05 UTC+2, Gregor Scholten wrote:
>
Am 15.08.2016 um 09:28 schrieb Nicolaas Vroom:
> >>>
I agree with the opinion that the experiment can not be performed
accurately in practice using light signals.
> >>
> >
I agree that you can call this a thought experiment, but that does not
mean that we can not discuss what the outcome of this experiment
could be.
>
>
141 The two postulates in Special Relativity
From: Tom Roberts
Datum: Tuesday 8 november 2016
On 10/29/16 10/29/16 - 5:17 AM, Nicolaas Vroom wrote:
>
And if that is the case the speed of light cannot be called constant.
142 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Sunday 13 november 2016
On Tuesday, 8 November 2016 09:14:57 UTC+1, Tom Roberts wrote:
>
You keep bringing up an overly simplistic statement that comes from SPECIAL
relativity over a century ago. We have learned A LOT since then,
including the
fact that the vacuum speed of light is not always c. But for most physical
situations of interest the difference between the actual speed and c is too
small to measure.
1) What is the speed of light?
To define the speed of light as a constant and equal to 299792458 m/sec is
okay for normal applications, but is not a complete answer on this question.
I'am well aware that the specific conditions (vacuum) and how the speed
is measured, should be mentioned.
2) Is the speed of light constant?
I mean by that going from A to B any where in the universe is the speed
always the same. This question is simpler as question 1.
I'am even willingly to conclude that the speed of light is not constant
when gravitation is involved.
143 The two postulates in Special Relativity
From: Phillip Helbig
Datum: Sunday 13 november 2016
In article
> >
You keep bringing up an overly simplistic statement that comes from SPECIAL
relativity over a century ago. We have learned A LOT since then,
including the
fact that the vacuum speed of light is not always c. But for most physical
situations of interest the difference between the actual speed and c is too
small to measure.
>
>
To define the speed of light as a constant and equal to 299792458 m/sec is
okay for normal applications, but is not a complete answer on this question.
>
I'am well aware that the specific conditions (vacuum) and how the speed
is measured, should be mentioned.
>
2) Is the speed of light constant?
>
I mean by that going from A to B any where in the universe is the speed
always the same. This question is simpler as question 1.
>
My interpretation of the comments above is that the speed of light
is not always c when gravitation is important.
>
I'am even willingly to conclude that the speed of light is not constant
when gravitation is involved.
>
When I study https://en.wikipedia.org/wiki/Speed_of_light IMO they only
mention that: the speed of light in vacuum (=c) is a physical constant.
144 The two postulates in Special Relativity
From: Roland Franzius
Datum: Sunday 13 november 2016
Translate message into English
- show quoted text -
c ist the constant multipliying the time variable in the wave equation
145 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Wednesday 16 november 2016
Nicolaas Vroom
>>
You keep bringing up an overly simplistic statement that comes from
SPECIAL relativity over a century ago. We have learned A LOT since
then, including the
fact that the vacuum speed of light is not always c. But for most
physical situations of interest the difference between the actual
speed and c is too small to measure.
>
>
To define the speed of light as a constant and equal to 299792458
m/sec is okay for normal applications
>
but is not a complete answer on
this question.
>
2) Is the speed of light constant?
I mean by that going from A to B any where in the universe is the
speed always the same. This question is simpler as question 1.
>
I'am even willingly to conclude that the speed of light is not
constant when gravitation is involved.
>
When I study https://en.wikipedia.org/wiki/Speed_of_light IMO they
only mention that: the speed of light in vacuum (=c) is a physical
constant.
>
Should this document not be updated to reflect the opinion that the
(vacuum) speed of light is not always c, specific when gravitation is
important?
146 The two postulates in Special Relativity
From: Poutnik
Datum: Wednesday 16 november 2016
Translate message into English
Dne 16/11/2016 v 06:48 Gregor Scholten napsal(a):
>
Nicolaas Vroom
>>>
>>
>
147 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Friday 18 november 2016
Nicolaas Vroom
>
On Monday, 29 August 2016 22:46:05 UTC+2, Gregor Scholten wrote:
>>
Am 15.08.2016 um 09:28 schrieb Nicolaas Vroom:
>
>> >>>
>> >>
>
>
>> >
>>
>
>
In the newsgroup sci,astro
In the post: "Link between dark matter and baryonic matter"
>>
>
148 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Friday 18 november 2016
On Sunday, 13 November 2016 17:43:04 UTC+1, Phillip Helbig wrote:
>
In article
> > >
> >
>
> >
>
> >
>
> >
>
> >
>
>
The answer is: no, it is not.
> >
>
> >
>
> >
>
149 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Friday 18 november 2016
Poutnik
>>>
I can only agree with you: that this should be obvious.
I doubt however if my statement or reasoning is overly simplistic.
In fact I have two questions:
1) What is the speed of light?
>>
>
>
The phase and group speed can be higher than c.
>
Light beam propagation speed
can be lower than c even for vacuum,
if the beam has a special spatial structure
and nonzero orbital angular momentum.
150 The two postulates in Special Relativity
From: Poutnik
Datum: Monday 21 november 2016
Dne 18/11/2016 v 02:41 Gregor Scholten napsal(a):
>
Poutnik
>>
>
>
>>
>
>
>>
>
"Subluminal group velocity and dispersion of Laguerre Gauss beams
in free space"
http://dx.doi.org/10.1038/srep26842
http://www.nature.com/articles/srep26842
is (remarkably for a paper in a Nature-group journal) open-access!
-- jt]]
- show quoted text -
151 The two postulates in Special Relativity
From: Maryann Tonn
Datum: Monday 21 november 2016
Poutnik wrote:
>
Dne 18/11/2016 v 02:41 Gregor Scholten napsal(a):
>>
Poutnik
>>>
>>
>
>>>
The phase and group speed can be higher than c.
>>
>
152 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Wednesday 30 november 2016
On Wednesday, 16 November 2016 06:48:37 UTC+1, Gregor Scholten wrote:
>
Nicolaas Vroom
> >
>
' x1(t) = + R * cos(omega*t) x2(t) = - R * cos(omega*t)
' y1(t) = + R * sin(omega*t) y2(t) = - R * sin(omega*t)
' z1(t) = 0 z2(t) = 0
Now think about doing a GR analysis of this same system? (Why) is it
suddenly a good idea to attach my coordinates to one of the stars?
-- jt]]
> >
Should this document not be updated to reflect the opinion that the
(vacuum) speed of light is not always c, specific when gravitation is
important?
>
153 The two postulates in Special Relativity
From: Gregor Scholten
Datum: Saturday 1 october 2016
Nicolaas Vroom
>> >
2) Is the speed of light constant?
I mean by that going from A to B any where in the universe is the
speed always the same. This question is simpler as question 1.
>>
>
>
Is there a local inertial frame.?
>
IMO in both cases you should take one star as the center of your
coordinate system.
154 The two postulates in Special Relativity
From: Nicolaas Vroom
Datum: Monday 5 december 2016
On Wednesday, 30 November 2016 18:42:49 UTC+1, Nicolaas Vroom wrote:
>
What does this specific say if you want to simulate the planets
around the sun or a small collections of star.
Is there a free-falling observer?
Is there a local inertial frame.?
IMO in both cases you should take one star as the center of your
coordinate system.
' x1(t) = + R * cos(omega*t) x2(t) = - R * cos(omega*t)
' y1(t) = + R * sin(omega*t) y2(t) = - R * sin(omega*t)
' z1(t) = 0 z2(t) = 0
>
Now think about doing a GR analysis of this same system? (Why) is it
suddenly a good idea to attach my coordinates to one of the stars?
-- jt]]